Weighted Average Flashcards: Choose Weights & Combine Means
Practise 42 original weighted-average prompts: choose weights, combine group means, compare stated grading policies, and repair common calculation errors.
Về bộ thẻ này
Choose what counts equally before calculating an average. These 42 weighted average flashcards use original short problems to practise relative weights, combined means, pooled success rates, and explicitly stated grading policies.
You’ll choose weights from a situation; turn relative weights into normalized shares; calculate means from frequencies or disjoint groups; and distinguish equal-assessment, pooled-points, and supplied category-weight policies. Selected inverse cards recover a missing group mean, group size, or target assessment score. Local mistake repairs address the denominator, mismatched score scales, equal averaging of unequal groups, and full-course contributions confused with completed-work percentages. Every front supplies the assumptions needed after shuffling.
The sequence introduces the formula and weight meanings before dependent calculations. It then mixes short computations with policy choices, range checks, inverses, and repairs. Related variants are separated by at least three other cards; the review scheduler handles long-term spacing. All cards use the weighted-average tag.
You should know ordinary means, percentages, and simple algebra. Weights are nonnegative and their total must be positive. Group-combination problems state their target set and use exact means unless rounding is explicitly mentioned. Grading examples define fictional policies; they do not reproduce a particular school or gradebook.
This evergreen Mathematics deck is not aligned to an exam or curriculum. It excludes negative and inverse-variance weights, survey weighting, investment returns, institutional GPA rules, missing-work assumptions, dropped work, extra credit, grouped-interval estimates, average-speed problems, and statistical inference. It includes basic pooling but no Simpson’s-paradox reversal datasets. Mechanical reversals are omitted when the inputs would not be uniquely determined; selected inverses give enough information to solve them.
The formula was checked against NIST’s weighted mean reference. Normalization, bounds, reconstructed totals, and inverse answers were independently derived from that formula. The grading calculations follow only the policies stated on their own fronts. No source exercises, competitor cards, textbook examples, exam questions, or source diagrams were copied or adapted.
AI tools assisted with drafting and the original decorative cover. Every final front and back was manually read in author review, and numerical answers were checked with exact arithmetic or substitution. This does not claim learner testing or guaranteed results. The CC0 dedication covers original wording, invented examples, organization, metadata, and generated cover to the extent applicable rights exist. Mathematical facts and cited materials retain their own status. This is independent study practice, with no affiliation to or endorsement by the cited organizations.
Thẻ trong bộ này
Thẻ 1
Câu hỏi
In a weighted arithmetic mean, what does a weight describe?
Câu trả lời
How much a value counts relative to the other values.
The weight might represent a frequency, a group size, or a stated policy. Choose its meaning before calculating.
Thẻ 2
Câu hỏi
For values xᵢ with nonnegative weights wᵢ and a positive total weight, what is the weighted arithmetic mean?
Câu trả lời
Divide the sum of weight × value by the sum of weights.
Thẻ 3
Câu hỏi
A list contains the value 4 twice and the value 9 three times. What frequency weights reproduce the mean of all five entries?
Câu trả lời
Weights 2 for 4 and 3 for 9.
Each weight counts how often its value occurs.
Thẻ 4
Câu hỏi
Two assessments have scores 9/12 and 36/40. No averaging policy is stated. Is the overall percentage uniquely determined?
Câu trả lời
No. The weighting policy is missing.
Giving each assessment equal weight and pooling earned/possible points answer different questions.
Thẻ 5
Câu hỏi
Relative weights are 2, 3, and 5. What are their normalized weights?
Câu trả lời
0.2, 0.3, and 0.5.
Divide each weight by the total, 10. Normalized weights sum to 1.
Thẻ 6
Câu hỏi
With nonnegative weights and positive total weight, where must a weighted arithmetic mean lie?
Câu trả lời
Between the smallest and largest values that have positive weight, inclusive.
Zero-weight values do not set the relevant endpoints.
Thẻ 7
Câu hỏi
Disjoint groups cover the whole target set and measure the same quantity on the same scale. Each group mean is exact. What weights give the mean of all individual observations?
Câu trả lời
The group sizes.
Group size × group mean reconstructs each group total. Add those totals and divide by the total number of observations.
Thẻ 8
Câu hỏi
What does a weighted arithmetic mean become when all weights are equal and positive?
Câu trả lời
The ordinary arithmetic mean.
The common weight cancels from numerator and denominator.
Thẻ 9
Câu hỏi
Values 14, 20, and 200 have respective weights 2, 3, and 0. What is their weighted mean?
Câu trả lời
17.6.
(2 × 14 + 3 × 20) / (2 + 3) = 88/5. The value 200 contributes nothing.
Thẻ 10
Câu hỏi
A category score is 90% and its course weight is 20%. Which number describes performance, and which describes relative influence?
