AP Chemistry Flashcards: Complete 9-Unit Course Review

Review all nine AP Chemistry units with 450 cards covering concepts, models, equations, calculation setup, and laboratory reasoning.

Mayelana naleli qoqo

Review AP® Chemistry through 450 independently written English flashcards arranged in the course's nine-unit sequence. The deck moves from atomic structure and compound structure through properties of substances and mixtures, reactions, kinetics, thermochemistry, equilibrium, acids and bases, and thermodynamics and electrochemistry. Prerequisites come before dependent models and calculations.

What the cards practice

The cards use five recall paths: concept to explanation; model or representation to interpretation; equation to meaning and use; short setup to a result with units and reasoning; and laboratory observation to a chemical conclusion. They cover definitions, relationships, conditions, contrasts, particle and energy models, focused calculation steps, measurements, errors, and visible changes.

Selected reverse and contrast prompts appear only when the reverse direction has one clear standalone target. The deck excludes mechanical permutations, graph-dependent prompts that require a missing figure, copied test formats, long multipart derivations, and visual recall tied to third-party figures. The review scheduler handles long-term spacing after installation.

See the official AP Chemistry course page for College Board's current course requirements.

The Common knowledge · CC0 1.0 label applies only to the independently written prompts, answers, examples, organization, metadata, and inherited original cover, to the extent applicable rights exist. It does not claim ownership of scientific facts or equations.

This is an independent, unofficial study aid. It is not affiliated with, endorsed by, sponsored by, or official material from College Board or the AP Program. AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this product. No College Board examination questions, answer choices, scoring materials, curriculum text, logos, or trade dress were copied.

Amakhadi akuleli qoqo

  1. Ikhadi 1

    Umbuzo

    What does one mole count?

    Impendulo

    Exactly 6.02214076 × 10^23 representative particles.

  2. Ikhadi 2

    Umbuzo

    What does a peak in an element's mass spectrum represent?

    Impendulo

    An isotope with a particular mass-to-charge ratio; for singly charged monatomic ions, the position tracks isotopic mass.

  3. Ikhadi 3

    Umbuzo

    What does an empirical formula show?

    Impendulo

    The lowest whole-number ratio of the elements' atoms in a compound.

  4. Ikhadi 4

    Umbuzo

    How does a mixture differ from a pure substance at the particle level?

    Impendulo

    A mixture contains chemically distinct representative units in variable proportions; a pure substance contains one element or compound with fixed composition. Different isotopes do not make an elemental sample a mixture.

  5. Ikhadi 5

    Umbuzo

    Which particles make up an atom's nucleus?

    Impendulo

    Protons and neutrons. Electrons occupy the space outside the nucleus.

  6. Ikhadi 6

    Umbuzo

    What does a larger binding energy on a PES spectrum mean?

    Impendulo

    More energy is required to remove that electron, so it is held more strongly by the nucleus.

  7. Ikhadi 7

    Umbuzo

    How does atomic radius generally change across a period and down a group?

    Impendulo

    It decreases from left to right as effective nuclear charge rises, and it increases down a group as additional electron shells increase distance and shielding.

  8. Ikhadi 8

    Umbuzo

    What typical ion charge do Group 1 metals form?

    Impendulo

    +1, by losing their one valence electron.

  9. Ikhadi 9

    Umbuzo

    How do you convert moles to particles?

    Impendulo

    Multiply by Avogadro's number: particles = moles × 6.022 × 10^23 mol^-1.

  10. Ikhadi 10

    Umbuzo

    How is average atomic mass estimated from isotope data?

    Impendulo

    Add each isotopic mass multiplied by its fractional abundance.

  11. Ikhadi 11

    Umbuzo

    How is an element's mass percent in a compound calculated?

    Impendulo

    Divide the mass contributed by that element by the compound's molar mass, then multiply by 100%.

  12. Ikhadi 12

    Umbuzo

    How can measured elemental composition reveal a sample's purity?

    Impendulo

    Compare the measured mass fraction with the fraction expected for the pure compound; a mismatch indicates another component.

  13. Ikhadi 13

    Umbuzo

    How do you build a ground-state electron configuration with the Aufbau principle?

    Impendulo

    For ordinary ground states, move through the periodic table in atomic-number order, filling each s, p, d, or f block as it appears. The subshell capacities are s², p⁶, d¹⁰, and f¹⁴. For example, Br is [Ar] 4s² 3d¹⁰ 4p⁵.

  14. Ikhadi 14

    Umbuzo

    What does the relative area or height of an ideal PES peak indicate?

    Impendulo

    The relative number of electrons in the corresponding subshell.

  15. Ikhadi 15

    Umbuzo

    How does first ionization energy generally change across a period and down a group?

    Impendulo

    It increases from left to right as effective nuclear charge rises, and it decreases down a group as distance and shielding make a valence electron easier to remove.

  16. Ikhadi 16

    Umbuzo

    Why do elements in the same group form similar compounds?

    Impendulo

    Their ground-state valence patterns repeat, including which outer subshells are full or partly full. That leads to similar bonding and typical ion charges.

  17. Ikhadi 17

    Umbuzo

    How do you convert a sample's mass to moles?

    Impendulo

    Divide its mass by its molar mass: n = m/M.

  18. Ikhadi 18

    Umbuzo

    Which mass-spectrum interpretation lies outside the usual single-element model used in this deck?

    Impendulo

    Assigning peaks in mixtures or peaks from multiply charged or polyatomic species; the standard model uses singly charged monatomic ions of one element.

  19. Ikhadi 19

    Umbuzo

    What does the law of definite proportions state?

    Impendulo

    Every pure sample of a given compound has the same element mass ratios.

  20. Ikhadi 20

    Umbuzo

    Why can two samples of the same mixture have different compositions?

    Impendulo

    Mixture components are physically combined, so their relative amounts are not fixed by a chemical formula.

  21. Ikhadi 21

    Umbuzo

    How does Coulomb's law connect charge and separation to attraction?

    Impendulo

    Attraction grows with the magnitude of the charge product and decreases with the square of the separation distance.

  22. Ikhadi 22

    Umbuzo

    Which PES electrons usually appear at the highest binding energy?

    Impendulo

    Core electrons closest to the nucleus, because they feel the strongest nuclear attraction.

  23. Ikhadi 23

    Umbuzo

    How does electron affinity generally change across a period and down a group?

    Impendulo

    Electron gain generally becomes more favorable from left to right across a period and less favorable down a group as distance and shielding increase. Stable subshell patterns create substantial exceptions.

  24. Ikhadi 24

    Umbuzo

    Why are alkali metals generally more reactive down the group?

    Impendulo

    Their valence electron is farther from the nucleus and easier to remove.

  25. Ikhadi 25

    Umbuzo

    How many moles are in 18.0 g of H₂O?

    Impendulo

    About 0.999 mol. Use 18.0 g ÷ 18.02 g mol^-1.

  26. Ikhadi 26

    Umbuzo

    An element is 75% isotope 10 and 25% isotope 11; what is its average atomic mass?

    Impendulo

    10.25 u. Calculate (0.75 × 10) + (0.25 × 11).

  27. Ikhadi 27

    Umbuzo

    A compound is 40.0% C, 6.7% H, and 53.3% O by mass; what is its empirical formula?

    Impendulo

    CH₂O. For a 100 g sample, convert each mass to moles and divide by the smallest amount.

  28. Ikhadi 28

    Umbuzo

    A 10.0 g impure sample contains 8.5 g of the target compound; what is its mass-percent purity?

    Impendulo

    85%. Calculate (8.5 g ÷ 10.0 g) × 100%.

  29. Ikhadi 29

    Umbuzo

    Which electrons are removed first when a transition metal forms a cation?

    Impendulo

    Electrons in the occupied orbital with the highest principal quantum number: 4s before 3d. For example, Fe²⁺ is [Ar] 3d⁶.

  30. Ikhadi 30

    Umbuzo

    A PES spectrum has peaks proportional to 2, 2, and 6 electrons; which configuration fits?

    Impendulo

    1s² 2s² 2p⁶, the configuration of Ne.

  31. Ikhadi 31

    Umbuzo

    How does electronegativity generally change across a period and down a group?

    Impendulo

    It increases from left to right across a period and decreases down a group as atomic size and shielding increase.

  32. Ikhadi 32

    Umbuzo

    What empirical formula results from Al³⁺ and O²⁻?

    Impendulo

    Al₂O₃, because two Al³⁺ ions balance three O²⁻ ions.

  33. Ikhadi 33

    Umbuzo

    How does a particle's mass in atomic mass units relate to its molar mass?

    Impendulo

    The numerical value is the same: a molecular or formula-unit mass of x u corresponds to a molar mass of x g mol^-1.

  34. Ikhadi 34

    Umbuzo

    What does the tallest isotope peak usually indicate in a simple mass spectrum?

    Impendulo

    The most abundant isotope, assuming comparable detection response and singly charged ions.

  35. Ikhadi 35

    Umbuzo

    How much oxygen is present in 25.0 g of a compound that is 32.0% oxygen by mass?

    Impendulo

    8.00 g O. Multiply 25.0 g by 0.320.

  36. Ikhadi 36

    Umbuzo

    What does a particle diagram with two unbonded species in changing ratios represent?

    Impendulo

    A mixture, because more than one particle type is present and the ratio is not fixed in a formula unit.

  37. Ikhadi 37

    Umbuzo

    What distinguishes valence electrons from core electrons?

    Impendulo

    Valence electrons are available for bonding or ion formation; main-group valence electrons occupy the outermost shell, while transition metals may also use (n−1)d electrons. Core electrons mainly shield nuclear charge.

  38. Ikhadi 38

    Umbuzo

    Why can PES peak groups reveal an atom's occupied subshells?

    Impendulo

    Electrons in different subshells require distinct removal energies, producing separate binding-energy groups.

  39. Ikhadi 39

    Umbuzo

    How do ion radii compare with neutral atoms and within an isoelectronic series?

    Impendulo

    Cations are smaller than their neutral atoms, while anions are larger. Among species with the same electron count, more protons pull the electrons closer and produce the smaller radius.

  40. Ikhadi 40

    Umbuzo

    What formula is expected for a compound between a Group 2 metal M and a Group 17 nonmetal X?

    Impendulo

    MX₂, because M forms M²⁺ and X forms X⁻.

  41. Ikhadi 41

    Umbuzo

    When is a covalent bond considered nonpolar?

    Impendulo

    When the bonded atoms have identical or very similar electronegativities, so the shared electron density is distributed approximately evenly.

  42. Ikhadi 42

    Umbuzo

    Why does a bonded pair of atoms have an equilibrium bond length?

    Impendulo

    At that separation, attractive and repulsive interactions balance at minimum potential energy.

  43. Ikhadi 43

    Umbuzo

    How are particles arranged in an ionic solid?

    Impendulo

    Cations and anions occupy a repeating three-dimensional lattice held by electrostatic attraction.

  44. Ikhadi 44

    Umbuzo

    What model explains bonding in a metal?

    Impendulo

    Positive metal cores are held together by attraction to mobile, delocalized valence electrons.

  45. Ikhadi 45

    Umbuzo

    How do you construct a Lewis diagram?

    Impendulo

    Count total valence electrons, adding electrons for a negative charge and subtracting them for a positive charge. Choose a skeleton, connect atoms with single bonds, complete terminal duets or octets, and place remaining electrons on the central atom. Add multiple bonds if needed, then check the electron total and formal charges.

  46. Ikhadi 46

    Umbuzo

    What does resonance mean in a molecule or ion?

    Impendulo

    Resonance uses two or more valid Lewis diagrams with the same atom arrangement but different electron placement. The actual electron distribution is a hybrid; equivalent contributors have equal weight.

  47. Ikhadi 47

    Umbuzo

    What determines molecular shape in VSEPR theory?

    Impendulo

    Electron domains around the central atom arrange to minimize repulsions.

  48. Ikhadi 48

    Umbuzo

    How does an ionic bond differ from a covalent bond?

    Impendulo

    Ionic bonding is attraction among oppositely charged ions in an extended structure; covalent bonding uses shared electron density between atoms.

  49. Ikhadi 49

    Umbuzo

    What happens to potential energy when bonded atoms are pushed much closer than equilibrium?

    Impendulo

    Potential energy rises sharply because nucleus–nucleus and electron–electron repulsions dominate.

  50. Ikhadi 50

    Umbuzo

    Why are many ionic solids brittle?

    Impendulo

    A shifted lattice can align like charges, creating strong repulsion that splits the crystal.

  51. Ikhadi 51

    Umbuzo

    What molecular shapes arise from two electron domains with no lone pairs and from three domains with zero or one lone pair?

    Impendulo

    Two bonding domains give linear with a 180° angle. Three domains with no lone pairs give trigonal planar with 120° angles; replacing one bond with a lone pair gives bent with an angle slightly below 120°.

