AP Calculus AB Flashcards: 8-Unit Formulas, Theorems & Concepts

Review all eight AP Calculus AB units with formula conditions, theorem hypotheses, notation, graph interpretation, and concept cards.

Mayelana naleli qoqo

Review the formulas, theorem conditions, notation, and representation links that support all eight AP Calculus AB units. The cards practice short recall in both useful directions: a name or situation can cue a formula, condition, theorem, or interpretation, and selected formulas or hypotheses can cue their meaning or use. Graph, table, symbolic, and word-based cards connect derivatives and integrals to rates, accumulation, extrema, concavity, motion, area, and volume.

The sequence starts with limits and the derivative definition, then builds through derivative rules and applications before moving to integration, differential equations, and applications of integration. Related variants are separated in the final order so one card does not simply reveal the next.

This is an AB-only review deck. It excludes parametric, polar, and vector-valued calculus; infinite sequences and series; integration by parts; partial fractions; improper integrals; logistic differential equations; arc length; and other BC-only material. It also excludes copied exam questions, mark schemes, curriculum prose, full theorem proofs, and long multi-step practice problems. Flashcards support recall; learners should still solve original practice problems and complete timed exam practice.

Every prompt, answer, explanation, metadata field, and ordering choice is independently written from common mathematical knowledge after checking the current official scope. No College Board question, mark scheme, curriculum text, logo, or trade dress is copied. AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this product. Official course requirements: AP Calculus AB Course.

Amakhadi akuleli qoqo

  1. Ikhadi 1

    Umbuzo

    What does limxaf(x)=L\lim_{x \to a} f(x)=L say?

    Impendulo

    The values of f(x)f(x) approach LL as xx approaches aa from both sides. The statement doesn't require f(a)=Lf(a)=L or even require f(a)f(a) to exist.

  2. Ikhadi 2

    Umbuzo

    How can a table estimate limxaf(x)\lim_{x \to a} f(x)?

    Impendulo

    Use inputs approaching aa from below and above, then look for a common output value. Values exactly at x=ax=a don't determine the limit.

  3. Ikhadi 3

    Umbuzo

    When does direct substitution evaluate a limit?

    Impendulo

    When the function is continuous at the target input. Then

    limxaf(x)=f(a).\lim_{x \to a} f(x)=f(a).
  4. Ikhadi 4

    Umbuzo

    Three conditions for continuity at x=ax=a?

    Impendulo

    f(a)f(a) exists, limxaf(x)\lim_{x \to a}f(x) exists, and

    limxaf(x)=f(a).\lim_{x \to a}f(x)=f(a).
  5. Ikhadi 5

    Umbuzo

    Intermediate Value Theorem: hypotheses and conclusion?

    Impendulo

    If ff is continuous on [a,b][a,b] and NN lies between f(a)f(a) and f(b)f(b), then some cc in [a,b][a,b] satisfies f(c)=Nf(c)=N. If NN is strictly between the endpoint values, cc lies in (a,b)(a,b).

  6. Ikhadi 6

    Umbuzo

    When does a two-sided limit equal LL?

    Impendulo

    Exactly when both one-sided limits equal LL:

    limxaf(x)=limxa+f(x)=L.\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)=L.

    If the one-sided limits differ, the two-sided limit doesn't exist.

  7. Ikhadi 7

    Umbuzo

    How do you read a finite limit from a graph?

    Impendulo

    Follow the graph toward the target xx-value from both sides. The common approached yy-value is the limit, regardless of a hole or a differently placed filled point.

  8. Ikhadi 8

    Umbuzo

    Limit law for a sum or difference?

    Impendulo

    If both component limits exist,

    limxa[f(x)±g(x)]=limxaf(x)±limxag(x).\lim_{x\to a}[f(x)\pm g(x)]=\lim_{x\to a}f(x)\pm\lim_{x\to a}g(x).
  9. Ikhadi 9

    Umbuzo

    What makes a discontinuity removable?

    Impendulo

    The finite two-sided limit exists, but the function value is missing or differs from that limit. Redefining the function at one point can make it continuous.

  10. Ikhadi 10

    Umbuzo

    Squeeze Theorem: usable form?

    Impendulo

    If g(x)f(x)h(x)g(x)\le f(x)\le h(x) near aa and

    limxag(x)=limxah(x)=L,\lim_{x\to a}g(x)=\lim_{x\to a}h(x)=L,

    then limxaf(x)=L\lim_{x\to a}f(x)=L.

  11. Ikhadi 11

    Umbuzo

    What does limxaf(x)=+\lim_{x\to a}f(x)=+\infty mean?

    Impendulo

    f(x)f(x) grows without bound above as xx approaches aa. It describes unbounded behavior, not a finite limit value.

  12. Ikhadi 12

    Umbuzo

    What must a table show for a left-hand limit?

    Impendulo

    Inputs less than the target and moving toward it. For limxaf(x)\lim_{x\to a^-}f(x), use x<ax<a with xx getting closer to aa.

  13. Ikhadi 13

    Umbuzo

    Limit law for a product?

    Impendulo

    If both limits exist,

    limxa[f(x)g(x)]=(limxaf(x))(limxag(x)).\lim_{x\to a}[f(x)g(x)]=\left(\lim_{x\to a}f(x)\right)\left(\lim_{x\to a}g(x)\right).
  14. Ikhadi 14

    Umbuzo

    Graph signature of a jump discontinuity?

    Impendulo

    The left- and right-hand limits are finite but unequal. The function approaches different heights from the two sides.

  15. Ikhadi 15

    Umbuzo

    Which theorem can guarantee a root on [a,b][a,b]?

    Impendulo

    The Intermediate Value Theorem. If ff is continuous on [a,b][a,b] and 00 lies between f(a)f(a) and f(b)f(b), then f(c)=0f(c)=0 for some cc in the interval.

  16. Ikhadi 16

    Umbuzo

    Horizontal asymptote from a limit at infinity?

    Impendulo

    If limxf(x)=L\lim_{x\to\infty}f(x)=L or limxf(x)=L\lim_{x\to-\infty}f(x)=L, then y=Ly=L is a horizontal asymptote in that direction.

  17. Ikhadi 17

    Umbuzo

    What does an open circle say about a graph's limit?

    Impendulo

    Only that the displayed point isn't included there. The limit depends on nearby behavior; it may still exist and equal the hole's height.

  18. Ikhadi 18

    Umbuzo

    Limit law for a quotient—and its condition?

    Impendulo

    If both limits exist and the denominator limit is nonzero,

    limxaf(x)g(x)=limxaf(x)limxag(x).\lim_{x\to a}\frac{f(x)}{g(x)}=\frac{\lim_{x\to a}f(x)}{\lim_{x\to a}g(x)}.

    The law doesn't apply when the denominator limit is 00.

  19. Ikhadi 19

    Umbuzo

    What does continuity on [a,b][a,b] require at the endpoints?

    Impendulo

    Continuity on (a,b)(a,b), right-continuity at aa, and left-continuity at bb:

    limxa+f(x)=f(a),limxbf(x)=f(b).\lim_{x\to a^+}f(x)=f(a),\qquad \lim_{x\to b^-}f(x)=f(b).
  20. Ikhadi 20

    Umbuzo

    When is the Squeeze Theorem a natural choice?

    Impendulo

    When a hard or oscillating expression can be trapped between two simpler expressions with the same limit.

  21. Ikhadi 21

    Umbuzo

    Vertical asymptote from one-sided behavior?

    Impendulo

    If at least one one-sided limit at x=ax=a is ++\infty or -\infty, then x=ax=a is a vertical asymptote.

  22. Ikhadi 22

    Umbuzo

    Limit at infinity of equal-degree rational functions?

    Impendulo

    The ratio of the leading coefficients:

    limx±anxn+bnxn+=anbn.\lim_{x\to\pm\infty}\frac{a_nx^n+\cdots}{b_nx^n+\cdots}=\frac{a_n}{b_n}.

    This assumes bn0b_n\ne0.

  23. Ikhadi 23

    Umbuzo

    When can a limit pass through a continuous outer function?

    Impendulo

    If limxag(x)=L\lim_{x\to a}g(x)=L and ff is continuous at LL, then

    limxaf(g(x))=f(L).\lim_{x\to a}f(g(x))=f(L).
  24. Ikhadi 24

    Umbuzo

    What makes a discontinuity infinite?

    Impendulo

    The function becomes unbounded on at least one side of the input, usually producing a vertical asymptote.

  25. Ikhadi 25

    Umbuzo

    Left limit =2=2 and right limit =5=5: two-sided limit?

    Impendulo

    It doesn't exist. A finite two-sided limit requires the two one-sided limits to agree.

  26. Ikhadi 26

    Umbuzo

    Standard trigonometric limit behind sinxx\frac{\sin x}{x}?

    Impendulo

    With angles in radians,

    limx0sinxx=1.\lim_{x\to0}\frac{\sin x}{x}=1.

    Equivalent scaled forms follow by substitution.

  27. Ikhadi 27

    Umbuzo

    Continuity of a composition?

    Impendulo

    If gg is continuous at aa and ff is continuous at g(a)g(a), then fgf\circ g is continuous at aa.

  28. Ikhadi 28

    Umbuzo

    Limit at infinity when a rational numerator has lower degree?

    Impendulo

    00. If the numerator's degree is less than the denominator's, the denominator dominates as x±x\to\pm\infty.

  29. Ikhadi 29

    Umbuzo

    What does the indeterminate form 0/00/0 tell you?

    Impendulo

    Direct substitution hasn't determined the limit. Simplify, use an appropriate limit method, or inspect another representation; 0/00/0 isn't the limit value.

  30. Ikhadi 30

    Umbuzo

    When do opposite infinite one-sided limits give a two-sided limit?

