Ionic Compound Naming Flashcards: Names, Formulas & Charge Balance
Practice ionic compound naming with 56 English flashcards on neutral formulas, Roman numerals, polyatomic-ion parentheses, and common errors.
Apie šį rinkinį
Practice ionic compound names and neutral formulas with 56 English flashcards. This focused deck is for high-school and introductory-college learners who know basic ions and want to apply charge balance consistently.
The cards practice names to formulas, selected formulas back to names, metal-charge inference, one polyatomic-group count, and short repairs of incorrect formulas or missing naming information. Ion charges and polyatomic-ion names are supplied where the target is applying a rule. This is compound-naming practice rather than a table of isolated ions; use the polyatomic ion flashcards for that prerequisite.
The sequence begins with neutrality, cation-first order, subscripts, and the smallest whole-number ratio of intact ions. Fixed-charge binary salts come next, followed by iron, copper, and tin Stock names. Polyatomic groups and ammonium then lead into mixed formula, naming, and error-repair prompts. Selected reverse directions and closely related variants are separated. Every card carries the ionic-naming tag; the review scheduler handles longer-term spacing.
Names follow the usual introductory convention: fixed-charge cations without Roman numerals, variable-charge monatomic metals with Stock Roman numerals, and familiar polyatomic-ion names. Aluminum and aluminium are accepted spelling variants; sodium hydrogen carbonate and sodium bicarbonate are both accepted. This convention does not exhaust all valid systematic names. Arbitrary name-to-example prompts and exhaustive reversals are omitted because they add ambiguity or repetition. Covalent naming, acids, hydrates, organic compounds, coordination complexes, peroxide and mercury(I) special cases, reactions, and solubility are outside this deck. No full-course or examination alignment is claimed.
The questions, explanations, order, and metadata were written independently with AI assistance. Naming and ion facts were checked against Purdue University’s ionic-naming rules and ion reference tables. No competitor cards, source exercise wording, examination questions, or source diagrams were copied. Reference works retain their own rights, and chemical facts are not claimed as proprietary. Original material, including the AI-generated decorative charge-symbol cover, is dedicated under CC0 1.0 to the extent applicable rights exist. This is independent study material without institutional endorsement.
Šio rinkinio kortelės
1 kortelė
Klausimas
In a neutral ionic formula unit, what must the total ionic charge be?
Atsakymas
Zero. The positive and negative charges must cancel.
2 kortelė
Klausimas
When naming a simple ionic compound, which ion is named first?
Atsakymas
The cation, followed by the anion.
3 kortelė
Klausimas
Write the formula for lithium fluoride using Li⁺ and F⁻.
Atsakymas
LiF. One ion of each kind gives +1 − 1 = 0.
4 kortelė
Klausimas
In CaCl₂, what does the subscript 2 count?
Atsakymas
Two chloride ions for each calcium ion. It does not mean that each chloride ion has a charge of −2.
5 kortelė
Klausimas
Name MgO using the usual fixed-charge ionic naming convention.
Atsakymas
Magnesium oxide. The ions are Mg²⁺ and O²⁻.
6 kortelė
Klausimas
What is the smallest neutral ratio of Al³⁺ ions to O²⁻ ions?
Atsakymas
Two Al³⁺ ions to three O²⁻ ions: +6 and −6 cancel.
7 kortelė
Klausimas
Write the formula for magnesium bromide using Mg²⁺ and Br⁻.
Atsakymas
MgBr₂. Two bromide ions balance one magnesium ion.
8 kortelė
Klausimas
Name Na₂S using the usual fixed-charge ionic naming convention.
Atsakymas
Sodium sulfide. The sulfur anion is called sulfide.
9 kortelė
Klausimas
Write the simplest formula for calcium oxide using Ca²⁺ and O²⁻.
Atsakymas
CaO. Equal and opposite charges give a 1:1 ion ratio.
10 kortelė
Klausimas
Write the formula for aluminum nitride using Al³⁺ and N³⁻.
Atsakymas
AlN. One ion of each kind is neutral. Aluminium nitride is the same compound, with the British spelling.
11 kortelė
Klausimas
Name Mg₃N₂ using the usual fixed-charge ionic naming convention.
Atsakymas
Magnesium nitride. Three Mg²⁺ ions balance two N³⁻ ions.
12 kortelė
Klausimas
Write the formula for lithium oxide using Li⁺ and O²⁻.
Atsakymas
Li₂O. Two lithium ions balance one oxide ion.
13 kortelė
Klausimas
Name CaF₂ using the usual fixed-charge ionic naming convention.
Atsakymas
Calcium fluoride. This convention uses the ion names without a di- prefix for the two fluoride ions.
14 kortelė
Klausimas
A student writes Mg₂O₂ for magnesium oxide, using Mg²⁺ and O²⁻. What is the simplest formula?
Atsakymas
MgO. The 2:2 ion ratio is neutral but reduces to 1:1.