  52. Ikhadi 52

    Umbuzo

    Why are metals electrically conductive as solids?

    Impendulo

    Their delocalized electrons can move through the solid when an electric field is applied.

  53. Ikhadi 53

    Umbuzo

    How is formal charge calculated for an atom in a Lewis diagram?

    Impendulo

    Formal charge = valence electrons − nonbonding electrons − half the bonding electrons.

  54. Ikhadi 54

    Umbuzo

    Why can't electronegativity difference alone classify a bond as ionic or covalent?

    Impendulo

    Bonding lies on a continuum. A larger difference means more ionic character, but the element types and especially the compound's properties give the best classification.

  55. Ikhadi 55

    Umbuzo

    Which shapes and bond-angle trends arise as lone pairs replace bonds in four electron domains?

    Impendulo

    Four bonds give tetrahedral with ideal 109.5° angles. One lone pair gives trigonal pyramidal with smaller angles; two lone pairs give bent with typically smaller angles again because lone pairs repel more strongly than bonding pairs.

  56. Ikhadi 56

    Umbuzo

    What feature of a potential-energy curve represents bond dissociation energy?

    Impendulo

    The energy difference from the curve's minimum to the separated-atoms limit.

  57. Ikhadi 57

    Umbuzo

    When does an ionic compound conduct electricity?

    Impendulo

    When molten or dissolved so its ions can move; not as a rigid solid lattice.

  58. Ikhadi 58

    Umbuzo

    What is a substitutional alloy?

    Impendulo

    An alloy in which atoms of a similar size replace some host-metal atoms in the lattice.

  59. Ikhadi 59

    Umbuzo

    How do two, three, and four electron domains map to hybridization?

    Impendulo

    Two domains map to sp, three to sp², and four to sp³, with ideal angles of 180°, 120°, and 109.5°. Hybridization involving d orbitals is outside this deck’s scope.

  60. Ikhadi 60

    Umbuzo

    What usually makes one resonance contributor more favorable than another?

    Impendulo

    Smaller formal-charge magnitudes, appropriate negative charge on more electronegative atoms, and complete valence shells where applicable.

  61. Ikhadi 61

    Umbuzo

    How many sigma and pi bonds are in single, double, and triple bonds?

    Impendulo

    A single bond has one sigma bond; a double has one sigma and one pi bond; a triple has one sigma and two pi bonds. Head-on sigma overlap is stronger than side-by-side pi overlap.

  62. Ikhadi 62

    Umbuzo

    Why is a polar covalent bond polar?

    Impendulo

    Unequal electronegativity creates an uneven sharing of electron density and partial charges.

  63. Ikhadi 63

    Umbuzo

    Which molecular shapes arise as lone pairs replace bonds in five electron domains?

    Impendulo

    Five bonds give trigonal bipyramidal; four bonds and one lone pair give seesaw; three bonds and two lone pairs give T-shaped; two bonds and three lone pairs give linear.

  64. Ikhadi 64

    Umbuzo

    How do ionic charge and ionic radius affect attraction between ions?

    Impendulo

    Larger charge magnitudes and smaller ionic radii produce stronger attraction because the charge product increases and the ion centers are closer.

  65. Ikhadi 65

    Umbuzo

    Why do ionic solids often have high melting points?

    Impendulo

    Many strong Coulombic attractions throughout the lattice must be overcome to free the ions.

  66. Ikhadi 66

    Umbuzo

    What is an interstitial alloy?

    Impendulo

    A smaller atom occupies holes between host-metal atoms, often making lattice layers harder to slide.

  67. Ikhadi 67

    Umbuzo

    What shape has six bonding domains and no lone pairs on the central atom?

    Impendulo

    Octahedral.

  68. Ikhadi 68

    Umbuzo

    Which elements commonly form incomplete octets in stable Lewis diagrams?

    Impendulo

    Hydrogen forms a duet, and electron-deficient central atoms such as boron or beryllium can have fewer than eight electrons.

  69. Ikhadi 69

    Umbuzo

    How do bond order and atomic size affect covalent bond length and strength?

    Impendulo

    Within a comparable bond family, higher bond order gives shorter, stronger bonds. Larger bonded atoms generally give longer bonds, which are often weaker because their orbitals overlap less effectively.

  70. Ikhadi 70

    Umbuzo

    What bonding model best fits a sample that is malleable and conducts as a solid?

    Impendulo

    Metallic bonding with mobile, delocalized electrons and nondirectional attractions.

  71. Ikhadi 71

    Umbuzo

    What shape has six electron domains, five bonds, and one lone pair?

    Impendulo

    Square pyramidal.

  72. Ikhadi 72

    Umbuzo

    Which lattice should have stronger attractions: MgO or NaCl, assuming similar separations?

    Impendulo

    MgO, because the charge product for Mg²⁺ and O²⁻ is larger than for Na⁺ and Cl⁻.

  73. Ikhadi 73

    Umbuzo

    Why are pure metals often malleable?

    Impendulo

    Metal cores can shift while the mobile electron sea maintains nondirectional attraction instead of exposing fixed like-charge planes.

  74. Ikhadi 74

    Umbuzo

    What is the best Lewis structure for CO₂?

    Impendulo

    O=C=O, with two lone pairs on each oxygen and no formal charges.

  75. Ikhadi 75

    Umbuzo

    What shape has six electron domains, four bonds, and two opposite lone pairs?

    Impendulo

    Square planar.

  76. Ikhadi 76

    Umbuzo

    What limitation does an odd total number of valence electrons create for a Lewis diagram?

    Impendulo

    At least one electron must remain unpaired, so not every atom can have a complete paired-electron octet.

  77. Ikhadi 77

    Umbuzo

    What does a higher bond order do to a bond's potential-energy curve?

    Impendulo

    It generally places the minimum at a shorter internuclear distance and makes the well deeper, corresponding to a shorter bond and a larger bond-dissociation energy.

  78. Ikhadi 78

    Umbuzo

    When can a carbon–carbon double bond produce geometric isomers?

    Impendulo

    When each carbon has two different substituents. The pi bond restricts rotation, so distinct spatial arrangements can persist.

  79. Ikhadi 79

    Umbuzo

    When may a third-period central atom exceed an octet in a Lewis diagram?

    Impendulo

    When the valid electron count and lower formal charges favor an expanded valence shell, as in species such as SF₆.

  80. Ikhadi 80

    Umbuzo

    How do you decide whether a molecule with polar bonds is polar overall?

    Impendulo

    Add the bond-dipole vectors using the molecular shape; symmetry may cancel them, while an asymmetric arrangement leaves a net dipole.

  81. Ikhadi 81

    Umbuzo

    Which interparticle forces act between all atoms and molecules?

    Impendulo

    London dispersion forces, caused by temporary and induced dipoles.

  82. Ikhadi 82

    Umbuzo

    What four broad solid types does this deck compare?

    Impendulo

    Ionic, metallic, molecular, and covalent-network solids.

  83. Ikhadi 83

    Umbuzo

    How do gas particles differ from liquid particles?

    Impendulo

    Gas particles are much farther apart and move independently; liquid particles stay close but can move past one another.

  84. Ikhadi 84

    Umbuzo

    What relationship connects pressure, volume, amount, and temperature for an ideal gas?

    Impendulo

    PV = nRT, with absolute temperature in kelvins and units consistent with R.

  85. Ikhadi 85

    Umbuzo

    What does temperature measure in kinetic molecular theory?

    Impendulo

    The particles' average translational kinetic energy.

  86. Ikhadi 86

    Umbuzo

    What two ideal-gas assumptions fail most clearly for real gases?

    Impendulo

    Particles have nonzero volume and experience intermolecular attractions.

  87. Ikhadi 87

    Umbuzo

    How is molarity defined?

    Impendulo

    Moles of solute per liter of solution: M = n/V.

  88. Ikhadi 88

    Umbuzo

    What must a correct particulate diagram of NaCl(aq) show?

    Impendulo

    Separated Na⁺ and Cl⁻ ions in a 1:1 ratio, each surrounded by oriented water molecules.

  89. Ikhadi 89

    Umbuzo

    Which separation method removes an insoluble solid from a liquid?

    Impendulo

    Filtration: the solid stays as residue while the liquid passes as filtrate.

  90. Ikhadi 90

    Umbuzo

    What does “like dissolves like” mean at the particle level?

    Impendulo

    A solute tends to dissolve when new solute–solvent attractions can compete with the attractions disrupted in the pure substances.

  91. Ikhadi 91

    Umbuzo

    What happens when matter absorbs electromagnetic radiation?

    Impendulo

    Its particles move to an allowed higher-energy state when the photon energy matches the energy gap.

  92. Ikhadi 92

    Umbuzo

    Which equations connect photon energy, frequency, and wavelength?

    Impendulo

    E = hν and c = λν.

  93. Ikhadi 93

    Umbuzo

    What is the Beer–Lambert law?

    Impendulo

    A = εbc: absorbance equals molar absorptivity at the chosen wavelength times path length times concentration.

  94. Ikhadi 94

    Umbuzo

    What molecular features generally strengthen London dispersion forces?

    Impendulo

    More electrons and a more polarizable cloud strengthen temporary dipoles; greater contact area and accessible π-electron density can also strengthen the attraction.

  95. Ikhadi 95

    Umbuzo

    Why do molecular solids usually have low melting points and fail to conduct electricity?

    Impendulo

    Distinct molecules are held together by relatively weak intermolecular forces, while their valence electrons stay localized in bonds and lone pairs.

  96. Ikhadi 96

    Umbuzo

    How do particles move in a solid?

    Impendulo

    They vibrate about fixed positions and do not translate past one another.

  97. Ikhadi 97

    Umbuzo

    What graph shapes connect V or P with T(K) or n for an ideal gas?

    Impendulo

    All four are straight lines through the origin: V versus T(K) at fixed n and P; P versus T(K) at fixed n and V; V versus n at fixed P and T; and P versus n at fixed V and T.

  98. Ikhadi 98

    Umbuzo

    At the same temperature, which gas has the greater average molecular speed: He or Xe?

    Impendulo

    He. Both have the same average kinetic energy, but KE = ½mv² means the lower-mass particles move faster.

  99. Ikhadi 99

    Umbuzo

    Why do real gases deviate more at high pressure?

    Impendulo

    Particles are crowded, so their own volume is no longer negligible compared with the container volume.

  100. Ikhadi 100

    Umbuzo

    Which relationship describes dilution when solute amount is conserved?

    Impendulo

    M₁V₁ = M₂V₂.

  101. Ikhadi 101

    Umbuzo

    Why does an aqueous ionic solution conduct electricity?

    Impendulo

    Dissolved ions are mobile and carry charge through the solution.

  102. Ikhadi 102

    Umbuzo

    Which property lets simple distillation separate two liquids?

    Impendulo

    A sufficient difference in volatility or boiling point, so the vapor is enriched in the more volatile component.

  103. Ikhadi 103

    Umbuzo

    Why are many ionic compounds soluble in water but poorly soluble in a nonpolar solvent?

    Impendulo

    Water can form strong ion–dipole attractions that stabilize separated ions; a nonpolar solvent cannot provide comparable attractions.

  104. Ikhadi 104

    Umbuzo

    Which molecular transition is commonly associated with microwave absorption?

    Impendulo

    A transition between quantized rotational energy levels.

  105. Ikhadi 105

    Umbuzo

    What frequency corresponds to a 600. nm photon?

    Impendulo

    5.00 × 10^14 s^-1. Use ν = c/λ with 600. nm = 6.00 × 10^-7 m.

  106. Ikhadi 106

    Umbuzo

    What is the absorbance to two significant figures when ε = 2.0 × 10² L mol^-1 cm^-1, b = 1.00 cm, and c = 0.0020 M?

    Impendulo

    0.40. Use A = εbc.

  107. Ikhadi 107

    Umbuzo

    What conditions allow hydrogen bonding between two molecules?

    Impendulo

    One molecule must donate an H covalently bonded to N, O, or F, and the other must provide a lone pair on N, O, or F. A molecule can be a donor, an acceptor, or both.

  108. Ikhadi 108

    Umbuzo

    Why are covalent-network solids often very hard with high melting points?

    Impendulo

    A continuous network of strong covalent bonds must be disrupted to deform or melt the solid.

  109. Ikhadi 109

    Umbuzo

    Why do a substance's solid and liquid phases usually have similar molar volumes?

    Impendulo

    Their particles remain in close contact in both phases, even though liquid particles can move past one another.

  110. Ikhadi 110

    Umbuzo

    How is a gas mixture's total pressure related to its component pressures?

    Impendulo

    Ptotal = ΣPi; each partial pressure is the pressure that component would exert alone in the same volume and temperature.

