Ouvrir l'app

Trigonal Bipyramidal Lone Pair Flashcards

Practice axial and equatorial lone-pair placement, count 90° contacts, and predict molecular shapes in a trigonal bipyramid.

Par Open Study Contributor

À propos de ce paquet

A lone pair on an equatorial site has two 90° neighbors. Move it to an axial site and it has three. These 28 VSEPR flashcards give you practice using that difference to reason about one, two, or three lone pairs in a trigonal bipyramid.

Start by finding the 90° contacts in the ideal five-site model. Then count which contacts involve lone pairs, work backward when the clues narrow down the sites, and compare layouts the way VSEPR does. The cards also ask you to read the molecular shape from the bonded sites and spot shortcuts that give the wrong answer.

This deck assumes you can read a Lewis structure and uses equivalent bonding domains when comparing repulsion. It sticks to five electron domains, so you can focus on placement instead of memorizing a full shape chart. Ideal site angles are for counting and comparing contacts. Predicting measured bond angles or inferring electron geometry from a shape alone takes more information than these exercises provide.

The exercises are original. Chemistry references include UT Austin’s electronic geometry notes and Davidson’s VSEPR model considerations.

Cartes de ce paquet

  1. Carte 1

    Question

    In an ideal trigonal bipyramid, which pairs of sites make a 90° angle at the center?

    Réponse

    Every axial–equatorial pair. The two axial sites are 180° apart, and any two equatorial sites are 120° apart.

  2. Carte 2

    Question

    In the VSEPR model, which 90° contact is more repulsive, lone pair–lone pair or lone pair–bonding domain?

    Réponse

    Lone pair–lone pair. A lone pair generally takes up more space around the central atom than a bonding domain.

  3. Carte 3

    Question

    How many distinct 90° contacts are there across all five sites of an ideal trigonal bipyramid?

    Réponse

    Six contacts. Pair each of the two axial sites with each of the three equatorial sites.

  4. Carte 4

    Question

    An ideal trigonal bipyramid has one axial lone pair and four bonding domains. How does swapping the lone pair with an equatorial bond change the number of 90° contacts involving that lone pair?

    Réponse

    The number drops from three to two. The lone pair had three equatorial neighbors at 90° and now has two axial neighbors at 90°.

  5. Carte 5

    Question

    In a trigonal bipyramid, the two axial sites and two equatorial sites carry bonds. What is the molecular shape?

    Réponse

    Seesaw. The bonded atoms occupy two opposite sites and two sites in the equatorial plane. The remaining equatorial site holds the lone pair.

  6. Carte 6

    Question

    A student counts three 90° neighbors at each axial site and two at each equatorial site. Why does adding those neighbor counts give 12 instead of the number of distinct contacts?

    Réponse

    Each contact was counted at both ends. Halve 12 to get six distinct 90° contacts.

  7. Carte 7

    Question

    Two lone pairs occupy equatorial sites in an ideal trigonal bipyramid. How many 90° lone pair–bonding domain contacts are there?

    Réponse

    Four contacts. Each lone pair makes a 90° contact with both axial bonds.

  8. Carte 8

    Question

    A bonded site in an ideal trigonal bipyramid has three 90° neighbors. Two of those neighbors hold lone pairs. How many equatorial lone pairs are there?

    Réponse

    Two equatorial lone pairs. A site with three 90° neighbors is axial, and all three of those neighbors are equatorial.

  9. Carte 9

    Question

    An ideal trigonal bipyramid has one lone pair. Four of its 90° contacts join two bonding domains. Where is the lone pair?

    Réponse

    At an equatorial site. Two axial bonds can pair with two equatorial bonds to give four contacts. An axial lone pair would leave only three such contacts.

  10. Carte 10

    Question

    Two lone pairs in an ideal trigonal bipyramid make zero 90° contacts with each other. What are the two possible arrangements by site type?

    Réponse

    Both could be axial or both could be equatorial. The first layout puts them 180° apart and the second puts them 120° apart.

  11. Carte 11

    Question

    An ideal trigonal bipyramid has one axial lone pair and one equatorial lone pair. How many 90° contacts join a lone pair to a bonding domain?

    Réponse

    Three contacts. The axial lone pair meets two equatorial bonds at 90°. The equatorial lone pair meets one axial bond at 90°.

  12. Carte 12

    Question

    Why does VSEPR put two lone pairs at equatorial sites in a trigonal bipyramid even though opposite axial sites would put them farther apart?

    Réponse

    Both layouts avoid a 90° contact between lone pairs. Two equatorial lone pairs make four 90° contacts with bonding domains, compared with six for two axial lone pairs.

  13. Carte 13

    Question

    In a trigonal bipyramid, bonds occupy both axial sites and just one equatorial site. What is the molecular shape?

    Réponse

    T-shaped. The axial bonds form the straight part of the T, and the equatorial bond projects sideways.

  14. Carte 14

    Question

    A student wants to choose the VSEPR arrangement by minimizing the total number of 90° contacts of all kinds in a trigonal bipyramid. Why can't that pick a layout?

