Truth Table Flashcards: Connectives & Logical Equivalence

84 truth-table flashcards on logical connectives, material conditionals, nested expressions, equivalence, and counterexamples, with short explanations.

O tomto balíčku

Practice propositional logic with 84 English truth-table flashcards. The set covers NOT (¬), AND (∧), inclusive OR (∨), exclusive OR (⊕), the material conditional (→), and the biconditional (↔). T means true and F means false. It suits learners starting formal logic or discrete mathematics.

Cards ask you to recall a connective’s truth conditions, identify a connective from its full rule, evaluate an expression from a stated assignment, and produce short output columns with an explicit row order. A few original statement-to-symbol tasks and one symbol-to-statement task connect the notation to English. Later cards practice De Morgan’s laws, double negation, conditional rewriting, biconditional and XOR expansions, negated conditionals, and the distinction between a conditional, its converse, inverse, and contrapositive.

The sequence introduces notation and simple connectives before nested expressions, logical equivalence, counterexamples, and tautology/contradiction/contingency classification. Selected equivalences have separate forward and reverse cards, placed apart. Answers start with the result and give a short reason. For a counterexample task, any assignment that makes the two outputs differ is a valid answer.

This is a focused practice set, not a full logic course or an exam syllabus. It excludes quantified statements, proof systems, circuits, and programming-language evaluation rules. It does not ask for a connective from a lone truth value, which would be ambiguous, or repeat every possible symbolic and English permutation. Material implication is used as a truth-functional rule; the cards do not treat it as a theory of causation or every everyday use of “if”.

For a short introduction, read truth values, conjunction and disjunction. For study habits, see how to use flashcards for math.

The questions, answers, examples, order, metadata, and cover were independently created with AI assistance. Logic facts were checked against the open textbook forall x: Calgary, especially its chapters on connective truth tables, complete truth tables, and semantic concepts, and by direct truth-value calculation. No textbook exercises, teaching prose, diagrams, examination questions, or competitor cards were copied. The original text and generated cover are released under CC0 1.0 to the extent applicable rights exist; reference-source text retains its own license. This is an independent resource, unaffiliated with the Open Logic Project or any school or examination provider.

Kartičky v tomto balíčku

  1. Kartička 1

    Otázka

    In classical propositional logic, what is a proposition?

    Odpoveď

    A statement with a truth value: true or false. A question or command is not a proposition in this setting.

  2. Kartička 2

    Otázka

    What does negation (¬p) do to the truth value of p?

    Odpoveď

    It reverses it: true becomes false, and false becomes true.

  3. Kartička 3

    Otázka

    When is the conjunction (p ∧ q) true?

    Odpoveď

    Only when p and q are both true.

  4. Kartička 4

    Otázka

    When is the inclusive disjunction (p ∨ q) true?

    Odpoveď

    When at least one of p and q is true, including when both are true.

  5. Kartička 5

    Otázka

    What does one valuation assign in a propositional truth table?

    Odpoveď

    One truth value to each proposition letter. The assignment stays fixed throughout that row.

  6. Kartička 6

    Otázka

    When is the material conditional (p → q) false?

    Odpoveď

    Only when p is true and q is false. Here p is the antecedent and q is the consequent.

  7. Kartička 7

    Otázka

    When is the biconditional (p ↔ q) true?

    Odpoveď

    When p and q have the same truth value: both true or both false.

  8. Kartička 8

    Otázka

    When is exclusive OR (p ⊕ q) true?

    Odpoveď

    When exactly one of p and q is true. It is false when their truth values match.

  9. Kartička 9

    Otázka

    What is the main connective in ((¬p) ∧ q)?

    Odpoveď

    ∧ (AND). It combines the whole left part, (¬p), with q.

  10. Kartička 10

    Otázka

    How many rows does a complete truth table with three distinct proposition letters need?

    Odpoveď

    8 rows: each of the three letters has two choices, so 2³ = 8.

  11. Kartička 11

    Otázka

    If p = F, what is (¬p)?

    Odpoveď

    T. Negation reverses F to T.

  12. Kartička 12

    Otázka

    If p = T and q = F, what is (p ∧ q)?

    Odpoveď

    F. AND needs both inputs to be true.

  13. Kartička 13

    Otázka

    If p = T and q = T, what is inclusive OR (p ∨ q)?

    Odpoveď

    T. Inclusive OR allows both inputs to be true.

  14. Kartička 14

    Otázka

    If p = T and q = T, what is the material conditional (p → q)?

    Odpoveď

    T. A true antecedent with a true consequent does not make the conditional false.

  15. Kartička 15

    Otázka

    If p = F and q = F, what is (p ↔ q)?

    Odpoveď

    T. The two truth values match, even though neither is true.

  16. Kartička 16

    Otázka

    If p = T and q = T, what is exclusive OR (p ⊕ q)?