  111. Ikhadi 111

    Umbuzo

    What microscopic events create gas pressure?

    Impendulo

    Gas particles collide with container walls and transfer momentum.

  112. Ikhadi 112

    Umbuzo

    Why do intermolecular attractions matter more for gases at low temperature?

    Impendulo

    Particles move more slowly, so attractions can alter their paths and promote condensation.

  113. Ikhadi 113

    Umbuzo

    What is the final concentration after 50.0 mL of 2.00 M solution is diluted to 200.0 mL?

    Impendulo

    0.500 M. Use M₂ = M₁V₁/V₂.

  114. Ikhadi 114

    Umbuzo

    What must a particulate representation of a solution communicate?

    Impendulo

    The relative concentrations of its components and the particle-level interactions among those components.

  115. Ikhadi 115

    Umbuzo

    What causes components to separate in chromatography?

    Impendulo

    They differ in attraction to the stationary phase and the mobile phase, so they travel at different rates.

  116. Ikhadi 116

    Umbuzo

    Why are many polar molecular solutes soluble in water?

    Impendulo

    Dipole attractions or hydrogen bonds with water can replace the solute–solute and water–water attractions disrupted during mixing.

  117. Ikhadi 117

    Umbuzo

    Why does an atom produce discrete spectral lines?

    Impendulo

    Its electrons can occupy only quantized energy levels, so only photons matching allowed energy differences are absorbed or emitted.

  118. Ikhadi 118

    Umbuzo

    How does photon energy change when frequency doubles?

    Impendulo

    It doubles because E = hν.

  119. Ikhadi 119

    Umbuzo

    Why is a calibration curve useful in spectrophotometry?

    Impendulo

    It relates measured absorbance to known concentrations, letting an unknown concentration be read by interpolation within the linear range.

  120. Ikhadi 120

    Umbuzo

    How does an ion–dipole attraction form, and how does it compare with dipole–dipole attraction?

    Impendulo

    An ion attracts the oppositely charged end of a polar molecule. Ion–dipole attractions tend to be stronger than dipole–dipole attractions.

  121. Ikhadi 121

    Umbuzo

    Which solid type is usually both conductive and malleable?

    Impendulo

    A metallic solid, because its delocalized electrons move and its nondirectional bonding tolerates layer shifts.

  122. Ikhadi 122

    Umbuzo

    How does a crystalline solid differ from an amorphous solid?

    Impendulo

    A crystalline solid has long-range repeating order; an amorphous solid lacks that long-range periodic arrangement.

  123. Ikhadi 123

    Umbuzo

    How is a gas component's partial pressure found from mole fraction?

    Impendulo

    Pi = XiPtotal.

  124. Ikhadi 124

    Umbuzo

    How does heating a fixed-volume gas affect its pressure in the ideal model?

    Impendulo

    Pressure rises because faster particles collide with the walls more forcefully and frequently.

  125. Ikhadi 125

    Umbuzo

    Why can attractions make a real gas's measured pressure lower than the ideal prediction?

    Impendulo

    Attractions pull approaching particles away from the walls, reducing momentum transfer during wall collisions.

  126. Ikhadi 126

    Umbuzo

    How many moles of ions result from complete dissolution of 0.20 mol CaCl₂?

    Impendulo

    0.60 mol ions: 0.20 mol Ca²⁺ plus 0.40 mol Cl⁻.

  127. Ikhadi 127

    Umbuzo

    How should water orient around Cl⁻ in a particle model?

    Impendulo

    Its partially positive hydrogen ends point toward Cl⁻.

  128. Ikhadi 128

    Umbuzo

    Can filtration separate dissolved components of a liquid solution?

    Impendulo

    No. Dissolved particles pass through the filter with the solvent; filtration only retains an insoluble solid.

  129. Ikhadi 129

    Umbuzo

    Why do nonpolar molecular solutes often dissolve in nonpolar solvents?

    Impendulo

    Both rely mainly on compatible London dispersion forces, so mixing can replace the attractions disrupted in the separate substances.

  130. Ikhadi 130

    Umbuzo

    What does a shorter absorbed wavelength imply about an energy transition?

    Impendulo

    A larger energy gap because E = hc/λ.

  131. Ikhadi 131

    Umbuzo

    What is the energy of a photon with frequency 5.0 × 10^14 s^-1?

    Impendulo

    3.3 × 10^-19 J. Multiply by Planck's constant: E = (6.626 × 10^-34 J·s)(5.0 × 10^14 s^-1).

  132. Ikhadi 132

    Umbuzo

    How does doubling cuvette path length affect absorbance in the linear Beer–Lambert range?

    Impendulo

    Absorbance doubles if concentration and molar absorptivity stay constant.

  133. Ikhadi 133

    Umbuzo

    How can noncovalent interactions affect a large biomolecule?

    Impendulo

    Attractions between molecules or between different regions of the same molecule help set its shape, which strongly affects its properties and function.

  134. Ikhadi 134

    Umbuzo

    Why does an ionic solid usually fail to conduct as a solid?

    Impendulo

    Its ions are fixed in lattice positions. The same substance conducts when molten or dissolved because the ions can then move.

  135. Ikhadi 135

    Umbuzo

    Why does a gas have no definite shape or volume?

    Impendulo

    Its widely spaced particles move constantly and experience minimal interparticle attraction, so they spread through the available container.

  136. Ikhadi 136

    Umbuzo

    What graph shapes show the inverse pressure–volume relationship for a fixed amount of ideal gas at constant temperature?

    Impendulo

    A plot of P against V is a decreasing curve, while P against 1/V is a straight line through the origin.

  137. Ikhadi 137

    Umbuzo

    At the same temperature, do different ideal gases have different average kinetic energies?

    Impendulo

    No. Average translational kinetic energy depends only on absolute temperature.

  138. Ikhadi 138

    Umbuzo

    Under which conditions is ideal-gas behavior most accurate?

    Impendulo

    Low pressure and high temperature, where particles are far apart and attractions matter least.

  139. Ikhadi 139

    Umbuzo

    What particle-level feature distinguishes a solution from a heterogeneous mixture?

    Impendulo

    A solution—whether solid, liquid, or gas—is uniform throughout; a heterogeneous mixture has regions or phases with different compositions.

  140. Ikhadi 140

    Umbuzo

    How should water orient around Na⁺ in a particulate model?

    Impendulo

    Its partially negative oxygen end points toward Na⁺.

  141. Ikhadi 141

    Umbuzo

    In paper chromatography, why does one solute spot travel farther than another?

    Impendulo

    It interacts more strongly with the mobile phase or more weakly with the stationary phase. With known phase polarities, that travel difference can reveal relative solute polarity.

  142. Ikhadi 142

    Umbuzo

    What energy competition helps explain whether an ionic solid dissolves?

    Impendulo

    The energy needed to separate lattice ions competes with the energy released when ion–solvent attractions form.

  143. Ikhadi 143

    Umbuzo

    Which molecular motions commonly absorb infrared radiation?

    Impendulo

    Bond vibrations whose changing dipole can interact with the radiation.

  144. Ikhadi 144

    Umbuzo

    Why must wavelength be converted to meters in c = λν when c is in m s^-1?

    Impendulo

    Consistent units are required so meters cancel correctly and frequency comes out in s^-1.

  145. Ikhadi 145

    Umbuzo

    How can fingerprints on a cuvette affect a visible-light absorbance reading?

    Impendulo

    They can absorb or scatter extra light, making measured absorbance too high and the inferred concentration too high.

  146. Ikhadi 146

    Umbuzo

    What causes and controls the strength of dipole–dipole attractions?

    Impendulo

    Opposite partial charges on neighboring polar molecules attract. Strength increases with larger molecular dipoles and depends on how favorably the dipoles are oriented.

  147. Ikhadi 147

    Umbuzo

    Why is graphite conductive and soft while diamond is insulating and hard?

    Impendulo

    Graphite has delocalized electrons within its sheets, so it conducts, and its layers can slide, so it is soft. Diamond has a rigid three-dimensional network of localized covalent bonds, making it hard and insulating.

  148. Ikhadi 148

    Umbuzo

    Why are gases much more compressible than liquids?

    Impendulo

    Gas particles have large empty spaces between them; liquid particles are already close together.

  149. Ikhadi 149

    Umbuzo

    What volume does 0.500 mol CO₂ occupy at 1.00 atm and 300. K if it behaves ideally?

    Impendulo

    12.3 L. Use V = nRT/P = (0.500 mol)(0.08206 L atm mol^-1 K^-1)(300. K)/(1.00 atm).

  150. Ikhadi 150

    Umbuzo

    Why does a lighter gas effuse faster than a heavier gas at the same temperature?

    Impendulo

    Its particles have a higher average speed because equal average kinetic energy is shared by less mass.

  151. Ikhadi 151

    Umbuzo

    How does finite particle volume affect a real gas at very high pressure?

    Impendulo

    The free volume available for particle motion is smaller than the container volume assumed by the ideal model.

  152. Ikhadi 152

    Umbuzo

    How should 250.0 mL of 0.100 M NaCl be prepared from solid NaCl?

    Impendulo

    Dissolve 0.0250 mol NaCl, or 1.46 g, then dilute to exactly 250.0 mL in a volumetric flask.

  153. Ikhadi 153

    Umbuzo

    What changes in a particle diagram when a solution is diluted without losing solute?

    Impendulo

    The solute-particle count stays constant while solvent volume and particle spacing increase.

  154. Ikhadi 154

    Umbuzo

    Why is fractional distillation better than simple distillation for liquids with close boiling points?

    Impendulo

    Repeated vaporization–condensation steps enrich the vapor in the more volatile component more effectively.

  155. Ikhadi 155

    Umbuzo

    Why are oil and water usually immiscible?

    Impendulo

    Water's strong hydrogen-bond network isn't replaced by equally strong water–oil attractions, so the substances separate into phases.

  156. Ikhadi 156

    Umbuzo

    Which molecular transition is commonly associated with ultraviolet or visible absorption?

    Impendulo

    A transition between electronic energy levels.

  157. Ikhadi 157

    Umbuzo

    Which photon carries more energy, blue light or red light?

    Impendulo

    Blue light, because it has shorter wavelength and higher frequency.

  158. Ikhadi 158

    Umbuzo

    Why is absorbance often measured at the wavelength of maximum absorbance in Beer–Lambert analysis?

    Impendulo

    It gives the largest concentration-sensitive signal, and the flat top near the maximum makes small wavelength-setting errors less influential.

  159. Ikhadi 159

    Umbuzo

    What creates a dipole–induced-dipole attraction, and what controls its strength?

    Impendulo

    A permanent dipole distorts a nearby nonpolar particle's electron cloud and creates an attractive temporary dipole. A larger permanent dipole and a more polarizable nonpolar partner make the attraction stronger.

  160. Ikhadi 160

    Umbuzo

    How do stronger intermolecular forces affect vapor pressure, boiling point, and melting point?

    Impendulo

    They lower vapor pressure and raise boiling point. Melting point often rises too, but the trend is less direct because melting rearranges rather than fully separates particles.

  161. Ikhadi 161

    Umbuzo

    How do particles behave in a liquid?

    Impendulo

    They stay in close contact while moving and colliding continuously. Temperature and interparticle attractions affect their arrangement and motion.

  162. Ikhadi 162

    Umbuzo

    Why must Celsius temperature be converted to kelvins in gas-law calculations?

    Impendulo

    Gas-law proportionalities require an absolute temperature scale whose zero corresponds to zero extrapolated thermal motion.

  163. Ikhadi 163

    Umbuzo

    How does raising temperature change a Maxwell–Boltzmann speed distribution?

    Impendulo

    The distribution broadens, its peak lowers and shifts right, and a larger fraction of particles have high speed.

  164. Ikhadi 164

    Umbuzo

    Why does the ideal-gas model treat collisions as elastic?

    Impendulo

    It assumes total kinetic energy is conserved in particle–particle and particle–wall collisions.

  165. Ikhadi 165

    Umbuzo

    How many moles of solute are in 75.0 mL of a 0.400 M solution?

    Impendulo

    0.0300 mol. Multiply 0.400 mol L^-1 by 0.0750 L.

  166. Ikhadi 166

    Umbuzo

    For equal solution volumes drawn at the same scale, what shows which solution is more concentrated?

    Impendulo

    The more concentrated diagram contains more solute particles in that equal volume.

  167. Ikhadi 167

    Umbuzo

    How do differences in intermolecular attractions let distillation separate a liquid solution?

    Impendulo

    They give the components different vapor pressures, so the vapor is enriched in the more volatile component.

  168. Ikhadi 168

    Umbuzo

    What comparison helps predict whether two liquids will be miscible?

    Impendulo

    Liquids with similar types and strengths of intermolecular attractions are more likely to mix uniformly.