Câu trả lời
90% is performance; 20% is relative influence.
Its full-course contribution is 0.20 × 90 = 18 percentage points.
Thẻ 11
Câu hỏi
Scores are 8/10 and 21/30. A policy gives each assessment equal weight after converting to percentages. What is the overall percentage?
Câu trả lời
75%.
The assessment percentages are 80% and 70%; their equal-weight mean is (80 + 70) / 2.
Thẻ 12
Câu hỏi
A recorded value is 6 on four occasions and 11 on two occasions. What is the mean over all six occasions?
Câu trả lời
23/3, or 7⅔.
(4 × 6 + 2 × 11) / 6 = 46/6.
Thẻ 13
Câu hỏi
All weights in a weighted mean are multiplied by 7. The original total weight is positive. What happens to the mean?
Câu trả lời
It stays the same.
Both numerator and denominator gain the same factor, which cancels.
Thẻ 14
Câu hỏi
A group has 15 observations and an exact mean of 12 units per observation. What is the total of its observations?
Câu trả lời
180 units.
15 × 12 = 180. Reconstruct totals before combining groups.
Thẻ 15
Câu hỏi
Scores are 8/10 and 21/30. A policy pools all earned points and all possible points. What is the overall percentage?
Câu trả lời
72.5%.
(8 + 21) / (10 + 30) × 100 = 29/40 × 100.
Thẻ 16
Câu hỏi
Two disjoint batches cover all trials in a target set. Each trial has one success/failure outcome. To pool exact batch success percentages, what should their weights represent?
Câu trả lời
The numbers of trials in the batches.
Success percentage × trial count reconstructs successes, after converting percentages to proportions.
Thẻ 17
Câu hỏi
Values 18 and 30 have relative weights 1 and 3. What is their weighted mean?
Câu trả lời
27.
(1 × 18 + 3 × 30) / 4 = 108/4.
Thẻ 18
Câu hỏi
Two disjoint groups cover all 25 observations of one quantity on the same scale. Their exact means are 12 for 10 observations and 17 for 15 observations. What is the combined mean?
Câu trả lời
15.
(10 × 12 + 15 × 17) / 25 = 375/25.
Thẻ 19
Câu hỏi
A course uses an 80% project score with weight 25% and a 68% exam score with weight 75%. These are all categories. What is the course percentage?
Câu trả lời
71%.
0.25 × 80 + 0.75 × 68 = 20 + 51.
Thẻ 20
Câu hỏi
Values 10 and 22 have weights 2 and 4. A solution reports the numerator 108 as the weighted mean. What single operation is missing?
Câu trả lời
Divide by the total weight, 6.
108/6 = 18. A weighted sum becomes a weighted mean only after the correct division.
Thẻ 21
Câu hỏi
A course category has a missing score and a positive weight. Is that equivalent to giving the category zero weight?
Câu trả lời
No.
A missing score is unknown; zero weight explicitly removes influence. A policy must say how missing work is treated.
Thẻ 22
Câu hỏi
Three disjoint groups cover all observations of one quantity on the same scale. Their (size, exact mean) pairs are (4, 5), (6, 8), and (10, 11). What is the combined mean?
Câu trả lời
8.9.
(4 × 5 + 6 × 8 + 10 × 11) / (4 + 6 + 10) = 178/20.
Thẻ 23
Câu hỏi
Completed work has score 84% and counts for 40% of a course. What contribution has it earned toward the full-course percentage?
Câu trả lời
33.6 percentage points.
0.40 × 84 = 33.6. The remaining 60% has not yet supplied a contribution.
Thẻ 24
Câu hỏi
Two disjoint batches cover all trials in a target set. Exactly 9/15 trials succeed in one batch and 21/25 in the other. What is the pooled success percentage?
Câu trả lời
75%.
(9 + 21) / (15 + 25) × 100 = 30/40 × 100.
Thẻ 25
Câu hỏi
Values with positive weights range from 30 to 80. A calculation gives a weighted arithmetic mean of 87. Can that result be correct under nonnegative weighting?
Câu trả lời
No.
87 exceeds every positively weighted value. Check the products, scales, and denominator.
Thẻ 26
Câu hỏi
Two disjoint groups cover a target set on one scale. Their exact means are 40 and 70, with sizes 6 and 18. A solution averages the means as (40 + 70)/2. What is the correct combined mean?
Câu trả lời
62.5.
Use the counts: (6 × 40 + 18 × 70) / 24 = 1500/24. Equal weighting would give each group equal influence.
Thẻ 27
Câu hỏi
Two completed course categories have scores 70% and 90%, with course weights 20% and 30%. The other 50% is unfinished. When completed weights are renormalized, what is the completed-work percentage?
Câu trả lời
82%.
(0.20 × 70 + 0.30 × 90) / 0.50 = 41/0.50. This is the completed-work result, not the contribution to the whole course.