    Odpoveď

    F. XOR requires exactly one true input.

  17. Kartička 17

    Otázka

    Does a true material conditional (p → q) establish that p causes q?

    Odpoveď

    No. Material implication is determined by truth values; it does not establish causation or capture every everyday use of “if”.

  18. Kartička 18

    Otázka

    What assignments are listed by the two-letter row order TT, TF, FT, FF?

    Odpoveď

    (p, q) = (T, T), (T, F), (F, T), (F, F). Each possible assignment appears once.

  19. Kartička 19

    Otázka

    In ¬(p ∨ q), does ¬ negate just p or the whole disjunction?

    Odpoveď

    The whole disjunction (p ∨ q). Evaluate that parenthesized expression before negating it.

  20. Kartička 20

    Otázka

    If p = F and q = T, what is the material conditional (p → q)?

    Odpoveď

    T. A material conditional with a false antecedent is true.

  21. Kartička 21

    Otázka

    If p = T and q = F, what is (p ↔ q)?

    Odpoveď

    F. The two truth values differ.

  22. Kartička 22

    Otázka

    If p = T and q = F, what is exclusive OR (p ⊕ q)?

    Odpoveď

    T. Exactly one input is true.

  23. Kartička 23

    Otázka

    Which standard connective is true exactly when both inputs are true?

    Odpoveď

    Conjunction (AND), written ∧.

  24. Kartička 24

    Otázka

    Which standard connective is false exactly when both inputs are false?

    Odpoveď

    Inclusive disjunction (OR), written ∨. The both-true case is true.

  25. Kartička 25

    Otázka

    Which standard connective takes one input and reverses its truth value?

    Odpoveď

    Negation (NOT), written ¬.

  26. Kartička 26

    Otázka

    If p = F and q = F, what is the material conditional (p → q)?

    Odpoveď

    T. Its only false case requires a true antecedent and a false consequent.

  27. Kartička 27

    Otázka

    Which standard connective is true exactly when its two inputs have matching truth values?

    Odpoveď

    The biconditional (if and only if), written ↔.

  28. Kartička 28

    Otázka

    Which standard connective is true exactly when its two inputs have different truth values?

    Odpoveď

    Exclusive OR (XOR), written ⊕.

  29. Kartička 29

    Otázka

    What is the main connective in ((p ∨ q) → (¬r))?

    Odpoveď

    → (the material conditional). The entire disjunction is the antecedent, and (¬r) is the consequent.

  30. Kartička 30

    Otázka

    Which standard connective is false exactly when its first input is true and its second input is false?

    Odpoveď

    The material conditional, written →. Input order matters.

  31. Kartička 31

    Otázka

    Give the output column for (p ∧ q), with (p, q) rows TT, TF, FT, FF.

    Odpoveď

    T, F, F, F. Only the both-true row satisfies AND.

  32. Kartička 32

    Otázka

    If p = T and q = F, what is ¬(p ∧ q)?

    Odpoveď

    T. First (p ∧ q) is F; negating it gives T.

  33. Kartička 33

    Otázka

    Let a mean “the archive is open” and b mean “the desk is staffed”. Symbolize “the archive is open and the desk is staffed”.

    Odpoveď

    (a ∧ b). Both statements are asserted.

  34. Kartička 34

    Otázka

    Give the output column for the material conditional (p → q), with (p, q) rows TT, TF, FT, FF.

    Odpoveď

    T, F, T, T. Only the true-antecedent, false-consequent row fails.

  35. Kartička 35

    Otázka

    What makes a formula a tautology in classical propositional logic?

    Odpoveď

    It is true on every possible valuation, not just the row currently being checked.

  36. Kartička 36

    Otázka

    Give the output column for inclusive OR (p ∨ q), with (p, q) rows TT, TF, FT, FF.

    Odpoveď

    T, T, T, F. Only the both-false row fails inclusive OR.

  37. Kartička 37

    Otázka

    When are two propositional formulas logically equivalent?

    Odpoveď

    When their final truth values match on every valuation of their combined proposition letters.

  38. Kartička 38

    Otázka

    Give the output column for (p ↔ q), with (p, q) rows TT, TF, FT, FF.

    Odpoveď

    T, F, F, T. The first and last rows have matching truth values.

  39. Kartička 39

    Otázka

    If p = F and q = T, what is (p ∨ (¬q)), using inclusive OR?

    Odpoveď

    F. Both p and (¬q) are F.

  40. Kartička 40

    Otázka

    If p = T and q = F, what is the material conditional (p → q)?

    Odpoveď

    F. This is its only false input combination.

  41. Kartička 41

    Otázka

    Give the output column for (¬p), with p rows T, F.

    Odpoveď

    F, T. Negation reverses each row.