  169. Ikhadi 169

    Umbuzo

    How can an absorption spectrum help identify a substance?

    Impendulo

    Its allowed energy gaps produce a characteristic pattern of absorbed wavelengths that can be compared with known spectra.

  170. Ikhadi 170

    Umbuzo

    How does absorbing or emitting a photon change an atom's or molecule's energy?

    Impendulo

    Absorption raises the species' energy by exactly the photon energy; emission lowers it by the same amount.

  171. Ikhadi 171

    Umbuzo

    What macroscopic evidence can support that a chemical reaction occurred?

    Impendulo

    Evidence can include gas formation, precipitate formation, a persistent color change, or an energy change, interpreted with particle-level changes.

  172. Ikhadi 172

    Umbuzo

    What does a net ionic equation include?

    Impendulo

    Only the dissolved or reacting species that undergo chemical change; spectator ions are omitted.

  173. Ikhadi 173

    Umbuzo

    What must a correct particulate reaction diagram conserve?

    Impendulo

    The number of atoms of every element and the total charge.

  174. Ikhadi 174

    Umbuzo

    What distinguishes a chemical change from a physical change?

    Impendulo

    A chemical change rearranges bonds into new substances; a physical change alters state or arrangement without changing chemical identity.

  175. Ikhadi 175

    Umbuzo

    What does a balanced equation's coefficient ratio provide?

    Impendulo

    The mole ratio among reacting and produced species.

  176. Ikhadi 176

    Umbuzo

    What is the equivalence point of a titration?

    Impendulo

    The point where titrant and analyte have reacted in the stoichiometric ratio given by the balanced equation.

  177. Ikhadi 177

    Umbuzo

    What defines a precipitation reaction?

    Impendulo

    Aqueous ions combine to form a sparingly soluble solid.

  178. Ikhadi 178

    Umbuzo

    What happens in a Brønsted–Lowry acid–base reaction?

    Impendulo

    A proton transfers from the acid (donor) to the base (acceptor). In aqueous solution, H₂O can play either role.

  179. Ikhadi 179

    Umbuzo

    What does oxidation mean in a redox reaction?

    Impendulo

    Loss of electrons and an increase in oxidation number.

  180. Ikhadi 180

    Umbuzo

    What particle-level change confirms that a process is chemical?

    Impendulo

    Atoms rearrange into new combinations, producing substances with different compositions.

  181. Ikhadi 181

    Umbuzo

    Which ions are spectators when AgNO₃(aq) reacts with NaCl(aq)?

    Impendulo

    Na⁺ and NO₃⁻. The net ionic reaction is Ag⁺(aq) + Cl⁻(aq) → AgCl(s).

  182. Ikhadi 182

    Umbuzo

    How does a particulate diagram reveal the limiting reactant?

    Impendulo

    After forming the maximum product allowed by the ratio, none of the limiting reactant remains while excess reactant particles do.

  183. Ikhadi 183

    Umbuzo

    Is melting ice a chemical or physical change?

    Impendulo

    A physical change. H₂O molecules remain H₂O while their arrangement and motion change.

  184. Ikhadi 184

    Umbuzo

    How is the limiting reactant identified from given amounts?

    Impendulo

    Convert each reactant to the same product amount using the balanced equation; the smaller product amount identifies the limiting reactant.

  185. Ikhadi 185

    Umbuzo

    How does an endpoint differ from an equivalence point?

    Impendulo

    The endpoint is an observed signal such as indicator color change; the equivalence point is the exact stoichiometric condition.

  186. Ikhadi 186

    Umbuzo

    How is complete combustion of a hydrocarbon in excess oxygen classified, and what products form?

    Impendulo

    It is a redox combustion reaction that forms CO₂ and H₂O.

  187. Ikhadi 187

    Umbuzo

    What are the conjugate acid and conjugate base in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Impendulo

    NH₄⁺ is the conjugate acid of NH₃, and OH⁻ is the conjugate base of H₂O.

  188. Ikhadi 188

    Umbuzo

    What does reduction mean in a redox reaction?

    Impendulo

    Gain of electrons and a decrease in oxidation number.

  189. Ikhadi 189

    Umbuzo

    Which common changes are physical rather than chemical?

    Impendulo

    Phase changes and the formation or separation of mixtures are physical when each substance keeps its composition.

  190. Ikhadi 190

    Umbuzo

    How are strong soluble electrolytes written in a complete ionic equation?

    Impendulo

    As separated aqueous ions; solids, liquids, gases, and weak electrolytes stay intact.

  191. Ikhadi 191

    Umbuzo

    A diagram starts with six A particles and four B₂ particles for 2A + B₂ → 2AB; what remains after completion?

    Impendulo

    One B₂ remains. Six A consume three B₂ and form six AB.

  192. Ikhadi 192

    Umbuzo

    Why is dissolving NaCl in water normally classified as a physical change?

    Impendulo

    Na⁺ and Cl⁻ separate and become hydrated, but retain their chemical identities. Removing the water recovers NaCl; the shift from ion–ion to ion–dipole attractions does not by itself form a new substance.

  193. Ikhadi 193

    Umbuzo

    What mass of AgCl can form from 25.0 mL of 0.200 M AgNO₃ mixed with excess Cl⁻?

    Impendulo

    0.717 g AgCl. The 1:1 reaction gives 0.00500 mol AgCl; multiply by 143.32 g mol^-1.

  194. Ikhadi 194

    Umbuzo

    What calculation finds unknown analyte moles at equivalence?

    Impendulo

    Use titrant moles, n = MV, then apply the balanced-reaction mole ratio.

  195. Ikhadi 195

    Umbuzo

    Which feature identifies an acid–base, redox, or precipitation reaction?

    Impendulo

    Acid–base reactions transfer protons, redox reactions change oxidation numbers through electron transfer, and precipitation reactions form a sparingly soluble solid.

  196. Ikhadi 196

    Umbuzo

    What is the net ionic equation for strong acid–strong base neutralization?

    Impendulo

    H⁺(aq) + OH⁻(aq) → H₂O(l).

  197. Ikhadi 197

    Umbuzo

    What is the oxidation number of sulfur in SO₄²⁻?

    Impendulo

    +6. Four oxygens contribute -8 total, so sulfur must be +6 to give -2 overall.

  198. Ikhadi 198

    Umbuzo

    Why can gas bubbles alone be ambiguous evidence of reaction?

    Impendulo

    Bubbles may also come from boiling or dissolved gas escaping, so the context and particle identities must support a chemical change.

  199. Ikhadi 199

    Umbuzo

    How is melting ice represented as a balanced physical-change equation?

    Impendulo

    H₂O(s) → H₂O(l). The formula and atom count stay the same because only the physical state changes.

  200. Ikhadi 200

    Umbuzo

    What does a particle diagram show when no reaction occurs after two aqueous ionic solutions mix?

    Impendulo

    All ions remain separated and solvated, with no new bonded particles, precipitate, or gas.

  201. Ikhadi 201

    Umbuzo

    Why is rusting iron a chemical change?

    Impendulo

    Iron atoms form new iron-oxide substances through electron transfer and new bonding.

  202. Ikhadi 202

    Umbuzo

    For 2H₂O₂(aq) → 2H₂O(l) + O₂(g), what volume of O₂ forms from 0.100 mol H₂O₂ at 298 K and 1.00 atm?

    Impendulo

    1.22 L O₂. The mole ratio gives 0.0500 mol O₂, then V = nRT/P.

  203. Ikhadi 203

    Umbuzo

    A 25.0 mL monoprotic acid sample requires 20.0 mL of 0.150 M NaOH; what is the acid concentration?

    Impendulo

    0.120 M. At 1:1 equivalence, moles acid = 0.0200 L × 0.150 M, then divide by 0.0250 L.

  204. Ikhadi 204

    Umbuzo

    Which salts does the minimum solubility rule in this deck treat as soluble?

    Impendulo

    All salts containing Na⁺, K⁺, NH₄⁺, or NO₃⁻ are treated as soluble in water.

  205. Ikhadi 205

    Umbuzo

    How are the strengths of a conjugate acid and its conjugate base related?

    Impendulo

    A stronger acid has a weaker conjugate base, and a stronger base has a weaker conjugate acid.

  206. Ikhadi 206

    Umbuzo

    How are oxidation and reduction half-reactions combined into one balanced equation?

    Impendulo

    Multiply them so electrons lost equal electrons gained, add the half-reactions, then cancel electrons and any identical species on both sides.

  207. Ikhadi 207

    Umbuzo

    How do molecular, complete ionic, and net ionic equations differ?

    Impendulo

    Molecular equations keep compounds intact, complete ionic equations split strong soluble electrolytes, and net ionic equations remove spectators. All three conserve atoms and charge.

  208. Ikhadi 208

    Umbuzo

    How should coefficients change particle counts in a reaction diagram?

    Impendulo

    They set whole-particle ratios while preserving each particle's chemical formula.

  209. Ikhadi 209

    Umbuzo

    Is separating a mixture by distillation a chemical or physical change?

    Impendulo

    A physical change. Components change phase and location but keep their chemical identities.

  210. Ikhadi 210

    Umbuzo

    What equation results from Cu → Cu²⁺ + 2e⁻ and Ag⁺ + e⁻ → Ag?

    Impendulo

    Cu + 2Ag⁺ → Cu²⁺ + 2Ag. Multiply the silver half-reaction by 2 and cancel 2e⁻; both atom counts and net charge then match.

  211. Ikhadi 211

    Umbuzo

    How is average reaction rate found from a reactant concentration?

    Impendulo

    Use the negative concentration change divided by elapsed time, adjusted by its stoichiometric coefficient when comparing species rates.

  212. Ikhadi 212

    Umbuzo

    What does a rate law express?

    Impendulo

    It shows how the measured rate depends on reactant concentrations. In rate = k[A]^m[B]^n, m and n are the orders in A and B, and m + n is the overall order.

  213. Ikhadi 213

    Umbuzo

    A plot of ln[A] versus time is linear; what is the order in A and its integrated rate law?

    Impendulo

    First order: ln[A]t = ln[A]0 − kt, so the plot's slope is −k.

  214. Ikhadi 214

    Umbuzo

    What is an elementary reaction?

    Impendulo

    A single step in a mechanism whose rate law follows directly from its reactant molecularity.

  215. Ikhadi 215

    Umbuzo

    What two collision conditions are needed for reaction?

    Impendulo

    Sufficient collision energy and a productive molecular orientation.

  216. Ikhadi 216

    Umbuzo

    What does activation energy represent on a reaction-energy profile?

    Impendulo

    The energy difference from the reactants to the transition state. The reaction coordinate tracks the step's structural progress, not elapsed time.

  217. Ikhadi 217

    Umbuzo

    What must the elementary steps of a valid mechanism do when added?

    Impendulo

    Cancel intermediates and reproduce the overall balanced reaction.

  218. Ikhadi 218

    Umbuzo

    How is a proposed mechanism tested against kinetics?

    Impendulo

    Its derived rate law must agree with the experimentally measured rate law.

  219. Ikhadi 219

    Umbuzo

    What does a pre-equilibrium approximation assume?

    Impendulo

    A fast reversible step reaches equilibrium before a later slow step consumes its intermediate.

  220. Ikhadi 220

    Umbuzo

    What does each peak on a multistep energy profile represent?

    Impendulo

    A transition state for one elementary step.

  221. Ikhadi 221

    Umbuzo

    How does a catalyst increase reaction rate?

    Impendulo

    It provides an alternate mechanism with a lower activation-energy pathway.

  222. Ikhadi 222

    Umbuzo

    Why does crushing a solid reactant usually increase its reaction rate?

    Impendulo

    Crushing increases exposed surface area, so more reactant particles can collide with the other reactant each second.

  223. Ikhadi 223

    Umbuzo

    How is reaction order found from initial-rate data?

    Impendulo

    Compare trials where one reactant concentration changes while the others stay constant, then match the rate factor to the concentration factor.

  224. Ikhadi 224

    Umbuzo

    A plot of [A] versus time is linear; what is the order in A and its integrated rate law?

    Impendulo

    Zero order: [A]t = [A]0 − kt, so the plot's slope is −k.

  225. Ikhadi 225

    Umbuzo

    What is the rate law for the elementary step 2A + B → products?

    Impendulo

    rate = k[A]²[B]. This inference is valid because the step is elementary.

    Translucent laboratory glassware, particle clusters, and flowing blue-to-amber energy curves on a dark background.

    amakhadi angu-450

    AP Chemistry Flashcards: Complete 9-Unit Course Review

    Funda leli qoqo mahhala

    I-Nibomo iyavuleka ukuze uqale ukufunda.

  226. Ikhadi 226

    Umbuzo

    How does raising temperature change a Maxwell–Boltzmann energy distribution and reaction rate?

