AP Chemistry Flashcards: Complete 9-Unit Course Review

Review all nine AP Chemistry units with 450 cards covering concepts, models, equations, calculation setup, and laboratory reasoning.

O ovom špilu

Review AP® Chemistry through 450 independently written English flashcards arranged in the course's nine-unit sequence. The deck moves from atomic structure and compound structure through properties of substances and mixtures, reactions, kinetics, thermochemistry, equilibrium, acids and bases, and thermodynamics and electrochemistry. Prerequisites come before dependent models and calculations.

What the cards practice

The cards use five recall paths: concept to explanation; model or representation to interpretation; equation to meaning and use; short setup to a result with units and reasoning; and laboratory observation to a chemical conclusion. They cover definitions, relationships, conditions, contrasts, particle and energy models, focused calculation steps, measurements, errors, and visible changes.

Selected reverse and contrast prompts appear only when the reverse direction has one clear standalone target. The deck excludes mechanical permutations, graph-dependent prompts that require a missing figure, copied test formats, long multipart derivations, and visual recall tied to third-party figures. The review scheduler handles long-term spacing after installation.

See the official AP Chemistry course page for College Board's current course requirements.

The Common knowledge · CC0 1.0 label applies only to the independently written prompts, answers, examples, organization, metadata, and inherited original cover, to the extent applicable rights exist. It does not claim ownership of scientific facts or equations.

This is an independent, unofficial study aid. It is not affiliated with, endorsed by, sponsored by, or official material from College Board or the AP Program. AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this product. No College Board examination questions, answer choices, scoring materials, curriculum text, logos, or trade dress were copied.

Kartice u ovom špilu

  1. Kartica 1

    Pitanje

    What does one mole count?

    Odgovor

    Exactly 6.02214076 × 10^23 representative particles.

  2. Kartica 2

    Pitanje

    What does a peak in an element's mass spectrum represent?

    Odgovor

    An isotope with a particular mass-to-charge ratio; for singly charged monatomic ions, the position tracks isotopic mass.

  3. Kartica 3

    Pitanje

    What does an empirical formula show?

    Odgovor

    The lowest whole-number ratio of the elements' atoms in a compound.

  4. Kartica 4

    Pitanje

    How does a mixture differ from a pure substance at the particle level?

    Odgovor

    A mixture contains chemically distinct representative units in variable proportions; a pure substance contains one element or compound with fixed composition. Different isotopes do not make an elemental sample a mixture.

  5. Kartica 5

    Pitanje

    Which particles make up an atom's nucleus?

    Odgovor

    Protons and neutrons. Electrons occupy the space outside the nucleus.

  6. Kartica 6

    Pitanje

    What does a larger binding energy on a PES spectrum mean?

    Odgovor

    More energy is required to remove that electron, so it is held more strongly by the nucleus.

  7. Kartica 7

    Pitanje

    How does atomic radius generally change across a period and down a group?

    Odgovor

    It decreases from left to right as effective nuclear charge rises, and it increases down a group as additional electron shells increase distance and shielding.

  8. Kartica 8

    Pitanje

    What typical ion charge do Group 1 metals form?

    Odgovor

    +1, by losing their one valence electron.

  9. Kartica 9

    Pitanje

    How do you convert moles to particles?

    Odgovor

    Multiply by Avogadro's number: particles = moles × 6.022 × 10^23 mol^-1.

  10. Kartica 10

    Pitanje

    How is average atomic mass estimated from isotope data?

    Odgovor

    Add each isotopic mass multiplied by its fractional abundance.

  11. Kartica 11

    Pitanje

    How is an element's mass percent in a compound calculated?

    Odgovor

    Divide the mass contributed by that element by the compound's molar mass, then multiply by 100%.

  12. Kartica 12

    Pitanje

    How can measured elemental composition reveal a sample's purity?

    Odgovor

    Compare the measured mass fraction with the fraction expected for the pure compound; a mismatch indicates another component.

  13. Kartica 13

    Pitanje

    How do you build a ground-state electron configuration with the Aufbau principle?

    Odgovor

    For ordinary ground states, move through the periodic table in atomic-number order, filling each s, p, d, or f block as it appears. The subshell capacities are s², p⁶, d¹⁰, and f¹⁴. For example, Br is [Ar] 4s² 3d¹⁰ 4p⁵.

  14. Kartica 14

    Pitanje

    What does the relative area or height of an ideal PES peak indicate?

    Odgovor

    The relative number of electrons in the corresponding subshell.

  15. Kartica 15

    Pitanje

    How does first ionization energy generally change across a period and down a group?

    Odgovor

    It increases from left to right as effective nuclear charge rises, and it decreases down a group as distance and shielding make a valence electron easier to remove.

  16. Kartica 16

    Pitanje

    Why do elements in the same group form similar compounds?

    Odgovor

    Their ground-state valence patterns repeat, including which outer subshells are full or partly full. That leads to similar bonding and typical ion charges.

  17. Kartica 17

    Pitanje

    How do you convert a sample's mass to moles?

    Odgovor

    Divide its mass by its molar mass: n = m/M.

  18. Kartica 18

    Pitanje

    Which mass-spectrum interpretation lies outside the usual single-element model used in this deck?

    Odgovor

    Assigning peaks in mixtures or peaks from multiply charged or polyatomic species; the standard model uses singly charged monatomic ions of one element.

  19. Kartica 19

    Pitanje

    What does the law of definite proportions state?

    Odgovor

    Every pure sample of a given compound has the same element mass ratios.

  20. Kartica 20

    Pitanje

    Why can two samples of the same mixture have different compositions?

    Odgovor

    Mixture components are physically combined, so their relative amounts are not fixed by a chemical formula.

  21. Kartica 21

    Pitanje

    How does Coulomb's law connect charge and separation to attraction?

    Odgovor

    Attraction grows with the magnitude of the charge product and decreases with the square of the separation distance.

  22. Kartica 22

    Pitanje

    Which PES electrons usually appear at the highest binding energy?

    Odgovor

    Core electrons closest to the nucleus, because they feel the strongest nuclear attraction.

  23. Kartica 23

    Pitanje

    How does electron affinity generally change across a period and down a group?

    Odgovor

    Electron gain generally becomes more favorable from left to right across a period and less favorable down a group as distance and shielding increase. Stable subshell patterns create substantial exceptions.

  24. Kartica 24

    Pitanje

    Why are alkali metals generally more reactive down the group?

    Odgovor

    Their valence electron is farther from the nucleus and easier to remove.

  25. Kartica 25

    Pitanje

    How many moles are in 18.0 g of H₂O?

    Odgovor

    About 0.999 mol. Use 18.0 g ÷ 18.02 g mol^-1.

  26. Kartica 26

    Pitanje

    An element is 75% isotope 10 and 25% isotope 11; what is its average atomic mass?

