Conditional Probability Flashcards: Two-Way Table Practice

Practice conditional probability with 44 original cards: choose the given group, calculate table ratios, reverse conditions, and repair denominator mistakes.

Tentang dek ini

Practice conditional probability with 44 original English flashcards built around small invented count tables. Each card asks for one result: a given group, an exact probability fraction, a needed count, a corrected setup, or a short interpretation. Row-given and column-given questions, a few reversed conditions, conditional complements, and joint and marginal contrasts make denominator choices visible. Exact group rates support short count reconstruction and one reverse-condition calculation. Limit cards address empty groups, zero overlaps, missing information, unequal selection weights, rounded rates, and causal claims.

The opening four cards establish notation, overlap, the count-ratio rule, and complete table categories. The remaining sequence mixes calculations, interpretations, count reconstruction, and error repair, introducing more demanding rates and limits later. Repeated-table variants are separated by at least three cards on other tasks; the review scheduler handles long-term spacing. Every prompt includes its own needed givens. Count-to-probability exercises state uniform item selection.

This is a compact recall and error-repair companion for high-school and introductory statistics learners. It excludes a broad Bayes theorem formula curriculum, continuous distributions, inference tests, independence proof drills, medical diagnosis, full course or exam coverage, full worksheet construction, and every forward/reverse permutation. These would require other practice formats or a wider scope. Recalling these fixed examples does not establish mastery of unfamiliar probability problems. Learn the method with conditional probability two-way table practice, then solve fresh problems with different counts. The statistics flashcard study guide gives broader review-planning context.

The prompts, invented counts, explanations, sequence, metadata, and original cover were independently created with AI assistance and reviewed for factual and arithmetic accuracy. Mathematical rules were checked against Penn State’s conditional probability lessons and the University of Minnesota’s two-way-table reference; no source exercises, wording, tables, figures, or exam material were copied. Original elements are released under CC0 1.0 to the extent applicable rights exist; third-party expression is excluded. This general topic deck claims no official examination alignment, affiliation, or endorsement.

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  1. Kad 1

    Soalan

    In P(A | B), which event is the given condition?

    Jawapan

    B. Restrict attention to outcomes in B; A is the event whose probability is requested.

  2. Kad 2

    Soalan

    When one item is selected uniformly from a finite collection, what count ratio gives P(A | B)?

    Jawapan

    Count in both A and B / count in B, provided the B count is positive. In probability notation, P(A | B) = P(A and B) / P(B), with P(B) > 0.

  3. Kad 3

    Soalan

    What does the event “A and B” include?

    Jawapan

    Only outcomes that satisfy both A and B. It is their overlap, also written A ∩ B; it need not include every outcome in B.

  4. Kad 4

    Soalan

    For a complete two-way count table, how many cells should each item contribute to?

    Jawapan

    One cell. Each variable’s categories must be mutually exclusive and exhaustive, so no item is duplicated or omitted.

  5. Kad 5

    Soalan

    Choose one token uniformly from this complete table. Each item appears once.

              Dot No dot
    Blue        6      9
    Not blue    4     11
    

    What is P(dot | blue)?

    Jawapan

    2/5. The blue group has 6 + 9 = 15 tokens; 6 have dots. Use 6/15 = 2/5.

  6. Kad 6

    Soalan

    Choose one ticket uniformly from this complete table. Each item appears once.

             Stamp No stamp
    Striped      9        6
    Plain        3       12
    

    What is P(striped | stamped)?

    Jawapan

    3/4. There are 9 + 3 = 12 stamped tickets; 9 are striped. Use 9/12 = 3/4.

  7. Kad 7

    Soalan

    Choose one paper flower uniformly from this complete table. Each item appears once.

             Folded Unfolded
    Red           5        7
    Not red      10        8
    

    A learner writes P(folded | red) = 5/15. What denominator should replace 15?

    Jawapan

    12. The condition is red, so use the red row total, 5 + 7. The 15 counts folded flowers instead.

  8. Kad 8

    Soalan

    A complete batch has 40 silver and 20 non-silver badges. Exactly 3/5 of the silver badges are numbered; all other silver badges are unnumbered. How many badges are both silver and numbered?

