Coding Interview Patterns Flashcards: Signals, Invariants & Complexity

Practice coding interview patterns with 210 English flashcards on problem signals, invariants, complexity, edge cases, and choosing between approaches. Language-agnostic DSA review to pair with hands-on coding.

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Coding interview patterns become useful when you can explain why an approach fits. These 210 English flashcards practice recognizing problem signals, stating invariants, checking prerequisites, comparing approaches, and diagnosing a broken assumption.

The sequence starts with constraints and complexity, then moves through arrays, strings, hashing, two pointers, sliding windows, prefix sums, binary search, intervals, stacks, linked lists, trees, heaps, tries, graphs, union-find, topological sorting, backtracking, greedy choices, dynamic programming, and bit techniques. Each topic builds from its basic idea toward the conditions that make it work.

Cards map short scenarios to candidate patterns, named patterns to invariants and costs, and failed assumptions to explanations or alternatives. Selected contrast prompts distinguish neighboring ideas such as subarrays and subsequences, BFS and DFS, or greedy choice and dynamic programming. Mechanical reverse cards, problem-number recall, language-specific API memorization, and full solution listings are excluded because they add little to this reasoning-focused review. Answer each prompt before turning the card, then test the idea by coding a fresh example.

This is a language-agnostic companion to practical DSA exercises. It complements the Blind 75 Python solutions deck by teaching reusable reasoning across problems. It was authored independently in English, not translated or paraphrased from another catalog package.

The questions, answers, organization, metadata, and original generated cover are released under CC0 1.0 to the extent applicable rights exist. Algorithm facts are common knowledge; no commercial deck text or third-party media was copied. This is an independent study resource with no affiliation to an employer or interview platform.

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  1. Kortti 1

    Kysymys

    Which input constraints should you clarify before choosing an interview algorithm?

    Vastaus

    Input size, value range, ordering, duplicates, allowed mutations, and the exact output. These determine which operations are affordable and which assumptions are valid.

  2. Kortti 2

    Kysymys

    What does a loop invariant describe?

    Vastaus

    A property that holds at a defined point in every iteration. Show it holds initially, survives an iteration, and implies the result when the loop ends.

  3. Kortti 3

    Kysymys

    When analyzing nested loops, why can multiplying their written bounds overestimate runtime?

    Vastaus

    The loops may share progress. If an inner pointer only advances across the input once, its total work can be O(n), even inside an outer loop.

  4. Kortti 4

    Kysymys

    What is the difference between auxiliary space and total space?

    Vastaus

    Auxiliary space counts extra working storage. Total space also includes the input and, depending on the stated convention, the output. State which measure you report.

  5. Kortti 5

    Kysymys

    What does amortized O(1) mean for an operation sequence?

    Vastaus

    The total cost of m operations is O(m), even if some individual operations are expensive. It is a sequence-wide bound, not a probability claim.

  6. Kortti 6

    Kysymys

    How does a counterexample help evaluate a proposed greedy rule?

    Vastaus

    One valid input where the rule fails disproves it. Try small cases that force a locally attractive choice to block a better later choice.

  7. Kortti 7

    Kysymys

    Why should an algorithm's correctness argument address termination separately?

    Vastaus

    Preserving the right property is not enough if the loop never stops. Identify a bounded measure that moves strictly toward termination.

  8. Kortti 8

    Kysymys

    What runtime lower bound follows from returning k separate results?

    Vastaus

    At least Ω(k) time to emit them, or more if each result has multiple elements. Include output size when analyzing enumeration algorithms.

  9. Kortti 9

    Kysymys

    What should you say when quoting expected O(1) hash-table lookup?

    Vastaus

    It assumes a suitable hash distribution and controlled load factor. It is not a worst-case guarantee; hashing a long key can also cost time.

  10. Kortti 10

    Kysymys

    Which edge cases best expose index and boundary errors?

    Vastaus

    Empty input, one element, all equal elements, and answers at either end. Also check the smallest input that enters each branch.

  11. Kortti 11

    Kysymys

    Why can sorting be an invalid optimization even when it reduces later search work?

    Vastaus

    Sorting may destroy required order or original indices. Preserve the needed information or choose an approach that respects the input contract.

  12. Kortti 12

    Kysymys

    What does an exchange argument establish in a greedy proof?

    Vastaus

    That an optimal solution can be changed to include the greedy choice without making its objective worse. The remaining problem must still fit the same reasoning.

  13. Kortti 13

    Kysymys

    Why can recursion use O(n) space even without an explicit collection?

    Vastaus

    Each active call occupies a stack frame. A chain of n calls can therefore need O(n) auxiliary space.

  14. Kortti 14

    Kysymys

    What evidence should accompany a faster solution after presenting brute force?

    Vastaus

    Name the repeated work or discarded search space, explain why the shortcut is safe, and give the resulting time and space bounds.

  15. Kortti 15

    Kysymys

    What makes an array useful when a problem repeatedly accesses positions by index?

    Vastaus

    Constant-time indexed access in the usual RAM model. Inserting or removing near the front can still require shifting O(n) elements.

  16. Kortti 16

    Kysymys

    What should 'one character' mean before solving a string problem?

    Vastaus

    Clarify whether the unit is a byte, code unit, Unicode code point, or user-perceived character. Indexing and length depend on that choice.

  17. Kortti 17

    Kysymys

    An unsorted array needs a duplicate-existence check. Which structure fits?

    Vastaus

    A hash set of values seen so far. Stop when a value is already present; expected O(n) time and O(n) space.

  18. Kortti 18

    Kysymys

    For two-sum on an unsorted array, what should a hash map store?

    Vastaus

    Previously seen values mapped to their indices. For each value x, look for target − x before inserting x, so the same position is not reused.

  19. Kortti 19

    Kysymys

    When does a frequency array beat a hash map for counting?

    Vastaus

    When keys come from a small known integer or character range. Direct indexing gives predictable access with space proportional to that range.

  20. Kortti 20

    Kysymys

    Why is repeated concatenation risky when constructing a long immutable string?

    Vastaus

    Each append may copy the existing prefix, producing quadratic total work. Collect pieces and join them, or use an appropriate mutable builder.

  21. Kortti 21

    Kysymys

    How can you group anagrams without comparing every pair of words?

    Vastaus

    Map a canonical character signature to a group. Sorted characters work; a frequency tuple works when the alphabet and character rules are fixed.