    Odgovor

    10.25 u. Calculate (0.75 × 10) + (0.25 × 11).

  27. Kartica 27

    Pitanje

    A compound is 40.0% C, 6.7% H, and 53.3% O by mass; what is its empirical formula?

    Odgovor

    CH₂O. For a 100 g sample, convert each mass to moles and divide by the smallest amount.

  28. Kartica 28

    Pitanje

    A 10.0 g impure sample contains 8.5 g of the target compound; what is its mass-percent purity?

    Odgovor

    85%. Calculate (8.5 g ÷ 10.0 g) × 100%.

  29. Kartica 29

    Pitanje

    Which electrons are removed first when a transition metal forms a cation?

    Odgovor

    Electrons in the occupied orbital with the highest principal quantum number: 4s before 3d. For example, Fe²⁺ is [Ar] 3d⁶.

  30. Kartica 30

    Pitanje

    A PES spectrum has peaks proportional to 2, 2, and 6 electrons; which configuration fits?

    Odgovor

    1s² 2s² 2p⁶, the configuration of Ne.

  31. Kartica 31

    Pitanje

    How does electronegativity generally change across a period and down a group?

    Odgovor

    It increases from left to right across a period and decreases down a group as atomic size and shielding increase.

  32. Kartica 32

    Pitanje

    What empirical formula results from Al³⁺ and O²⁻?

    Odgovor

    Al₂O₃, because two Al³⁺ ions balance three O²⁻ ions.

  33. Kartica 33

    Pitanje

    How does a particle's mass in atomic mass units relate to its molar mass?

    Odgovor

    The numerical value is the same: a molecular or formula-unit mass of x u corresponds to a molar mass of x g mol^-1.

  34. Kartica 34

    Pitanje

    What does the tallest isotope peak usually indicate in a simple mass spectrum?

    Odgovor

    The most abundant isotope, assuming comparable detection response and singly charged ions.

  35. Kartica 35

    Pitanje

    How much oxygen is present in 25.0 g of a compound that is 32.0% oxygen by mass?

    Odgovor

    8.00 g O. Multiply 25.0 g by 0.320.

  36. Kartica 36

    Pitanje

    What does a particle diagram with two unbonded species in changing ratios represent?

    Odgovor

    A mixture, because more than one particle type is present and the ratio is not fixed in a formula unit.

  37. Kartica 37

    Pitanje

    What distinguishes valence electrons from core electrons?

    Odgovor

    Valence electrons are available for bonding or ion formation; main-group valence electrons occupy the outermost shell, while transition metals may also use (n−1)d electrons. Core electrons mainly shield nuclear charge.

  38. Kartica 38

    Pitanje

    Why can PES peak groups reveal an atom's occupied subshells?

    Odgovor

    Electrons in different subshells require distinct removal energies, producing separate binding-energy groups.

  39. Kartica 39

    Pitanje

    How do ion radii compare with neutral atoms and within an isoelectronic series?

    Odgovor

    Cations are smaller than their neutral atoms, while anions are larger. Among species with the same electron count, more protons pull the electrons closer and produce the smaller radius.

  40. Kartica 40

    Pitanje

    What formula is expected for a compound between a Group 2 metal M and a Group 17 nonmetal X?

    Odgovor

    MX₂, because M forms M²⁺ and X forms X⁻.

  41. Kartica 41

    Pitanje

    When is a covalent bond considered nonpolar?

    Odgovor

    When the bonded atoms have identical or very similar electronegativities, so the shared electron density is distributed approximately evenly.

  42. Kartica 42

    Pitanje

    Why does a bonded pair of atoms have an equilibrium bond length?

    Odgovor

    At that separation, attractive and repulsive interactions balance at minimum potential energy.

  43. Kartica 43

    Pitanje

    How are particles arranged in an ionic solid?

    Odgovor

    Cations and anions occupy a repeating three-dimensional lattice held by electrostatic attraction.

  44. Kartica 44

    Pitanje

    What model explains bonding in a metal?

    Odgovor

    Positive metal cores are held together by attraction to mobile, delocalized valence electrons.

  45. Kartica 45

    Pitanje

    How do you construct a Lewis diagram?

    Odgovor

    Count total valence electrons, adding electrons for a negative charge and subtracting them for a positive charge. Choose a skeleton, connect atoms with single bonds, complete terminal duets or octets, and place remaining electrons on the central atom. Add multiple bonds if needed, then check the electron total and formal charges.

  46. Kartica 46

    Pitanje

    What does resonance mean in a molecule or ion?

    Odgovor

    Resonance uses two or more valid Lewis diagrams with the same atom arrangement but different electron placement. The actual electron distribution is a hybrid; equivalent contributors have equal weight.

  47. Kartica 47

    Pitanje

    What determines molecular shape in VSEPR theory?

    Odgovor

    Electron domains around the central atom arrange to minimize repulsions.

  48. Kartica 48

    Pitanje

    How does an ionic bond differ from a covalent bond?

    Odgovor

    Ionic bonding is attraction among oppositely charged ions in an extended structure; covalent bonding uses shared electron density between atoms.

  49. Kartica 49

    Pitanje

    What happens to potential energy when bonded atoms are pushed much closer than equilibrium?

    Odgovor

    Potential energy rises sharply because nucleus–nucleus and electron–electron repulsions dominate.

  50. Kartica 50

    Pitanje

    Why are many ionic solids brittle?

    Odgovor

    A shifted lattice can align like charges, creating strong repulsion that splits the crystal.

  51. Kartica 51

    Pitanje

    What molecular shapes arise from two electron domains with no lone pairs and from three domains with zero or one lone pair?

    Odgovor

    Two bonding domains give linear with a 180° angle. Three domains with no lone pairs give trigonal planar with 120° angles; replacing one bond with a lone pair gives bent with an angle slightly below 120°.

  52. Kartica 52

    Pitanje

    Why are metals electrically conductive as solids?

    Odgovor

    Their delocalized electrons can move through the solid when an electric field is applied.

  53. Kartica 53

    Pitanje

    How is formal charge calculated for an atom in a Lewis diagram?

    Odgovor

    Formal charge = valence electrons − nonbonding electrons − half the bonding electrons.

  54. Kartica 54

    Pitanje

    Why can't electronegativity difference alone classify a bond as ionic or covalent?

    Odgovor

    Bonding lies on a continuum. A larger difference means more ionic character, but the element types and especially the compound's properties give the best classification.

  55. Kartica 55

    Pitanje

    Which shapes and bond-angle trends arise as lone pairs replace bonds in four electron domains?

    Odgovor

    Four bonds give tetrahedral with ideal 109.5° angles. One lone pair gives trigonal pyramidal with smaller angles; two lone pairs give bent with typically smaller angles again because lone pairs repel more strongly than bonding pairs.

  56. Kartica 56

    Pitanje

    What feature of a potential-energy curve represents bond dissociation energy?