    Jawapan

    24 badges. Apply the within-silver rate to the silver total: (3/5) × 40 = 24.

  9. Kad 9

    Soalan

    Choose one book uniformly from this complete table. Each item appears once.

               Borrowed On shelf
    Hardback          8       10
    Paperback        15        7
    

    What is P(borrowed | hardback)?

    Jawapan

    4/9. The hardback group contains 8 + 10 = 18 books; 8 are borrowed. Use 8/18 = 4/9.

  10. Kad 10

    Soalan

    In a complete registration list, P(completed | online) = 3/4 under uniform selection. What does 3/4 describe in context?

    Jawapan

    Three quarters of the online registrations are completed. The fraction describes the online group, not all registrations or the group of completed registrations.

  11. Kad 11

    Soalan

    Choose one tile uniformly from this complete table. Each item appears once.

               Marked Unmarked
    Round           7        3
    Not round       5        9
    

    What is P(round | marked)?

    Jawapan

    7/12. The marked column has 7 + 5 = 12 tiles; 7 are round.

  12. Kad 12

    Soalan

    Choose one token uniformly from this complete table. Each item appears once.

              Dot No dot
    Blue        6      9
    Not blue    4     11
    

    What is P(blue | dot)?

    Jawapan

    3/5. The dotted group has 6 + 4 = 10 tokens; 6 are blue. Use 6/10 = 3/5.

  13. Kad 13

    Soalan

    Choose one folder uniformly from this complete table. Each item appears once.

         Tagged Untagged
    New       4        6
    Old       8       12
    

    A learner calls 4/10 the probability of “new and tagged.” What fraction answers that joint-probability question?

    Jawapan

    2/15. “New and tagged” means 4 folders out of all 30: 4/30 = 2/15. The 4/10 ratio conditions on new.

  14. Kad 14

    Soalan

    Choose one bead uniformly from this complete table. Each item appears once.

               Holed Solid
    Green          0     8
    Not green      5     7
    

    What is P(holed | green)?

    Jawapan

    0. The green group is nonempty: 0 + 8 = 8. No green bead is holed, so the ratio is 0/8 = 0.

  15. Kad 15

    Soalan

    Choose one cup uniformly from this complete table. Each item appears once.

              Handle No handle
    Blue           9         6
    Not blue       3        12
    

    What is P(no handle | blue)?

    Jawapan

    2/5. Of the 15 blue cups, 6 have no handle. Use 6/15 = 2/5; the condition stays blue.

  16. Kad 16

    Soalan

    In a complete collection of envelopes, 18 are both small and sealed. Exactly 3/4 of all small envelopes are sealed. How many small envelopes are there?

    Jawapan

    24 envelopes. If n is the small-group total, (3/4) × n = 18, so n = 18 ÷ (3/4) = 24.

  17. Kad 17

    Soalan

    Choose one button uniformly from this complete table. Each item appears once.

              Hole No hole
    Green        6       4
    Not green    4      12
    

    What is P(hole | green)?

    Jawapan

    3/5. The green row has 6 + 4 = 10 buttons; 6 have holes. Use 6/10 = 3/5.

  18. Kad 18

    Soalan

    A complete note collection gives P(blue | sealed) = 2/7 under uniform selection. Which group is the denominator of this fraction?

    Jawapan

    All sealed notes. The numerator counts notes that are both blue and sealed.

  19. Kad 19

    Soalan

    A complete collection has 40 large and 30 small labels. Exactly 1/4 of the large labels are stamped; all other large labels are unstamped. How many large labels are unstamped?

    Jawapan

    30 labels. There are (1/4) × 40 = 10 stamped large labels; 40 − 10 = 30 are unstamped.

  20. Kad 20

    Soalan

    Choose one book uniformly from this complete table. Each item appears once.

               Borrowed On shelf
    Hardback          8       10
    Paperback        15        7
    

    What is P(hardback | borrowed)?

    Jawapan

    8/23. The borrowed group has 8 + 15 = 23 books; 8 are hardbacks. The 18-book hardback row is not the given group.

  21. Kad 21

    Soalan

    A batch has 60 small and 40 large boxes, with no other sizes. Exactly 1/5 of small boxes and 3/10 of large boxes are marked; the rest are unmarked. Choose one box uniformly. What is P(small | marked)?