    Impendulo

    The distribution shifts and broadens toward higher energies, so a larger fraction of collisions exceeds the activation-energy threshold and can react.

  227. Ikhadi 227

    Umbuzo

    How is ΔH read from a reaction-energy profile?

    Impendulo

    ΔH = energy of products − energy of reactants.

  228. Ikhadi 228

    Umbuzo

    What is a reaction intermediate?

    Impendulo

    A species formed in one mechanism step and consumed in a later step, so it cancels from the overall equation.

  229. Ikhadi 229

    Umbuzo

    Why can't overall reaction coefficients usually supply rate-law exponents?

    Impendulo

    The overall equation hides the mechanism; exponents come from experiment unless the reaction is a stated elementary step.

  230. Ikhadi 230

    Umbuzo

    How does pre-equilibrium remove an intermediate from a rate law?

    Impendulo

    Use the fast-step equilibrium relation to express the intermediate concentration in terms of stable reactants.

  231. Ikhadi 231

    Umbuzo

    What does each valley between peaks represent on a multistep profile?

    Impendulo

    A reaction intermediate.

  232. Ikhadi 232

    Umbuzo

    Does a catalyst change ΔH or the equilibrium constant?

    Impendulo

    No. It changes the pathway and rates, not reactant/product energies or the equilibrium composition.

  233. Ikhadi 233

    Umbuzo

    For 2A → B, how are disappearance of A and appearance of B related?

    Impendulo

    Reaction rate = -(1/2)Δ[A]/Δt = Δ[B]/Δt.

  234. Ikhadi 234

    Umbuzo

    How do the units of k depend on a rate law's overall order?

    Impendulo

    They must make the rate unit M s^-1: zero order uses M s^-1, first order s^-1, and second order M^-1 s^-1.

  235. Ikhadi 235

    Umbuzo

    A plot of 1/[A] versus time is linear; what is the order in A and its integrated rate law?

    Impendulo

    Second order: 1/[A]t = 1/[A]0 + kt, so the plot's slope is +k.

  236. Ikhadi 236

    Umbuzo

    What is molecularity?

    Impendulo

    The number of reacting particles in an elementary step, such as unimolecular or bimolecular.

  237. Ikhadi 237

    Umbuzo

    How does raising temperature affect k in the qualitative Arrhenius model?

    Impendulo

    k increases, often sharply, because a larger fraction of collisions can reach the transition state. Arrhenius-equation calculations are outside this deck’s scope.

  238. Ikhadi 238

    Umbuzo

    A reactant falls from 0.80 M to 0.50 M in 30. s; what is its average disappearance rate to two significant figures?

    Impendulo

    0.010 M s^-1. Use -(0.50 − 0.80) M ÷ 30. s.

  239. Ikhadi 239

    Umbuzo

    How does a catalyst differ from an intermediate in a mechanism?

    Impendulo

    A catalyst is consumed early and regenerated later; an intermediate is formed early and consumed later.

  240. Ikhadi 240

    Umbuzo

    For 2NO₂ → NO₃ + NO (slow), followed by NO₃ + CO → NO₂ + CO₂ (fast), what rate law is predicted?

    Impendulo

    rate = k[NO₂]². The first step is elementary and rate-limiting, so its molecularity sets the observed rate law.

  241. Ikhadi 241

    Umbuzo

    On a multistep reaction-energy profile, which feature often identifies the rate-determining step?

    Impendulo

    The step with the largest activation barrier measured from its preceding valley to its peak.

  242. Ikhadi 242

    Umbuzo

    If changing [B] leaves rate unchanged, what is the order in B?

    Impendulo

    Zero order, so [B]^0 = 1 in the measured rate law.

  243. Ikhadi 243

    Umbuzo

    What mechanism changes can binding, acid–base, or surface catalysis introduce?

    Impendulo

    They can orient reactants, lower activation barriers, or create new bound, protonated, or deprotonated intermediates and elementary steps; the catalyst is regenerated.

  244. Ikhadi 244

    Umbuzo

    What is special about a first-order reaction's half-life?

    Impendulo

    It is constant and independent of starting concentration: t1/2 = ln 2/k. Radioactive decay is a common first-order example.

  245. Ikhadi 245

    Umbuzo

    Why is a termolecular elementary collision uncommon?

    Impendulo

    Three particles must collide simultaneously with suitable energy and orientation, which is much less probable than one- or two-particle events.

  246. Ikhadi 246

    Umbuzo

    On a reaction-energy profile, how are reverse activation energy, forward activation energy, and ΔH related?

    Impendulo

    Ea,reverse = Ea,forward − ΔH. The reverse barrier is measured from products to the same transition state.

  247. Ikhadi 247

    Umbuzo

    Why can correct orientation matter even above the activation energy?

    Impendulo

    The colliding reactive sites must align so old bonds can break and new bonds can form along the reaction pathway.

  248. Ikhadi 248

    Umbuzo

    How does detecting a proposed reaction intermediate affect a mechanism claim?

    Impendulo

    It supports a mechanism that contains that intermediate, but it doesn't prove that mechanism is unique.

  249. Ikhadi 249

    Umbuzo

    For 2NO ⇌ N₂O₂ (fast equilibrium), followed by N₂O₂ + O₂ → 2NO₂ (slow), what observed rate law results?

    Impendulo

    rate = kobs[NO]²[O₂]. Start with rate = k₂[N₂O₂][O₂], use [N₂O₂] = K[NO]² from the fast equilibrium, then substitute.

  250. Ikhadi 250

    Umbuzo

    What does the highest point of a one-step energy profile represent?

    Impendulo

    The transition state, an unstable arrangement at the top of the activation barrier.

  251. Ikhadi 251

    Umbuzo

    What sign does q have for an endothermic system?

    Impendulo

    Positive, because the system absorbs heat from the surroundings.

  252. Ikhadi 252

    Umbuzo

    How does an exothermic reaction appear on an enthalpy diagram?

    Impendulo

    Products lie below reactants, so ΔH is negative.

  253. Ikhadi 253

    Umbuzo

    What condition defines thermal equilibrium?

    Impendulo

    Objects in contact have the same temperature, so there is no net heat transfer.

  254. Ikhadi 254

    Umbuzo

    What equations relate heat capacity and temperature change to heat transfer?

    Impendulo

    Use q = mcΔT with specific heat capacity, or q = nCₘΔT with molar heat capacity.

  255. Ikhadi 255

    Umbuzo

    Why is temperature constant during a phase-change plateau?

    Impendulo

    Added or removed energy changes interparticle potential energy instead of average kinetic energy.

  256. Ikhadi 256

    Umbuzo

    What does ΔHrxn describe?

    Impendulo

    The heat absorbed or released at constant pressure for the reaction exactly as written under the stated conditions.

  257. Ikhadi 257

    Umbuzo

    How is reaction enthalpy estimated from average bond enthalpies?

    Impendulo

    ΔHrxn ≈ Σ(bonds broken) − Σ(bonds formed).

  258. Ikhadi 258

    Umbuzo

    What is the standard enthalpy of formation of an element in its standard state?

    Impendulo

    Zero by definition.

  259. Ikhadi 259

    Umbuzo

    In a Hess’s law calculation, how should a step change when the target needs twice its reverse?

    Impendulo

    Reverse the equation, double every coefficient, and multiply its ΔH by -2.

  260. Ikhadi 260

    Umbuzo

    How can energy cross a system boundary during a process?

    Impendulo

    As heat or work. Heat transferred to or work done on the system increases its energy; heat transferred from or work done by the system decreases it.

  261. Ikhadi 261

    Umbuzo

    How does an endothermic reaction appear on an enthalpy diagram?

    Impendulo

    Products lie above reactants, so ΔH is positive.

  262. Ikhadi 262

    Umbuzo

    How are heat gained by a system and heat lost by its surroundings related in an isolated setup?

    Impendulo

    qsystem = -qsurroundings.

  263. Ikhadi 263

    Umbuzo

    In coffee-cup calorimetry, how is reaction heat related to solution heat?

    Impendulo

    qrxn = -qsolution when calorimeter heat is negligible and pressure is constant.

  264. Ikhadi 264

    Umbuzo

    What heat is required to melt n moles at the melting point?

    Impendulo

    q = nΔHfus.

  265. Ikhadi 265

    Umbuzo

    How does reversing a reaction change ΔH?

    Impendulo

    It reverses the sign of ΔH.

  266. Ikhadi 266

    Umbuzo

    Why is breaking a bond endothermic?

    Impendulo

    Energy must be supplied to separate atoms against their bonding attraction.

  267. Ikhadi 267

    Umbuzo

    How is ΔH°rxn calculated from standard enthalpies of formation?

    Impendulo

    ΣνΔHf°(products) − ΣνΔHf°(reactants).

  268. Ikhadi 268

    Umbuzo

    How does multiplying an equation by 3 affect its ΔH?

    Impendulo

    Multiply ΔH by 3 because enthalpy change scales with reaction amount.

  269. Ikhadi 269

    Umbuzo

    Why can an exothermic dissolution warm the solution?

    Impendulo

    The solution warms because forming solute–solvent attractions releases more energy than is absorbed in separating the original particles. The net potential-energy decrease raises particle kinetic energy and temperature.

  270. Ikhadi 270

    Umbuzo

    Does an energy diagram's activation barrier determine ΔH?

    Impendulo

    No. ΔH depends on reactant and product energy levels, while the barrier controls kinetics.

  271. Ikhadi 271

    Umbuzo

    Why does heat flow from a warmer object to a cooler object?

    Impendulo

    Energy transfers through collisions until their average kinetic energies, and therefore temperatures, equalize.

  272. Ikhadi 272

    Umbuzo

    How much heat warms 100.0 g of water by 5.0°C?

    Impendulo

    2.1 kJ. Use q = (100.0 g)(4.184 J g^-1 °C^-1)(5.0°C).

  273. Ikhadi 273

    Umbuzo

    How are the molar enthalpies of a phase change and its reverse related?

    Impendulo

    They have equal magnitudes and opposite signs, such as ΔHcond = -ΔHvap and ΔHfreeze = -ΔHfus.

  274. Ikhadi 274

    Umbuzo

    How does doubling every coefficient in a thermochemical equation affect ΔH?

    Impendulo

    It doubles ΔH.

  275. Ikhadi 275

    Umbuzo

    Why is forming a bond exothermic?

    Impendulo

    Atoms move to a lower-potential-energy bonded arrangement and release energy.

  276. Ikhadi 276

    Umbuzo

    What formation equation defines ΔHf° for CO₂(g)?

    Impendulo

    C(s, graphite) + O₂(g) → CO₂(g), forming exactly one mole from elements in standard states.

  277. Ikhadi 277

    Umbuzo

    What should happen to intermediate species when equations in a Hess’s law calculation are added?

    Impendulo

    They cancel, leaving the target overall reaction.

  278. Ikhadi 278

    Umbuzo

    If the surroundings warm during a process, what is the likely sign of qsystem?

    Impendulo

    Negative; the system likely released heat to the surroundings.

  279. Ikhadi 279

    Umbuzo

    For a profile with reactants at 40 kJ and products at 10 kJ, what is ΔH?

    Impendulo

    -30 kJ for the reaction as drawn.

  280. Ikhadi 280

    Umbuzo

    Assuming no phase change, what determines the final temperature when two substances exchange heat in an insulated container?

    Impendulo

    Energy conservation: q_warm + q_cool = 0. Use each substance's mass, heat capacity, and initial temperature to solve for the common final temperature.

  281. Ikhadi 281

    Umbuzo

    How would heat loss to the room affect an exothermic calorimetry result?

    Impendulo

    The observed temperature rise is too small, so the calculated magnitude of released heat is too low.

  282. Ikhadi 282

    Umbuzo

    What heat expression covers warming a liquid without a phase change?

    Impendulo

    q = mcΔT, not nΔHphase.

  283. Ikhadi 283

    Umbuzo

    If forming 1 mol of product has ΔH = -50 kJ mol^-1, what is q when 2 mol forms?

    Impendulo

    -100 kJ. Use q = nΔH = (2 mol)(-50 kJ mol^-1).

  284. Ikhadi 284

    Umbuzo

    Breaking reactant bonds requires 500 kJ, and forming product bonds releases 650 kJ; what is the estimated ΔH?

    Impendulo

    -150 kJ, from 500 − 650.

  285. Ikhadi 285

    Umbuzo

    For CO(g) + ½O₂(g) → CO₂(g), what is ΔH°rxn if ΔHf°[CO] = -110.5 and ΔHf°[CO₂] = -393.5 kJ mol^-1?

    Impendulo

    -283.0 kJ. Use -393.5 - [-110.5 + ½(0)], since ΔHf°[O₂(g)] = 0.

  286. Ikhadi 286

    Umbuzo

    In a Hess’s law calculation, two valid steps have ΔH values +25 kJ and -60 kJ; what is the combined ΔH?