15 kortelė
Klausimas
Name Al₂S₃ using the usual fixed-charge ionic naming convention.
Atsakymas
Aluminum sulfide (also spelled aluminium sulfide). Two Al³⁺ ions balance three S²⁻ ions.
16 kortelė
Klausimas
Write the formula for sodium phosphide using Na⁺ and P³⁻.
Atsakymas
Na₃P. Three sodium ions balance one phosphide ion.
17 kortelė
Klausimas
Name LiF using the usual fixed-charge ionic naming convention.
Atsakymas
Lithium fluoride. Name the lithium cation first and the fluoride anion second.
18 kortelė
Klausimas
Write the formula for magnesium oxide using Mg²⁺ and O²⁻.
Atsakymas
MgO. The smallest neutral ratio is one magnesium ion to one oxide ion.
19 kortelė
Klausimas
In the Stock name iron(III) chloride, what does III specify?
Atsakymas
A +3 charge on each iron ion. For this monatomic ion, its charge equals its oxidation state; III is not an atom count.
20 kortelė
Klausimas
Name FeCl₂ using Stock nomenclature. Chloride is Cl⁻.
Atsakymas
Iron(II) chloride. Two chloride ions total −2, so the iron ion is Fe²⁺.
21 kortelė
Klausimas
What is the charge on each copper ion in Cu₂O, taking oxide as O²⁻?
Atsakymas
+1. The two copper ions together must supply +2, so each is Cu⁺.
22 kortelė
Klausimas
Write the formula for tin(IV) oxide, using oxide O²⁻.
Atsakymas
SnO₂. One Sn⁴⁺ ion balances two oxide ions; reduce a crossed 2:4 ratio to 1:2.
23 kortelė
Klausimas
Name Fe₂O₃ using Stock nomenclature. Oxide is O²⁻.
Atsakymas
Iron(III) oxide. Three oxide ions total −6; divided between two iron ions, that requires Fe³⁺.
24 kortelė
Klausimas
Write the formula for copper(II) bromide, using bromide Br⁻.
Atsakymas
CuBr₂. One Cu²⁺ ion needs two bromide ions.
25 kortelė
Klausimas
Name SnCl₂ using Stock nomenclature. Chloride is Cl⁻.
Atsakymas
Tin(II) chloride. Two Cl⁻ ions require one Sn²⁺ ion.
26 kortelė
Klausimas
Write the formula for iron(II) chloride, using chloride Cl⁻.
Atsakymas
FeCl₂. One Fe²⁺ ion balances two chloride ions.
27 kortelė
Klausimas
Name CuO using Stock nomenclature. Oxide is O²⁻.
Atsakymas
Copper(II) oxide. The 1:1 ratio requires Cu²⁺ to balance O²⁻.
28 kortelė
Klausimas
Write the formula for iron(III) sulfide, using sulfide S²⁻.
Atsakymas
Fe₂S₃. Two Fe³⁺ ions supply +6 and three sulfide ions supply −6.
29 kortelė
Klausimas
Why is the name copper chloride insufficient to choose a single formula in introductory Stock nomenclature?
Atsakymas
It omits the copper oxidation state. Copper(I) chloride is CuCl; copper(II) chloride is CuCl₂.
30 kortelė
Klausimas
Name SnO₂ using Stock nomenclature. Oxide is O²⁻.
Atsakymas
Tin(IV) oxide. Two oxide ions total −4, so the tin ion is Sn⁴⁺.
31 kortelė
Klausimas
A student labels Fe₂O₃ as iron(II) oxide. Keeping the name iron(II) oxide, what formula should replace it?
Atsakymas
FeO. Fe²⁺ and O²⁻ balance in a 1:1 ratio; Fe₂O₃ instead corresponds to iron(III) oxide.
32 kortelė
Klausimas
Name CaCl₂ using the usual introductory fixed-charge convention.
Atsakymas
Calcium chloride. Calcium is treated as Ca²⁺, so this convention omits the Roman numeral. An explicit oxidation-state name is not a different compound.
33 kortelė
Klausimas
Write the formula for sodium nitrate using Na⁺ and NO₃⁻.
Atsakymas
NaNO₃. One nitrate ion balances one sodium ion; keep the nitrate formula intact.
34 kortelė
Klausimas
Name K₂CO₃. The polyatomic ion CO₃²⁻ is carbonate.
Atsakymas
Potassium carbonate. Two K⁺ ions balance one carbonate ion.
35 kortelė
Klausimas
When writing a conventional ionic formula, when do you put a polyatomic ion in parentheses?
Atsakymas
When more than one of that whole ion is needed. Put the count outside the parentheses and leave the ion’s internal subscripts unchanged.
36 kortelė
Klausimas
Write the formula for calcium hydroxide using Ca²⁺ and OH⁻.
Atsakymas
Ca(OH)₂. Two whole hydroxide ions balance one calcium ion.
37 kortelė
Klausimas
Name NH₄Cl. NH₄⁺ is ammonium.