Thẻ 28
Câu hỏi
Values 24 and 36 have normalized weights 0.25 and 0.75. What is their weighted mean?
Câu trả lời
33.
0.25 × 24 + 0.75 × 36 = 6 + 27. No further division is needed because the weights sum to 1.
Thẻ 29
Câu hỏi
All weights in a proposed weighted arithmetic mean are zero. Is the mean defined?
Câu trả lời
No.
The total weight is zero, so the formula would divide by zero.
Thẻ 30
Câu hỏi
Two disjoint groups cover all 20 observations of one quantity on one scale. The combined mean is exactly 16. One group has 8 observations with exact mean 10; the other has 12. What is the second group’s mean?
Câu trả lời
20.
The second total is 20 × 16 − 8 × 10 = 240; divide by 12. Check: (80 + 240)/20 = 16.
Thẻ 31
Câu hỏi
Completed work has score 76% and weight 60%. A final exam has weight 40%. With no other categories, what final-exam percentage gives a course result of 80%?
Câu trả lời
86%.
0.60 × 76 + 0.40 × x = 80, so x = (80 − 45.6)/0.40 = 86.
Thẻ 32
Câu hỏi
Two reported group means use some of the same observations. Can weighting them by group sizes automatically recover the mean of the distinct observations?
Câu trả lời
No. Overlapping observations would be counted more than once.
You need information that removes the duplicate contribution before reconstructing the target total and count.
Thẻ 33
Câu hỏi
Values 20 and 80 have positive weights 4 and 1. Without calculating the mean, which value is it closer to?
Câu trả lời
20.
With two distinct values, the mean is closer to the one with the larger weight. Its distance from 20 is one fifth of the 60-unit gap.
Thẻ 34
Câu hỏi
Two disjoint groups cover a target set on one scale. One has 12 observations with exact mean 18; the other has exact mean 30. The combined mean is exactly 26. How many observations are in the second group?
Câu trả lời
24 observations.
(216 + 30n)/(12 + n) = 26 gives 4n = 96. Check: (216 + 720)/36 = 26.
Thẻ 35
Câu hỏi
Completed work worth 25% of a course has score 92%. A solution calls 92 the percentage points already earned toward the whole course. What is the correct contribution?
Câu trả lời
23 percentage points.
0.25 × 92 = 23. The 92% score describes performance on completed work.
Thẻ 36
Câu hỏi
Two disjoint batches cover all trials. Their exact success rates are 50% of 10 trials and 90% of 30 trials. A solution reports their equal mean, 70%, as the pooled rate. What is the pooled rate?
Câu trả lời
80%.
(0.50 × 10 + 0.90 × 30)/40 × 100 = 32/40 × 100. Weight the rates by their trial counts.
Thẻ 37
Câu hỏi
Two categories have course weights 30% and 70%. Only the first score, 90%, is known. Is the final course percentage determined?
Câu trả lời
No. The second score is still needed.
The known contribution is 27 percentage points; the final result is 27 + 0.70 × the second score.
Thẻ 38
Câu hỏi
Two disjoint groups cover a set on one scale, with sizes 10 and 30. Their means, rounded to the nearest whole unit, are reported as 8 and 12. Does weighting these reports give the exact combined mean?
Câu trả lời
No; it gives an estimate of 11 units.
(10 × 8 + 30 × 12)/40 = 11, but rounding discarded information about both true group totals.
Thẻ 39
Câu hỏi
Completed work has score 50% and weight 70%. The remaining assessment has weight 30% and a maximum score of 100%. Is a final course result of 80% attainable?
Câu trả lời
No. The maximum is 65%.
0.70 × 50 + 0.30 × 100 = 65. Reaching 80 would require 150% on the remaining assessment.
Thẻ 40
Câu hỏi
Scores 0.8 and 70 represent 80% and 70%. Equal assessment weights are intended. What must be repaired before averaging the two recorded numbers?
Câu trả lời
Put both scores on the same scale.
Use 80 and 70 for a percentage result of 75%, or 0.8 and 0.7 for a proportion of 0.75.
Thẻ 41
Câu hỏi
Completed categories contribute 36 percentage points and occupy 45% of a course. The remaining 55% receives score 80%. What is the final course percentage?
Câu trả lời
80%.
36 + 0.55 × 80 = 80. Add full-course contributions; do not average the contribution 36 with the score 80.
Thẻ 42
Câu hỏi
A policy gives two groups equal influence, regardless of size. Their exact means on one scale are 10 and 22. What is the policy-weighted mean?
Câu trả lời
16.
(10 + 22)/2 = 16. This answers the equal-group policy; it need not equal the mean across individuals.
42 thẻ
Weighted Average Flashcards: Choose Weights & Combine Means
Nibomo sẽ mở ra để bạn bắt đầu học.