    Impendulo

    They don't. For example, ++\infty from the left and -\infty from the right mean the two-sided limit doesn't exist, though a vertical asymptote may be present.

  31. Ikhadi 31

    Umbuzo

    How do you choose a parameter to make a piecewise function continuous?

    Impendulo

    Set the relevant one-sided formulas and the function value equal at the join, then solve the resulting equation for the parameter.

  32. Ikhadi 32

    Umbuzo

    Value of limx01cosxx\lim_{x\to0}\frac{1-\cos x}{x}?

    Impendulo

    00. Rationalizing gives a product involving sinx/x\sin x/x and a factor that approaches 00.

  33. Ikhadi 33

    Umbuzo

    Can limxaf(x)\lim_{x\to a}f(x) exist when f(a)f(a) doesn't?

    Impendulo

    Yes. A limit uses nearby values, so a hole at x=ax=a can coexist with a finite two-sided limit.

  34. Ikhadi 34

    Umbuzo

    What graph behavior makes a finite limit fail even without a jump?

    Impendulo

    Unbounded or persistent oscillating behavior near the input can prevent a finite limit. Check both sides rather than relying on the plotted point.

  35. Ikhadi 35

    Umbuzo

    Average rate of change of ff on [a,b][a,b]?

    Impendulo

    f(b)f(a)ba\frac{f(b)-f(a)}{b-a}

    It is the slope of the secant line through (a,f(a))(a,f(a)) and (b,f(b))(b,f(b)).

  36. Ikhadi 36

    Umbuzo

    Derivative at x=ax=a using an increment hh?

    Impendulo

    f(a)=limh0f(a+h)f(a)hf'(a)=\lim_{h\to0}\frac{f(a+h)-f(a)}{h}

    The derivative exists only if this finite limit exists.

  37. Ikhadi 37

    Umbuzo

    Tangent-line equation to y=f(x)y=f(x) at x=ax=a?

    Impendulo

    yf(a)=f(a)(xa)y-f(a)=f'(a)(x-a)

    This requires f(a)f'(a) to exist.

  38. Ikhadi 38

    Umbuzo

    What does differentiability imply about continuity?

    Impendulo

    If ff is differentiable at aa, then ff is continuous at aa. The converse is false: continuity alone doesn't guarantee differentiability.

  39. Ikhadi 39

    Umbuzo

    Power rule for derivatives?

    Impendulo

    ddxxn=nxn1\frac{d}{dx}x^n=nx^{n-1}

    Apply it where the original real-valued power function and its derivative are defined.

  40. Ikhadi 40

    Umbuzo

    Units of f(x)f'(x)?

    Impendulo

    Output units of ff per input unit of xx. A derivative is a rate of change, so its units are a quotient.

  41. Ikhadi 41

    Umbuzo

    Derivative at x=ax=a using xax\to a?

    Impendulo

    f(a)=limxaf(x)f(a)xaf'(a)=\lim_{x\to a}\frac{f(x)-f(a)}{x-a}

    This is equivalent to the hh-form after setting h=xah=x-a.

  42. Ikhadi 42

    Umbuzo

    How does a graph of ff show the sign of ff'?

    Impendulo

    f(x)>0f'(x)>0 where ff rises as xx increases, and f(x)<0f'(x)<0 where ff falls. A horizontal tangent gives f(x)=0f'(x)=0 when the derivative exists.

  43. Ikhadi 43

    Umbuzo

    Derivative of a constant?

    Impendulo

    ddxC=0\frac{d}{dx}C=0

    A constant function has zero rate of change.

  44. Ikhadi 44

    Umbuzo

    Derivative of sinx\sin x?

    Impendulo

    ddx(sinx)=cosx\frac{d}{dx}(\sin x)=\cos x

    The angle must be measured in radians for the standard formula.

  45. Ikhadi 45

    Umbuzo

    Product rule?

    Impendulo

    ddx[f(x)g(x)]=f(x)g(x)+f(x)g(x)\frac{d}{dx}[f(x)g(x)]=f'(x)g(x)+f(x)g'(x)

    Differentiating each factor and multiplying the results is not the product rule.

  46. Ikhadi 46

    Umbuzo

    How can nearby table values estimate f(a)f'(a)?

    Impendulo

    Use a difference quotient with inputs close to aa. A symmetric estimate is

    f(a)f(a+h)f(ah)2h.f'(a)\approx\frac{f(a+h)-f(a-h)}{2h}.

    Smaller hh often helps, subject to the data's precision.

  47. Ikhadi 47

    Umbuzo

    What does f(x)f''(x) measure?

    Impendulo

    The rate of change of f(x)f'(x) with respect to xx. Its units are the units of ff per square input unit.

  48. Ikhadi 48

    Umbuzo

    Instantaneous rate of change of ff at aa?

    Impendulo

    f(a)f'(a). It is the limit of average rates over intervals shrinking to aa, and geometrically it is the tangent-line slope.

  49. Ikhadi 49

    Umbuzo

    Derivative of a sum or difference?

    Impendulo

    ddx[f(x)±g(x)]=f(x)±g(x)\frac{d}{dx}[f(x)\pm g(x)]=f'(x)\pm g'(x)
  50. Ikhadi 50

    Umbuzo

    Derivative of cosx\cos x?

    Impendulo

    ddx(cosx)=sinx\frac{d}{dx}(\cos x)=-\sin x

    The standard formula assumes radians.

  51. Ikhadi 51

    Umbuzo

    Quotient rule?

    Impendulo

    For g(x)0g(x)\ne0,

    ddx[f(x)g(x)]=f(x)g(x)f(x)g(x)[g(x)]2.\frac{d}{dx}\left[\frac{f(x)}{g(x)}\right]=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}.

    The order in the numerator matters.

  52. Ikhadi 52

    Umbuzo

    Common notations for the first derivative?

    Impendulo

    f(x)f'(x), yy', dydx\dfrac{dy}{dx}, and ddxf(x)\dfrac{d}{dx}f(x). They describe the same derivative in different contexts.

  53. Ikhadi 53

    Umbuzo

    Derivative of exe^x?

    Impendulo

    ddxex=ex\frac{d}{dx}e^x=e^x
  54. Ikhadi 54

    Umbuzo

    What graph features can make ff nondifferentiable?

    Impendulo

    A discontinuity, corner, cusp, vertical tangent, or other failure of the difference-quotient limit. Continuity is necessary but not sufficient.

  55. Ikhadi 55

    Umbuzo

    Derivative of tanx\tan x?

    Impendulo

    Where tanx\tan x is defined,

    ddx(tanx)=sec2x.\frac{d}{dx}(\tan x)=\sec^2x.

    Angles are in radians.

  56. Ikhadi 56

    Umbuzo

    What does the derivative function ff' assign to each input?

    Impendulo

    The instantaneous rate of change—or tangent slope—of ff at that input, wherever the derivative exists.

  57. Ikhadi 57

    Umbuzo

    Derivative of lnx\ln x?

    Impendulo

    For x>0x>0,

    ddxlnx=1x.\frac{d}{dx}\ln x=\frac1x.

    More generally, d(lnx)/dx=1/xd(\ln|x|)/dx=1/x for x0x\ne0.

  58. Ikhadi 58

    Umbuzo

    How does the power rule handle roots or negative powers?

    Impendulo

    Rewrite them as xnx^n and apply nxn1nx^{n-1} on intervals where the real-valued expression is defined. Domain restrictions still matter.

  59. Ikhadi 59

    Umbuzo

    Derivative of cscx\csc x?

    Impendulo

    Where cscx\csc x is defined,

    ddx(cscx)=cscxcotx.\frac{d}{dx}(\csc x)=-\csc x\cot x.

    Angles are in radians.

  60. Ikhadi 60

    Umbuzo

    If f(x)>0f'(x)>0 throughout an interval, what does ff do there?

    Impendulo

    ff is increasing on that interval.

  61. Ikhadi 61

    Umbuzo

    Derivative of axa^x for a constant base?

    Impendulo

    For a>0a>0,

    ddxax=axlna.\frac{d}{dx}a^x=a^x\ln a.

    When a=1a=1, the derivative is 00.

  62. Ikhadi 62

    Umbuzo

    How can a graph estimate f(a)f'(a)?

    Impendulo

    Estimate the slope of the tangent line at x=ax=a, using two convenient points on a drawn tangent when available. A steeper tangent has a derivative with larger magnitude.

  63. Ikhadi 63

    Umbuzo

    Derivative of secx\sec x?

    Impendulo

    Where secx\sec x is defined,

    ddx(secx)=secxtanx.\frac{d}{dx}(\sec x)=\sec x\tan x.

    Angles are in radians.

  64. Ikhadi 64

    Umbuzo

    If f(x)>0f''(x)>0, how is ff' changing?

    Impendulo

    ff' is increasing. This is also the derivative condition associated with ff being concave up.

  65. Ikhadi 65

    Umbuzo

    Derivative of logax\log_a x?

    Impendulo

    For x>0x>0, a>0a>0, and a1a\ne1,

    ddxlogax=1xlna.\frac{d}{dx}\log_a x=\frac{1}{x\ln a}.
  66. Ikhadi 66

    Umbuzo

    Product rule from a table at x=ax=a?

    Impendulo

    For h=fgh=fg,

    h(a)=f(a)g(a)+f(a)g(a).h'(a)=f'(a)g(a)+f(a)g'(a).

    Use the four table entries at the same input.

  67. Ikhadi 67

    Umbuzo

    Derivative of cotx\cot x?

    Impendulo

    Where cotx\cot x is defined,

    ddx(cotx)=csc2x.\frac{d}{dx}(\cot x)=-\csc^2x.

    Angles are in radians.

  68. Ikhadi 68

    Umbuzo

    Why isn't x|x| differentiable at x=0x=0?

    Impendulo

    Its left-hand slope is 1-1 and right-hand slope is 11. The one-sided derivative limits disagree, creating a corner.