  22. Kortti 22

    Kysymys

    What information does a set lose compared with a frequency map?

    Vastaus

    Multiplicity. A set can answer whether a value exists but cannot distinguish one occurrence from several.

  23. Kortti 23

    Kysymys

    How can a hash set support finding the longest consecutive integer run in expected O(n) time?

    Vastaus

    Start scanning a run only at values whose predecessor is absent. Each distinct value then belongs to one forward scan; iterate distinct values.

  24. Kortti 24

    Kysymys

    Why can a mutable object be a dangerous hash-map key?

    Vastaus

    Changing fields used by its hash or equality can make the stored entry unreachable by ordinary lookup. Use immutable keys or stable key values.

  25. Kortti 25

    Kysymys

    An array contains only integers from 0 through k. When is counting sort attractive?

    Vastaus

    When k is small enough: count each value and reconstruct the order in O(n + k) time with O(k) count storage. General arbitrary keys need another approach.

  26. Kortti 26

    Kysymys

    How can a single scan find both the minimum value and its earliest index?

    Vastaus

    Keep the current minimum and index; update only on a strictly smaller value. Updating on equality would select a later occurrence.

  27. Kortti 27

    Kysymys

    How do you compare two strings as multisets of characters?

    Vastaus

    Compare character counts under the same character interpretation. Order does not matter, but every character's multiplicity does.

  28. Kortti 28

    Kysymys

    Why does a hash collision not imply that two keys are equal?

    Vastaus

    A hash compresses many possible keys into fewer codes. A correct table also checks key equality when resolving collisions.

  29. Kortti 29

    Kysymys

    When is sorting a useful preprocessing step for detecting duplicate values?

    Vastaus

    When reordering is allowed and O(n log n) time is acceptable. Equal values become adjacent, so a scan finds duplicates without a separate hash set.

  30. Kortti 30

    Kysymys

    What is the key distinction between a subarray and a subsequence?

    Vastaus

    A subarray is contiguous. A subsequence preserves relative order but may skip positions. Sliding-window methods usually depend on contiguity.

  31. Kortti 31

    Kysymys

    For an unsorted two-sum query, how do hashing and sorting trade off?

    Vastaus

    Hashing gives expected O(n) time with O(n) extra storage. Sorting plus two pointers costs O(n log n) time and requires care with original indices and mutation.

  32. Kortti 32

    Kysymys

    How can a frequency map detect whether any permutation of a string can be a palindrome?

    Vastaus

    Count odd frequencies. At most one character may have an odd count; all other occurrences must form mirrored pairs.

  33. Kortti 33

    Kysymys

    Why must compound hash keys encode boundaries unambiguously?

    Vastaus

    Naive concatenation can merge different tuples into the same key, such as (1, 23) and (12, 3). Use tuples or a length-aware encoding.

  34. Kortti 34

    Kysymys

    What does coordinate compression preserve about numeric values?

    Vastaus

    Their relative order and equality, by replacing distinct sorted values with ranks. It does not preserve numeric distances or sums.

  35. Kortti 35

    Kysymys

    How can you compute products except self without division?

    Vastaus

    Combine the product strictly before each position with the product strictly after it. Prefix and suffix passes handle zeros; use a numeric type large enough for the products.

  36. Kortti 36

    Kysymys

    Why can a count of matching pairs overflow even when every input value fits in an integer?

    Vastaus

    The number of matching pairs can grow quadratically with the input length. Size the result type for the count, not just the input values.

  37. Kortti 37

    Kysymys

    A sorted array needs a pair with a target sum. Which search pattern fits?

    Vastaus

    Opposite-end two pointers. Compare the endpoint sum with the target and move the endpoint that can move the sum in the needed direction.

  38. Kortti 38

    Kysymys

    What invariant supports in-place removal of unwanted array values with read and write pointers?

    Vastaus

    The prefix before write contains exactly the retained values from the processed input, in order. Read scans every input position once.

  39. Kortti 39

    Kysymys

    How can two pointers check a palindrome without constructing a reversed string?

    Vastaus

    Compare matching elements from opposite ends and move inward. Any mismatch rejects it; the pointers meeting or crossing completes the check.

  40. Kortti 40

    Kysymys

    When does a fixed-size sliding window apply?

    Vastaus

    When every candidate is a contiguous block of the same length and its summary can be updated as one element enters and one leaves.

  41. Kortti 41

    Kysymys

    What invariant should a longest-window algorithm restore after adding a new rightmost element?

    Vastaus

    The current window satisfies the required constraint. Move the left boundary and update state until validity returns, then consider its length.

  42. Kortti 42

    Kysymys

    Why is moving the left pointer safe when a sorted-array endpoint sum is too small?

    Vastaus

    With that left value, every candidate at or before the current right endpoint gives an equally small or smaller sum. The left position cannot form a valid pair.

  43. Kortti 43

    Kysymys

    How does a three-way partition maintain separate regions?

    Vastaus

    Track a low region, a middle region, an unclassified region, and a high region. Each step shrinks the unclassified region by placing one element correctly.

  44. Kortti 44

    Kysymys

    How do you update the sum when a fixed-size window moves one position?

    Vastaus

    Subtract the outgoing value and add the incoming value. After initializing the first window, all moves together take O(n) time.

  45. Kortti 45

    Kysymys

    Why can a variable sliding window run in O(n) despite a nested shrink loop?

    Vastaus

    Each boundary advances at most n times. With constant-time state updates, the total number of additions and removals is linear.

  46. Kortti 46

    Kysymys

    For the longest substring without repeated characters, what window state is useful?

    Vastaus

    Character counts or last-seen positions. Move the left boundary past the conflicting occurrence while ensuring it never moves backward.

  47. Kortti 47

    Kysymys

    Why does opposite-end target-sum search fail on a generally unsorted array?

    Vastaus

    Moving an endpoint no longer changes the sum predictably. The algorithm can discard a valid pair because the order-based elimination proof is missing.

  48. Kortti 48

    Kysymys

    A positive-number array needs the shortest nonempty subarray with sum at least a positive T. When should the left boundary move?

    Vastaus

    While the current sum is at least T, record the length and remove the leftmost value. Positive values make further shrinking reduce the sum predictably.

  49. Kortti 49

    Kysymys

    For windows with at most k distinct values, what must happen when an outgoing count becomes zero?

    Vastaus

    Remove that value from the active distinct set or decrement the distinct counter. A zero count must not still count as present.