  42. Kartička 42

    Otázka

    Let s mean “the scan succeeds” and a mean “the alert appears”. Symbolize “if the scan succeeds, the alert appears”, using material implication.

    Odpoveď

    (s → a). The scan statement is the antecedent; the alert statement is the consequent.

  43. Kartička 43

    Otázka

    Give the output column for exclusive OR (p ⊕ q), with (p, q) rows TT, TF, FT, FF.

    Odpoveď

    F, T, T, F. Exactly one input is true in the middle two rows.

  44. Kartička 44

    Otázka

    What makes a formula a contradiction in classical propositional logic?

    Odpoveď

    It is false on every possible valuation.

  45. Kartička 45

    Otázka

    If p = T, q = F and r = T, what is ((p ∧ q) ∨ r), using inclusive OR?

    Odpoveď

    T. The conjunction is F, but r is T, so the disjunction is T.

  46. Kartička 46

    Otázka

    Simplify ¬(¬p) without changing its truth value.

    Odpoveď

    p. Two negations restore the original truth value.

  47. Kartička 47

    Otázka

    Let d mean “the door is unlocked” and c mean “the code is accepted”. Symbolize “the door is unlocked if and only if the code is accepted”.

    Odpoveď

    (d ↔ c). Both directions of the conditional are required.

  48. Kartička 48

    Otázka

    What makes a propositional formula contingent?

    Odpoveď

    It is true on at least one valuation and false on at least one other valuation.

  49. Kartička 49

    Otázka

    If p = T and q = T, what is (p → (¬q)), using material implication?

    Odpoveď

    F. Its antecedent is T and its consequent (¬q) is F.

  50. Kartička 50

    Otázka

    Use De Morgan’s law to rewrite ¬(p ∧ q) with negations only on letters.

    Odpoveď

    ((¬p) ∨ (¬q)). At least one conjunct must be false; ∨ is inclusive OR.

  51. Kartička 51

    Otázka

    Let n mean “the north path is open” and e mean “the east path is open”. Symbolize “at least one of these paths is open, possibly both”.

    Odpoveď

    (n ∨ e). This is inclusive OR.

  52. Kartička 52

    Otázka

    Classify (p ∨ (¬p)): tautology, contradiction or contingent? Use classical logic and inclusive OR.

    Odpoveď

    Tautology. Whether p is T or F, one disjunct is T.

  53. Kartička 53

    Otázka

    If p = F and q = F, what is ¬(p ∨ q), using inclusive OR?

    Odpoveď

    T. The disjunction is F, so its negation is T.

  54. Kartička 54

    Otázka

    Use De Morgan’s law to rewrite ¬(p ∨ q) with negations only on letters. Use inclusive OR.

    Odpoveď

    ((¬p) ∧ (¬q)). Both disjuncts must be false.

  55. Kartička 55

    Otázka

    Let w mean “the window is closed” and h mean “the heater is on”. Read (h → w) as an English material conditional.

    Odpoveď

    If the heater is on, then the window is closed. The formula itself makes no causal claim.

  56. Kartička 56

    Otázka

    Classify (p ∧ (¬p)): tautology, contradiction or contingent?

    Odpoveď

    Contradiction. The two conjuncts cannot both be true on any valuation.

  57. Kartička 57

    Otázka

    Rewrite the material conditional (p → q) using only NOT and inclusive OR.

    Odpoveď

    ((¬p) ∨ q). It is false exactly when p is T and q is F.

  58. Kartička 58

    Otázka

    If p = T, q = T and r = F, what is ((p ⊕ q) ↔ r), where ⊕ is exclusive OR?

    Odpoveď

    T. The XOR is F and r is F, so the biconditional compares matching values.

  59. Kartička 59

    Otázka

    Write an expression with exactly two NOT operators that is equivalent to p.

    Odpoveď

    ¬(¬p). Negating twice leaves every truth value unchanged.

  60. Kartička 60

    Otázka

    Classify (p ∧ q): tautology, contradiction or contingent?

    Odpoveď

    Contingent. It is T at p = T, q = T and F at p = F, q = T.

  61. Kartička 61

    Otázka

    What is the contrapositive of the material conditional (p → q)?

    Odpoveď

    ((¬q) → (¬p)). Swap the two sides and negate both.

  62. Kartička 62

    Otázka

    Rewrite ¬(p → q) using AND and NOT, with → meaning material implication.

    Odpoveď

    (p ∧ (¬q)). A material conditional fails exactly when its antecedent is true and its consequent is false.

  63. Kartička 63

    Otázka

    Rewrite ((¬p) ∨ (¬q)) as one negation of a conjunction, using inclusive OR.

    Odpoveď

    ¬(p ∧ q). This is De Morgan’s law in the reverse direction.

  64. Kartička 64

    Otázka

    Give the output column for (p ∨ (¬q)), with (p, q) rows TT, TF, FT, FF and inclusive OR.