    Réponse

    The total stays at six whichever sites carry lone pairs. Compare the contact types, giving priority to avoiding 90° contacts between two lone pairs.

  15. Carte 15

    Question

    Exactly two sites in an ideal trigonal bipyramid hold lone pairs. No two bonding domains meet at 90°. What is the lone-pair placement?

    Réponse

    Both lone pairs are axial. The three bonding domains all lie in the equatorial plane, 120° apart.

  16. Carte 16

    Question

    For two lone pairs in a trigonal bipyramid, a mixed axial–equatorial layout has three 90° lone pair–bond contacts and one 90° contact between lone pairs. The all-equatorial layout has four 90° lone pair–bond contacts and zero contacts between lone pairs at 90°. Which layout does VSEPR favor?

    Réponse

    The all-equatorial layout. Avoiding the 90° contact between lone pairs takes priority over saving one 90° lone pair–bond contact.

  17. Carte 17

    Question

    Start with two equatorial lone pairs in an ideal trigonal bipyramid. Swap one of them with an axial bond. What happens to the number of 90° contacts between two bonding domains?

    Réponse

    It stays at two. Before the swap, two axial bonds meet one equatorial bond at 90°. After it, one axial bond meets two equatorial bonds at 90°.

  18. Carte 18

    Question

    With three lone pairs in a trigonal bipyramid, why does VSEPR favor putting all three in the equatorial plane?

    Réponse

    That is the only layout with zero 90° contacts between lone pairs. Any other three-site layout puts lone pairs in both site types, creating 90° lone pair–lone pair contacts.

  19. Carte 19

    Question

    An ideal trigonal bipyramid has three lone pairs and exactly one axial bond. What is the angle between the two bonds in that hypothetical layout?

    Réponse

    90°. The second bond must occupy an equatorial site, so the two bonds use different site types.

  20. Carte 20

    Question

    In an ideal trigonal bipyramid, three lone pairs occupy one axial site and two equatorial sites. How many 90° lone pair–lone pair contacts do they make?

    Réponse

    Two contacts. The axial lone pair meets each equatorial lone pair at 90°. The two equatorial lone pairs are 120° apart.

  21. Carte 21

    Question

    In an ideal trigonal bipyramid, four 90° contacts join two bonding domains and none joins two lone pairs. How many 90° contacts join a lone pair to a bonding domain?

    Réponse

    Two contacts. There are six distinct 90° contacts altogether, so subtract the four contacts between bonding domains.

  22. Carte 22

    Question

    Two hypothetical trigonal bipyramids each contain three lone pairs. In one, the two bonds are both equatorial. In the other, one bond is axial and one is equatorial. Which layout has more 90° lone pair–bonding domain contacts?

    Réponse

    The layout with both bonds equatorial has four, compared with three for the mixed layout. With both bonds equatorial, each meets two axial lone pairs at 90°.

  23. Carte 23

    Question

    All three equatorial sites of a trigonal bipyramid hold lone pairs. Why do the remaining bonds give a linear molecular shape?

    Réponse

    The two bonds occupy opposite axial sites, 180° apart. The molecular shape follows the bonded atoms.

  24. Carte 24

    Question

    A seesaw molecule is modeled by placing one lone pair on an equatorial site. Does the 120° angle between the remaining equatorial sites predict their exact measured bond angle?

    Réponse

    No. The 120° value comes from the ideal trigonal bipyramid. Real bonding domains can shift when the lone pair repels them.

  25. Carte 25

    Question

    In an ideal trigonal bipyramid, lone pairs occupy sites P and Q, which are 120° apart. A bond at site R is 90° from both. What type of site is R?

    Réponse

    Axial. The 120° angle places P and Q in the equatorial plane. Only an axial site makes a 90° angle with both.

  26. Carte 26

    Question

    An ideal trigonal bipyramid has exactly three lone pairs. Two 90° contacts join lone pairs to each other, and three join lone pairs to bonding domains. How many axial sites hold lone pairs?

    Réponse

    One axial site holds a lone pair. A layout with two axial lone pairs would also have two 90° contacts between lone pairs, but it would have four 90° lone pair–bonding domain contacts.

  27. Carte 27

    Question

    A five-domain model shows a lone pair on one equatorial site and bonds on the other four sites. A student calls the molecular shape trigonal bipyramidal because five sites are occupied. What did they count incorrectly?

    Réponse

    They counted the lone-pair site as part of the molecular shape. All five domains determine the electron geometry, while the four bonded sites give a seesaw molecular shape.

  28. Carte 28

    Question

    Every 90° contact in an ideal trigonal bipyramid is between a lone pair and a bonding domain. If the total number of lone pairs is unknown, what two layouts fit?

    Réponse

    Either both axial sites hold lone pairs and all equatorial sites hold bonds, or all three equatorial sites hold lone pairs and both axial sites hold bonds. Each axial–equatorial pair has one site of each kind.

Three teal tiles on a ceramic disc with a brass spindle and two orange collars, one above the disc and one below.

28 cartes

Trigonal Bipyramidal Lone Pair Flashcards

Réviser ce paquet gratuitement

Nibomo s'ouvre pour que vous puissiez commencer à réviser.

Paquets similaires