Ionic Compound Naming Flashcards: Names, Formulas & Charge Balance
Practice ionic compound naming with 56 English flashcards on neutral formulas, Roman numerals, polyatomic-ion parentheses, and common errors.
Informazioni su questo mazzo
Practice ionic compound names and neutral formulas with 56 English flashcards. This focused deck is for high-school and introductory-college learners who know basic ions and want to apply charge balance consistently.
The cards practice names to formulas, selected formulas back to names, metal-charge inference, one polyatomic-group count, and short repairs of incorrect formulas or missing naming information. Ion charges and polyatomic-ion names are supplied where the target is applying a rule. This is compound-naming practice rather than a table of isolated ions; use the polyatomic ion flashcards for that prerequisite.
The sequence begins with neutrality, cation-first order, subscripts, and the smallest whole-number ratio of intact ions. Fixed-charge binary salts come next, followed by iron, copper, and tin Stock names. Polyatomic groups and ammonium then lead into mixed formula, naming, and error-repair prompts. Selected reverse directions and closely related variants are separated. Every card carries the ionic-naming tag; the review scheduler handles longer-term spacing.
Names follow the usual introductory convention: fixed-charge cations without Roman numerals, variable-charge monatomic metals with Stock Roman numerals, and familiar polyatomic-ion names. Aluminum and aluminium are accepted spelling variants; sodium hydrogen carbonate and sodium bicarbonate are both accepted. This convention does not exhaust all valid systematic names. Arbitrary name-to-example prompts and exhaustive reversals are omitted because they add ambiguity or repetition. Covalent naming, acids, hydrates, organic compounds, coordination complexes, peroxide and mercury(I) special cases, reactions, and solubility are outside this deck. No full-course or examination alignment is claimed.
The questions, explanations, order, and metadata were written independently with AI assistance. Naming and ion facts were checked against Purdue University’s ionic-naming rules and ion reference tables. No competitor cards, source exercise wording, examination questions, or source diagrams were copied. Reference works retain their own rights, and chemical facts are not claimed as proprietary. Original material, including the AI-generated decorative charge-symbol cover, is dedicated under CC0 1.0 to the extent applicable rights exist. This is independent study material without institutional endorsement.
Carte in questo mazzo
Carta 1
Domanda
In a neutral ionic formula unit, what must the total ionic charge be?
Risposta
Zero. The positive and negative charges must cancel.
Carta 2
Domanda
When naming a simple ionic compound, which ion is named first?
Risposta
The cation, followed by the anion.
Carta 3
Domanda
Write the formula for lithium fluoride using Li⁺ and F⁻.
Risposta
LiF. One ion of each kind gives +1 − 1 = 0.
Carta 4
Domanda
In CaCl₂, what does the subscript 2 count?
Risposta
Two chloride ions for each calcium ion. It does not mean that each chloride ion has a charge of −2.
Carta 5
Domanda
Name MgO using the usual fixed-charge ionic naming convention.
Risposta
Magnesium oxide. The ions are Mg²⁺ and O²⁻.
Carta 6
Domanda
What is the smallest neutral ratio of Al³⁺ ions to O²⁻ ions?
Risposta
Two Al³⁺ ions to three O²⁻ ions: +6 and −6 cancel.
Carta 7
Domanda
Write the formula for magnesium bromide using Mg²⁺ and Br⁻.
Risposta
MgBr₂. Two bromide ions balance one magnesium ion.
Carta 8
Domanda
Name Na₂S using the usual fixed-charge ionic naming convention.
Risposta
Sodium sulfide. The sulfur anion is called sulfide.
Carta 9
Domanda
Write the simplest formula for calcium oxide using Ca²⁺ and O²⁻.
Risposta
CaO. Equal and opposite charges give a 1:1 ion ratio.
Carta 10
Domanda
Write the formula for aluminum nitride using Al³⁺ and N³⁻.
Risposta
AlN. One ion of each kind is neutral. Aluminium nitride is the same compound, with the British spelling.
Carta 11
Domanda
Name Mg₃N₂ using the usual fixed-charge ionic naming convention.
Risposta
Magnesium nitride. Three Mg²⁺ ions balance two N³⁻ ions.
Carta 12
Domanda
Write the formula for lithium oxide using Li⁺ and O²⁻.
Risposta
Li₂O. Two lithium ions balance one oxide ion.
Carta 13
Domanda
Name CaF₂ using the usual fixed-charge ionic naming convention.
Risposta
Calcium fluoride. This convention uses the ion names without a di- prefix for the two fluoride ions.
Carta 14
Domanda
A student writes Mg₂O₂ for magnesium oxide, using Mg²⁺ and O²⁻. What is the simplest formula?
Risposta
MgO. The 2:2 ion ratio is neutral but reduces to 1:1.