  69. Ikhadi 69

    Umbuzo

    Constant-multiple rule?

    Impendulo

    For a constant cc,

    ddx[cf(x)]=cf(x).\frac{d}{dx}[c f(x)]=c f'(x).
  70. Ikhadi 70

    Umbuzo

    Quotient rule from a table at x=ax=a?

    Impendulo

    For h=f/gh=f/g with g(a)0g(a)\ne0,

    h(a)=f(a)g(a)f(a)g(a)[g(a)]2.h'(a)=\frac{f'(a)g(a)-f(a)g'(a)}{[g(a)]^2}.
  71. Ikhadi 71

    Umbuzo

    Chain rule for f(g(x))f(g(x))?

    Impendulo

    ddxf(g(x))=f(g(x))g(x)\frac{d}{dx}f(g(x))=f'(g(x))g'(x)

    Differentiate the outer function at the unchanged inner input, then multiply by the inner derivative.

  72. Ikhadi 72

    Umbuzo

    How do you identify inner and outer functions in a composite?

    Impendulo

    Find the expression evaluated first—that is the inner function. The operation applied to its result is the outer function.

  73. Ikhadi 73

    Umbuzo

    Core rule when differentiating an implicit equation in xx and yy?

    Impendulo

    Treat yy as a differentiable function of xx. Every derivative of an expression involving yy gains a factor of dy/dxdy/dx by the chain rule.

  74. Ikhadi 74

    Umbuzo

    Derivative of an inverse function at xx?

    Impendulo

    If ff is differentiable and one-to-one near f1(x)f^{-1}(x), with f(f1(x))0f'(f^{-1}(x))\ne0,

    [f1](x)=1f(f1(x)).[f^{-1}]'(x)=\frac{1}{f'(f^{-1}(x))}.
  75. Ikhadi 75

    Umbuzo

    Derivative of arcsinx\arcsin x?

    Impendulo

    For x<1|x|<1,

    ddx(arcsinx)=11x2.\frac{d}{dx}(\arcsin x)=\frac{1}{\sqrt{1-x^2}}.
  76. Ikhadi 76

    Umbuzo

    Notation for the third derivative of ff?

    Impendulo

    f(x)f'''(x) or d3fdx3\dfrac{d^3f}{dx^3}. The exponent on dd indicates derivative order; it is not an ordinary power.

  77. Ikhadi 77

    Umbuzo

    If h(x)=f(g(x))h(x)=f(g(x)), what table entries give h(a)h'(a)?

    Impendulo

    h(a)=f(g(a))g(a)h'(a)=f'(g(a))g'(a)

    Use g(a)g(a) to find the input needed for the table entry of ff'.

  78. Ikhadi 78

    Umbuzo

    For x2+y2=r2x^2+y^2=r^2, what is dy/dxdy/dx?

    Impendulo

    Where y0y\ne0,

    dydx=xy.\frac{dy}{dx}=-\frac{x}{y}.

    Differentiate to get 2x+2y(dy/dx)=02x+2y(dy/dx)=0.

  79. Ikhadi 79

    Umbuzo

    If f(a)=bf(a)=b, how do you find [f1](b)[f^{-1}]'(b)?

    Impendulo

    Provided f(a)0f'(a)\ne0,

    [f1](b)=1f(a).[f^{-1}]'(b)=\frac{1}{f'(a)}.

    The inverse swaps the input-output pair (a,b)(a,b).

  80. Ikhadi 80

    Umbuzo

    Derivative of arctanx\arctan x?

    Impendulo

    For every real xx,

    ddx(arctanx)=11+x2.\frac{d}{dx}(\arctan x)=\frac{1}{1+x^2}.
  81. Ikhadi 81

    Umbuzo

    Derivative of eg(x)e^{g(x)}?

    Impendulo

    ddxeg(x)=eg(x)g(x)\frac{d}{dx}e^{g(x)}=e^{g(x)}g'(x)

    The extra factor is the chain rule.

  82. Ikhadi 82

    Umbuzo

    Slope of a tangent to an implicit curve F(x,y)=0F(x,y)=0?

    Impendulo

    Differentiate the relation with respect to xx, solve for dy/dxdy/dx, then substitute the point. Confirm the point lies on the curve and the resulting slope is defined.

  83. Ikhadi 83

    Umbuzo

    Why must f(a)0f'(a)\ne0 to use [f1](f(a))=1/f(a)[f^{-1}]'(f(a))=1/f'(a)?

    Impendulo

    Because the reciprocal slope would be undefined when f(a)=0f'(a)=0. The inverse may have a vertical tangent or fail to be differentiable there.

  84. Ikhadi 84

    Umbuzo

    Derivative of arccosx\arccos x?

    Impendulo

    For x<1|x|<1,

    ddx(arccosx)=11x2.\frac{d}{dx}(\arccos x)=-\frac{1}{\sqrt{1-x^2}}.
  85. Ikhadi 85

    Umbuzo

    How do you find d2y/dx2d^2y/dx^2 for an implicit relation?

    Impendulo

    Differentiate the first-derivative equation again with respect to xx, include dy/dxdy/dx factors, then substitute the known expression for dy/dxdy/dx if needed.

  86. Ikhadi 86

    Umbuzo

    Derivative of ln(g(x))\ln(g(x))?

    Impendulo

    Where g(x)>0g(x)>0,

    ddxln(g(x))=g(x)g(x).\frac{d}{dx}\ln(g(x))=\frac{g'(x)}{g(x)}.

    For lng(x)\ln|g(x)|, the same derivative holds where g(x)0g(x)\ne0.

  87. Ikhadi 87

    Umbuzo

    Derivative of yny^n when y=y(x)y=y(x)?

    Impendulo

    ddx(yn)=nyn1dydx\frac{d}{dx}(y^n)=ny^{n-1}\frac{dy}{dx}

    The dy/dxdy/dx factor comes from the chain rule.

  88. Ikhadi 88

    Umbuzo

    How are tangent slopes of inverse graphs related?

    Impendulo

    At reflected points (a,b)(a,b) and (b,a)(b,a), the slopes are reciprocals when both are defined and nonzero.

  89. Ikhadi 89

    Umbuzo

    Derivative of arcsin(g(x))\arcsin(g(x))?

    Impendulo

    ddxarcsin(g(x))=g(x)1[g(x)]2,g(x)<1.\frac{d}{dx}\arcsin(g(x))=\frac{g'(x)}{\sqrt{1-[g(x)]^2}},\qquad |g(x)|<1.
  90. Ikhadi 90

    Umbuzo

    Derivative of sin(g(x))\sin(g(x))?

    Impendulo

    ddxsin(g(x))=cos(g(x))g(x)\frac{d}{dx}\sin(g(x))=\cos(g(x))g'(x)
  91. Ikhadi 91

    Umbuzo

    Horizontal tangent on an implicit curve: derivative condition?

    Impendulo

    dy/dx=0dy/dx=0 at a valid point, with the derivative defined there. In a fraction for dy/dxdy/dx, the numerator is typically zero while the denominator is nonzero.

  92. Ikhadi 92

    Umbuzo

    How do you differentiate f1(x)f^{-1}(x) without solving for the inverse?

    Impendulo

    Use the reciprocal derivative formula and the matching original input: find aa with f(a)=xf(a)=x, then compute 1/f(a)1/f'(a).

  93. Ikhadi 93

    Umbuzo

    Difference between f(x)f''(x) and [f(x)]2[f'(x)]^2?

    Impendulo

    f(x)f''(x) is the derivative of f(x)f'(x). The expression [f(x)]2[f'(x)]^2 is the square of the first derivative; they are generally unrelated.

  94. Ikhadi 94

    Umbuzo

    Derivative of [g(x)]n[g(x)]^n?

    Impendulo

    ddx[g(x)]n=n[g(x)]n1g(x)\frac{d}{dx}[g(x)]^n=n[g(x)]^{n-1}g'(x)

    This combines the power rule with the chain rule.

  95. Ikhadi 95

    Umbuzo

    Vertical tangent on an implicit curve: derivative clue?

    Impendulo

    dy/dxdy/dx becomes unbounded or undefined while the curve still has a vertical tangent. In a simplified derivative fraction, the denominator is often zero and the numerator nonzero.

  96. Ikhadi 96

    Umbuzo

    Table formula for an inverse derivative at x=bx=b?

    Impendulo

    Find aa in the table with f(a)=bf(a)=b. If f(a)0f'(a)\ne0, then

    [f1](b)=1f(a).[f^{-1}]'(b)=\frac{1}{f'(a)}.
  97. Ikhadi 97

    Umbuzo

    Derivative of arctan(g(x))\arctan(g(x))?

    Impendulo

    ddxarctan(g(x))=g(x)1+[g(x)]2\frac{d}{dx}\arctan(g(x))=\frac{g'(x)}{1+[g(x)]^2}
  98. Ikhadi 98

    Umbuzo

    How do product and chain rules combine in f(x)g(h(x))f(x)g(h(x))?

    Impendulo

    ddx[f(x)g(h(x))]=f(x)g(h(x))+f(x)g(h(x))h(x).\frac{d}{dx}[f(x)g(h(x))]=f'(x)g(h(x))+f(x)g'(h(x))h'(x).

    Use the product rule outside and the chain rule on the composite factor.

  99. Ikhadi 99

    Umbuzo

    Why can d2y/dx2d^2y/dx^2 depend on both xx and yy?

    Impendulo

    An implicit relation may never solve explicitly for yy. After differentiating twice and replacing dy/dxdy/dx, the result can naturally remain a function of both coordinates.

  100. Ikhadi 100

    Umbuzo

    A quantity yy changes through uu, which changes with xx. How are the rates connected?