Atsakymas
Ammonium chloride. The cation is the whole NH₄⁺ ion, even though it contains no metal.
38 kortelė
Klausimas
Write the formula for aluminum sulfate using Al³⁺ and SO₄²⁻.
Atsakymas
Al₂(SO₄)₃. Two aluminum ions supply +6 and three intact sulfate ions supply −6.
39 kortelė
Klausimas
Name Mg(NO₃)₂. NO₃⁻ is nitrate.
Atsakymas
Magnesium nitrate. One Mg²⁺ ion is balanced by two nitrate ions.
40 kortelė
Klausimas
Write the formula for ammonium phosphate using NH₄⁺ and PO₄³⁻.
Atsakymas
(NH₄)₃PO₄. Three ammonium ions balance one phosphate ion; only ammonium needs parentheses.
41 kortelė
Klausimas
How many whole hydroxide ions are represented in one formula unit of Ba(OH)₂?
Atsakymas
Two hydroxide ions. The outer subscript multiplies the entire OH group, giving two O atoms and two H atoms.
42 kortelė
Klausimas
Name Fe₂(SO₄)₃ using Stock nomenclature. SO₄²⁻ is sulfate.
Atsakymas
Iron(III) sulfate. Three sulfate ions total −6, so each of the two iron ions has charge +3.
43 kortelė
Klausimas
Write the formula for calcium nitrate using Ca²⁺ and NO₃⁻.
Atsakymas
Ca(NO₃)₂. Two intact nitrate ions supply −2 to balance calcium’s +2.
44 kortelė
Klausimas
Name (NH₄)₂SO₄. NH₄⁺ is ammonium and SO₄²⁻ is sulfate.
Atsakymas
Ammonium sulfate. Two ammonium ions balance one sulfate ion.
45 kortelė
Klausimas
Write the formula for magnesium phosphate using Mg²⁺ and PO₄³⁻.
Atsakymas
Mg₃(PO₄)₂. Three magnesium ions and two phosphate ions give +6 and −6.
46 kortelė
Klausimas
Name NaHCO₃. HCO₃⁻ is hydrogen carbonate, also called bicarbonate.
Atsakymas
Sodium hydrogen carbonate, also called sodium bicarbonate. HCO₃⁻ is one intact anion.
47 kortelė
Klausimas
Repair AlOH₃ as the formula for aluminum hydroxide, using Al³⁺ and OH⁻.
Atsakymas
Al(OH)₃. Three whole hydroxide ions are needed. AlOH₃ fails to multiply the oxygen count along with the hydrogen count.
48 kortelė
Klausimas
Write the formula for ammonium sulfite using NH₄⁺ and SO₃²⁻.
Atsakymas
(NH₄)₂SO₃. Two ammonium ions balance one sulfite ion; sulfite retains its three oxygen atoms.
49 kortelė
Klausimas
Name Cu(NO₃)₂ using Stock nomenclature. NO₃⁻ is nitrate.
Atsakymas
Copper(II) nitrate. Two nitrate ions total −2, requiring Cu²⁺.
50 kortelė
Klausimas
Write the formula for iron(III) sulfate, using sulfate SO₄²⁻.
Atsakymas
Fe₂(SO₄)₃. Two Fe³⁺ ions balance three sulfate ions.
51 kortelė
Klausimas
Repair K(CO₃)₂ as the formula for potassium carbonate, using K⁺ and CO₃²⁻.
Atsakymas
K₂CO₃. Two potassium ions balance one carbonate ion. A single carbonate group needs no parentheses.
52 kortelė
Klausimas
Can Mg(NO₃)₂ be simplified to MgNO₃ by removing the outer subscript? Use Mg²⁺ and NO₃⁻.
Atsakymas
No. The ion ratio is already 1:2. Removing the outer 2 would leave total charge +1 instead of zero.
53 kortelė
Klausimas
Name Ca(OH)₂. OH⁻ is hydroxide.
Atsakymas
Calcium hydroxide. The two hydroxide ions balance one Ca²⁺ ion; the ion name stays hydroxide.
54 kortelė
Klausimas
What is the charge on each copper ion in Cu₃(PO₄)₂, taking phosphate as PO₄³⁻?
Atsakymas
+2. Two phosphate ions total −6, shared equally among three copper ions as +2 each.
55 kortelė
Klausimas
Write the formula for sodium nitrite using Na⁺ and NO₂⁻.
Atsakymas
NaNO₂. One nitrite ion balances one sodium ion. Keep NO₂⁻ intact; NO₃⁻ would be nitrate.
56 kortelė
Klausimas
Repair NH₄SO₄ as the formula for ammonium sulfate, using NH₄⁺ and SO₄²⁻.
Atsakymas
(NH₄)₂SO₄. Two whole ammonium ions are required to balance one sulfate ion; the 2 goes outside the ammonium parentheses.
56 kortelės
Ionic Compound Naming Flashcards: Names, Formulas & Charge Balance
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