  50. Kortti 50

    Kysymys

    What changes when a fixed-window length exceeds the input length?

    Vastaus

    There is no complete window. Return the contract's empty or missing-result value instead of treating a partial block as a valid candidate.

  51. Kortti 51

    Kysymys

    How do you merge two sorted arrays with forward pointers?

    Vastaus

    Repeatedly take the smaller unconsumed element, then append the remaining suffix. Each element is consumed once, giving O(m + n) time.

  52. Kortti 52

    Kysymys

    Why must a minimum-cover substring track multiplicities of required characters?

    Vastaus

    A target can require the same character more than once. A set of required characters would mark an undersupplied window as complete.

  53. Kortti 53

    Kysymys

    How can counting subarrays with exactly k distinct values, for k ≥ 1, use an at-most helper?

    Vastaus

    Compute atMost(k) − atMost(k − 1). The helper counts all valid subarrays ending at each right boundary after restoring the distinct-value limit.

  54. Kortti 54

    Kysymys

    Why can a negative value break the usual shortest-sum sliding-window argument?

    Vastaus

    Removing it increases the sum, and adding one can decrease the sum. The monotonic relation between window size and sum no longer holds.

  55. Kortti 55

    Kysymys

    What does 'fast and slow pointers' mean when removing duplicates from a sorted array?

    Vastaus

    A read pointer scans candidates while a write pointer marks the next unique slot. Sorting makes equal values adjacent, so the retained prefix can stay compact.

  56. Kortti 56

    Kysymys

    What invariant prevents overwriting unread data during a backward merge into spare array capacity?

    Vastaus

    The suffix after the write pointer already contains the largest merged elements. Filling from the end leaves the remaining source elements unread and intact.

  57. Kortti 57

    Kysymys

    Why is 'find a contiguous range' alone insufficient to justify a variable sliding window?

    Vastaus

    You also need a safe boundary-movement rule. Check how adding and removing elements affect the condition; contiguity by itself gives no such guarantee.

  58. Kortti 58

    Kysymys

    After restoring an at-most window's validity, why are there right − left + 1 valid subarrays ending at right?

    Vastaus

    Every suffix starting between left and right is valid when removing elements cannot violate the constraint. Count those starts, including the one-element suffix.

  59. Kortti 59

    Kysymys

    How can you avoid duplicate value pairs in a sorted two-pointer enumeration?

    Vastaus

    After emitting a pair, skip equal values on both sides. First confirm the output wants unique value pairs, since index-pair counting needs different handling.

  60. Kortti 60

    Kysymys

    When does a character-frequency sliding window detect an anagram of a pattern?

    Vastaus

    When the window has the pattern's length and identical character counts. Maintain count differences or a mismatch counter as the window moves.

  61. Kortti 61

    Kysymys

    What does a prefix-sum array P mean when P[0] = 0?

    Vastaus

    P[i] is the sum of the first i input elements. The extra zero represents the empty prefix and makes ranges beginning at index 0 work uniformly.

  62. Kortti 62

    Kysymys

    When is binary search valid on a Boolean predicate over ordered candidates?

    Vastaus

    When the predicate changes at most once, such as false then true. The search uses that monotonic boundary to discard a whole interval.

  63. Kortti 63

    Kysymys

    Which workload favors a difference array?

    Vastaus

    Many range additions followed by final value reconstruction. Mark each range's start and end changes, then take one prefix sum.

  64. Kortti 64

    Kysymys

    In a lower-bound search over [lo, hi), what does hi initially equal for an n-element array?

    Vastaus

    n, an exclusive boundary. The result can equal n when no element is at least the target, so do not index the array without checking.

  65. Kortti 65

    Kysymys

    For a static array, how do prefix sums answer the half-open range [l, r)?

    Vastaus

    Return P[r] − P[l]. Building P takes O(n) time and space; each range-sum query then takes O(1).

  66. Kortti 66

    Kysymys

    How can prefix sums count subarrays whose sum equals k when negative values are allowed?

    Vastaus

    For each current prefix p, add the number of earlier prefixes equal to p − k, then record p. A frequency map gives expected O(n) time.

  67. Kortti 67

    Kysymys

    Why is binary-searching an answer different from binary-searching an input array?

    Vastaus

    The candidates are possible result values. A feasibility check tells which side contains the boundary, even if the original input is unsorted.

  68. Kortti 68

    Kysymys

    How does a difference array encode an addition of v to [l, r)?

    Vastaus

    Add v at l and subtract v at r, using a boundary slot when needed. The reconstructed prefix totals apply v only within that range.

  69. Kortti 69

    Kysymys

    For lower bound, how should equality with the target move the search boundary?

    Vastaus

    Move hi to mid. An equal element is a candidate, but an earlier equal or qualifying element may still exist.

  70. Kortti 70

    Kysymys

    Why initialize the prefix-frequency map with zero appearing once?

    Vastaus

    It represents the empty prefix before the array. This lets a subarray starting at index 0 contribute to the count.

  71. Kortti 71

    Kysymys

    Why are plain prefix sums inconvenient for many interleaved point updates and range-sum queries?

    Vastaus

    Changing one value can invalidate a long suffix of prefix sums. A Fenwick tree or segment tree can support both operations in O(log n).

  72. Kortti 72

    Kysymys

    How can you binary-search the minimum capacity needed to finish ordered work within a deadline?

    Vastaus

    Define whether a capacity suffices, prove larger capacities remain feasible, bracket a feasible answer, and search for the first feasible capacity.

  73. Kortti 73

    Kysymys

    What must every binary-search iteration do to guarantee termination?

    Vastaus

    Strictly shrink the candidate interval while preserving the boundary invariant. Mixing inclusive and exclusive update rules can leave the same interval unchanged.

  74. Kortti 74

    Kysymys

    For the longest subarray with a specified sum, which occurrence of each prefix sum should you retain?

    Vastaus

    The earliest index. For a later endpoint, it gives the longest matching span; overwriting it with a later occurrence can shorten the answer.

  75. Kortti 75

    Kysymys

    What runtime should you report for binary search with a nonconstant feasibility check?

    Vastaus

    O(C log R), where C is one check's cost and R is the number of discrete candidates. Include any preprocessing separately.

  76. Kortti 76

    Kysymys

    How can prefix sums turn a longest balanced binary subarray into an equal-prefix problem?

    Vastaus

    Map one symbol to +1 and the other to −1. Equal prefix sums enclose a zero-sum range with equal counts of the two symbols.