    Impendulo

    When the functions are differentiable, the chain rule gives

    dydx=dydududx.\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}.
  101. Ikhadi 101

    Umbuzo

    What local property lets a function have an inverse derivative?

    Impendulo

    The function must be one-to-one near the point, differentiable there, and have a nonzero derivative. Then the inverse is locally differentiable with reciprocal slope.

  102. Ikhadi 102

    Umbuzo

    Derivative of ag(x)a^{g(x)}?

    Impendulo

    For a>0a>0,

    ddxag(x)=ag(x)ln(a)g(x).\frac{d}{dx}a^{g(x)}=a^{g(x)}\ln(a)\,g'(x).
  103. Ikhadi 103

    Umbuzo

    How should Q(t)Q'(t) be interpreted in context?

    Impendulo

    At time tt, the quantity QQ changes at an instantaneous rate of Q(t)Q'(t) output units per unit of time. Include the quantity, time, direction or sign, and units.

  104. Ikhadi 104

    Umbuzo

    Position, velocity, and acceleration relationships?

    Impendulo

    For position s(t)s(t),

    v(t)=s(t),a(t)=v(t)=s(t).v(t)=s'(t),\qquad a(t)=v'(t)=s''(t).
  105. Ikhadi 105

    Umbuzo

    Central idea of a related-rates problem?

    Impendulo

    Write an equation connecting the changing quantities, differentiate it with respect to time, then use the data for the specified instant.

  106. Ikhadi 106

    Umbuzo

    Linearization of ff near x=ax=a?

    Impendulo

    L(x)=f(a)+f(a)(xa)L(x)=f(a)+f'(a)(x-a)

    For xx close to aa, f(x)L(x)f(x)\approx L(x).

  107. Ikhadi 107

    Umbuzo

    L’Hospital’s Rule: basic conditions?

    Impendulo

    For a quotient with differentiable numerator and denominator near the target, denominator derivative nonzero nearby, and indeterminate form 0/00/0 or /\infty/\infty, the original limit equals the limit of the derivative quotient when that latter limit exists or is infinite.

  108. Ikhadi 108

    Umbuzo

    If distance is in meters and time in seconds, units of acceleration?

    Impendulo

    Meters per second squared, m/s2\text{m}/\text{s}^2. Acceleration is the rate of change of velocity with respect to time.

  109. Ikhadi 109

    Umbuzo

    Speed in terms of velocity?

    Impendulo

    speed=v(t)\text{speed}=|v(t)|

    Velocity includes direction; speed is nonnegative magnitude.

  110. Ikhadi 110

    Umbuzo

    Why do xx and yy gain dx/dtdx/dt and dy/dtdy/dt in related rates?

    Impendulo

    They are functions of time. Differentiating an expression such as x2x^2 with respect to tt gives 2x(dx/dt)2x(dx/dt) by the chain rule.

  111. Ikhadi 111

    Umbuzo

    Differential approximation connecting dxdx and dydy?

    Impendulo

    dy=f(x)dxdy=f'(x)\,dx

    For a small change Δx\Delta x, the actual change satisfies Δyf(x)Δx\Delta y\approx f'(x)\Delta x.

  112. Ikhadi 112

    Umbuzo

    Which indeterminate forms directly allow L’Hospital’s Rule?

    Impendulo

    0/00/0 and /\infty/\infty. Other indeterminate forms must first be rewritten as an appropriate quotient.

  113. Ikhadi 113

    Umbuzo

    How do you estimate an instantaneous contextual rate from a table?

    Impendulo

    Use a nearby difference quotient, preferably with times on both sides of the target. Report the result with output units per time unit.

  114. Ikhadi 114

    Umbuzo

    What does positive acceleration say about velocity?

    Impendulo

    Velocity is increasing. It does not by itself say the object moves forward or speeds up; the sign of velocity also matters.

  115. Ikhadi 115

    Umbuzo

    Related rates: when should numerical values be substituted?

    Impendulo

    After differentiating the general relationship with respect to time. Substituting fixed values too early can erase the rates being sought.

  116. Ikhadi 116

    Umbuzo

    How does concavity predict linearization error?

    Impendulo

    Near the tangency point, a concave-up graph generally lies above its tangent line, so the linearization underestimates. A concave-down graph generally lies below, so it overestimates.

  117. Ikhadi 117

    Umbuzo

    Why can't L’Hospital’s Rule be applied directly to a product?

    Impendulo

    The rule applies to quotients with 0/00/0 or /\infty/\infty form. Rewrite an indeterminate product such as 00\cdot\infty as a quotient first.

  118. Ikhadi 118

    Umbuzo

    When is a particle moving in the positive direction?

    Impendulo

    When v(t)>0v(t)>0. Position then increases as time increases.

  119. Ikhadi 119

    Umbuzo

    How can velocity show a change of direction?

    Impendulo

    Velocity changes sign. A time with v(t)=0v(t)=0 is only a candidate; confirm the sign differs on the two sides.

  120. Ikhadi 120

    Umbuzo

    First equation to seek in a geometric related-rates problem?

    Impendulo

    A geometric constraint involving the changing quantities, such as a Pythagorean, area, volume, or similar-triangle relation.

  121. Ikhadi 121

    Umbuzo

    Tangent-line approximation of f(a+Δx)f(a+\Delta x)?

    Impendulo

    f(a+Δx)f(a)+f(a)Δxf(a+\Delta x)\approx f(a)+f'(a)\Delta x

    It is most reliable for small Δx|\Delta x| where the function is well approximated by its tangent.

  122. Ikhadi 122

    Umbuzo

    When may L’Hospital’s Rule be applied more than once?

    Impendulo

    When the derivative quotient still has 0/00/0 or /\infty/\infty form and the rule's conditions continue to hold.

  123. Ikhadi 123

    Umbuzo

    What must a contextual derivative sentence include?

    Impendulo

    The changing quantity, the instant or input, the rate's sign or direction when relevant, and correct output-per-input units.

  124. Ikhadi 124

    Umbuzo

    Velocity negative and acceleration positive: what happens?

    Impendulo

    The particle moves in the negative direction while its velocity increases toward zero. Its speed decreases as long as velocity and acceleration have opposite signs.

  125. Ikhadi 125

    Umbuzo

    How should a negative related rate be interpreted?

    Impendulo

    The measured quantity is decreasing at that instant. Keep the sign and state the units; don't silently report only its magnitude.

  126. Ikhadi 126

    Umbuzo

    When is local linearity a sound approximation tool?

    Impendulo

    When ff is differentiable near the base point and the target input is close enough that curvature has limited effect.

  127. Ikhadi 127

    Umbuzo

    Can L’Hospital’s Rule handle a one-sided limit?

    Impendulo

    Yes, if the required indeterminate form and differentiability conditions hold on that side and the derivative-quotient limit exists or is infinite.

  128. Ikhadi 128

    Umbuzo

    When is speed increasing?

    Impendulo

    When velocity and acceleration have the same sign, so v(t)a(t)>0v(t)a(t)>0.

  129. Ikhadi 129

    Umbuzo

    Volume changes with time: notation for its rate?

    Impendulo

    dV/dtdV/dt. Its units are cubic length units per time unit.

  130. Ikhadi 130

    Umbuzo

    Why are similar triangles useful in related rates?

    Impendulo

    They can reduce several changing lengths to one constraint before differentiation, keeping the rate equation tied to the geometry.

  131. Ikhadi 131

    Umbuzo

    Meaning of dy=f(x)dxdy=f'(x)dx in approximation?

    Impendulo

    dydy is the tangent-line estimate of the actual output change Δy\Delta y caused by an input change dxdx.

  132. Ikhadi 132

    Umbuzo

    What conclusion does L’Hospital’s Rule permit?

    Impendulo

    Under its conditions,

    limf(x)g(x)=limf(x)g(x).\lim\frac{f(x)}{g(x)}=\lim\frac{f'(x)}{g'(x)}.

    It does not say the two quotients are equal as functions.

  133. Ikhadi 133

    Umbuzo

    When is speed decreasing?

    Impendulo

    When velocity and acceleration have opposite signs, so v(t)a(t)<0v(t)a(t)<0.

  134. Ikhadi 134

    Umbuzo

    What does a tangent slope read from a contextual graph represent?

    Impendulo

    The instantaneous rate of the vertical quantity with respect to the horizontal quantity, with vertical units per horizontal unit.

  135. Ikhadi 135

    Umbuzo

    Does v(t)=0v(t)=0 guarantee a particle changes direction?

    Impendulo

    No. It is momentarily at rest, but direction changes only if velocity changes sign across that time.

  136. Ikhadi 136

    Umbuzo

    How do you translate “QQ increases by 3 units per minute” into derivative notation?

    Impendulo

    dQ/dt=3dQ/dt=3 in the stated time interval or at the stated instant. “Decreases by 3” would give dQ/dt=3dQ/dt=-3.

  137. Ikhadi 137

    Umbuzo

    Extreme Value Theorem: hypothesis and conclusion?

    Impendulo

    If ff is continuous on the closed interval [a,b][a,b], then ff has at least one absolute minimum value and at least one absolute maximum value on [a,b][a,b].

  138. Ikhadi 138

    Umbuzo

    What is a critical number of ff?

    Impendulo

    A number cc in the domain of ff where f(c)=0f'(c)=0 or f(c)f'(c) doesn't exist.

  139. Ikhadi 139

    Umbuzo

    First derivative test for a local maximum?

    Impendulo

    ff' changes from positive to negative at the critical point, so ff changes from increasing to decreasing.

  140. Ikhadi 140

    Umbuzo

    Second-derivative sign for concave up?

    Impendulo

    If f(x)>0f''(x)>0 on an interval, then ff is concave up there and ff' is increasing.

  141. Ikhadi 141

    Umbuzo

    If the graph of ff' is above the xx-axis, what does ff do?