    Jawapan

    1/2. There are (1/5) × 60 = 12 marked small boxes and (3/10) × 40 = 12 marked large boxes. The marked group has 24 boxes, so use 12/24.

  22. Kad 22

    Soalan

    Choose one label uniformly from this complete table. Each item appears once.

                Stamped Unstamped
    Purple            0         0
    Not purple        6        10
    

    What is P(stamped | purple) under the count-ratio rule?

    Jawapan

    Undefined. The purple group is empty, so the ratio would be 0/0. This rule requires a positive conditioning-group count.

  23. Kad 23

    Soalan

    Choose one tile uniformly from this complete table. Each item appears once.

               Marked Unmarked
    Round           7        3
    Not round       5        9
    

    What is P(not round | unmarked)?

    Jawapan

    3/4. The unmarked group has 3 + 9 = 12 tiles; 9 are not round. Use 9/12 = 3/4.

  24. Kad 24

    Soalan

    Choose one parcel uniformly from this complete table. Each item appears once.

           Sealed Open
    Small       6    9
    Large      10    5
    

    A learner writes P(small) = 6/16. What fraction gives P(small), with no condition?

    Jawapan

    1/2. All 15 small parcels count, out of 30 total: 15/30 = 1/2. The 6/16 ratio is P(small | sealed).

  25. Kad 25

    Soalan

    Choose one order uniformly from this complete table. Each item appears once.

               Printed Unprinted
    Early           11         4
    Not early        7         8
    

    What is P(printed | not early)?

    Jawapan

    7/15. The not-early row has 7 + 8 = 15 orders; 7 are printed.

  26. Kad 26

    Soalan

    A complete collection has 80 cards. Exactly 3/8 of all cards are both blue and dotted. How many cards are both blue and dotted?

    Jawapan

    30 cards. The rate uses the whole collection: (3/8) × 80 = 30.

  27. Kad 27

    Soalan

    For uniform selection from a complete pin collection, P(round | gold) = 1/4. A learner labels 3/4 as P(round | not gold). Which conditional probability does 3/4 actually give?

    Jawapan

    P(not round | gold). Take the complement of the requested event while keeping the condition gold: 1 − 1/4 = 3/4. The non-gold group can have a different rate.

  28. Kad 28

    Soalan

    In a nonempty red-tag group, exactly 2/3 are square. No other counts or rates are supplied. Can you determine the fraction of square tags that are red?

    Jawapan

    No. You need the count that is both red and square and the total square count, or equivalent proportions. The within-red rate alone does not determine the reverse condition.

  29. Kad 29

    Soalan

    Choose one notebook uniformly from this complete table. Each item appears once.

            Lined Blank
    Small       2     6
    Medium      5     3
    Large       3     1
    

    What is P(medium | lined)?

    Jawapan

    1/2. The lined column contains 2 + 5 + 3 = 10 notebooks; 5 are medium. Use 5/10.

  30. Kad 30

    Soalan

    Uniform selection from a complete list of 50 workshop attendees gives P(brings pen | morning session) = 4/5. To which population does this result directly apply?

    Jawapan

    The morning-session attendees in that 50-person list. This fraction alone does not establish the rate for attendees at other workshops.

  31. Kad 31

    Soalan

    Choose one tile uniformly from this complete table. Each item appears once.

              Dot No dot
    Blue        5      7
    Not blue    4      8
    

    What is P(dot), without a given color?

    Jawapan

    3/8. There are 5 + 4 = 9 dotted tiles among 24 total. Use 9/24 = 3/8.

  32. Kad 32

    Soalan

    For uniform selection from a collection of tags, P(square | red) = 2/5. A learner says, “Two fifths of the square tags are red.” What group should replace “square tags”?

    Jawapan

    The red tags. The result says two fifths of red tags are square. It does not give P(red | square).

  33. Kad 33

    Soalan

    Choose one ribbon uniformly from this complete table. Each item appears once.

            Dot No dot
    Red       4      6
    Blue      2      3
    Yellow    6      9
    

    A learner uses 4/(4 + 2) for P(red | dot). What fraction corrects the missing category?