  77. Kortti 77

    Kysymys

    What is upper bound in a sorted array?

    Vastaus

    The first position whose value is strictly greater than the target, or n if none exists. Lower bound instead finds the first value at least the target.

  78. Kortti 78

    Kysymys

    Why must a prefix-sum counting algorithm query before recording the current prefix?

    Vastaus

    Recording first can count the empty subarray ending at the current boundary, especially for target zero. Query only earlier prefixes for nonempty ranges.

  79. Kortti 79

    Kysymys

    How do you safely compute a midpoint in a fixed-width integer search?

    Vastaus

    Use lo + (hi − lo) / 2 with integer division when the nonnegative difference fits the type. Choose bounds or a wider type that also keep the subtraction safe.

  80. Kortti 80

    Kysymys

    Why can duplicate values degrade searching a rotated sorted array to O(n)?

    Vastaus

    Equal endpoints and midpoint can hide which side is sorted. Some cases permit discarding only one boundary element at a time.

  81. Kortti 81

    Kysymys

    What preprocessing usually simplifies merging overlapping intervals?

    Vastaus

    Sort by start coordinate. Keep the current merged interval and either extend its end or emit it when the next interval starts beyond it.

  82. Kortti 82

    Kysymys

    Which data structure matches nested bracket validation?

    Vastaus

    A stack of unmatched opening brackets. Each closing bracket must match the most recent unmatched opener, and the stack must be empty at the end.

  83. Kortti 83

    Kysymys

    A problem asks for each element's next greater element. Which pattern is promising?

    Vastaus

    A monotonic stack of unresolved positions. A new larger value resolves the smaller pending values it overtakes.

  84. Kortti 84

    Kysymys

    Why must interval endpoint conventions be explicit?

    Vastaus

    Touching endpoints overlap for closed intervals, but adjacent half-open intervals do not. The convention changes merge tests and event ordering.

  85. Kortti 85

    Kysymys

    How can a sweep line find the maximum number of simultaneous intervals?

    Vastaus

    Turn starts and ends into signed events, sort by coordinate, and track the running active count. Handle same-coordinate ties according to the endpoint convention.

  86. Kortti 86

    Kysymys

    Why is one pass after sorting enough to merge intervals?

    Vastaus

    No later interval starts earlier than the next one being inspected. Once that start is beyond the current end, future intervals cannot bridge the gap.

  87. Kortti 87

    Kysymys

    What information should a stack store for next-greater distances?

    Vastaus

    Indices, so the distance is currentIndex − previousIndex. Values alone do not identify positions or distinguish repeated occurrences.

  88. Kortti 88

    Kysymys

    Why is counting opening and closing brackets insufficient to validate their sequence?

    Vastaus

    Counts ignore order and nesting. A closing bracket may appear before its opener, or bracket types may cross despite balanced totals.

  89. Kortti 89

    Kysymys

    For half-open intervals [start, end), how should equal-time starts and ends affect room counts?

    Vastaus

    Process ends before starts, or aggregate their net change before evaluating the active count for the next segment. A room freed at time t can be reused at t.

  90. Kortti 90

    Kysymys

    Why is a monotonic-stack algorithm often O(n) even though one step can pop many items?

    Vastaus

    Each item is pushed once and popped at most once. Summed across the scan, stack operations are linear.

  91. Kortti 91

    Kysymys

    How can a stack help simplify an absolute filesystem path lexically?

    Vastaus

    Process components: ignore empty components and '.', pop for '..' when possible, and push ordinary names. This lexical result does not resolve symbolic links.

  92. Kortti 92

    Kysymys

    How can a monotonic deque find each sliding-window maximum?

    Vastaus

    Keep candidate indices in decreasing value order. Remove expired indices from the front and dominated values from the back; the front gives the maximum.

  93. Kortti 93

    Kysymys

    What mistake can lose coverage when merging an interval contained inside the current one?

    Vastaus

    Replacing the current end with the new end. Use the larger end so a nested interval cannot shrink the merged coverage.

  94. Kortti 94

    Kysymys

    For a strictly next-greater query, what should happen to an equal-valued stack entry?

    Vastaus

    Do not resolve it with the equal value. With a decreasing stack of unresolved indices, pop only when the new value is strictly greater.

  95. Kortti 95

    Kysymys

    What event allows a monotonic stack to finalize a rectangle in a histogram?

    Vastaus

    A shorter bar supplies a right limit for taller bars being popped. A popped bar's candidate span starts after the new stack top, or at index 0 if the stack is empty. Handle equal heights consistently.

  96. Kortti 96

    Kysymys

    What comparison detects overlap between two nonempty half-open intervals?

    Vastaus

    max(start1, start2) < min(end1, end2). A strict comparison excludes intervals that only touch.

  97. Kortti 97

    Kysymys

    How does a stack support evaluating a postfix arithmetic expression?

    Vastaus

    Push operands; for an operator, pop its right operand and then its left operand, compute, and push the result. Preserve order for subtraction and division.

  98. Kortti 98

    Kysymys

    Why can a newer value dominate an older value in a sliding-window maximum deque?

    Vastaus

    If the newer value is at least as large, it expires no earlier and is never worse as a future maximum. The older candidate can be removed.

  99. Kortti 99

    Kysymys

    How can you merge two already sorted lists of disjoint intervals to find their intersections?

    Vastaus

    Compare one interval from each list, emit any overlap, then advance the one with the earlier end. Total time is O(m + n).

  100. Kortti 100

    Kysymys

    Why must a histogram stack algorithm handle bars still pending after the scan?

    Vastaus

    Those bars may extend to the array's end and contain the largest rectangle. Flush them using the end boundary or a suitable sentinel.

  101. Kortti 101

    Kysymys

    What must you save before reversing a singly linked list node's next pointer?

    Vastaus

    Its original next node. Otherwise rewiring can lose access to the remaining list.

  102. Kortti 102

    Kysymys

    Why does a dummy head simplify linked-list insertion and deletion?

    Vastaus

    It supplies a predecessor even when the real head changes. The same pointer update can handle both the first node and interior nodes.

  103. Kortti 103

    Kysymys

    How do fast and slow pointers detect a cycle in a singly linked list?

    Vastaus

    Advance one pointer one step and the other two. A meeting implies a cycle; reaching null with the fast pointer means the list terminates.

  104. Kortti 104

    Kysymys

    What does a recursive binary-tree traversal use for auxiliary space?