    Impendulo

    ff is increasing because f(x)>0f'(x)>0.

  142. Ikhadi 142

    Umbuzo

    First step in an optimization model?

    Impendulo

    Define the objective quantity and the constraint, including the feasible domain. Rewrite the objective as a function of one variable before differentiating.

  143. Ikhadi 143

    Umbuzo

    Mean Value Theorem: hypotheses and conclusion?

    Impendulo

    If ff is continuous on [a,b][a,b] and differentiable on (a,b)(a,b), then some cc in (a,b)(a,b) satisfies

    f(c)=f(b)f(a)ba.f'(c)=\frac{f(b)-f(a)}{b-a}.
  144. Ikhadi 144

    Umbuzo

    Candidates test for absolute extrema on [a,b][a,b]?

    Impendulo

    Assuming ff is continuous on [a,b][a,b], evaluate ff at every critical number in (a,b)(a,b) and at both endpoints. The largest value is the absolute maximum; the smallest is the absolute minimum.

    Abstract calculus graph with a glowing orange curve, tangent line, shaded area under the curve, and layered contour lines on a dark grid.

    amakhadi angu-288

    AP Calculus AB Flashcards: 8-Unit Formulas, Theorems & Concepts

    Funda leli qoqo mahhala

    I-Nibomo iyavuleka ukuze uqale ukufunda.

  145. Ikhadi 145

    Umbuzo

    First derivative test for a local minimum?

    Impendulo

    ff' changes from negative to positive at the critical point, so ff changes from decreasing to increasing.

  146. Ikhadi 146

    Umbuzo

    What must happen at an inflection point?

    Impendulo

    The graph's concavity changes. A zero or undefined value of ff'' is only a candidate; verify a concavity change.

  147. Ikhadi 147

    Umbuzo

    If ff' has a local maximum, what can that say about ff?

    Impendulo

    ff'' may change from positive to negative there, so ff may change from concave up to concave down. Confirm the sign change rather than relying only on the point.

  148. Ikhadi 148

    Umbuzo

    How do you confirm an optimization answer is absolute?

    Impendulo

    Compare objective values at all feasible critical points and relevant endpoints, or use a justified monotonicity argument over the feasible domain.

  149. Ikhadi 149

    Umbuzo

    Rolle’s Theorem: hypotheses and conclusion?

    Impendulo

    If ff is continuous on [a,b][a,b], differentiable on (a,b)(a,b), and f(a)=f(b)f(a)=f(b), then some cc in (a,b)(a,b) satisfies f(c)=0f'(c)=0.

  150. Ikhadi 150

    Umbuzo

    Difference between absolute and relative extrema?

    Impendulo

    An absolute maximum is at least every other value on the stated domain, and an absolute minimum is at most every other value. A relative extremum makes the corresponding comparison only with nearby values.

  151. Ikhadi 151

    Umbuzo

    If ff is continuous at a critical number cc and ff' is positive on both sides, is there a local extremum?

    Impendulo

    No. The function is increasing through cc, so it has no local extremum there.

  152. Ikhadi 152

    Umbuzo

    Second derivative test for a local minimum?

    Impendulo

    If f(c)=0f'(c)=0 and f(c)>0f''(c)>0, then ff has a local minimum at cc.

  153. Ikhadi 153

    Umbuzo

    Zeros of ff' correspond to what features of ff?

    Impendulo

    Horizontal tangents where ff' exists. They are critical numbers and possible extrema, but each needs further sign or value analysis.

  154. Ikhadi 154

    Umbuzo

    Implicit relation: how can dy/dxdy/dx reveal local behavior?

    Impendulo

    Its sign shows whether the relation's local branch rises or falls as xx increases; zeros and undefined values mark possible horizontal or vertical tangents.

  155. Ikhadi 155

    Umbuzo

    Which theorem links an average slope to an instantaneous slope?

    Impendulo

    The Mean Value Theorem, provided the function is continuous on the closed interval and differentiable on its interior.

  156. Ikhadi 156

    Umbuzo

    How can an implicit derivative locate a horizontal tangent?

    Impendulo

    At a valid point on the relation, find where the simplified numerator of dy/dxdy/dx is zero while its denominator is nonzero, then confirm the local branch has the expected behavior.

  157. Ikhadi 157

    Umbuzo

    Derivative-sign chart: where is ff decreasing?

    Impendulo

    On intervals where f(x)<0f'(x)<0.

  158. Ikhadi 158

    Umbuzo

    Second derivative test for a local maximum?

    Impendulo

    If f(c)=0f'(c)=0 and f(c)<0f''(c)<0, then ff has a local maximum at cc.

  159. Ikhadi 159

    Umbuzo

    If ff' is increasing, what is the concavity of ff?

    Impendulo

    ff is concave up on that interval, assuming the relevant derivatives exist.

  160. Ikhadi 160

    Umbuzo

    Why must an optimization domain be stated?

    Impendulo

    The context can exclude algebraic candidates and add boundary cases. Absolute extrema depend on the feasible inputs, not just on where the derivative is zero.

  161. Ikhadi 161

    Umbuzo

    Which theorem guarantees absolute extrema, not where they occur?

    Impendulo

    The Extreme Value Theorem. Continuity on a closed interval guarantees at least one maximum value and one minimum value, but finding them requires analysis.

  162. Ikhadi 162

    Umbuzo

    Can f(c)f'(c) fail to exist at a local extremum?

    Impendulo

    Yes. Corners, cusps, or other nondifferentiable domain points can be local extrema, which is why critical numbers include points where ff' is undefined.

  163. Ikhadi 163

    Umbuzo

    For a function continuous at cc, what same-sign pattern in ff' rules out a local extremum there?

    Impendulo

    If ff' is positive on both sides of cc, or negative on both sides, then ff keeps the same monotonic direction through cc and has no local extremum there.

  164. Ikhadi 164

    Umbuzo

    If f(c)=0f'(c)=0 and f(c)=0f''(c)=0, what does the second derivative test conclude?

    Impendulo

    Nothing. The test is inconclusive; use a first-derivative sign change, higher analysis, or direct comparison.

  165. Ikhadi 165

    Umbuzo

    If the graph of ff' crosses from negative to positive, what feature does ff have?

    Impendulo

    A local minimum at the crossing input, provided the input is in the domain of ff.

  166. Ikhadi 166

    Umbuzo

    How can an implicit derivative locate a vertical tangent?

    Impendulo

    Find valid points where the simplified dy/dxdy/dx denominator is zero and numerator is nonzero, then confirm the curve has the expected local behavior.

  167. Ikhadi 167

    Umbuzo

    Which extra condition turns the Mean Value Theorem into Rolle’s Theorem?

    Impendulo

    f(a)=f(b)f(a)=f(b). The average slope becomes zero, so the guaranteed instantaneous slope is also zero.

  168. Ikhadi 168

    Umbuzo

    Why are endpoints included in the candidates test?

    Impendulo

    An absolute maximum or minimum on a closed interval can occur at an endpoint even though no two-sided derivative test applies there.

  169. Ikhadi 169

    Umbuzo

    If f(x)=0f'(x)=0 throughout an interval, what is ff there?

    Impendulo

    ff is constant on that interval, assuming the usual continuity and differentiability conditions that let the Mean Value Theorem apply.

  170. Ikhadi 170

    Umbuzo

    Second-derivative sign for concave down?

    Impendulo

    If f(x)<0f''(x)<0 on an interval, then ff is concave down there and ff' is decreasing.

  171. Ikhadi 171

    Umbuzo

    Graph of ff' has a local minimum: possible effect on ff?

    Impendulo

    ff'' may change from negative to positive, so ff may change from concave down to concave up. Verify the sign change.

  172. Ikhadi 172

    Umbuzo

    What should the final line of an optimization solution state?

    Impendulo

    The requested maximum or minimum quantity in context, with units and the feasible input that produces it when relevant.

  173. Ikhadi 173

    Umbuzo

    Can Rolle’s Theorem be used if ff has a corner inside (a,b)(a,b)?

    Impendulo

    No. A corner breaks differentiability on the open interval, so the theorem's hypotheses are not satisfied.

  174. Ikhadi 174

    Umbuzo

    How do ff'' zeros help analyze a graph?

    Impendulo

    They are candidates for changes in concavity. Test the sign of ff'' on both sides; a zero alone doesn't guarantee an inflection point.

  175. Ikhadi 175

    Umbuzo

    What does the accumulation function F(x)=axf(t)dtF(x)=\int_a^x f(t)\,dt measure?

    Impendulo

    The signed net accumulation of ff from aa to xx. Contributions above the axis are positive; contributions below it are negative.

  176. Ikhadi 176

    Umbuzo

    Left Riemann sum on equal subintervals?

    Impendulo

    If Δx=(ba)/n\Delta x=(b-a)/n and xi=a+iΔxx_i=a+i\Delta x, then

    Ln=i=1nf(xi1)Δx.L_n=\sum_{i=1}^{n} f(x_{i-1})\Delta x.
  177. Ikhadi 177

    Umbuzo

    What does abf(x)dx\int_a^b f(x)\,dx represent geometrically?

    Impendulo

    Signed area between the graph and the xx-axis from aa to bb, when ff is integrable. Regions below the axis subtract from regions above it.

  178. Ikhadi 178

    Umbuzo

    Fundamental Theorem of Calculus: evaluate a definite integral?

    Impendulo

    If ff is continuous on [a,b][a,b] and FF is an antiderivative of ff, then

    abf(x)dx=F(b)F(a).\int_a^b f(x)\,dx=F(b)-F(a).
  179. Ikhadi 179

    Umbuzo

    Derivative of F(x)=axf(t)dtF(x)=\int_a^x f(t)\,dt?

    Impendulo

    If ff is continuous, then

    F(x)=f(x).F'(x)=f(x).

    This connects accumulation with instantaneous rate.