Carta 15
Domanda
Name Al₂S₃ using the usual fixed-charge ionic naming convention.
Risposta
Aluminum sulfide (also spelled aluminium sulfide). Two Al³⁺ ions balance three S²⁻ ions.
Carta 16
Domanda
Write the formula for sodium phosphide using Na⁺ and P³⁻.
Risposta
Na₃P. Three sodium ions balance one phosphide ion.
Carta 17
Domanda
Name LiF using the usual fixed-charge ionic naming convention.
Risposta
Lithium fluoride. Name the lithium cation first and the fluoride anion second.
Carta 18
Domanda
Write the formula for magnesium oxide using Mg²⁺ and O²⁻.
Risposta
MgO. The smallest neutral ratio is one magnesium ion to one oxide ion.
Carta 19
Domanda
In the Stock name iron(III) chloride, what does III specify?
Risposta
A +3 charge on each iron ion. For this monatomic ion, its charge equals its oxidation state; III is not an atom count.
Carta 20
Domanda
Name FeCl₂ using Stock nomenclature. Chloride is Cl⁻.
Risposta
Iron(II) chloride. Two chloride ions total −2, so the iron ion is Fe²⁺.
Carta 21
Domanda
What is the charge on each copper ion in Cu₂O, taking oxide as O²⁻?
Risposta
+1. The two copper ions together must supply +2, so each is Cu⁺.
Carta 22
Domanda
Write the formula for tin(IV) oxide, using oxide O²⁻.
Risposta
SnO₂. One Sn⁴⁺ ion balances two oxide ions; reduce a crossed 2:4 ratio to 1:2.
Carta 23
Domanda
Name Fe₂O₃ using Stock nomenclature. Oxide is O²⁻.
Risposta
Iron(III) oxide. Three oxide ions total −6; divided between two iron ions, that requires Fe³⁺.
Carta 24
Domanda
Write the formula for copper(II) bromide, using bromide Br⁻.
Risposta
CuBr₂. One Cu²⁺ ion needs two bromide ions.
Carta 25
Domanda
Name SnCl₂ using Stock nomenclature. Chloride is Cl⁻.
Risposta
Tin(II) chloride. Two Cl⁻ ions require one Sn²⁺ ion.
Carta 26
Domanda
Write the formula for iron(II) chloride, using chloride Cl⁻.
Risposta
FeCl₂. One Fe²⁺ ion balances two chloride ions.
Carta 27
Domanda
Name CuO using Stock nomenclature. Oxide is O²⁻.
Risposta
Copper(II) oxide. The 1:1 ratio requires Cu²⁺ to balance O²⁻.
Carta 28
Domanda
Write the formula for iron(III) sulfide, using sulfide S²⁻.
Risposta
Fe₂S₃. Two Fe³⁺ ions supply +6 and three sulfide ions supply −6.
Carta 29
Domanda
Why is the name copper chloride insufficient to choose a single formula in introductory Stock nomenclature?
Risposta
It omits the copper oxidation state. Copper(I) chloride is CuCl; copper(II) chloride is CuCl₂.
Carta 30
Domanda
Name SnO₂ using Stock nomenclature. Oxide is O²⁻.
Risposta
Tin(IV) oxide. Two oxide ions total −4, so the tin ion is Sn⁴⁺.
Carta 31
Domanda
A student labels Fe₂O₃ as iron(II) oxide. Keeping the name iron(II) oxide, what formula should replace it?
Risposta
FeO. Fe²⁺ and O²⁻ balance in a 1:1 ratio; Fe₂O₃ instead corresponds to iron(III) oxide.
Carta 32
Domanda
Name CaCl₂ using the usual introductory fixed-charge convention.
Risposta
Calcium chloride. Calcium is treated as Ca²⁺, so this convention omits the Roman numeral. An explicit oxidation-state name is not a different compound.
Carta 33
Domanda
Write the formula for sodium nitrate using Na⁺ and NO₃⁻.
Risposta
NaNO₃. One nitrate ion balances one sodium ion; keep the nitrate formula intact.
Carta 34
Domanda
Name K₂CO₃. The polyatomic ion CO₃²⁻ is carbonate.
Risposta
Potassium carbonate. Two K⁺ ions balance one carbonate ion.
Carta 35
Domanda
When writing a conventional ionic formula, when do you put a polyatomic ion in parentheses?
Risposta
When more than one of that whole ion is needed. Put the count outside the parentheses and leave the ion’s internal subscripts unchanged.
Carta 36
Domanda
Write the formula for calcium hydroxide using Ca²⁺ and OH⁻.
Risposta
Ca(OH)₂. Two whole hydroxide ions balance one calcium ion.
Carta 37
Domanda
Name NH₄Cl. NH₄⁺ is ammonium.