    Vastaus

    O(h) call-stack space, where h is tree height. This is O(log n) for a balanced tree but O(n) for a chain.

  105. Kortti 105

    Kysymys

    During iterative list reversal, what do prev and current represent?

    Vastaus

    prev heads the reversed processed prefix; current heads the unprocessed suffix. Rewire one node while preserving access to the suffix.

    An abstract row of teal and amber tiles connects to a branching tree and a small network of nodes on a dark blue background.

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    Coding Interview Patterns Flashcards: Signals, Invariants & Complexity

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  106. Kortti 106

    Kysymys

    How can you remove the nth node from the end of a list in one pass?

    Vastaus

    Start lead at the head and lag at a dummy head. Advance lead n nodes, then move both until lead is null; remove lag.next. Reject invalid n according to the input contract.

  107. Kortti 107

    Kysymys

    Which tree traversal naturally computes a value that depends on both children's results?

    Vastaus

    Postorder. Process left and right subtrees before combining their results at the parent.

  108. Kortti 108

    Kysymys

    How can you locate a cycle's entry after Floyd's two-speed pointers meet?

    Vastaus

    Reset one pointer to the head and move both one step at a time. Their next meeting is the entry; this follows from the distances modulo the cycle length.

  109. Kortti 109

    Kysymys

    What is the difference between tree depth and tree height?

    Vastaus

    Depth measures distance from the root to a node; height measures the longest downward distance to a leaf. State whether distances count edges or nodes.

  110. Kortti 110

    Kysymys

    How can you merge two sorted linked lists using O(1) auxiliary node storage?

    Vastaus

    Relink the smaller current node onto the result tail, advancing that list. Attach the remaining suffix when one list ends; existing nodes are reused.

  111. Kortti 111

    Kysymys

    When is breadth-first traversal more natural than depth-first traversal on a tree?

    Vastaus

    When results are grouped by depth or you need the nearest qualifying node by edge count. A queue processes one distance layer before the next.

  112. Kortti 112

    Kysymys

    Why must linked-list intersection compare node identity rather than node value?

    Vastaus

    Intersection means sharing the same node object and suffix. Separate nodes can hold equal values without the lists intersecting.

  113. Kortti 113

    Kysymys

    Why is checking only immediate children insufficient to validate a binary search tree?

    Vastaus

    A descendant can satisfy its parent yet violate an ancestor's constraint. Carry inherited lower and upper bounds, with an explicit duplicate policy.

  114. Kortti 114

    Kysymys

    What is the lowest common ancestor of two nodes in a rooted tree?

    Vastaus

    The deepest node that is an ancestor of both, allowing a node to be its own ancestor.

  115. Kortti 115

    Kysymys

    What property makes inorder traversal useful in a binary search tree?

    Vastaus

    It visits keys in sorted order under the tree's duplicate policy. In a strict BST, each visited key must be greater than the previous one.

  116. Kortti 116

    Kysymys

    Why must maximum tree-path sum separate its returned value from its global candidate?

    Vastaus

    The parent can extend only one downward branch. A complete path considered at the current node may join both children, but that fork cannot be extended upward.

  117. Kortti 117

    Kysymys

    How can two pointers find the intersection of two acyclic singly linked lists without measuring lengths?

    Vastaus

    After reaching a list's end, switch that pointer to the other head. Each traverses both lengths, so they meet at the shared node or at null.

  118. Kortti 118

    Kysymys

    What extra information makes preorder serialization unambiguous for an arbitrary binary tree?

    Vastaus

    Explicit null-child markers or another equivalent shape encoding. Values in preorder alone do not determine the structure.

  119. Kortti 119

    Kysymys

    Why can repeated subtree-height calculations make a tree-balance check O(n²)?

    Vastaus

    The same descendants may be scanned from many ancestors. Return height and balance together in one postorder traversal to visit each node once.

  120. Kortti 120

    Kysymys

    How does BST ordering guide a lowest-common-ancestor search for two existing distinct keys?

    Vastaus

    Move left if both keys are smaller and right if both are larger. The first split, or a node matching one key, is their lowest common ancestor.

  121. Kortti 121

    Kysymys

    What runtime does a search in an ordinary unbalanced BST guarantee?

    Vastaus

    O(h), where h is its height, and O(n) in the worst case. Logarithmic search requires a balance guarantee or a stated expected-shape assumption.

  122. Kortti 122

    Kysymys

    When computing a root-to-leaf path sum, why is reaching a null child insufficient for success?

    Vastaus

    A valid endpoint must be a leaf with no children. A missing child beside an existing child does not finish a root-to-leaf path.

  123. Kortti 123

    Kysymys

    What does a min-heap guarantee about its root and children?

    Vastaus

    The root is a minimum element, and each parent is no larger than its children. The whole array representation is not sorted.

  124. Kortti 124

    Kysymys

    A stream needs the k largest values seen so far. Which heap should you maintain?

    Vastaus

    A min-heap of at most k values. Its root is the smallest retained value, so a larger arrival can replace it.

  125. Kortti 125

    Kysymys

    What shared structure does a trie store?

    Vastaus

    Prefixes of keys. Following one edge per symbol reaches a key's prefix node, while a terminal marker distinguishes a complete stored key.

  126. Kortti 126

    Kysymys

    What are the usual binary-heap costs for peek, insertion, and root removal?

    Vastaus

    Peek is O(1); insertion and root removal are O(log n). Moving a changed element along one root-to-leaf path restores heap order.

  127. Kortti 127

    Kysymys

    How can a heap merge k sorted input streams?

    Vastaus

    Keep each nonempty stream's next element in a min-heap. Emit the minimum and replace it with that stream's next item. With k streams and N total elements, O(k + N log k) time includes initialization for k ≥ 2.

  128. Kortti 128

    Kysymys

    Why is bottom-up heap construction O(n), not O(n log n)?

    Vastaus

    Most nodes are near the leaves and can move only a short distance. Summing each node's possible sift-down work across all heights is linear.

  129. Kortti 129

    Kysymys

    How do two heaps support a running median?

    Vastaus

    Keep the lower half in a max-heap and the upper half in a min-heap, with sizes differing by at most one and every lower value no greater than every upper value.

  130. Kortti 130

    Kysymys

    What is a trie's lookup cost for a key of length L?

    Vastaus

    O(L) when each child transition is O(1). Child maps or ordered child containers can change that transition cost; space depends on stored prefixes and representation.