    Impendulo

    -35 kJ, provided the equations add to the target reaction.

  287. Ikhadi 287

    Umbuzo

    Why is “bonds breaking releases energy” incorrect?

    Impendulo

    Bond breaking absorbs energy; the overall reaction releases energy only when forming new bonds releases more than breaking old bonds requires.

  288. Ikhadi 288

    Umbuzo

    How would melting appear on an energy diagram?

    Impendulo

    The liquid lies above the solid, so ΔHfus is positive; the diagram represents a physical, endothermic change.

  289. Ikhadi 289

    Umbuzo

    Can two objects at the same temperature exchange energy microscopically?

    Impendulo

    Yes, but their energy transfers balance, so there is no net heat flow.

  290. Ikhadi 290

    Umbuzo

    Why must the calorimeter's heat capacity be included when it isn't negligible?

    Impendulo

    The apparatus can absorb or release heat, so include q_cal = C_calΔT in the energy balance: q_process + q_solution + q_cal = 0.

  291. Ikhadi 291

    Umbuzo

    What makes chemical equilibrium dynamic?

    Impendulo

    Forward and reverse reactions continue at equal rates even though macroscopic concentrations stay constant.

  292. Ikhadi 292

    Umbuzo

    For aA + bB ⇌ cC, what is the concentration-form expression for Q?

    Impendulo

    Q = [C]^c / ([A]^a[B]^b), using current rather than necessarily equilibrium concentrations.

  293. Ikhadi 293

    Umbuzo

    What does K much greater than 1 indicate?

    Impendulo

    Products predominate at equilibrium, though K says nothing about reaction speed.

  294. Ikhadi 294

    Umbuzo

    How does reversing a reaction change its equilibrium constant?

    Impendulo

    K becomes 1/K.

  295. Ikhadi 295

    Umbuzo

    Can a reversible system reach equilibrium when it starts with only products?

    Impendulo

    Yes, if the reverse reaction is possible. The equilibrium composition depends on temperature, initial amounts, and volume or pressure.

  296. Ikhadi 296

    Umbuzo

    How do Q and K predict reaction direction?

    Impendulo

    Q < K shifts forward, Q > K shifts reverse, and Q = K means equilibrium.

  297. Ikhadi 297

    Umbuzo

    Which species are omitted from a heterogeneous equilibrium expression?

    Impendulo

    Pure solids and pure liquids because their activities are effectively constant.

  298. Ikhadi 298

    Umbuzo

    How does increasing a dissolved reactant's concentration or a gaseous reactant's partial pressure affect equilibrium at constant temperature when other Q terms are initially unchanged?

    Impendulo

    It lowers Q relative to K, so the system shifts toward products until Q = K again. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that pure phase remains present.

  299. Ikhadi 299

    Umbuzo

    What does a flat concentration-time graph mean at equilibrium?

    Impendulo

    Each concentration is constant, not necessarily equal to the others.

  300. Ikhadi 300

    Umbuzo

    For A ⇌ B in one fixed volume, a particulate model shows 16 A and 0 B initially, then 4 A and 12 B at equilibrium. What changed, what predominates, and what is Kc?

    Impendulo

    The net change was forward: 12 A particles became 12 B particles. B predominates at equilibrium, and Kc = [B]/[A] = 12/4 = 3.0 because both counts come from the same fixed volume.

  301. Ikhadi 301

    Umbuzo

    What can Ksp tell you about a salt's solubility, and when can two Ksp values be compared directly?

    Impendulo

    Ksp > 1 indicates a soluble salt. For salts with the same dissolution stoichiometry, a larger Ksp generally means greater molar solubility; across different stoichiometries, calculate molar solubility before comparing.

  302. Ikhadi 302

    Umbuzo

    What is the common-ion effect on solubility?

    Impendulo

    Adding an ion already in the dissolution equilibrium usually decreases the solid's molar solubility.

  303. Ikhadi 303

    Umbuzo

    How does uniform dilution shift an aqueous equilibrium based on the stoichiometric powers in Q?

    Impendulo

    It shifts toward the side with the larger sum of stoichiometric coefficients for dissolved species included in Q. If the sums are equal, dilution causes no shift by this effect; pure solids and liquids remain omitted.

  304. Ikhadi 304

    Umbuzo

    What happens if a reversible reaction starts with reactants only?

    Impendulo

    The forward rate is initially largest; products form, the reverse rate grows, and the rates eventually become equal.

  305. Ikhadi 305

    Umbuzo

    What is the purpose of an ICE table?

    Impendulo

    To organize initial, change, and equilibrium concentrations using reaction stoichiometry.

  306. Ikhadi 306

    Umbuzo

    Can a reaction with a very large K be slow?

    Impendulo

    Yes. K describes thermodynamic equilibrium position, while rate depends on kinetics and activation energy.

  307. Ikhadi 307

    Umbuzo

    What happens to Q immediately after product concentration increases?

    Impendulo

    Q increases; if it rises above K, the reaction shifts toward reactants.

  308. Ikhadi 308

    Umbuzo

    How does multiplying every reaction coefficient by 2 affect K?

    Impendulo

    The new equilibrium constant is K².

  309. Ikhadi 309

    Umbuzo

    For A ⇌ B, Kc = 4.0 and initially [A] = 1.0 M and [B] = 0, what are the equilibrium concentrations?

    Impendulo

    [A] = 0.20 M and [B] = 0.80 M. Let x form: Kc = x/(1.0 − x) = 4.0, so x = 0.80 M.

  310. Ikhadi 310

    Umbuzo

    What macroscopic properties stay constant at equilibrium?

    Impendulo

    Properties such as concentration, color, and pressure remain constant when external conditions are fixed.

  311. Ikhadi 311

    Umbuzo

    How does decreasing volume shift a gaseous equilibrium?

    Impendulo

    Toward the side with fewer moles of gas, if the two sides have different gaseous mole counts.

  312. Ikhadi 312

    Umbuzo

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kc?

    Impendulo

    Kc = [NH₃]² / ([N₂][H₂]³).

  313. Ikhadi 313

    Umbuzo

    For CaF₂(s) ⇌ Ca²⁺ + 2F⁻, how is Ksp written in terms of molar solubility s in pure water?

    Impendulo

    Ksp = s(2s)² = 4s³ because [Ca²⁺] = s and [F⁻] = 2s.

  314. Ikhadi 314

    Umbuzo

    What does K much less than 1 indicate?

    Impendulo

    Reactants predominate at equilibrium.

  315. Ikhadi 315

    Umbuzo

    How does decreasing a dissolved product's concentration or a gaseous product's partial pressure affect equilibrium when other Q terms are initially unchanged?

    Impendulo

    It lowers Q and drives a net forward reaction until equilibrium returns. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that phase remains.

  316. Ikhadi 316

    Umbuzo

    Does equilibrium mean the reaction has stopped?

    Impendulo

    No. Both directions continue, but equal rates produce no net macroscopic change.

  317. Ikhadi 317

    Umbuzo

    Why does adding NaF reduce CaF₂ solubility?

    Impendulo

    The added F⁻ raises Qsp, shifting the dissolution equilibrium toward solid CaF₂.

  318. Ikhadi 318

    Umbuzo

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kp when P_N₂ = 0.50 atm, P_H₂ = 1.50 atm, and P_NH₃ = 0.25 atm?

    Impendulo

    0.037. Use Kp = (P_NH₃)²/[(P_N₂)(P_H₂)³] = (0.25)²/[(0.50)(1.50)³]. Use equilibrium partial pressures directly; Kc↔Kp conversion isn't assessed.

  319. Ikhadi 319

    Umbuzo

    What happens to Q when a gaseous equilibrium mixture is compressed at constant temperature if products have fewer gas moles?

    Impendulo

    Q falls relative to K, so the reaction shifts toward products.

  320. Ikhadi 320

    Umbuzo

    How do K and Q transform when a reaction is reversed, its coefficients are multiplied, or reactions are added?

    Impendulo

    They follow the same algebra: reversing takes the reciprocal, multiplying every coefficient by c raises the value to the power c, and adding reactions multiplies their K or Q values.

  321. Ikhadi 321

    Umbuzo

    When is the small-x approximation acceptable?

    Impendulo

    When x is small relative to the initial concentration and the final result confirms the neglected change is suitably small.

  322. Ikhadi 322

    Umbuzo

    What graph feature shows a disturbance followed by re-equilibration?

    Impendulo

    A sudden or gradual concentration change followed by new constant plateaus while rates return to equality.

  323. Ikhadi 323

    Umbuzo

    If Q = 0.20 and K = 5.0, which direction is favored next?

    Impendulo

    Forward, because Q < K.

  324. Ikhadi 324

    Umbuzo

    At equilibrium, are reactant and product concentrations equal?

    Impendulo

    Not necessarily. They are constant, while forward and reverse rates are equal.

  325. Ikhadi 325

    Umbuzo

    CaF₂ has Ksp = 3.2 × 10^-11 in pure water; what is its molar solubility?

    Impendulo

    2.0 × 10^-4 M. If the molar solubility is s, then [Ca²⁺] = s, [F⁻] = 2s, and Ksp = 4s³.

  326. Ikhadi 326

    Umbuzo

    For N₂ + 3H₂ ⇌ 2NH₃, how is Qp written?

    Impendulo

    Qp = (P_NH₃)²/[(P_N₂)(P_H₂)³], using the current partial pressures rather than necessarily equilibrium values.

  327. Ikhadi 327

    Umbuzo

    How does heating shift an endothermic forward reaction?

    Impendulo

    Toward products, and K increases because temperature changes the equilibrium constant.

  328. Ikhadi 328

    Umbuzo

    Why do both forward and reverse rates change as equilibrium is approached?

    Impendulo

    As reactant and product concentrations change, the collision frequencies for the two directions change until their rates match.

  329. Ikhadi 329

    Umbuzo

    CaF₂ has Ksp = 3.2 × 10^-11. What is its molar solubility in 0.10 M NaF?

    Impendulo

    About 3.2 × 10^-9 M. With [F⁻] ≈ 0.10 M, Ksp = [Ca²⁺][F⁻]² gives s = (3.2 × 10^-11)/(0.10)². The common ion lowers solubility but does not change Ksp at constant temperature.

  330. Ikhadi 330

    Umbuzo

    What concentration data must be used to calculate Kc?

    Impendulo

    Equilibrium concentrations, each raised to its stoichiometric coefficient and excluding pure solids and liquids.

  331. Ikhadi 331

    Umbuzo

    What is a Brønsted–Lowry acid?

    Impendulo

    A proton donor.

  332. Ikhadi 332

    Umbuzo

    How is pH defined?

    Impendulo

    pH = -log[H₃O⁺].

  333. Ikhadi 333

    Umbuzo

    What is Ka for HA + H₂O ⇌ H₃O⁺ + A⁻?

    Impendulo

    Ka = [H₃O⁺][A⁻]/[HA].

  334. Ikhadi 334

    Umbuzo

    How does stabilizing a base affect its basicity and the strength of its conjugate acid?

    Impendulo

    It makes the base weaker and its conjugate acid stronger. A more stable base is less willing to accept H⁺.

  335. Ikhadi 335

    Umbuzo

    What is a Brønsted–Lowry base?

    Impendulo

    A proton acceptor.

  336. Ikhadi 336

    Umbuzo

    At 25°C, what are Kw and the relationship between pH and pOH?

    Impendulo

    Kw = [H₃O⁺][OH⁻] = 1.0 × 10^-14. Taking negative logarithms gives pH + pOH = 14.00.

  337. Ikhadi 337

    Umbuzo

    What is Kb for B + H₂O ⇌ BH⁺ + OH⁻?

    Impendulo

    Kb = [BH⁺][OH⁻]/[B].

  338. Ikhadi 338

    Umbuzo

    Why can lowering pH increase the solubility of a salt containing a basic anion?

    Impendulo

    H₃O⁺ consumes the anion, pulling the dissolution equilibrium toward more dissolved ions.

  339. Ikhadi 339

    Umbuzo

    What are conjugate acid–base pairs?

    Impendulo

    Species that differ by exactly one proton.

  340. Ikhadi 340

    Umbuzo

    What is the pH of 1.0 × 10^-3 M HCl?

    Impendulo

    3.00, assuming complete dissociation and negligible water contribution.

  341. Ikhadi 341

    Umbuzo

    How are pKa and pKb defined?

    Impendulo

    pKa = -log Ka, and pKb = -log Kb.

  342. Ikhadi 342

    Umbuzo

    Why does acid strength increase across a row of comparable hydrides?

    Impendulo

    Increasing electronegativity stabilizes the conjugate base and polarizes the H–A bond.

  343. Ikhadi 343

    Umbuzo

    What is an amphiprotic species?