    Odgovor

    The energy difference from the curve's minimum to the separated-atoms limit.

  57. Kartica 57

    Pitanje

    When does an ionic compound conduct electricity?

    Odgovor

    When molten or dissolved so its ions can move; not as a rigid solid lattice.

  58. Kartica 58

    Pitanje

    What is a substitutional alloy?

    Odgovor

    An alloy in which atoms of a similar size replace some host-metal atoms in the lattice.

  59. Kartica 59

    Pitanje

    How do two, three, and four electron domains map to hybridization?

    Odgovor

    Two domains map to sp, three to sp², and four to sp³, with ideal angles of 180°, 120°, and 109.5°. Hybridization involving d orbitals is outside this deck’s scope.

  60. Kartica 60

    Pitanje

    What usually makes one resonance contributor more favorable than another?

    Odgovor

    Smaller formal-charge magnitudes, appropriate negative charge on more electronegative atoms, and complete valence shells where applicable.

  61. Kartica 61

    Pitanje

    How many sigma and pi bonds are in single, double, and triple bonds?

    Odgovor

    A single bond has one sigma bond; a double has one sigma and one pi bond; a triple has one sigma and two pi bonds. Head-on sigma overlap is stronger than side-by-side pi overlap.

  62. Kartica 62

    Pitanje

    Why is a polar covalent bond polar?

    Odgovor

    Unequal electronegativity creates an uneven sharing of electron density and partial charges.

  63. Kartica 63

    Pitanje

    Which molecular shapes arise as lone pairs replace bonds in five electron domains?

    Odgovor

    Five bonds give trigonal bipyramidal; four bonds and one lone pair give seesaw; three bonds and two lone pairs give T-shaped; two bonds and three lone pairs give linear.

  64. Kartica 64

    Pitanje

    How do ionic charge and ionic radius affect attraction between ions?

    Odgovor

    Larger charge magnitudes and smaller ionic radii produce stronger attraction because the charge product increases and the ion centers are closer.

  65. Kartica 65

    Pitanje

    Why do ionic solids often have high melting points?

    Odgovor

    Many strong Coulombic attractions throughout the lattice must be overcome to free the ions.

  66. Kartica 66

    Pitanje

    What is an interstitial alloy?

    Odgovor

    A smaller atom occupies holes between host-metal atoms, often making lattice layers harder to slide.

  67. Kartica 67

    Pitanje

    What shape has six bonding domains and no lone pairs on the central atom?

    Odgovor

    Octahedral.

  68. Kartica 68

    Pitanje

    Which elements commonly form incomplete octets in stable Lewis diagrams?

    Odgovor

    Hydrogen forms a duet, and electron-deficient central atoms such as boron or beryllium can have fewer than eight electrons.

  69. Kartica 69

    Pitanje

    How do bond order and atomic size affect covalent bond length and strength?

    Odgovor

    Within a comparable bond family, higher bond order gives shorter, stronger bonds. Larger bonded atoms generally give longer bonds, which are often weaker because their orbitals overlap less effectively.

  70. Kartica 70

    Pitanje

    What bonding model best fits a sample that is malleable and conducts as a solid?

    Odgovor

    Metallic bonding with mobile, delocalized electrons and nondirectional attractions.

  71. Kartica 71

    Pitanje

    What shape has six electron domains, five bonds, and one lone pair?

    Odgovor

    Square pyramidal.

  72. Kartica 72

    Pitanje

    Which lattice should have stronger attractions: MgO or NaCl, assuming similar separations?

    Odgovor

    MgO, because the charge product for Mg²⁺ and O²⁻ is larger than for Na⁺ and Cl⁻.

  73. Kartica 73

    Pitanje

    Why are pure metals often malleable?

    Odgovor

    Metal cores can shift while the mobile electron sea maintains nondirectional attraction instead of exposing fixed like-charge planes.

  74. Kartica 74

    Pitanje

    What is the best Lewis structure for CO₂?

    Odgovor

    O=C=O, with two lone pairs on each oxygen and no formal charges.

  75. Kartica 75

    Pitanje

    What shape has six electron domains, four bonds, and two opposite lone pairs?

    Odgovor

    Square planar.

  76. Kartica 76

    Pitanje

    What limitation does an odd total number of valence electrons create for a Lewis diagram?

    Odgovor

    At least one electron must remain unpaired, so not every atom can have a complete paired-electron octet.

  77. Kartica 77

    Pitanje

    What does a higher bond order do to a bond's potential-energy curve?

    Odgovor

    It generally places the minimum at a shorter internuclear distance and makes the well deeper, corresponding to a shorter bond and a larger bond-dissociation energy.

  78. Kartica 78

    Pitanje

    When can a carbon–carbon double bond produce geometric isomers?

    Odgovor

    When each carbon has two different substituents. The pi bond restricts rotation, so distinct spatial arrangements can persist.

  79. Kartica 79

    Pitanje

    When may a third-period central atom exceed an octet in a Lewis diagram?

    Odgovor

    When the valid electron count and lower formal charges favor an expanded valence shell, as in species such as SF₆.

  80. Kartica 80

    Pitanje

    How do you decide whether a molecule with polar bonds is polar overall?

    Odgovor

    Add the bond-dipole vectors using the molecular shape; symmetry may cancel them, while an asymmetric arrangement leaves a net dipole.

  81. Kartica 81

    Pitanje

    Which interparticle forces act between all atoms and molecules?

    Odgovor

    London dispersion forces, caused by temporary and induced dipoles.

  82. Kartica 82

    Pitanje

    What four broad solid types does this deck compare?

    Odgovor

    Ionic, metallic, molecular, and covalent-network solids.

  83. Kartica 83

    Pitanje

    How do gas particles differ from liquid particles?

    Odgovor

    Gas particles are much farther apart and move independently; liquid particles stay close but can move past one another.

  84. Kartica 84

    Pitanje

    What relationship connects pressure, volume, amount, and temperature for an ideal gas?

    Odgovor

    PV = nRT, with absolute temperature in kelvins and units consistent with R.

  85. Kartica 85

    Pitanje

    What does temperature measure in kinetic molecular theory?

    Odgovor

    The particles' average translational kinetic energy.

  86. Kartica 86

    Pitanje

    What two ideal-gas assumptions fail most clearly for real gases?

    Odgovor

    Particles have nonzero volume and experience intermolecular attractions.

  87. Kartica 87

    Pitanje

    How is molarity defined?

    Odgovor

    Moles of solute per liter of solution: M = n/V.

  88. Kartica 88

    Pitanje

    What must a correct particulate diagram of NaCl(aq) show?

    Odgovor

    Separated Na⁺ and Cl⁻ ions in a 1:1 ratio, each surrounded by oriented water molecules.

  89. Kartica 89

    Pitanje

    Which separation method removes an insoluble solid from a liquid?