    Odpoveď

    T, T, F, T. The only false row has p = F and q = T.

  65. Kartička 65

    Otázka

    What is the converse of (p → q)?

    Odpoveď

    (q → p). Swap the antecedent and consequent without negating either.

  66. Kartička 66

    Otázka

    Rewrite (p ↔ q) as an AND of two material conditionals.

    Odpoveď

    ((p → q) ∧ (q → p)). Both directions must hold.

  67. Kartička 67

    Otázka

    Rewrite ((¬p) ∧ (¬q)) as one negation of an inclusive disjunction.

    Odpoveď

    ¬(p ∨ q). This is De Morgan’s law in the reverse direction.

  68. Kartička 68

    Otázka

    Give one valuation showing that (p ∨ q) and (p ∧ q) are not equivalent. Use inclusive OR.

    Odpoveď

    p = T, q = F gives T for the OR and F for the AND. The swapped assignment also works.

  69. Kartička 69

    Otázka

    What is the inverse of (p → q)?

    Odpoveď

    ((¬p) → (¬q)). Negate both sides without swapping them.

  70. Kartička 70

    Otázka

    Rewrite ((¬p) ∨ q) as a single material conditional, using inclusive OR.

    Odpoveď

    (p → q). Both expressions fail exactly when p is T and q is F.

  71. Kartička 71

    Otázka

    Rewrite exclusive OR (p ⊕ q) using AND, inclusive OR and NOT.

    Odpoveď

    ((p ∨ q) ∧ ¬(p ∧ q)). Require at least one true input and rule out both being true.

  72. Kartička 72

    Otázka

    A formula is true for p = T and q = F. Is that enough to call it a tautology?

    Odpoveď

    No. A tautology must be true on every valuation. One true row establishes only that it can be true.

  73. Kartička 73

    Otázka

    Is a material conditional (p → q) logically equivalent to its contrapositive ((¬q) → (¬p))?

    Odpoveď

    Yes. Both are false exactly when p is T and q is F.

  74. Kartička 74

    Otázka

    Give one valuation showing that (p → q) and its converse (q → p) are not equivalent. Use material implication.

    Odpoveď

    p = T, q = F. Then (p → q) is F and (q → p) is T.

  75. Kartička 75

    Otázka

    Rewrite ((p → q) ∧ (q → p)) using one connective, with both arrows meaning material implication.

    Odpoveď

    (p ↔ q). This is the biconditional.

  76. Kartička 76

    Otázka

    What does one valuation with different outputs prove about two formulas?

    Odpoveď

    They are not logically equivalent. Equivalence requires agreement on every valuation.

  77. Kartička 77

    Otázka

    Give one valuation showing that (p → q) and its inverse ((¬p) → (¬q)) are not equivalent. Use material implication.

    Odpoveď

    p = T, q = F. The original is F, while the inverse has a false antecedent and is T.

  78. Kartička 78

    Otázka

    Give one valuation showing that ¬(p ∧ q) and ((¬p) ∧ (¬q)) are not equivalent.

    Odpoveď

    p = T, q = F. The negated conjunction is T; the conjunction of negations is F.

  79. Kartička 79

    Otázka

    Which connective does ((p ∨ q) ∧ ¬(p ∧ q)) express? Here ∨ is inclusive OR.

    Odpoveď

    Exclusive OR: (p ⊕ q). Exactly one input must be true.

  80. Kartička 80

    Otázka

    If (p ↔ q) is true on one row, does that show that the formulas p and q are logically equivalent?

    Odpoveď

    No. They match on that row only. Logical equivalence requires the biconditional to be true on every valuation.

  81. Kartička 81

    Otázka

    Are the converse (q → p) and inverse ((¬p) → (¬q)) of (p → q) equivalent to each other? Use material implication.

    Odpoveď

    Yes. They are contrapositives of each other, and both are false exactly when q is T and p is F.

  82. Kartička 82

    Otázka

    At p = T, q = F and r = F, compare ((p ∨ q) ∧ r) with (p ∨ (q ∧ r)). Use inclusive OR.

    Odpoveď

    The first is F; the second is T. Parentheses change which operations combine first.

  83. Kartička 83

    Otázka

    Rewrite (p ∧ (¬q)) as the negation of one material conditional.

    Odpoveď

    ¬(p → q). The conjunction describes exactly the conditional’s false case.

  84. Kartička 84

    Otázka

    Among AND (∧), inclusive OR (∨), XOR (⊕), material conditional (→) and biconditional (↔), which has outputs T, F, F, T for (p, q) rows TT, TF, FT, FF?

    Odpoveď

    Biconditional (↔). It is true on the two rows where the inputs match.

The AND, OR and NOT symbols on a navy study tile, with light and dark tokens on an ivory background.

84 kartičiek

Truth Table Flashcards: Connectives & Logical Equivalence

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