  131. Kortti 131

    Kysymys

    Why does a trie node need a terminal marker even if it has children?

    Vastaus

    A stored key can be a prefix of another key. The marker distinguishes a complete word from a prefix that merely leads to longer words.

  132. Kortti 132

    Kysymys

    When does sorting make more sense than a top-k heap?

    Vastaus

    When you need the entire sorted order or k is close to n and a full sort is acceptable. A heap's advantage is strongest when only a small retained subset is needed.

  133. Kortti 133

    Kysymys

    Why does a priority queue not by itself support efficient arbitrary deletion?

    Vastaus

    The heap efficiently exposes only its root. Removing another item needs its position, an indexed-heap design, or a lazy-deletion scheme with cleanup.

  134. Kortti 134

    Kysymys

    What output cost remains after a trie reaches a requested prefix?

    Vastaus

    Enumerating matching completions still costs time proportional to the visited subtree and emitted text. Prefix lookup does not make all autocomplete results free.

  135. Kortti 135

    Kysymys

    How can a priority queue break tied priorities without comparing the payloads?

    Vastaus

    Attach a unique increasing sequence number and compare priority first, then sequence number. Equal-priority items can then leave in insertion order without requiring an order on their payloads.

  136. Kortti 136

    Kysymys

    Why can a trie use more memory than a hash set of complete strings?

    Vastaus

    Nodes and child containers have overhead, especially for sparse branches. Shared prefixes save repeated symbols but do not guarantee a smaller representation.

  137. Kortti 137

    Kysymys

    What should graph modeling identify before choosing a traversal?

    Vastaus

    The states as vertices and legal transitions as edges, including direction and cost. A grid cell, word, or puzzle configuration can be a vertex.

  138. Kortti 138

    Kysymys

    When does ordinary BFS find a shortest path?

    Vastaus

    When every edge has the same nonnegative cost, including the unweighted case. Processing vertices by distance layer makes first discovery a shortest-edge-count path.

  139. Kortti 139

    Kysymys

    What is the space cost of an adjacency list compared with an adjacency matrix?

    Vastaus

    A list uses O(V + E) space; a matrix uses O(V²). A matrix gives constant-time edge lookup, while lists efficiently enumerate actual neighbors.

  140. Kortti 140

    Kysymys

    Which pattern finds all vertices reachable from a start vertex?

    Vastaus

    DFS or BFS with a visited set. Each reachable vertex and edge is processed a bounded number of times with adjacency lists.

  141. Kortti 141

    Kysymys

    What role does a parent map play in shortest-path traversal?

    Vastaus

    It records the predecessor used to reach each state. After reaching the target, follow parents backward and reverse the sequence to recover a path.

  142. Kortti 142

    Kysymys

    Why should BFS mark a vertex visited when enqueuing it?

    Vastaus

    To prevent several parents from adding it before its first removal. First enqueue already fixes its distance in an unweighted graph.

  143. Kortti 143

    Kysymys

    When is Dijkstra's algorithm appropriate?

    Vastaus

    For shortest paths with nonnegative edge weights. Its greedy finalization relies on no later path reducing a settled distance through a negative edge.

  144. Kortti 144

    Kysymys

    How can a grid traversal avoid confusing physical cells with full search states?

    Vastaus

    Include all information that changes future moves in the visited key, such as remaining obstacle removals or collected keys. Position alone may merge different states.

  145. Kortti 145

    Kysymys

    How do you detect a directed cycle with DFS?

    Vastaus

    Track unvisited, active, and finished vertices. An edge to an active vertex closes a cycle on the current recursion path.

  146. Kortti 146

    Kysymys

    Why can DFS with a visited set fail to find a shortest unweighted path?

    Vastaus

    Its first discovered route may follow a deep detour. DFS reachability order is not distance order; BFS provides that guarantee.

  147. Kortti 147

    Kysymys

    What does a topological ordering guarantee?

    Vastaus

    For every directed edge u → v, u appears before v. Such an ordering exists exactly when the directed graph is acyclic.

  148. Kortti 148

    Kysymys

    Why should stale priority-queue entries be skipped in a common Dijkstra implementation?

    Vastaus

    A vertex can receive a better distance after an older entry was pushed. Skip an entry whose stored distance differs from the current best distance.

  149. Kortti 149

    Kysymys

    For an undirected simple graph, why does DFS ignore the edge back to its parent when detecting cycles?

    Vastaus

    That edge is the same tree edge traversed in reverse, not a new cycle. A different already-visited neighbor indicates a cycle.

  150. Kortti 150

    Kysymys

    What does union-find answer efficiently?

    Vastaus

    Whether elements belong to the same connected component while components are merged. It does not store the actual connecting paths.

  151. Kortti 151

    Kysymys

    How does Kahn's algorithm build a topological ordering?

    Vastaus

    Enqueue all zero-indegree vertices, repeatedly remove one, and decrement its outgoing neighbors' indegrees. Enqueue each neighbor when its indegree becomes zero.

  152. Kortti 152

    Kysymys

    Which shortest-path algorithm handles edges weighted only 0 or 1 without a heap?

    Vastaus

    0–1 BFS with a deque. Push a relaxed zero-cost neighbor to the front and a one-cost neighbor to the back, preserving distance order.

  153. Kortti 153

    Kysymys

    Why is a boolean visited flag usually wrong for Dijkstra at first enqueue?

    Vastaus

    The first tentative distance need not be the shortest. Allow improvements; a vertex becomes settled when its smallest current distance is removed from the queue.

  154. Kortti 154

    Kysymys

    How do path compression and union by size or rank affect union-find complexity?

    Vastaus

    Together they give O(α(n)) amortized time per operation, where α is the inverse Ackermann function. The bound is effectively tiny for practical input sizes.

  155. Kortti 155

    Kysymys

    What does processing fewer than V vertices in Kahn's algorithm reveal?

    Vastaus

    A directed cycle remains. No vertex in the cyclic remainder can reach indegree zero after all removable dependencies are processed.

  156. Kortti 156

    Kysymys

    How can BFS compute distance from every grid cell to the nearest source?

    Vastaus

    Initialize the queue with all sources at distance zero. This multi-source BFS expands the nearest-source distance layers together.

  157. Kortti 157

    Kysymys

    Why can a topological ordering be nonunique?

    Vastaus

    Several vertices may currently have no remaining prerequisites. Choosing them in different orders can produce different valid orderings.