    Odgovor

    Filtration: the solid stays as residue while the liquid passes as filtrate.

  90. Kartica 90

    Pitanje

    What does “like dissolves like” mean at the particle level?

    Odgovor

    A solute tends to dissolve when new solute–solvent attractions can compete with the attractions disrupted in the pure substances.

  91. Kartica 91

    Pitanje

    What happens when matter absorbs electromagnetic radiation?

    Odgovor

    Its particles move to an allowed higher-energy state when the photon energy matches the energy gap.

  92. Kartica 92

    Pitanje

    Which equations connect photon energy, frequency, and wavelength?

    Odgovor

    E = hν and c = λν.

  93. Kartica 93

    Pitanje

    What is the Beer–Lambert law?

    Odgovor

    A = εbc: absorbance equals molar absorptivity at the chosen wavelength times path length times concentration.

  94. Kartica 94

    Pitanje

    What molecular features generally strengthen London dispersion forces?

    Odgovor

    More electrons and a more polarizable cloud strengthen temporary dipoles; greater contact area and accessible π-electron density can also strengthen the attraction.

  95. Kartica 95

    Pitanje

    Why do molecular solids usually have low melting points and fail to conduct electricity?

    Odgovor

    Distinct molecules are held together by relatively weak intermolecular forces, while their valence electrons stay localized in bonds and lone pairs.

  96. Kartica 96

    Pitanje

    How do particles move in a solid?

    Odgovor

    They vibrate about fixed positions and do not translate past one another.

  97. Kartica 97

    Pitanje

    What graph shapes connect V or P with T(K) or n for an ideal gas?

    Odgovor

    All four are straight lines through the origin: V versus T(K) at fixed n and P; P versus T(K) at fixed n and V; V versus n at fixed P and T; and P versus n at fixed V and T.

  98. Kartica 98

    Pitanje

    At the same temperature, which gas has the greater average molecular speed: He or Xe?

    Odgovor

    He. Both have the same average kinetic energy, but KE = ½mv² means the lower-mass particles move faster.

  99. Kartica 99

    Pitanje

    Why do real gases deviate more at high pressure?

    Odgovor

    Particles are crowded, so their own volume is no longer negligible compared with the container volume.

  100. Kartica 100

    Pitanje

    Which relationship describes dilution when solute amount is conserved?

    Odgovor

    M₁V₁ = M₂V₂.

  101. Kartica 101

    Pitanje

    Why does an aqueous ionic solution conduct electricity?

    Odgovor

    Dissolved ions are mobile and carry charge through the solution.

  102. Kartica 102

    Pitanje

    Which property lets simple distillation separate two liquids?

    Odgovor

    A sufficient difference in volatility or boiling point, so the vapor is enriched in the more volatile component.

  103. Kartica 103

    Pitanje

    Why are many ionic compounds soluble in water but poorly soluble in a nonpolar solvent?

    Odgovor

    Water can form strong ion–dipole attractions that stabilize separated ions; a nonpolar solvent cannot provide comparable attractions.

  104. Kartica 104

    Pitanje

    Which molecular transition is commonly associated with microwave absorption?

    Odgovor

    A transition between quantized rotational energy levels.

  105. Kartica 105

    Pitanje

    What frequency corresponds to a 600. nm photon?

    Odgovor

    5.00 × 10^14 s^-1. Use ν = c/λ with 600. nm = 6.00 × 10^-7 m.

  106. Kartica 106

    Pitanje

    What is the absorbance to two significant figures when ε = 2.0 × 10² L mol^-1 cm^-1, b = 1.00 cm, and c = 0.0020 M?

    Odgovor

    0.40. Use A = εbc.

  107. Kartica 107

    Pitanje

    What conditions allow hydrogen bonding between two molecules?

    Odgovor

    One molecule must donate an H covalently bonded to N, O, or F, and the other must provide a lone pair on N, O, or F. A molecule can be a donor, an acceptor, or both.

  108. Kartica 108

    Pitanje

    Why are covalent-network solids often very hard with high melting points?

    Odgovor

    A continuous network of strong covalent bonds must be disrupted to deform or melt the solid.

  109. Kartica 109

    Pitanje

    Why do a substance's solid and liquid phases usually have similar molar volumes?

    Odgovor

    Their particles remain in close contact in both phases, even though liquid particles can move past one another.

  110. Kartica 110

    Pitanje

    How is a gas mixture's total pressure related to its component pressures?

    Odgovor

    Ptotal = ΣPi; each partial pressure is the pressure that component would exert alone in the same volume and temperature.

  111. Kartica 111

    Pitanje

    What microscopic events create gas pressure?

    Odgovor

    Gas particles collide with container walls and transfer momentum.

  112. Kartica 112

    Pitanje

    Why do intermolecular attractions matter more for gases at low temperature?

    Odgovor

    Particles move more slowly, so attractions can alter their paths and promote condensation.

  113. Kartica 113

    Pitanje

    What is the final concentration after 50.0 mL of 2.00 M solution is diluted to 200.0 mL?

    Odgovor

    0.500 M. Use M₂ = M₁V₁/V₂.

  114. Kartica 114

    Pitanje

    What must a particulate representation of a solution communicate?

    Odgovor

    The relative concentrations of its components and the particle-level interactions among those components.

  115. Kartica 115

    Pitanje

    What causes components to separate in chromatography?

    Odgovor

    They differ in attraction to the stationary phase and the mobile phase, so they travel at different rates.

  116. Kartica 116

    Pitanje

    Why are many polar molecular solutes soluble in water?

    Odgovor

    Dipole attractions or hydrogen bonds with water can replace the solute–solute and water–water attractions disrupted during mixing.

  117. Kartica 117

    Pitanje

    Why does an atom produce discrete spectral lines?

    Odgovor

    Its electrons can occupy only quantized energy levels, so only photons matching allowed energy differences are absorbed or emitted.

  118. Kartica 118

    Pitanje

    How does photon energy change when frequency doubles?

    Odgovor

    It doubles because E = hν.

  119. Kartica 119

    Pitanje

    Why is a calibration curve useful in spectrophotometry?

    Odgovor

    It relates measured absorbance to known concentrations, letting an unknown concentration be read by interpolation within the linear range.

  120. Kartica 120

    Pitanje

    How does an ion–dipole attraction form, and how does it compare with dipole–dipole attraction?

    Odgovor

    An ion attracts the oppositely charged end of a polar molecule. Ion–dipole attractions tend to be stronger than dipole–dipole attractions.

  121. Kartica 121

    Pitanje

    Which solid type is usually both conductive and malleable?

    Odgovor

    A metallic solid, because its delocalized electrons move and its nondirectional bonding tolerates layer shifts.

  122. Kartica 122

    Pitanje

    How does a crystalline solid differ from an amorphous solid?

    Odgovor

    A crystalline solid has long-range repeating order; an amorphous solid lacks that long-range periodic arrangement.