  180. Ikhadi 180

    Umbuzo

    Why do all antiderivatives of the same function differ by a constant?

    Impendulo

    If F=fF'=f and G=fG'=f on an interval, then (FG)=0(F-G)'=0, so FG=CF-G=C on that interval.

  181. Ikhadi 181

    Umbuzo

    Right Riemann sum on equal subintervals?

    Impendulo

    If Δx=(ba)/n\Delta x=(b-a)/n and xi=a+iΔxx_i=a+i\Delta x, then

    Rn=i=1nf(xi)Δx.R_n=\sum_{i=1}^{n} f(x_i)\Delta x.
  182. Ikhadi 182

    Umbuzo

    How does reversing integral bounds change the value?

    Impendulo

    It changes the sign:

    baf(x)dx=abf(x)dx.\int_b^a f(x)\,dx=-\int_a^b f(x)\,dx.
  183. Ikhadi 183

    Umbuzo

    Net Change Theorem?

    Impendulo

    If Q(t)Q'(t) is the rate of change of a quantity, then

    Q(b)Q(a)=abQ(t)dt.Q(b)-Q(a)=\int_a^b Q'(t)\,dt.
  184. Ikhadi 184

    Umbuzo

    Derivative of ag(x)f(t)dt\int_a^{g(x)} f(t)\,dt?

    Impendulo

    If ff is continuous on an interval containing aa and the range of gg, and gg is differentiable, then

    ddxag(x)f(t)dt=f(g(x))g(x).\frac{d}{dx}\int_a^{g(x)} f(t)\,dt=f(g(x))g'(x).
  185. Ikhadi 185

    Umbuzo

    Power rule for antiderivatives?

    Impendulo

    For n1n\ne-1,

    xndx=xn+1n+1+C.\int x^n\,dx=\frac{x^{n+1}}{n+1}+C.
  186. Ikhadi 186

    Umbuzo

    Midpoint Riemann sum on equal subintervals?

    Impendulo

    With midpoint mi=(xi1+xi)/2m_i=(x_{i-1}+x_i)/2,

    Mn=i=1nf(mi)Δx.M_n=\sum_{i=1}^{n} f(m_i)\Delta x.
  187. Ikhadi 187

    Umbuzo

    How can an integral be split at an interior point cc?

    Impendulo

    For acba\le c\le b,

    abf(x)dx=acf(x)dx+cbf(x)dx.\int_a^b f(x)\,dx=\int_a^c f(x)\,dx+\int_c^b f(x)\,dx.
  188. Ikhadi 188

    Umbuzo

    Derivative of G(x)=xbf(t)dtG(x)=\int_x^b f(t)\,dt?

    Impendulo

    If ff is continuous, then

    G(x)=f(x).G'(x)=-f(x).

    The variable lower bound produces the negative sign.

  189. Ikhadi 189

    Umbuzo

    Antiderivative of 1/x1/x?

    Impendulo

    On any interval not crossing zero,

    1xdx=lnx+C.\int \frac1x\,dx=\ln|x|+C.
  190. Ikhadi 190

    Umbuzo

    Trapezoidal approximation on equal subintervals?

    Impendulo

    Tn=Δx2[f(x0)+2f(x1)++2f(xn1)+f(xn)].T_n=\frac{\Delta x}{2}\left[f(x_0)+2f(x_1)+\cdots+2f(x_{n-1})+f(x_n)\right].
  191. Ikhadi 191

    Umbuzo

    How do geometric regions help evaluate a definite integral?

    Impendulo

    Replace each familiar region with its geometric area, then attach a positive sign above the axis and a negative sign below it.

  192. Ikhadi 192

    Umbuzo

    Basic antiderivatives of sine and cosine?

    Impendulo

    sinxdx=cosx+C,cosxdx=sinx+C.\int \sin x\,dx=-\cos x+C,\qquad \int \cos x\,dx=\sin x+C.
  193. Ikhadi 193

    Umbuzo

    Definite integral as a limit of Riemann sums?

    Impendulo

    For an integrable function and sample points xix_i^*,

    abf(x)dx=limmaxΔxi0if(xi)Δxi.\int_a^b f(x)\,dx=\lim_{\max\Delta x_i\to0}\sum_i f(x_i^*)\Delta x_i.
  194. Ikhadi 194

    Umbuzo

    Constant-multiple rule for integrals?

    Impendulo

    For a constant kk,

    abkf(x)dx=kabf(x)dx.\int_a^b kf(x)\,dx=k\int_a^b f(x)\,dx.

    The analogous rule holds for indefinite integrals.

  195. Ikhadi 195

    Umbuzo

    What pattern suggests uu-substitution?

    Impendulo

    A composite expression paired with its derivative, such as f(g(x))g(x)f(g(x))g'(x). Set u=g(x)u=g(x) so du=g(x)dxdu=g'(x)\,dx.

  196. Ikhadi 196

    Umbuzo

    How should bounds change in a definite uu-substitution?

    Impendulo

    If u=g(x)u=g(x), replace the xx-bounds a,ba,b with uu-bounds g(a),g(b)g(a),g(b). Then finish entirely in uu, or return to xx before applying the original bounds.

  197. Ikhadi 197

    Umbuzo

    What condition makes F(x)=axf(t)dtF(x)=\int_a^x f(t)\,dt differentiable with F(x)=f(x)F'(x)=f(x)?

    Impendulo

    Continuity of ff on an interval containing aa and xx is the standard AP Calculus condition.

  198. Ikhadi 198

    Umbuzo

    Sum-and-difference rule for definite integrals?

    Impendulo

    For integrable ff and gg,

    ab[f(x)±g(x)]dx=abf(x)dx±abg(x)dx.\int_a^b [f(x)\pm g(x)]\,dx=\int_a^b f(x)\,dx\pm\int_a^b g(x)\,dx.
  199. Ikhadi 199

    Umbuzo

    Basic antiderivative of exe^x?

    Impendulo

    exdx=ex+C.\int e^x\,dx=e^x+C.
  200. Ikhadi 200

    Umbuzo

    Basic antiderivatives of sec2x\sec^2x and csc2x\csc^2x?

    Impendulo

    sec2xdx=tanx+C,csc2xdx=cotx+C.\int\sec^2x\,dx=\tan x+C,\qquad \int\csc^2x\,dx=-\cot x+C.
  201. Ikhadi 201

    Umbuzo

    For an increasing integrable function, how do left and right sums compare with the integral?

    Impendulo

    On the same partition, the left sum is an underestimate and the right sum is an overestimate. Reverse those conclusions when the function is decreasing.

  202. Ikhadi 202

    Umbuzo

    How does concavity predict trapezoidal and midpoint error?

    Impendulo

    For a concave-up function, trapezoidal sums overestimate and midpoint sums underestimate. For a concave-down function, the directions reverse.

  203. Ikhadi 203

    Umbuzo

    Why might polynomial long division help before integrating a rational function?

    Impendulo

    When the numerator's degree is at least the denominator's, division rewrites the expression as a polynomial plus a simpler proper rational function.

  204. Ikhadi 204

    Umbuzo

    What denominator pattern suggests an arctangent antiderivative?

    Impendulo

    After completing the square and scaling, a form like

    11+u2du=arctanu+C.\int\frac{1}{1+u^2}\,du=\arctan u+C.
  205. Ikhadi 205

    Umbuzo

    Basic antiderivatives of secxtanx\sec x\tan x and cscxcotx\csc x\cot x?

    Impendulo

    secxtanxdx=secx+C,cscxcotxdx=cscx+C.\int\sec x\tan x\,dx=\sec x+C,\qquad \int\csc x\cot x\,dx=-\csc x+C.
  206. Ikhadi 206

    Umbuzo

    How does an initial condition determine an antiderivative?

    Impendulo

    First find the family F(x)+CF(x)+C. Substitute the given point, such as y(a)=by(a)=b, and solve for CC.

  207. Ikhadi 207

    Umbuzo

    Should a definite-integral answer include +C+C?

    Impendulo

    No. A definite integral is one number or quantity. The constant of integration belongs to an indefinite integral or general antiderivative.

  208. Ikhadi 208

    Umbuzo

    Why does an indefinite integral include +C+C?

    Impendulo

    Differentiation loses additive constants. The +C+C represents every function with the stated derivative.

  209. Ikhadi 209

    Umbuzo

    When is F(x)=axf(t)dtF(x)=\int_a^x f(t)\,dt increasing?

    Impendulo

    Where F(x)=f(x)>0F'(x)=f(x)>0. It is decreasing where f(x)<0f(x)<0.

  210. Ikhadi 210

    Umbuzo

    How is the concavity of F(x)=axf(t)dtF(x)=\int_a^x f(t)\,dt determined?

    Impendulo

    Since F(x)=f(x)F'(x)=f(x), FF is concave up where ff is increasing and concave down where ff is decreasing, assuming the needed derivatives exist.

  211. Ikhadi 211

    Umbuzo

    How is abf(x)dx\int_a^b |f(x)|\,dx interpreted?

    Impendulo

    As total geometric area between ff and the xx-axis. Split at zeros of ff and make every regional contribution nonnegative.

  212. Ikhadi 212

    Umbuzo

    What constant-factor check completes many uu-substitutions?

    Impendulo

    Compare du=g(x)dxdu=g'(x)\,dx with the remaining factor. Multiply or divide by a constant so the integrand contains exactly the needed differential.

  213. Ikhadi 213

    Umbuzo

    How do you recover Δx\Delta x from a sigma-form Riemann sum on [a,b][a,b]?

    Impendulo

    Identify the factor multiplying each function value. For nn equal subintervals, it should be

    Δx=ban.\Delta x=\frac{b-a}{n}.
  214. Ikhadi 214

    Umbuzo

    Riemann sum for unequal subinterval widths?