  158. Kortti 158

    Kysymys

    What happens when union-find receives an edge whose endpoints already share a representative?

    Vastaus

    The edge connects vertices already in one component. In incremental construction of an undirected forest, adding it creates a cycle.

  159. Kortti 159

    Kysymys

    Which algorithm can handle negative edge weights and detect a reachable negative cycle?

    Vastaus

    Bellman–Ford. Repeatedly relax all edges; an improvement after V − 1 full rounds indicates a negative cycle reachable from the source.

  160. Kortti 160

    Kysymys

    Why does traversal need an outer loop to count every connected component of an undirected graph?

    Vastaus

    One traversal reaches only one component. Start another traversal from each still-unvisited vertex and increment the component count.

  161. Kortti 161

    Kysymys

    How can topological order simplify shortest paths in a weighted DAG?

    Vastaus

    Relax each vertex's outgoing edges in topological order. Every predecessor is processed first, so negative weights are allowed and total time is O(V + E).

  162. Kortti 162

    Kysymys

    When should you use BFS or DFS instead of union-find for connectivity?

    Vastaus

    When the graph is static and you need traversal details such as paths or component members. Union-find is especially useful for repeated incremental edge additions and connectivity queries.

  163. Kortti 163

    Kysymys

    What is the difference between a minimum spanning tree and a shortest-path tree?

    Vastaus

    A minimum spanning tree minimizes total connecting edge weight. A shortest-path tree preserves shortest routes from a chosen source; neither objective implies the other.

  164. Kortti 164

    Kysymys

    Why can stopping at the first meeting be unsafe in bidirectional BFS with arbitrary node-by-node expansion?

    Vastaus

    A first meeting under an arbitrary expansion order may not minimize the combined distances. Use a layer-based stopping rule that accounts for both search depths.

  165. Kortti 165

    Kysymys

    Which signal suggests backtracking rather than a single greedy choice?

    Vastaus

    The task asks for all valid arrangements, or choices must be tried and undone because no safe local choice is known. Build a partial candidate and explore legal extensions.

  166. Kortti 166

    Kysymys

    What belongs in a backtracking state?

    Vastaus

    Enough information to determine legal next choices and recognize completion, such as the current position, chosen items, and remaining constraints.

  167. Kortti 167

    Kysymys

    What makes a pruning condition safe?

    Vastaus

    It proves that no completion of the current partial state can satisfy the goal or improve the required objective. A guess about likely failure is insufficient.

  168. Kortti 168

    Kysymys

    How do combinations differ from permutations during generation?

    Vastaus

    Combinations ignore order, so restrict future choices to later positions. Permutations care about order, so track which positions are already used.

  169. Kortti 169

    Kysymys

    What should be true after a backtracking recursive call returns?

    Vastaus

    The caller's mutable search state is restored exactly to its pre-choice state. Undo additions and constraint updates before trying a sibling choice.

  170. Kortti 170

    Kysymys

    When generating unique subsets from sorted values, how do you skip duplicates safely?

    Vastaus

    At one recursion depth, skip a value equal to the previous sibling candidate. Still allow equal values at deeper levels when the input provides multiple copies.

  171. Kortti 171

    Kysymys

    Why can backtracking output alone require exponential time?

    Vastaus

    A set with n distinct elements has 2^n subsets. Explicitly listing all subsets cannot be polynomial in n; copying their contents adds further cost.

  172. Kortti 172

    Kysymys

    Why should a completed mutable candidate usually be copied before saving it?

    Vastaus

    Later backtracking steps will modify the working candidate. Saving only a reference can make all recorded answers reflect subsequent changes.

  173. Kortti 173

    Kysymys

    What is the main risk of memoizing backtracking solely by the current index?

    Vastaus

    Different histories can leave different remaining choices or constraints. The memo key must include every part of the state that affects future results.

  174. Kortti 174

    Kysymys

    For selecting the most nonoverlapping intervals, which greedy choice is justified?

    Vastaus

    Choose the available interval with the earliest finishing time, then continue with compatible intervals. This leaves at least as much room for the remaining selections.

  175. Kortti 175

    Kysymys

    What is the difference between greedy choice and dynamic programming?

    Vastaus

    Greedy commits to a choice proven safe without exploring all alternatives. DP evaluates and combines subproblem alternatives when that local commitment is not justified.

  176. Kortti 176

    Kysymys

    Why does choosing the largest coin repeatedly fail for some coin systems?

    Vastaus

    The locally largest coin can leave an expensive remainder. With denominations 1, 3, 4 and amount 6, greedy uses 4 + 1 + 1, while 3 + 3 uses fewer coins.

  177. Kortti 177

    Kysymys

    How does a farthest-reachable frontier solve reachability in a nonnegative jump-length array?

    Vastaus

    Scan positions no farther than the current frontier and extend it with each reachable index plus its jump length. If the next position lies beyond the frontier, progress is impossible.

  178. Kortti 178

    Kysymys

    Why does choosing the shortest interval not always maximize the number of nonoverlapping intervals?

    Vastaus

    A short interval can cross the boundary between two compatible intervals and block both. Duration alone does not measure the future scheduling space it consumes.

  179. Kortti 179

    Kysymys

    What must be proved before pruning a combination-sum branch because its sum exceeds the target?

    Vastaus

    Remaining choices cannot reduce the sum. The pruning is safe for nonnegative additions under the stated goal, but negative numbers can make it invalid.

  180. Kortti 180

    Kysymys

    How does branch and bound differ from ordinary feasibility pruning?

    Vastaus

    It uses a bound on the best objective reachable from a partial state. Prune only when that bound cannot beat the best complete answer already found.

  181. Kortti 181

    Kysymys

    What question distinguishes a greedy proof from evidence that a heuristic often works?

    Vastaus

    Can every discarded alternative be ruled out for all valid inputs? Examples and benchmarks support a heuristic, but do not establish the safe-choice property.

  182. Kortti 182

    Kysymys

    Why is earliest-finish interval scheduling insufficient when intervals have different rewards?

    Vastaus

    Maximizing count and maximizing reward are different objectives. A single high-reward interval can beat several low-reward intervals, so weighted scheduling needs more information.

  183. Kortti 183

    Kysymys

    Which combination of properties makes dynamic programming promising?

    Vastaus

    Repeated subproblems and a recurrence that combines their results. Define a state whose answer is independent of the path used to reach it.

  184. Kortti 184

    Kysymys

    What should a DP state definition say before you write a recurrence?