  123. Kartica 123

    Pitanje

    How is a gas component's partial pressure found from mole fraction?

    Odgovor

    Pi = XiPtotal.

  124. Kartica 124

    Pitanje

    How does heating a fixed-volume gas affect its pressure in the ideal model?

    Odgovor

    Pressure rises because faster particles collide with the walls more forcefully and frequently.

  125. Kartica 125

    Pitanje

    Why can attractions make a real gas's measured pressure lower than the ideal prediction?

    Odgovor

    Attractions pull approaching particles away from the walls, reducing momentum transfer during wall collisions.

  126. Kartica 126

    Pitanje

    How many moles of ions result from complete dissolution of 0.20 mol CaCl₂?

    Odgovor

    0.60 mol ions: 0.20 mol Ca²⁺ plus 0.40 mol Cl⁻.

  127. Kartica 127

    Pitanje

    How should water orient around Cl⁻ in a particle model?

    Odgovor

    Its partially positive hydrogen ends point toward Cl⁻.

  128. Kartica 128

    Pitanje

    Can filtration separate dissolved components of a liquid solution?

    Odgovor

    No. Dissolved particles pass through the filter with the solvent; filtration only retains an insoluble solid.

  129. Kartica 129

    Pitanje

    Why do nonpolar molecular solutes often dissolve in nonpolar solvents?

    Odgovor

    Both rely mainly on compatible London dispersion forces, so mixing can replace the attractions disrupted in the separate substances.

  130. Kartica 130

    Pitanje

    What does a shorter absorbed wavelength imply about an energy transition?

    Odgovor

    A larger energy gap because E = hc/λ.

  131. Kartica 131

    Pitanje

    What is the energy of a photon with frequency 5.0 × 10^14 s^-1?

    Odgovor

    3.3 × 10^-19 J. Multiply by Planck's constant: E = (6.626 × 10^-34 J·s)(5.0 × 10^14 s^-1).

  132. Kartica 132

    Pitanje

    How does doubling cuvette path length affect absorbance in the linear Beer–Lambert range?

    Odgovor

    Absorbance doubles if concentration and molar absorptivity stay constant.

  133. Kartica 133

    Pitanje

    How can noncovalent interactions affect a large biomolecule?

    Odgovor

    Attractions between molecules or between different regions of the same molecule help set its shape, which strongly affects its properties and function.

  134. Kartica 134

    Pitanje

    Why does an ionic solid usually fail to conduct as a solid?

    Odgovor

    Its ions are fixed in lattice positions. The same substance conducts when molten or dissolved because the ions can then move.

  135. Kartica 135

    Pitanje

    Why does a gas have no definite shape or volume?

    Odgovor

    Its widely spaced particles move constantly and experience minimal interparticle attraction, so they spread through the available container.

  136. Kartica 136

    Pitanje

    What graph shapes show the inverse pressure–volume relationship for a fixed amount of ideal gas at constant temperature?

    Odgovor

    A plot of P against V is a decreasing curve, while P against 1/V is a straight line through the origin.

  137. Kartica 137

    Pitanje

    At the same temperature, do different ideal gases have different average kinetic energies?

    Odgovor

    No. Average translational kinetic energy depends only on absolute temperature.

  138. Kartica 138

    Pitanje

    Under which conditions is ideal-gas behavior most accurate?

    Odgovor

    Low pressure and high temperature, where particles are far apart and attractions matter least.

  139. Kartica 139

    Pitanje

    What particle-level feature distinguishes a solution from a heterogeneous mixture?

    Odgovor

    A solution—whether solid, liquid, or gas—is uniform throughout; a heterogeneous mixture has regions or phases with different compositions.

  140. Kartica 140

    Pitanje

    How should water orient around Na⁺ in a particulate model?

    Odgovor

    Its partially negative oxygen end points toward Na⁺.

  141. Kartica 141

    Pitanje

    In paper chromatography, why does one solute spot travel farther than another?

    Odgovor

    It interacts more strongly with the mobile phase or more weakly with the stationary phase. With known phase polarities, that travel difference can reveal relative solute polarity.

  142. Kartica 142

    Pitanje

    What energy competition helps explain whether an ionic solid dissolves?

    Odgovor

    The energy needed to separate lattice ions competes with the energy released when ion–solvent attractions form.

  143. Kartica 143

    Pitanje

    Which molecular motions commonly absorb infrared radiation?

    Odgovor

    Bond vibrations whose changing dipole can interact with the radiation.

  144. Kartica 144

    Pitanje

    Why must wavelength be converted to meters in c = λν when c is in m s^-1?

    Odgovor

    Consistent units are required so meters cancel correctly and frequency comes out in s^-1.

  145. Kartica 145

    Pitanje

    How can fingerprints on a cuvette affect a visible-light absorbance reading?

    Odgovor

    They can absorb or scatter extra light, making measured absorbance too high and the inferred concentration too high.

  146. Kartica 146

    Pitanje

    What causes and controls the strength of dipole–dipole attractions?

    Odgovor

    Opposite partial charges on neighboring polar molecules attract. Strength increases with larger molecular dipoles and depends on how favorably the dipoles are oriented.

  147. Kartica 147

    Pitanje

    Why is graphite conductive and soft while diamond is insulating and hard?

    Odgovor

    Graphite has delocalized electrons within its sheets, so it conducts, and its layers can slide, so it is soft. Diamond has a rigid three-dimensional network of localized covalent bonds, making it hard and insulating.

  148. Kartica 148

    Pitanje

    Why are gases much more compressible than liquids?

    Odgovor

    Gas particles have large empty spaces between them; liquid particles are already close together.

  149. Kartica 149

    Pitanje

    What volume does 0.500 mol CO₂ occupy at 1.00 atm and 300. K if it behaves ideally?

    Odgovor

    12.3 L. Use V = nRT/P = (0.500 mol)(0.08206 L atm mol^-1 K^-1)(300. K)/(1.00 atm).

  150. Kartica 150

    Pitanje

    Why does a lighter gas effuse faster than a heavier gas at the same temperature?

    Odgovor

    Its particles have a higher average speed because equal average kinetic energy is shared by less mass.

  151. Kartica 151

    Pitanje

    How does finite particle volume affect a real gas at very high pressure?

    Odgovor

    The free volume available for particle motion is smaller than the container volume assumed by the ideal model.

  152. Kartica 152

    Pitanje

    How should 250.0 mL of 0.100 M NaCl be prepared from solid NaCl?

    Odgovor

    Dissolve 0.0250 mol NaCl, or 1.46 g, then dilute to exactly 250.0 mL in a volumetric flask.

  153. Kartica 153

    Pitanje

    What changes in a particle diagram when a solution is diluted without losing solute?

    Odgovor

    The solute-particle count stays constant while solvent volume and particle spacing increase.