    Impendulo

    If xi1x_{i-1} to xix_i has width Δxi\Delta x_i and sample point xix_i^*, use

    if(xi)Δxi.\sum_i f(x_i^*)\Delta x_i.
  215. Ikhadi 215

    Umbuzo

    Does continuity guarantee integrability on a closed interval?

    Impendulo

    Yes. A function continuous on [a,b][a,b] is integrable there. Some discontinuous functions are also integrable, so continuity is sufficient, not necessary.

  216. Ikhadi 216

    Umbuzo

    Antiderivative pattern for g(x)/g(x)g'(x)/g(x)?

    Impendulo

    Where g(x)0g(x)\ne0,

    g(x)g(x)dx=lng(x)+C.\int\frac{g'(x)}{g(x)}\,dx=\ln|g(x)|+C.
  217. Ikhadi 217

    Umbuzo

    What algebraic rewrites often reveal a basic antiderivative?

    Impendulo

    Split sums, factor out constants, simplify rational powers, and rewrite radicals as exponents. Then apply known antiderivative rules term by term.

  218. Ikhadi 218

    Umbuzo

    What units does abr(t)dt\int_a^b r(t)\,dt have?

    Impendulo

    Rate units multiplied by input units. For example, liters per minute integrated over minutes gives liters.

  219. Ikhadi 219

    Umbuzo

    What is a differential equation?

    Impendulo

    An equation that relates an unknown function to one or more of its derivatives. A solution is a function that makes the equation true on an interval.

  220. Ikhadi 220

    Umbuzo

    How does a verbal rate statement become a differential equation?

    Impendulo

    Name the changing quantity and its independent variable, translate its rate as a derivative, and express that derivative using the stated relationship. For example, “rate proportional to yy” becomes dy/dt=kydy/dt=ky.

  221. Ikhadi 221

    Umbuzo

    How do you verify that y=f(x)y=f(x) solves a differential equation?

    Impendulo

    Differentiate ff as needed, substitute yy and its derivatives into the equation, and confirm both sides agree on the claimed interval.

  222. Ikhadi 222

    Umbuzo

    General solution versus particular solution?

    Impendulo

    A general solution contains an arbitrary constant and represents a family of solution curves. A particular solution uses an initial condition to determine that constant.

  223. Ikhadi 223

    Umbuzo

    What does one segment in a slope field show?

    Impendulo

    At (x,y)(x,y), its slope equals the value of dy/dxdy/dx given by the differential equation at that point.

  224. Ikhadi 224

    Umbuzo

    What units does the constant kk have in dy/dt=kydy/dt=ky?

    Impendulo

    Inverse time units, such as per hour. That makes the exponent ktkt dimensionless.

  225. Ikhadi 225

    Umbuzo

    How do you verify a proposed solution to an initial value problem?

    Impendulo

    Check both requirements: the function must satisfy the differential equation throughout the stated interval, and it must satisfy the given initial condition.

  226. Ikhadi 226

    Umbuzo

    What makes a first-order differential equation separable?

    Impendulo

    It can be rearranged so all yy factors accompany dydy and all xx factors accompany dxdx, such as

    g(y)dy=f(x)dx.g(y)\,dy=f(x)\,dx.
  227. Ikhadi 227

    Umbuzo

    What is an initial value problem?

    Impendulo

    A differential equation paired with a value such as y(x0)=y0y(x_0)=y_0. It asks for a solution through (x0,y0)(x_0,y_0); depending on the equation, there may be zero, one, or multiple such solutions.

  228. Ikhadi 228

    Umbuzo

    What is an isocline in a slope field?

    Impendulo

    A curve along which the differential equation gives the same slope. For dy/dx=F(x,y)dy/dx=F(x,y), an isocline satisfies F(x,y)=kF(x,y)=k for a constant kk.

  229. Ikhadi 229

    Umbuzo

    How do you draw a slope-field segment at (x0,y0)(x_0,y_0)?

    Impendulo

    Evaluate the differential equation at (x0,y0)(x_0,y_0) to find the slope, then draw a short segment through that point with the resulting slope.

  230. Ikhadi 230

    Umbuzo

    General solution of dy/dt=kydy/dt=ky?

    Impendulo

    y=Cekty=Ce^{kt}

    for a constant CC. The zero solution is included by C=0C=0.

  231. Ikhadi 231

    Umbuzo

    Core method for solving a separable differential equation?

    Impendulo

    Separate the variables, integrate both sides, include a constant of integration, and solve for yy when practical. Then apply any initial condition.

  232. Ikhadi 232

    Umbuzo

    How should a solution curve follow a slope field?

    Impendulo

    It must pass through its initial point and remain tangent to the short field segments it crosses. It should not be drawn by connecting segment endpoints.

  233. Ikhadi 233

    Umbuzo

    If dy/dx=f(x)dy/dx=f(x), what pattern appears in its slope field?

    Impendulo

    Every point with the same xx-coordinate has the same slope, so the segments repeat vertically in columns.

  234. Ikhadi 234

    Umbuzo

    Why is one integration constant enough after integrating both sides?

    Impendulo

    Two constants can be combined: C2C1C_2-C_1 is still an arbitrary constant. Write a single CC.

  235. Ikhadi 235

    Umbuzo

    Solution of dy/dt=kydy/dt=ky with y(0)=y0y(0)=y_0?

    Impendulo

    y(t)=y0ekt.y(t)=y_0e^{kt}.
  236. Ikhadi 236

    Umbuzo

    Can one differential equation have infinitely many solutions?

    Impendulo

    Yes. A differential equation commonly describes a family of solution functions. An initial condition may select one particular solution when the relevant conditions support uniqueness.

  237. Ikhadi 237

    Umbuzo

    What is an equilibrium solution of dy/dx=F(y)dy/dx=F(y)?

    Impendulo

    A constant solution y=cy=c where F(c)=0F(c)=0. In the slope field, the segments along that horizontal line have zero slope.

  238. Ikhadi 238

    Umbuzo

    For continuous ff, particular solution of dy/dx=f(x)dy/dx=f(x) with y(a)=by(a)=b?

    Impendulo

    y(x)=b+axf(t)dt.y(x)=b+\int_a^x f(t)\,dt.

    The Fundamental Theorem of Calculus gives y=f(x)y'=f(x), and y(a)=by(a)=b.

  239. Ikhadi 239

    Umbuzo

    What can be lost when dividing to separate variables?

    Impendulo

    Equilibrium solutions that make the divided factor zero. Check those constant solutions directly in the original differential equation.

  240. Ikhadi 240

    Umbuzo

    In dy/dt=kydy/dt=ky, what do the signs of kk mean?

    Impendulo

    For a positive quantity, k>0k>0 produces exponential growth, k<0k<0 produces exponential decay, and k=0k=0 keeps the quantity constant.

  241. Ikhadi 241

    Umbuzo

    How can a table of slopes identify the matching differential equation?

    Impendulo

    Test representative (x,y)(x,y) entries in each candidate equation. Match zeros, signs, and repeated slope patterns before checking exact numerical values.

  242. Ikhadi 242

    Umbuzo

    How does the sign of dy/dxdy/dx describe a solution?

    Impendulo

    The solution is increasing where dy/dx>0dy/dx>0 and decreasing where dy/dx<0dy/dx<0. At one point, dy/dx=0dy/dx=0 gives a horizontal tangent; a constant y=cy=c is an equilibrium only when the derivative equation gives zero all along that level.

  243. Ikhadi 243

    Umbuzo

    How can a differential equation determine a solution's concavity?

    Impendulo

    Differentiate the equation with respect to the independent variable to obtain yy'', using the chain rule for any yy-dependence. Then use the sign of yy'' along the solution.

  244. Ikhadi 244

    Umbuzo

    Why must a differential-equation solution include an interval or domain?

    Impendulo

    Algebraic steps may introduce restrictions, and the formula must remain differentiable and satisfy the original equation throughout the interval containing the initial point.

  245. Ikhadi 245

    Umbuzo

    Doubling time for exponential growth y=y0ekty=y_0e^{kt}?

    Impendulo

    For k>0k>0,

    Td=ln2k.T_d=\frac{\ln2}{k}.

    It is independent of the initial amount.

  246. Ikhadi 246

    Umbuzo

    How can a slope field reveal whether dy/dxdy/dx depends only on yy?

    Impendulo

    Slopes repeat horizontally: every point at the same height has the same segment slope.

  247. Ikhadi 247

    Umbuzo

    How is an initial condition used after separation?

    Impendulo

    Substitute the given xx and yy values into the integrated relationship to solve for the arbitrary constant, then state the resulting particular solution.

  248. Ikhadi 248

    Umbuzo

    How do units check a model dy/dt=F(t,y)dy/dt=F(t,y)?

    Impendulo

    The right side must have the same units as dy/dtdy/dt: units of yy per unit of tt. A mismatch signals an incorrect translation or parameter unit.

  249. Ikhadi 249

    Umbuzo

    Why should a separated solution be checked in the original equation?

    Impendulo

    Division, logarithms, square roots, or algebraic rearrangement can lose or introduce branches. Direct substitution confirms the formula and its stated domain.

  250. Ikhadi 250

    Umbuzo

    Half-life for exponential decay y=y0ekty=y_0e^{kt}?

    Impendulo

    For k<0k<0,

    T1/2=ln(1/2)k=ln2k.T_{1/2}=\frac{\ln(1/2)}{k}=\frac{\ln2}{|k|}.
  251. Ikhadi 251

    Umbuzo

    Average value of ff on [a,b][a,b]?

    Impendulo

    For integrable ff and a<ba<b,

    favg=1baabf(x)dx.f_{\text{avg}}=\frac{1}{b-a}\int_a^b f(x)\,dx.
  252. Ikhadi 252

    Umbuzo

    Displacement from velocity v(t)v(t) on [a,b][a,b]?