    Impendulo

    A species that can donate or accept a proton, such as HCO₃⁻.

  344. Ikhadi 344

    Umbuzo

    What amounts remain after a limited amount of strong base partially neutralizes weak acid HA?

    Impendulo

    Subtract the reacted moles from HA and form the same number of moles of A⁻. The result gives the remaining HA and formed A⁻ amounts before any equilibrium or buffer-pH calculation.

  345. Ikhadi 345

    Umbuzo

    How are Ka, Kb, pKa, and pKb related for a conjugate pair at 25°C?

    Impendulo

    KaKb = Kw = 1.0 × 10^-14, and pKa + pKb = pKw = 14.00.

  346. Ikhadi 346

    Umbuzo

    When does pH have little effect on a salt's solubility?

    Impendulo

    When neither dissolved ion reacts appreciably with H₃O⁺ or OH⁻.

  347. Ikhadi 347

    Umbuzo

    How does H₂O act in HCl + H₂O → H₃O⁺ + Cl⁻ and in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Impendulo

    It acts as a base in the first reaction by accepting H⁺, and as an acid in the second by donating H⁺.

  348. Ikhadi 348

    Umbuzo

    After mixing weak base B with strong acid, what controls the final solution in the three stoichiometric regimes?

    Impendulo

    Excess B leaves a B/BH⁺ buffer; equimolar amounts leave BH⁺, so the solution is acidic; excess strong acid sets the pH from the remaining H₃O⁺.

  349. Ikhadi 349

    Umbuzo

    What two components make a typical weak-acid buffer?

    Impendulo

    A weak acid and a significant amount of its conjugate base.

  350. Ikhadi 350

    Umbuzo

    What do the successive half-equivalence pH values approximate in a diprotic weak-acid titration?

    Impendulo

    The first approximates pKa₁ and the second approximates pKa₂ because each conjugate pair has equal concentrations at its half-equivalence point.

  351. Ikhadi 351

    Umbuzo

    Which acid is stronger, one with pKa 2 or pKa 5?

    Impendulo

    The acid with pKa 2; lower pKa means larger Ka.

  352. Ikhadi 352

    Umbuzo

    What is the Henderson–Hasselbalch equation?

    Impendulo

    pH = pKa + log([A⁻]/[HA]).

  353. Ikhadi 353

    Umbuzo

    Why are larger binary hydrides down a group often stronger acids?

    Impendulo

    The H–A bond becomes weaker as the central atom grows, so proton release is easier.

  354. Ikhadi 354

    Umbuzo

    What mainly determines buffer capacity?

    Impendulo

    The concentrations of both members of the conjugate acid–base pair. Increasing both concentrations at a fixed ratio increases capacity without changing pH; capacity is best balanced for added acid and base when their concentrations are similar.

  355. Ikhadi 355

    Umbuzo

    Why does acid increase CaCO₃ solubility?

    Impendulo

    H₃O⁺ converts CO₃²⁻ to HCO₃⁻ or carbonic acid species, reducing free carbonate and driving more CaCO₃ to dissolve.

  356. Ikhadi 356

    Umbuzo

    What does pH < pKa imply for a weak-acid pair?

    Impendulo

    The protonated form HA predominates over A⁻.

  357. Ikhadi 357

    Umbuzo

    What happens when stoichiometrically equal amounts of a monoprotic weak acid and strong base are mixed?

    Impendulo

    The weak acid is consumed to its conjugate base; at equivalence, the solution isn't a buffer containing both forms.

  358. Ikhadi 358

    Umbuzo

    What is [H₃O⁺] when pH = 4.50?

    Impendulo

    3.2 × 10^-5 M, from [H₃O⁺] = 10^-pH.

  359. Ikhadi 359

    Umbuzo

    What is the pH of 0.010 M Ba(OH)₂ at 25°C?

    Impendulo

    About 12.30. Complete dissociation gives [OH⁻] = 0.020 M, so pOH = 1.70. At 25°C, pH + pOH = 14.00, so pH = 12.30.

  360. Ikhadi 360

    Umbuzo

    How does a buffer respond to a small amount of added strong acid?

    Impendulo

    Its conjugate base consumes H⁺, converting to the weak acid and limiting the pH change.

  361. Ikhadi 361

    Umbuzo

    Why is the equivalence-point solution basic in a monoprotic weak-acid–strong-base titration?

    Impendulo

    The conjugate base produced at equivalence reacts with water to form OH⁻, so the pH is above neutral—above 7.00 at 25°C.

  362. Ikhadi 362

    Umbuzo

    How is percent ionization calculated for a weak acid or weak base?

    Impendulo

    For HA, use ([H₃O⁺]equilibrium ÷ [HA]initial) × 100%. For B, use ([BH⁺]equilibrium ÷ [B]initial) × 100%, under the usual monoprotic setup.

  363. Ikhadi 363

    Umbuzo

    When is Henderson–Hasselbalch useful for an initial buffer-pH calculation?

    Impendulo

    Use it when both members of a conjugate acid–base pair are present in meaningful amounts, including after in-scope stoichiometry creates a buffer. Calculating the pH change after acid or base is added to an existing buffer is outside this deck’s scope.

  364. Ikhadi 364

    Umbuzo

    Why does adding oxygen atoms usually strengthen oxyacids with the same central atom?

    Impendulo

    Extra oxygens withdraw electron density and delocalize negative charge in the conjugate base.

  365. Ikhadi 365

    Umbuzo

    A prepared buffer is accidentally diluted to twice its intended volume; what happens to its pH and capacity?

    Impendulo

    Its pH stays nearly the same, and its capacity per liter is halved because both component concentrations halve. The total neutralizing moles in the sample remain unchanged.

  366. Ikhadi 366

    Umbuzo

    How does adding OH⁻ affect Mg(OH)₂ solubility?

    Impendulo

    It decreases solubility through the common-ion effect, shifting Mg(OH)₂(s) ⇌ Mg²⁺ + 2OH⁻ toward the solid.

  367. Ikhadi 367

    Umbuzo

    A buffer has equal [A⁻] and [HA]; what is its pH?

    Impendulo

    pH = pKa because log(1) = 0.

  368. Ikhadi 368

    Umbuzo

    How should a weak acid–strong base mixture be solved before equivalence?

    Impendulo

    First use mole stoichiometry; if both HA and A⁻ remain, use the resulting buffer relation.

  369. Ikhadi 369

    Umbuzo

    Why can pure neutral water have a pH other than 7.00?

    Impendulo

    Kw changes with temperature. Neutrality means [H₃O⁺] = [OH⁻], while pH = 7.00 only when Kw = 1.0 × 10^-14 at 25°C.

  370. Ikhadi 370

    Umbuzo

    25.0 mL of 0.200 M HCl is diluted to 100.0 mL; what is the pH?

    Impendulo

    1.301. Dilution gives [H₃O⁺] = (0.200 M)(25.0 mL)/(100.0 mL) = 0.0500 M, so pH = -log(0.0500).

  371. Ikhadi 371

    Umbuzo

    How does a buffer respond to a small amount of added strong base?

    Impendulo

    The weak acid consumes OH⁻, forming conjugate base and water.

  372. Ikhadi 372

    Umbuzo

    How do you find the final pH after mixing a strong acid and strong base at 25°C?

    Impendulo

    Use H₃O⁺ + OH⁻ → 2H₂O and compare their moles. Divide excess H₃O⁺ or OH⁻ by the total volume, then calculate pH or pOH from that excess concentration. Equal moles give pH 7.00 at 25°C.

  373. Ikhadi 373

    Umbuzo

    What distinguishes acid strength from acid concentration?

    Impendulo

    Strength is the equilibrium tendency to donate H⁺, reflected by Ka or pKa; concentration is the amount of acid per solution volume.

  374. Ikhadi 374

    Umbuzo

    If [A⁻]/[HA] = 10, how does pH compare with pKa?

    Impendulo

    pH = pKa + 1 because log 10 = 1.

  375. Ikhadi 375

    Umbuzo

    Which conjugate base is more stable, one with localized or resonance-delocalized charge?

    Impendulo

    The resonance-delocalized conjugate base, which generally corresponds to the stronger acid.

  376. Ikhadi 376

    Umbuzo

    Which 1.0 L buffer has greater capacity: 1.0 mol each of HA/A⁻ or 0.10 mol each at the same ratio?

    Impendulo

    The 1.0 mol pair; both have the same initial pH, but the larger amounts neutralize more added acid or base.

  377. Ikhadi 377

    Umbuzo

    For BHX(s) ⇌ BH⁺ + X⁻, why can raising pH increase the salt's solubility?

    Impendulo

    OH⁻ consumes BH⁺ to form B and H₂O, so dissolution shifts right to replace BH⁺. This is a qualitative prediction, not a pH-dependent solubility calculation.

  378. Ikhadi 378

    Umbuzo

    What does pH > pKa imply for a weak-acid pair?

    Impendulo

    The deprotonated form A⁻ predominates over HA.

  379. Ikhadi 379

    Umbuzo

    For HA + B ⇌ A⁻ + BH⁺, which side is favored when pKa(HA) = 4 and pKa(BH⁺) = 9?

    Impendulo

    Products are favored. Proton transfer moves toward the weaker acid–base pair, and K ≈ 10^(9 − 4) = 10^5.

  380. Ikhadi 380

    Umbuzo

    What is the pOH when [OH⁻] = 2.5 × 10^-4 M?

    Impendulo

    3.60, from -log(2.5 × 10^-4).

  381. Ikhadi 381

    Umbuzo

    What is the pH of 0.100 M HA when Ka = 1.0 × 10^-5?

    Impendulo

    About 3.00. The ICE setup gives Ka = x²/(0.100 − x); x ≈ 1.0 × 10^-3 M, and the 1.0% change validates the approximation.

  382. Ikhadi 382

    Umbuzo

    Why does a buffer fail after too much strong acid is added?

    Impendulo

    Its conjugate base is depleted, so added H⁺ is no longer consumed effectively.

  383. Ikhadi 383

    Umbuzo

    What do two clear equivalence regions on an acid titration curve suggest?

    Impendulo

    At least two distinguishable titratable protons; on a clean ideal curve with exactly two equivalence regions, this is consistent with a diprotic acid.

  384. Ikhadi 384

    Umbuzo

    A buffer has pKa 4.8 and [A⁻]/[HA] = 0.10; what is pH?

    Impendulo

    3.8, from 4.8 + log(0.10).

  385. Ikhadi 385

    Umbuzo

    Why is HCl stronger than HF in water despite F being more electronegative?

    Impendulo

    The H–F bond is much stronger; bond strength dominates this down-group binary-acid comparison.

  386. Ikhadi 386

    Umbuzo

    Why does percent ionization increase when a weak acid is diluted?

    Impendulo

    Dilution shifts ionization toward more particles, so a larger fraction ionizes even though [H₃O⁺] decreases.

  387. Ikhadi 387

    Umbuzo

    A buffer contains more HA than A⁻. Which addition can it neutralize in greater amount: strong acid or strong base?

    Impendulo

    Strong base. The larger HA reserve consumes more added OH⁻; a buffer with more A⁻ than HA instead has greater capacity for added strong acid.

  388. Ikhadi 388

    Umbuzo

    Why can removing a basic anion increase a salt's molar solubility without changing Ksp?

    Impendulo

    The equilibrium shifts to replace the consumed ion; Ksp remains fixed at the same temperature.

  389. Ikhadi 389

    Umbuzo

    Why can an acid–base indicator change color as pH changes?

    Impendulo

    Its protonated and deprotonated forms have different colors or other observable properties, and their relative amounts change with pH.

  390. Ikhadi 390

    Umbuzo

    What buffer results from mixing 1.0 mol HA with 0.40 mol OH⁻?

    Impendulo

    0.60 mol HA and 0.40 mol A⁻ remain, forming a buffer before any equilibrium calculation.

  391. Ikhadi 391

    Umbuzo

    What is the pH of 0.200 M weak base B when Kb = 2.0 × 10^-5 at 25°C?

    Impendulo

    About 11.30. The ICE setup gives Kb = x²/(0.200 − x); x ≈ 2.0 × 10^-3 M OH⁻, and the 1.0% change validates the approximation.

  392. Ikhadi 392

    Umbuzo

    Why does a weak acid alone not make an effective buffer?

    Impendulo

    It lacks a substantial conjugate-base reserve to consume added strong acid.

  393. Ikhadi 393

    Umbuzo

    What controls pH after excess strong base passes equivalence?

    Impendulo

    The concentration of excess OH⁻ after accounting for reaction stoichiometry and total volume.

  394. Ikhadi 394

    Umbuzo

    How should an indicator be chosen for a titration?

    Impendulo

    Its color-change range should fall within the steep pH change near the equivalence point.

  395. Ikhadi 395

    Umbuzo

    How can a measured pH and known pKa give a conjugate-base/acid ratio?