  154. Kartica 154

    Pitanje

    Why is fractional distillation better than simple distillation for liquids with close boiling points?

    Odgovor

    Repeated vaporization–condensation steps enrich the vapor in the more volatile component more effectively.

  155. Kartica 155

    Pitanje

    Why are oil and water usually immiscible?

    Odgovor

    Water's strong hydrogen-bond network isn't replaced by equally strong water–oil attractions, so the substances separate into phases.

  156. Kartica 156

    Pitanje

    Which molecular transition is commonly associated with ultraviolet or visible absorption?

    Odgovor

    A transition between electronic energy levels.

  157. Kartica 157

    Pitanje

    Which photon carries more energy, blue light or red light?

    Odgovor

    Blue light, because it has shorter wavelength and higher frequency.

  158. Kartica 158

    Pitanje

    Why is absorbance often measured at the wavelength of maximum absorbance in Beer–Lambert analysis?

    Odgovor

    It gives the largest concentration-sensitive signal, and the flat top near the maximum makes small wavelength-setting errors less influential.

  159. Kartica 159

    Pitanje

    What creates a dipole–induced-dipole attraction, and what controls its strength?

    Odgovor

    A permanent dipole distorts a nearby nonpolar particle's electron cloud and creates an attractive temporary dipole. A larger permanent dipole and a more polarizable nonpolar partner make the attraction stronger.

  160. Kartica 160

    Pitanje

    How do stronger intermolecular forces affect vapor pressure, boiling point, and melting point?

    Odgovor

    They lower vapor pressure and raise boiling point. Melting point often rises too, but the trend is less direct because melting rearranges rather than fully separates particles.

  161. Kartica 161

    Pitanje

    How do particles behave in a liquid?

    Odgovor

    They stay in close contact while moving and colliding continuously. Temperature and interparticle attractions affect their arrangement and motion.

  162. Kartica 162

    Pitanje

    Why must Celsius temperature be converted to kelvins in gas-law calculations?

    Odgovor

    Gas-law proportionalities require an absolute temperature scale whose zero corresponds to zero extrapolated thermal motion.

  163. Kartica 163

    Pitanje

    How does raising temperature change a Maxwell–Boltzmann speed distribution?

    Odgovor

    The distribution broadens, its peak lowers and shifts right, and a larger fraction of particles have high speed.

  164. Kartica 164

    Pitanje

    Why does the ideal-gas model treat collisions as elastic?

    Odgovor

    It assumes total kinetic energy is conserved in particle–particle and particle–wall collisions.

  165. Kartica 165

    Pitanje

    How many moles of solute are in 75.0 mL of a 0.400 M solution?

    Odgovor

    0.0300 mol. Multiply 0.400 mol L^-1 by 0.0750 L.

  166. Kartica 166

    Pitanje

    For equal solution volumes drawn at the same scale, what shows which solution is more concentrated?

    Odgovor

    The more concentrated diagram contains more solute particles in that equal volume.

  167. Kartica 167

    Pitanje

    How do differences in intermolecular attractions let distillation separate a liquid solution?

    Odgovor

    They give the components different vapor pressures, so the vapor is enriched in the more volatile component.

  168. Kartica 168

    Pitanje

    What comparison helps predict whether two liquids will be miscible?

    Odgovor

    Liquids with similar types and strengths of intermolecular attractions are more likely to mix uniformly.

  169. Kartica 169

    Pitanje

    How can an absorption spectrum help identify a substance?

    Odgovor

    Its allowed energy gaps produce a characteristic pattern of absorbed wavelengths that can be compared with known spectra.

  170. Kartica 170

    Pitanje

    How does absorbing or emitting a photon change an atom's or molecule's energy?

    Odgovor

    Absorption raises the species' energy by exactly the photon energy; emission lowers it by the same amount.

  171. Kartica 171

    Pitanje

    What macroscopic evidence can support that a chemical reaction occurred?

    Odgovor

    Evidence can include gas formation, precipitate formation, a persistent color change, or an energy change, interpreted with particle-level changes.

  172. Kartica 172

    Pitanje

    What does a net ionic equation include?

    Odgovor

    Only the dissolved or reacting species that undergo chemical change; spectator ions are omitted.

  173. Kartica 173

    Pitanje

    What must a correct particulate reaction diagram conserve?

    Odgovor

    The number of atoms of every element and the total charge.

  174. Kartica 174

    Pitanje

    What distinguishes a chemical change from a physical change?

    Odgovor

    A chemical change rearranges bonds into new substances; a physical change alters state or arrangement without changing chemical identity.

  175. Kartica 175

    Pitanje

    What does a balanced equation's coefficient ratio provide?

    Odgovor

    The mole ratio among reacting and produced species.

  176. Kartica 176

    Pitanje

    What is the equivalence point of a titration?

    Odgovor

    The point where titrant and analyte have reacted in the stoichiometric ratio given by the balanced equation.

  177. Kartica 177

    Pitanje

    What defines a precipitation reaction?

    Odgovor

    Aqueous ions combine to form a sparingly soluble solid.

  178. Kartica 178

    Pitanje

    What happens in a Brønsted–Lowry acid–base reaction?

    Odgovor

    A proton transfers from the acid (donor) to the base (acceptor). In aqueous solution, H₂O can play either role.

  179. Kartica 179

    Pitanje

    What does oxidation mean in a redox reaction?

    Odgovor

    Loss of electrons and an increase in oxidation number.

  180. Kartica 180

    Pitanje

    What particle-level change confirms that a process is chemical?

    Odgovor

    Atoms rearrange into new combinations, producing substances with different compositions.

  181. Kartica 181

    Pitanje

    Which ions are spectators when AgNO₃(aq) reacts with NaCl(aq)?

    Odgovor

    Na⁺ and NO₃⁻. The net ionic reaction is Ag⁺(aq) + Cl⁻(aq) → AgCl(s).

  182. Kartica 182

    Pitanje

    How does a particulate diagram reveal the limiting reactant?

    Odgovor

    After forming the maximum product allowed by the ratio, none of the limiting reactant remains while excess reactant particles do.

  183. Kartica 183

    Pitanje

    Is melting ice a chemical or physical change?

    Odgovor

    A physical change. H₂O molecules remain H₂O while their arrangement and motion change.

  184. Kartica 184

    Pitanje

    How is the limiting reactant identified from given amounts?

    Odgovor

    Convert each reactant to the same product amount using the balanced equation; the smaller product amount identifies the limiting reactant.

  185. Kartica 185

    Pitanje

    How does an endpoint differ from an equivalence point?

    Odgovor

    The endpoint is an observed signal such as indicator color change; the equivalence point is the exact stoichiometric condition.

  186. Kartica 186

    Pitanje

    How is complete combustion of a hydrocarbon in excess oxygen classified, and what products form?

    Odgovor

    It is a redox combustion reaction that forms CO₂ and H₂O.