Risposta
Ammonium chloride. The cation is the whole NH₄⁺ ion, even though it contains no metal.
Carta 38
Domanda
Write the formula for aluminum sulfate using Al³⁺ and SO₄²⁻.
Risposta
Al₂(SO₄)₃. Two aluminum ions supply +6 and three intact sulfate ions supply −6.
Carta 39
Domanda
Name Mg(NO₃)₂. NO₃⁻ is nitrate.
Risposta
Magnesium nitrate. One Mg²⁺ ion is balanced by two nitrate ions.
Carta 40
Domanda
Write the formula for ammonium phosphate using NH₄⁺ and PO₄³⁻.
Risposta
(NH₄)₃PO₄. Three ammonium ions balance one phosphate ion; only ammonium needs parentheses.
Carta 41
Domanda
How many whole hydroxide ions are represented in one formula unit of Ba(OH)₂?
Risposta
Two hydroxide ions. The outer subscript multiplies the entire OH group, giving two O atoms and two H atoms.
Carta 42
Domanda
Name Fe₂(SO₄)₃ using Stock nomenclature. SO₄²⁻ is sulfate.
Risposta
Iron(III) sulfate. Three sulfate ions total −6, so each of the two iron ions has charge +3.
Carta 43
Domanda
Write the formula for calcium nitrate using Ca²⁺ and NO₃⁻.
Risposta
Ca(NO₃)₂. Two intact nitrate ions supply −2 to balance calcium’s +2.
Carta 44
Domanda
Name (NH₄)₂SO₄. NH₄⁺ is ammonium and SO₄²⁻ is sulfate.
Risposta
Ammonium sulfate. Two ammonium ions balance one sulfate ion.
Carta 45
Domanda
Write the formula for magnesium phosphate using Mg²⁺ and PO₄³⁻.
Risposta
Mg₃(PO₄)₂. Three magnesium ions and two phosphate ions give +6 and −6.
Carta 46
Domanda
Name NaHCO₃. HCO₃⁻ is hydrogen carbonate, also called bicarbonate.
Risposta
Sodium hydrogen carbonate, also called sodium bicarbonate. HCO₃⁻ is one intact anion.
Carta 47
Domanda
Repair AlOH₃ as the formula for aluminum hydroxide, using Al³⁺ and OH⁻.
Risposta
Al(OH)₃. Three whole hydroxide ions are needed. AlOH₃ fails to multiply the oxygen count along with the hydrogen count.
Carta 48
Domanda
Write the formula for ammonium sulfite using NH₄⁺ and SO₃²⁻.
Risposta
(NH₄)₂SO₃. Two ammonium ions balance one sulfite ion; sulfite retains its three oxygen atoms.
Carta 49
Domanda
Name Cu(NO₃)₂ using Stock nomenclature. NO₃⁻ is nitrate.
Risposta
Copper(II) nitrate. Two nitrate ions total −2, requiring Cu²⁺.
Carta 50
Domanda
Write the formula for iron(III) sulfate, using sulfate SO₄²⁻.
Risposta
Fe₂(SO₄)₃. Two Fe³⁺ ions balance three sulfate ions.
Carta 51
Domanda
Repair K(CO₃)₂ as the formula for potassium carbonate, using K⁺ and CO₃²⁻.
Risposta
K₂CO₃. Two potassium ions balance one carbonate ion. A single carbonate group needs no parentheses.
Carta 52
Domanda
Can Mg(NO₃)₂ be simplified to MgNO₃ by removing the outer subscript? Use Mg²⁺ and NO₃⁻.
Risposta
No. The ion ratio is already 1:2. Removing the outer 2 would leave total charge +1 instead of zero.
Carta 53
Domanda
Name Ca(OH)₂. OH⁻ is hydroxide.
Risposta
Calcium hydroxide. The two hydroxide ions balance one Ca²⁺ ion; the ion name stays hydroxide.
Carta 54
Domanda
What is the charge on each copper ion in Cu₃(PO₄)₂, taking phosphate as PO₄³⁻?
Risposta
+2. Two phosphate ions total −6, shared equally among three copper ions as +2 each.
Carta 55
Domanda
Write the formula for sodium nitrite using Na⁺ and NO₂⁻.
Risposta
NaNO₂. One nitrite ion balances one sodium ion. Keep NO₂⁻ intact; NO₃⁻ would be nitrate.
Carta 56
Domanda
Repair NH₄SO₄ as the formula for ammonium sulfate, using NH₄⁺ and SO₄²⁻.
Risposta
(NH₄)₂SO₄. Two whole ammonium ions are required to balance one sulfate ion; the 2 goes outside the ammonium parentheses.
56 carte
Ionic Compound Naming Flashcards: Names, Formulas & Charge Balance
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