    Impendulo

    Rearrange Henderson–Hasselbalch: [A⁻]/[HA] = 10^(pH − pKa).

  396. Ikhadi 396

    Umbuzo

    Can a weak base and its conjugate acid form a buffer?

    Impendulo

    Yes, when both are present in significant amounts.

  397. Ikhadi 397

    Umbuzo

    For equal-volume buffers with the same conjugate-base/acid ratio, how does adding the same amount of strong acid affect a more concentrated versus less concentrated buffer?

    Impendulo

    The concentrated buffer changes pH less because it has greater capacity.

  398. Ikhadi 398

    Umbuzo

    How does equivalence-point pH compare for strong acid–strong base, weak acid–strong base, and weak base–strong acid titrations at 25°C?

    Impendulo

    Strong acid–strong base: pH 7.00. Weak acid–strong base: above 7.00 because the conjugate base reacts with water. Weak base–strong acid: below 7.00 because the conjugate acid reacts with water.

  399. Ikhadi 399

    Umbuzo

    Why should mole ratios replace concentration ratios after mixing buffer solutions?

    Impendulo

    Both components share the same final volume, so that volume cancels in [A⁻]/[HA].

  400. Ikhadi 400

    Umbuzo

    How does adding a little strong acid change a buffer's conjugate-base and conjugate-acid amounts?

    Impendulo

    The conjugate base decreases and its conjugate acid increases by the amount of strong acid consumed.

  401. Ikhadi 401

    Umbuzo

    What does entropy measure qualitatively?

    Impendulo

    The dispersal of matter and energy among available microstates.

  402. Ikhadi 402

    Umbuzo

    How is standard reaction entropy calculated?

    Impendulo

    ΔS°rxn = ΣνS°(products) − ΣνS°(reactants).

  403. Ikhadi 403

    Umbuzo

    What equation gives ΔG° from ΔH° and ΔS°, and what standard states do the degree symbols assume?

    Impendulo

    ΔG° = ΔH° − TΔS°. The standard states are pure substances, 1.0 M solutions, and gases at 1 atm or 1 bar; T is in kelvins and energy units must match.

  404. Ikhadi 404

    Umbuzo

    Does thermodynamic favorability guarantee a fast reaction?

    Impendulo

    No. A favorable reaction can be slow when its activation barrier is large.

  405. Ikhadi 405

    Umbuzo

    What is ΔG at equilibrium?

    Impendulo

    Zero under the current conditions because there is no net driving force.

  406. Ikhadi 406

    Umbuzo

    Why can an endothermic dissolution still be thermodynamically favorable?

    Impendulo

    A sufficiently positive entropy change can make TΔS exceed positive ΔH, giving negative ΔG.

  407. Ikhadi 407

    Umbuzo

    How can an unfavorable reaction be driven by a favorable one?

    Impendulo

    Couple them so their equations and ΔG values add to a negative overall ΔG.

  408. Ikhadi 408

    Umbuzo

    Where does oxidation occur in every electrochemical cell?

    Impendulo

    At the anode.

  409. Ikhadi 409

    Umbuzo

    How are standard cell potential and standard free energy related?

    Impendulo

    ΔG° = -nFE°cell.

  410. Ikhadi 410

    Umbuzo

    What equation gives cell potential under nonstandard conditions?

    Impendulo

    E = E° − (RT/nF) ln Q. When Q = 1, ln Q = 0, so E = E°.

  411. Ikhadi 411

    Umbuzo

    How is electrical charge related to current and time?

    Impendulo

    q = It.

  412. Ikhadi 412

    Umbuzo

    Which phase has greater molar entropy, liquid water or ice at the same temperature?

    Impendulo

    Liquid water because its molecules have more accessible arrangements and motion.

  413. Ikhadi 413

    Umbuzo

    Do elements in their standard states have zero standard molar entropy?

    Impendulo

    No. Their ΔHf° is zero, but their absolute S° values are positive above 0 K.

  414. Ikhadi 414

    Umbuzo

    How do the four ΔH° and ΔS° sign combinations determine thermodynamic favorability across temperature?

    Impendulo

    ΔH° < 0 and ΔS° > 0 is favorable at every temperature; ΔH° > 0 and ΔS° < 0 is thermodynamically unfavored at every temperature. If both are positive, favorability requires high temperature; if both are negative, it requires low temperature.

  415. Ikhadi 415

    Umbuzo

    What does it indicate when a thermodynamically favored process does not occur at a measurable rate?

    Impendulo

    It is under kinetic control, commonly because of a high activation energy; no measurable reaction does not mean the system is at equilibrium.

  416. Ikhadi 416

    Umbuzo

    How are ΔG° and K related?

    Impendulo

    ΔG° = -RT ln K.

  417. Ikhadi 417

    Umbuzo

    What two contributions compete in dissolving an ionic solid?

    Impendulo

    Enthalpy changes from separating and solvating particles, and entropy changes from their new dispersal and solvent organization.

  418. Ikhadi 418

    Umbuzo

    What must cancel when coupled reactions are added?

    Impendulo

    Shared intermediates, leaving the desired net reaction.

  419. Ikhadi 419

    Umbuzo

    Where does reduction occur in every electrochemical cell?

    Impendulo

    At the cathode.

  420. Ikhadi 420

    Umbuzo

    What sign of E°cell indicates a favorable standard galvanic reaction?

    Impendulo

    Positive E°cell, corresponding to negative ΔG°.

  421. Ikhadi 421

    Umbuzo

    If Q increases for a galvanic reaction, how does E change at fixed temperature?

    Impendulo

    E decreases according to the Nernst equation. Le Châtelier's principle does not apply to an operating cell away from equilibrium; use Q and Nernst reasoning instead.

  422. Ikhadi 422

    Umbuzo

    How are moles of electrons found from charge?

    Impendulo

    Moles e⁻ = q/F, where F ≈ 96485 C mol^-1 e⁻.

  423. Ikhadi 423

    Umbuzo

    How does producing more gas particles usually affect system entropy?

    Impendulo

    It increases entropy because the particles have more positional microstates.

  424. Ikhadi 424

    Umbuzo

    Can a dissolution with negative ΔH be unfavorable?

    Impendulo

    Yes. A sufficiently negative entropy change at the stated temperature can make ΔG positive.

  425. Ikhadi 425

    Umbuzo

    When can a process with ΔH > 0 and ΔS > 0 become favorable?

    Impendulo

    At sufficiently high temperature, when TΔS exceeds ΔH.

  426. Ikhadi 426

    Umbuzo

    How does a catalyst affect ΔG?

    Impendulo

    It does not change ΔG; it lowers the activation barrier for both directions.

  427. Ikhadi 427

    Umbuzo

    For A → B, ΔGf°(A) = -50 kJ mol^-1 and ΔGf°(B) = -80 kJ mol^-1. What is ΔG°rxn?

    Impendulo

    -30 kJ mol^-1. Use ΣνΔGf°(products) − ΣνΔGf°(reactants) = -80 − (-50).

  428. Ikhadi 428

    Umbuzo

    Why can dissolving a gas in a liquid have a negative entropy change?

    Impendulo

    Gas particles lose much of their translational freedom when confined and solvated in the liquid.

  429. Ikhadi 429

    Umbuzo

    If coupled steps have ΔG values +20 kJ and -35 kJ, what is overall ΔG?

    Impendulo

    -15 kJ, so the combined process is thermodynamically favorable under those conditions.

  430. Ikhadi 430

    Umbuzo

    What role does each half-cell solution play in an electrochemical cell?

    Impendulo

    It supplies dissolved redox species at an electrode interface and carries ions within its compartment. Separate compartments prevent direct mixing while the external circuit and salt bridge connect the half-cells.

  431. Ikhadi 431

    Umbuzo

    How is E°cell found from standard reduction potentials?

    Impendulo

    E°cell = E°cathode − E°anode, using both tabulated values as reductions.

  432. Ikhadi 432

    Umbuzo

    How does a cell's potential magnitude change as Q approaches or moves away from K, and what is E at equilibrium?

    Impendulo

    |E| falls toward zero as Q approaches K and grows as the system moves farther from equilibrium. At equilibrium, Q = K and E = 0.

  433. Ikhadi 433

    Umbuzo

    How many moles of electrons pass when 1.93 × 10^5 C flows?

    Impendulo

    2.00 mol e⁻, from q/F.

  434. Ikhadi 434

    Umbuzo

    How does a salt bridge maintain charge balance in a galvanic cell?

    Impendulo

    Anions migrate toward the anode compartment and cations toward the cathode compartment, countering the net charge imbalances created by the two half-reactions.

  435. Ikhadi 435

    Umbuzo

    Why does raising a substance's temperature generally increase its entropy?

    Impendulo

    Energy spreads across more accessible particle energy states, increasing the number of possible microscopic arrangements.

  436. Ikhadi 436

    Umbuzo

    When can a process with ΔH < 0 and ΔS < 0 be favorable?

    Impendulo

    At sufficiently low temperature, where the unfavorable -TΔS term is small.

  437. Ikhadi 437

    Umbuzo

    Why can diamond persist even though graphite is more stable at standard conditions?

    Impendulo

    Conversion has a large activation barrier, so diamond is kinetically persistent.

  438. Ikhadi 438

    Umbuzo

    What do the external circuit and measuring device do in an electrochemical cell?

    Impendulo

    The circuit carries electrons from anode to cathode; a voltmeter measures potential difference, while an ammeter in series measures current.

  439. Ikhadi 439

    Umbuzo

    At constant temperature, how does increasing the volume available to a gas affect its entropy?

    Impendulo

    Entropy increases because the gas particles can occupy more positions in the larger space, so more microstates are accessible.

  440. Ikhadi 440

    Umbuzo

    How does reversing one coupled reaction affect its ΔG?

    Impendulo

    It reverses the sign of that reaction's ΔG.

  441. Ikhadi 441

    Umbuzo

    Why is n required in ΔG° = -nFE°?

    Impendulo

    It is the moles of electrons transferred per balanced reaction, linking charge flow to reaction extent.

  442. Ikhadi 442

    Umbuzo

    What makes an electrolytic cell operate?

    Impendulo

    An external power source drives a thermodynamically unfavorable redox reaction; oxidation still occurs at the anode and reduction at the cathode.

  443. Ikhadi 443

    Umbuzo

    In an Mⁿ⁺/M concentration cell, which half-cell is the anode: the dilute or concentrated ion solution?

    Impendulo

    The dilute half-cell. Oxidation produces Mⁿ⁺ there, while reduction consumes Mⁿ⁺ in the concentrated half-cell, so electrons flow from dilute to concentrated as the concentrations move toward equality.

  444. Ikhadi 444

    Umbuzo

    How is deposited metal mass found from current and time?

    Impendulo

    Find q = It, convert q/F to moles e⁻, use the half-reaction ratio to moles metal, then multiply by molar mass.

  445. Ikhadi 445

    Umbuzo

    Given product S° total 500 J mol^-1 K^-1 and reactant total 420 J mol^-1 K^-1, what is ΔS°?

    Impendulo

    +80 J mol^-1 K^-1.

  446. Ikhadi 446

    Umbuzo

    How do electrode masses change in a Zn–Cu galvanic cell?

    Impendulo

    The Zn anode loses mass as Zn → Zn²⁺ + 2e⁻, while the Cu cathode gains mass as Cu²⁺ + 2e⁻ → Cu.

  447. Ikhadi 447

    Umbuzo

    What is ΔG° when ΔH° = 50 kJ mol^-1, ΔS° = 0.200 kJ mol^-1 K^-1, and T = 300 K?

    Impendulo

    -10 kJ mol^-1, from ΔG° = 50 − (300)(0.200).

  448. Ikhadi 448

    Umbuzo

    Why can temperature change a solid's solubility?

    Impendulo

    Temperature changes the balance of ΔH and TΔS, so it changes the free energy of dissolution and the equilibrium constant.

  449. Ikhadi 449

    Umbuzo

    What does the size of ΔG° relative to RT imply about K?

    Impendulo

    ΔG° near zero gives K near 1. When |ΔG°| is much larger than RT, K is far from 1: negative ΔG° gives K ≫ 1, while positive ΔG° gives K ≪ 1.

  450. Ikhadi 450

    Umbuzo

    Bubbles form at an inert cathode in acidic solution; which half-reaction can explain them?

    Impendulo

    2H⁺ + 2e⁻ → H₂(g). Gas evolution at the cathode can be direct evidence of reduction.

Translucent laboratory glassware, particle clusters, and flowing blue-to-amber energy curves on a dark background.

amakhadi angu-450

AP Chemistry Flashcards: Complete 9-Unit Course Review

Funda leli qoqo mahhala

I-Nibomo iyavuleka ukuze uqale ukufunda.