  187. Kartica 187

    Pitanje

    What are the conjugate acid and conjugate base in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Odgovor

    NH₄⁺ is the conjugate acid of NH₃, and OH⁻ is the conjugate base of H₂O.

  188. Kartica 188

    Pitanje

    What does reduction mean in a redox reaction?

    Odgovor

    Gain of electrons and a decrease in oxidation number.

  189. Kartica 189

    Pitanje

    Which common changes are physical rather than chemical?

    Odgovor

    Phase changes and the formation or separation of mixtures are physical when each substance keeps its composition.

  190. Kartica 190

    Pitanje

    How are strong soluble electrolytes written in a complete ionic equation?

    Odgovor

    As separated aqueous ions; solids, liquids, gases, and weak electrolytes stay intact.

  191. Kartica 191

    Pitanje

    A diagram starts with six A particles and four B₂ particles for 2A + B₂ → 2AB; what remains after completion?

    Odgovor

    One B₂ remains. Six A consume three B₂ and form six AB.

  192. Kartica 192

    Pitanje

    Why is dissolving NaCl in water normally classified as a physical change?

    Odgovor

    Na⁺ and Cl⁻ separate and become hydrated, but retain their chemical identities. Removing the water recovers NaCl; the shift from ion–ion to ion–dipole attractions does not by itself form a new substance.

  193. Kartica 193

    Pitanje

    What mass of AgCl can form from 25.0 mL of 0.200 M AgNO₃ mixed with excess Cl⁻?

    Odgovor

    0.717 g AgCl. The 1:1 reaction gives 0.00500 mol AgCl; multiply by 143.32 g mol^-1.

  194. Kartica 194

    Pitanje

    What calculation finds unknown analyte moles at equivalence?

    Odgovor

    Use titrant moles, n = MV, then apply the balanced-reaction mole ratio.

  195. Kartica 195

    Pitanje

    Which feature identifies an acid–base, redox, or precipitation reaction?

    Odgovor

    Acid–base reactions transfer protons, redox reactions change oxidation numbers through electron transfer, and precipitation reactions form a sparingly soluble solid.

  196. Kartica 196

    Pitanje

    What is the net ionic equation for strong acid–strong base neutralization?

    Odgovor

    H⁺(aq) + OH⁻(aq) → H₂O(l).

  197. Kartica 197

    Pitanje

    What is the oxidation number of sulfur in SO₄²⁻?

    Odgovor

    +6. Four oxygens contribute -8 total, so sulfur must be +6 to give -2 overall.

  198. Kartica 198

    Pitanje

    Why can gas bubbles alone be ambiguous evidence of reaction?

    Odgovor

    Bubbles may also come from boiling or dissolved gas escaping, so the context and particle identities must support a chemical change.

  199. Kartica 199

    Pitanje

    How is melting ice represented as a balanced physical-change equation?

    Odgovor

    H₂O(s) → H₂O(l). The formula and atom count stay the same because only the physical state changes.

  200. Kartica 200

    Pitanje

    What does a particle diagram show when no reaction occurs after two aqueous ionic solutions mix?

    Odgovor

    All ions remain separated and solvated, with no new bonded particles, precipitate, or gas.

  201. Kartica 201

    Pitanje

    Why is rusting iron a chemical change?

    Odgovor

    Iron atoms form new iron-oxide substances through electron transfer and new bonding.

  202. Kartica 202

    Pitanje

    For 2H₂O₂(aq) → 2H₂O(l) + O₂(g), what volume of O₂ forms from 0.100 mol H₂O₂ at 298 K and 1.00 atm?

    Odgovor

    1.22 L O₂. The mole ratio gives 0.0500 mol O₂, then V = nRT/P.

  203. Kartica 203

    Pitanje

    A 25.0 mL monoprotic acid sample requires 20.0 mL of 0.150 M NaOH; what is the acid concentration?

    Odgovor

    0.120 M. At 1:1 equivalence, moles acid = 0.0200 L × 0.150 M, then divide by 0.0250 L.

  204. Kartica 204

    Pitanje

    Which salts does the minimum solubility rule in this deck treat as soluble?

    Odgovor

    All salts containing Na⁺, K⁺, NH₄⁺, or NO₃⁻ are treated as soluble in water.

  205. Kartica 205

    Pitanje

    How are the strengths of a conjugate acid and its conjugate base related?

    Odgovor

    A stronger acid has a weaker conjugate base, and a stronger base has a weaker conjugate acid.

  206. Kartica 206

    Pitanje

    How are oxidation and reduction half-reactions combined into one balanced equation?

    Odgovor

    Multiply them so electrons lost equal electrons gained, add the half-reactions, then cancel electrons and any identical species on both sides.

  207. Kartica 207

    Pitanje

    How do molecular, complete ionic, and net ionic equations differ?

    Odgovor

    Molecular equations keep compounds intact, complete ionic equations split strong soluble electrolytes, and net ionic equations remove spectators. All three conserve atoms and charge.

  208. Kartica 208

    Pitanje

    How should coefficients change particle counts in a reaction diagram?

    Odgovor

    They set whole-particle ratios while preserving each particle's chemical formula.

  209. Kartica 209

    Pitanje

    Is separating a mixture by distillation a chemical or physical change?

    Odgovor

    A physical change. Components change phase and location but keep their chemical identities.

  210. Kartica 210

    Pitanje

    What equation results from Cu → Cu²⁺ + 2e⁻ and Ag⁺ + e⁻ → Ag?

    Odgovor

    Cu + 2Ag⁺ → Cu²⁺ + 2Ag. Multiply the silver half-reaction by 2 and cancel 2e⁻; both atom counts and net charge then match.

  211. Kartica 211

    Pitanje

    How is average reaction rate found from a reactant concentration?

    Odgovor

    Use the negative concentration change divided by elapsed time, adjusted by its stoichiometric coefficient when comparing species rates.

  212. Kartica 212

    Pitanje

    What does a rate law express?

    Odgovor

    It shows how the measured rate depends on reactant concentrations. In rate = k[A]^m[B]^n, m and n are the orders in A and B, and m + n is the overall order.

  213. Kartica 213

    Pitanje

    A plot of ln[A] versus time is linear; what is the order in A and its integrated rate law?

    Odgovor

    First order: ln[A]t = ln[A]0 − kt, so the plot's slope is −k.

  214. Kartica 214

    Pitanje

    What is an elementary reaction?

    Odgovor

    A single step in a mechanism whose rate law follows directly from its reactant molecularity.

  215. Kartica 215

    Pitanje

    What two collision conditions are needed for reaction?

    Odgovor

    Sufficient collision energy and a productive molecular orientation.

  216. Kartica 216

    Pitanje

    What does activation energy represent on a reaction-energy profile?

    Odgovor

    The energy difference from the reactants to the transition state. The reaction coordinate tracks the step's structural progress, not elapsed time.