    Impendulo

    s(b)s(a)=abv(t)dt.s(b)-s(a)=\int_a^b v(t)\,dt.

    Velocity below zero contributes negative displacement.

  253. Ikhadi 253

    Umbuzo

    Area between vertical curves y=f(x)y=f(x) and y=g(x)y=g(x)?

    Impendulo

    On intervals where f(x)g(x)f(x)\ge g(x),

    A=ab[f(x)g(x)]dx.A=\int_a^b [f(x)-g(x)]\,dx.

    Think top minus bottom.

  254. Ikhadi 254

    Umbuzo

    Volume from known cross-sectional area A(x)A(x)?

    Impendulo

    If slices are perpendicular to the xx-axis,

    V=abA(x)dx.V=\int_a^b A(x)\,dx.
  255. Ikhadi 255

    Umbuzo

    Mean Value Theorem for Integrals: hypotheses and conclusion?

    Impendulo

    If ff is continuous on [a,b][a,b], then some c[a,b]c\in[a,b] satisfies

    f(c)=1baabf(x)dx.f(c)=\frac{1}{b-a}\int_a^b f(x)\,dx.

    If a<ba<b, a point can also be chosen in (a,b)(a,b).

  256. Ikhadi 256

    Umbuzo

    Velocity and acceleration from position s(t)s(t)?

    Impendulo

    v(t)=s(t),a(t)=v(t)=s(t).v(t)=s'(t),\qquad a(t)=v'(t)=s''(t).
  257. Ikhadi 257

    Umbuzo

    Cross-sectional area when each slice is a square?

    Impendulo

    If the base segment has length s(x)s(x), then

    A(x)=[s(x)]2.A(x)=[s(x)]^2.
  258. Ikhadi 258

    Umbuzo

    How do you find accumulation from an inflow rate and an outflow rate?

    Impendulo

    Integrate the net rate:

    Q(b)Q(a)=ab[rin(t)rout(t)]dt.Q(b)-Q(a)=\int_a^b [r_{\text{in}}(t)-r_{\text{out}}(t)]\,dt.
  259. Ikhadi 259

    Umbuzo

    Area between horizontal curves written as x=R(y)x=R(y) and x=L(y)x=L(y)?

    Impendulo

    On intervals where R(y)L(y)R(y)\ge L(y),

    A=cd[R(y)L(y)]dy.A=\int_c^d [R(y)-L(y)]\,dy.

    Think right minus left.

  260. Ikhadi 260

    Umbuzo

    Disc-method volume formula?

    Impendulo

    For radius R(x)R(x) and slices perpendicular to the xx-axis,

    V=πab[R(x)]2dx.V=\pi\int_a^b [R(x)]^2\,dx.
  261. Ikhadi 261

    Umbuzo

    What units does average value have?

    Impendulo

    The same units as the original function. Integration adds an input unit, and division by interval length removes it.

  262. Ikhadi 262

    Umbuzo

    Total distance traveled from velocity v(t)v(t)?

    Impendulo

    distance=abv(t)dt.\text{distance}=\int_a^b |v(t)|\,dt.

    Split the interval wherever v(t)=0v(t)=0 and its sign changes.

  263. Ikhadi 263

    Umbuzo

    Cross-sectional area when each slice is a rectangle?

    Impendulo

    If the slice has base b(x)b(x) and height h(x)h(x), then

    A(x)=b(x)h(x).A(x)=b(x)h(x).

    Use the stated relationship to express both in the integration variable.

  264. Ikhadi 264

    Umbuzo

    How do you determine bounds for area between curves?

    Impendulo

    Use the stated region boundaries or solve the curve-intersection equations. Check whether additional intersections inside the interval require splitting.

  265. Ikhadi 265

    Umbuzo

    How is a rotation radius measured from a horizontal axis y=ky=k?

    Impendulo

    As vertical distance: yk|y-k|. For washers, identify which boundary stays farther from the axis over the interval.

  266. Ikhadi 266

    Umbuzo

    When is a particle moving to the right or left?

    Impendulo

    It moves right where v(t)>0v(t)>0 and left where v(t)<0v(t)<0. Position alone does not determine direction.

  267. Ikhadi 267

    Umbuzo

    Cross-sectional area when the diameter of a semicircle is d(x)d(x)?

    Impendulo

    The radius is d(x)/2d(x)/2, so

    A(x)=12π(d(x)2)2=π8[d(x)]2.A(x)=\frac12\pi\left(\frac{d(x)}2\right)^2=\frac{\pi}{8}[d(x)]^2.
  268. Ikhadi 268

    Umbuzo

    Why must an area integral be split where curves intersect?

    Impendulo

    The top/bottom or right/left relationship may switch there. Splitting keeps each integrand nonnegative and prevents signed cancellation.

  269. Ikhadi 269

    Umbuzo

    How can a velocity table approximate displacement?

    Impendulo

    Use a left, right, midpoint, or trapezoidal sum for v(t)dt\int v(t)\,dt. Each term is velocity times a time width.

  270. Ikhadi 270

    Umbuzo

    Washer-method volume formula?

    Impendulo

    For outer radius R(x)R(x) and inner radius r(x)r(x),

    V=πab([R(x)]2[r(x)]2)dx.V=\pi\int_a^b ([R(x)]^2-[r(x)]^2)\,dx.
  271. Ikhadi 271

    Umbuzo

    How do you recover position from velocity and an initial position?

    Impendulo

    If s(a)s(a) is known,

    s(t)=s(a)+atv(u)du.s(t)=s(a)+\int_a^t v(u)\,du.
  272. Ikhadi 272

    Umbuzo

    How do you choose between vertical and horizontal area slices?

    Impendulo

    Choose the direction that describes the region with fewer pieces. Vertical slices use top minus bottom; horizontal slices use right minus left.

  273. Ikhadi 273

    Umbuzo

    Cross-sectional area of an equilateral triangle with side s(x)s(x)?

    Impendulo

    A(x)=34[s(x)]2.A(x)=\frac{\sqrt3}{4}[s(x)]^2.
  274. Ikhadi 274

    Umbuzo

    How can a table approximate the average value of ff on [a,b][a,b]?

    Impendulo

    First approximate abf(x)dx\int_a^b f(x)\,dx with an appropriate Riemann or trapezoidal sum, then divide by bab-a.

  275. Ikhadi 275

    Umbuzo

    Single expression for area between two curves?

    Impendulo

    When the functions are integrable,

    A=abf(x)g(x)dx.A=\int_a^b |f(x)-g(x)|\,dx.

    For hand evaluation, split where their order changes.

  276. Ikhadi 276

    Umbuzo

    How is a rotation radius measured from a vertical axis x=kx=k?

    Impendulo

    As horizontal distance: xk|x-k|. With dydy slices, write the relevant boundaries as xx-functions of yy.

  277. Ikhadi 277

    Umbuzo

    How can a rate table approximate total change with unequal time gaps?

    Impendulo

    Multiply a representative rate on each interval by that interval's actual width, then sum. Do not assume a common Δt\Delta t when the table is uneven.

  278. Ikhadi 278

    Umbuzo

    When should a volume integral use dydy?

    Impendulo

    When slices perpendicular to the yy-axis make the cross-sectional area easiest to express as A(y)A(y). Then use V=cdA(y)dyV=\int_c^d A(y)\,dy.

  279. Ikhadi 279

    Umbuzo

    What signals that a washer, not a disc, is needed?

    Impendulo

    The rotated region leaves a hole around the axis. Subtract the inner circular area from the outer circular area.

  280. Ikhadi 280

    Umbuzo

    What base length is used for cross sections over a planar region?

    Impendulo

    Use the distance across the base region within each slice: top minus bottom for vertical slices, or right minus left for horizontal slices.

  281. Ikhadi 281

    Umbuzo

    Why must total distance split at velocity sign changes?

    Impendulo

    Distance accumulates speed v|v|, not signed velocity. A single integral of vv would cancel motion in opposite directions.

  282. Ikhadi 282

    Umbuzo

    When does an accumulated quantity reach a local maximum?

    Impendulo

    When its net rate changes from positive to negative. A zero rate alone is only a candidate; check the sign change.

  283. Ikhadi 283

    Umbuzo

    What distinguishes area from a definite integral?

    Impendulo

    Area is nonnegative. A definite integral is signed and may be zero or negative because regions below the axis subtract.

  284. Ikhadi 284

    Umbuzo

    How do position, velocity, and acceleration graphs correspond?

    Impendulo

    Velocity is the slope of position, and acceleration is the slope of velocity. Conversely, signed area under velocity gives position change, and signed area under acceleration gives velocity change.

  285. Ikhadi 285

    Umbuzo

    How do you interpret ab[r(t)c(t)]dt\int_a^b [r(t)-c(t)]\,dt in context?

    Impendulo

    As net change: total amount added by rr minus total amount removed by cc over the interval. State the resulting quantity and units.

  286. Ikhadi 286

    Umbuzo

    What units does a volume integral A(x)dx\int A(x)\,dx have?

    Impendulo

    Cubic units. Cross-sectional area contributes square units and slice thickness contributes one more length unit.

  287. Ikhadi 287

    Umbuzo

    How can a graph of a rate reveal the largest accumulated value?

    Impendulo

    Compare accumulation at endpoints and at times where the rate is zero or undefined. Compute signed areas to track the quantity's changes from its initial value.

  288. Ikhadi 288

    Umbuzo

    Why should a contextual integral answer include a sentence?

    Impendulo

    The number alone does not say whether it represents displacement, distance, area, volume, or net change. Name the quantity, interval, and units.

Abstract calculus graph with a glowing orange curve, tangent line, shaded area under the curve, and layered contour lines on a dark grid.

amakhadi angu-288

AP Calculus AB Flashcards: 8-Unit Formulas, Theorems & Concepts

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