    Vastaus

    Exactly what one table entry means, including its input boundary and any remaining resource or constraint. Ambiguous states lead to mismatched transitions.

  185. Kortti 185

    Kysymys

    How do top-down memoization and bottom-up tabulation differ?

    Vastaus

    Memoization computes states on demand through calls and caches them. Tabulation processes states in an explicit dependency order, often avoiding recursion overhead.

  186. Kortti 186

    Kysymys

    What determines the runtime of a DP with a finite state table?

    Vastaus

    The number of states actually evaluated times the work per state, plus preprocessing and output reconstruction. Count transitions rather than just table dimensions.

  187. Kortti 187

    Kysymys

    Why are base cases part of a DP's meaning rather than convenient initial values?

    Vastaus

    They encode valid empty or smallest subproblems. A wrong base value can invent impossible solutions or remove legitimate ones from every later transition.

  188. Kortti 188

    Kysymys

    For 0/1 knapsack compressed to one capacity array, why iterate capacities downward?

    Vastaus

    Each item must be used at most once. Descending order reads the previous item's state instead of reusing an update made for the current item.

  189. Kortti 189

    Kysymys

    When can a DP table be compressed to a few rows or variables?

    Vastaus

    When future states depend only on a bounded slice of earlier states. Keep those dependencies until their last use; reconstruction may need additional storage.

  190. Kortti 190

    Kysymys

    What recurrence models choosing nonadjacent values for maximum sum?

    Vastaus

    At each position, compare skipping it with taking it plus the best result before its neighbor. The base cases must specify whether choosing nothing is allowed.

  191. Kortti 191

    Kysymys

    What DP state counts paths through a blocked grid when moves are only right or down?

    Vastaus

    The number of ways to reach each cell from above or from the left. Blocked cells contribute zero; initialize an unblocked starting cell to one.

  192. Kortti 192

    Kysymys

    For unbounded knapsack, why can capacities run upward within an item's pass?

    Vastaus

    Reusing the current item's updated smaller-capacity result is allowed. Ascending order lets that item contribute more than once.

  193. Kortti 193

    Kysymys

    How can loop order change coin-change counting from combinations to ordered sequences?

    Vastaus

    Processing coin types outside amounts builds combinations without ordering them. Processing amounts outside all coin choices counts different last-coin sequences separately.

  194. Kortti 194

    Kysymys

    What is the key distinction between longest common subsequence and longest common substring?

    Vastaus

    A subsequence may skip characters; a substring must stay contiguous. Their DP transitions differ because a substring match cannot carry through a mismatch.

  195. Kortti 195

    Kysymys

    Why is O(nW) knapsack called pseudopolynomial?

    Vastaus

    It is polynomial in the numeric capacity W, but W can be exponential in the number of bits used to encode it. It is not polynomial in input bit length.

  196. Kortti 196

    Kysymys

    For longest increasing subsequence, what does tails[length − 1] represent in the O(n log n) method?

    Vastaus

    The smallest possible final value of an increasing subsequence of that length among processed values. The tails array itself need not be one actual subsequence.

  197. Kortti 197

    Kysymys

    Why do counting and minimization DPs use different unreachable-state values?

    Vastaus

    A count uses zero ways. A minimization state needs an explicit unreachable marker or infinity so an impossible predecessor cannot look like a cheap solution.

  198. Kortti 198

    Kysymys

    What state supports edit distance between two strings?

    Vastaus

    The minimum edits needed to transform one prefix into the other. Transitions account for insertion, deletion, and replacement or a matching final character.

  199. Kortti 199

    Kysymys

    How can a DP recover one chosen solution instead of only its score?

    Vastaus

    Store predecessor or choice information, or recompute choices from the full table. Walk backward from the final state to reconstruct the selected decisions.

  200. Kortti 200

    Kysymys

    Why must an LIS implementation choose its binary-search boundary according to strictness?

    Vastaus

    For a strictly increasing subsequence, replace the first tail at least equal to the value. A nondecreasing subsequence instead uses the first strictly greater tail.

  201. Kortti 201

    Kysymys

    What operation tests whether bit i of a nonnegative integer mask is set?

    Vastaus

    Check whether mask AND (1 shifted left by i) is nonzero. Ensure i is inside the integer representation's supported bit range.

  202. Kortti 202

    Kysymys

    Why does XOR recover a unique value when every other value occurs exactly twice?

    Vastaus

    Equal values cancel because x XOR x = 0, and XOR is associative and commutative. XORing all values leaves the single unpaired value.

  203. Kortti 203

    Kysymys

    What does x AND (x − 1) do for a positive integer x?

    Vastaus

    It clears x's lowest set bit. Repeating it counts set bits in time proportional to the number of set bits.

  204. Kortti 204

    Kysymys

    When does a bitmask make a useful DP state?

    Vastaus

    When a small set of items is either included or excluded and future choices depend on that subset. n items give 2^n possible masks, so n must be small.

  205. Kortti 205

    Kysymys

    How do you set a bit and clear a bit without changing the others?

    Vastaus

    Set bit i with mask OR (1 shifted left by i). Clear it with mask AND the bitwise complement of that single-bit mask, respecting the chosen word width.

  206. Kortti 206

    Kysymys

    What makes a memoized recurrence invalid when it depends on mutable global state omitted from the key?

    Vastaus

    The same key can have different answers under different global conditions. Include the relevant state in the key or remove that dependency.

  207. Kortti 207

    Kysymys

    What condition recognizes a power of two among integers?

    Vastaus

    x > 0 and x AND (x − 1) = 0. The positivity check excludes zero, which also makes the bitwise expression zero.

  208. Kortti 208

    Kysymys

    Why does bitwise complement need a width convention in language-agnostic reasoning?

    Vastaus

    Complement flips all bits in the representation. Fixed-width and arbitrary-precision signed integers can produce different-looking values; mask to the intended width when necessary.

  209. Kortti 209

    Kysymys

    How can two unique values be recovered when every other value occurs twice?

    Vastaus

    XOR all values, choose a set bit in that nonzero result, and partition by that bit. XOR within each group; the two unique values fall into different groups.

  210. Kortti 210

    Kysymys

    Why is memoization alone insufficient to handle cyclic state dependencies?

    Vastaus

    A call may revisit an unfinished state before any value is cached. Use cycle handling or a problem-specific iterative method; ordinary DAG-style DP assumes an acyclic dependency order.

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210 korttia

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