    Jawapan

    1/3. Include every dotted ribbon: 4 + 2 + 6 = 12. Use 4/12 = 1/3.

  34. Kad 34

    Soalan

    A complete tray has 10 red and 10 non-red pieces. The selector is more likely to choose each red piece than each non-red piece. Can counts alone justify P(red) = 10/20?

    Jawapan

    No. The count ratio needs uniform item selection. With unequal selection probabilities, use the pieces’ selection weights; equal counts do not imply equal chances.

  35. Kad 35

    Soalan

    Choose one basket uniformly from this complete table. Each item appears once.

               Lid No lid
    Round        4     10
    Not round    9      5
    

    What is P(no lid | round)?

    Jawapan

    5/7. The round row contains 4 + 10 = 14 baskets; 10 have no lid. Use 10/14 = 5/7.

  36. Kad 36

    Soalan

    Under uniform selection from a complete collection of items, P(sealed | blue) = 3/5 and P(blue | sealed) = 1/2. Which group does the 1/2 rate describe?

    Jawapan

    The sealed items. Half of that group is blue; the 3/5 rate instead describes the blue group.

  37. Kad 37

    Soalan

    A complete list contains only morning (20) and afternoon (50) entries. Exactly 10 in each group are checked; the rest are unchecked. A learner says the checked fractions are equal because both counts are 10. Which group has the larger checked fraction?

    Jawapan

    The morning group. Its fraction is 10/20 = 1/2, while the afternoon fraction is 10/50 = 1/5. Compare within-group rates, not raw counts.

  38. Kad 38

    Soalan

    A complete collection has 25 red and 15 non-red tokens. Exactly 18 tokens have dots, including 8 red tokens. Every other token has no dot. How many non-red tokens have dots?

    Jawapan

    10 tokens. The dotted column splits into red and non-red: 18 − 8 = 10.

  39. Kad 39

    Soalan

    Choose one entry uniformly from this complete table. Each item appears once.

           Checked Unchecked
    Bus          6         4
    Walk         3         7
    Cycle        9         1
    

    What is P(not bus | checked)?

    Jawapan

    2/3. The checked group contains 6 + 3 + 9 = 18 entries. The walk and cycle entries give 3 + 9 = 12 non-bus entries, so use 12/18 = 2/3.

  40. Kad 40

    Soalan

    In an observational club list, 4/5 of members who attend a workshop finish a project, versus 2/5 of those who do not attend. Does this comparison alone prove that workshop attendance causes project completion?

    Jawapan

    No. The conditional rates describe an association in that list. Other differences between the groups can explain it; the comparison alone does not establish causation.

  41. Kad 41

    Soalan

    Choose one bookmark uniformly from this complete table. Each item appears once.

                Folded Flat
    Orange           7    5
    Not orange       3    9
    

    What is P(orange and folded)?

    Jawapan

    7/24. The joint event contains 7 bookmarks out of all 24. Neither a row nor a column is specified as a given condition.

  42. Kad 42

    Soalan

    Choose one card uniformly from this complete table. Each item appears once.

              Star No star
    Blue         8       6
    Not blue     5      11
    

    What count belongs in the denominator of P(blue | star)?

    Jawapan

    13. The given group is the star column: 8 + 5 = 13 cards.

  43. Kad 43

    Soalan

    A complete group has 300 items. Its marked percentage is reported as 33%, rounded to the nearest whole percent. Must exactly 99 items be marked?

    Jawapan

    No. A rounded rate does not fix an exact count. Both 98/300 ≈ 32.67% and 99/300 = 33% round to 33%.

  44. Kad 44

    Soalan

    Choose one chip uniformly from this complete table. Each item appears once.

             Marked Unmarked
    Red           3        5
    Not red       4        8
    

    A learner writes P(marked | red) = 8/3. What fraction corrects the inverted ratio?

    Jawapan

    3/8. There are 3 marked red chips out of 3 + 5 = 8 red chips. A conditional probability cannot exceed 1.

A low four-cell sorting tray holds teal and amber tokens, with one row highlighted teal.

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Conditional Probability Flashcards: Two-Way Table Practice

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