  217. Kartica 217

    Pitanje

    What must the elementary steps of a valid mechanism do when added?

    Odgovor

    Cancel intermediates and reproduce the overall balanced reaction.

  218. Kartica 218

    Pitanje

    How is a proposed mechanism tested against kinetics?

    Odgovor

    Its derived rate law must agree with the experimentally measured rate law.

  219. Kartica 219

    Pitanje

    What does a pre-equilibrium approximation assume?

    Odgovor

    A fast reversible step reaches equilibrium before a later slow step consumes its intermediate.

  220. Kartica 220

    Pitanje

    What does each peak on a multistep energy profile represent?

    Odgovor

    A transition state for one elementary step.

  221. Kartica 221

    Pitanje

    How does a catalyst increase reaction rate?

    Odgovor

    It provides an alternate mechanism with a lower activation-energy pathway.

  222. Kartica 222

    Pitanje

    Why does crushing a solid reactant usually increase its reaction rate?

    Odgovor

    Crushing increases exposed surface area, so more reactant particles can collide with the other reactant each second.

  223. Kartica 223

    Pitanje

    How is reaction order found from initial-rate data?

    Odgovor

    Compare trials where one reactant concentration changes while the others stay constant, then match the rate factor to the concentration factor.

  224. Kartica 224

    Pitanje

    A plot of [A] versus time is linear; what is the order in A and its integrated rate law?

    Odgovor

    Zero order: [A]t = [A]0 − kt, so the plot's slope is −k.

  225. Kartica 225

    Pitanje

    What is the rate law for the elementary step 2A + B → products?

    Odgovor

    rate = k[A]²[B]. This inference is valid because the step is elementary.

    Translucent laboratory glassware, particle clusters, and flowing blue-to-amber energy curves on a dark background.

    450 kartica

    AP Chemistry Flashcards: Complete 9-Unit Course Review

    Učite iz ovog špila besplatno

    Nibomo se otvara kako biste mogli početi učiti.

  226. Kartica 226

    Pitanje

    How does raising temperature change a Maxwell–Boltzmann energy distribution and reaction rate?

    Odgovor

    The distribution shifts and broadens toward higher energies, so a larger fraction of collisions exceeds the activation-energy threshold and can react.

  227. Kartica 227

    Pitanje

    How is ΔH read from a reaction-energy profile?

    Odgovor

    ΔH = energy of products − energy of reactants.

  228. Kartica 228

    Pitanje

    What is a reaction intermediate?

    Odgovor

    A species formed in one mechanism step and consumed in a later step, so it cancels from the overall equation.

  229. Kartica 229

    Pitanje

    Why can't overall reaction coefficients usually supply rate-law exponents?

    Odgovor

    The overall equation hides the mechanism; exponents come from experiment unless the reaction is a stated elementary step.

  230. Kartica 230

    Pitanje

    How does pre-equilibrium remove an intermediate from a rate law?

    Odgovor

    Use the fast-step equilibrium relation to express the intermediate concentration in terms of stable reactants.

  231. Kartica 231

    Pitanje

    What does each valley between peaks represent on a multistep profile?

    Odgovor

    A reaction intermediate.

  232. Kartica 232

    Pitanje

    Does a catalyst change ΔH or the equilibrium constant?

    Odgovor

    No. It changes the pathway and rates, not reactant/product energies or the equilibrium composition.

  233. Kartica 233

    Pitanje

    For 2A → B, how are disappearance of A and appearance of B related?

    Odgovor

    Reaction rate = -(1/2)Δ[A]/Δt = Δ[B]/Δt.

  234. Kartica 234

    Pitanje

    How do the units of k depend on a rate law's overall order?

    Odgovor

    They must make the rate unit M s^-1: zero order uses M s^-1, first order s^-1, and second order M^-1 s^-1.

  235. Kartica 235

    Pitanje

    A plot of 1/[A] versus time is linear; what is the order in A and its integrated rate law?

    Odgovor

    Second order: 1/[A]t = 1/[A]0 + kt, so the plot's slope is +k.

  236. Kartica 236

    Pitanje

    What is molecularity?

    Odgovor

    The number of reacting particles in an elementary step, such as unimolecular or bimolecular.

  237. Kartica 237

    Pitanje

    How does raising temperature affect k in the qualitative Arrhenius model?

    Odgovor

    k increases, often sharply, because a larger fraction of collisions can reach the transition state. Arrhenius-equation calculations are outside this deck’s scope.

  238. Kartica 238

    Pitanje

    A reactant falls from 0.80 M to 0.50 M in 30. s; what is its average disappearance rate to two significant figures?

    Odgovor

    0.010 M s^-1. Use -(0.50 − 0.80) M ÷ 30. s.

  239. Kartica 239

    Pitanje

    How does a catalyst differ from an intermediate in a mechanism?

    Odgovor

    A catalyst is consumed early and regenerated later; an intermediate is formed early and consumed later.

  240. Kartica 240

    Pitanje

    For 2NO₂ → NO₃ + NO (slow), followed by NO₃ + CO → NO₂ + CO₂ (fast), what rate law is predicted?

    Odgovor

    rate = k[NO₂]². The first step is elementary and rate-limiting, so its molecularity sets the observed rate law.

  241. Kartica 241

    Pitanje

    On a multistep reaction-energy profile, which feature often identifies the rate-determining step?

    Odgovor

    The step with the largest activation barrier measured from its preceding valley to its peak.

  242. Kartica 242

    Pitanje

    If changing [B] leaves rate unchanged, what is the order in B?

    Odgovor

    Zero order, so [B]^0 = 1 in the measured rate law.

  243. Kartica 243

    Pitanje

    What mechanism changes can binding, acid–base, or surface catalysis introduce?

    Odgovor

    They can orient reactants, lower activation barriers, or create new bound, protonated, or deprotonated intermediates and elementary steps; the catalyst is regenerated.

  244. Kartica 244

    Pitanje

    What is special about a first-order reaction's half-life?

    Odgovor

    It is constant and independent of starting concentration: t1/2 = ln 2/k. Radioactive decay is a common first-order example.

  245. Kartica 245

    Pitanje

    Why is a termolecular elementary collision uncommon?

    Odgovor

    Three particles must collide simultaneously with suitable energy and orientation, which is much less probable than one- or two-particle events.

  246. Kartica 246

    Pitanje

    On a reaction-energy profile, how are reverse activation energy, forward activation energy, and ΔH related?

    Odgovor

    Ea,reverse = Ea,forward − ΔH. The reverse barrier is measured from products to the same transition state.

  247. Kartica 247

    Pitanje

    Why can correct orientation matter even above the activation energy?

    Odgovor

    The colliding reactive sites must align so old bonds can break and new bonds can form along the reaction pathway.

  248. Kartica 248

    Pitanje

    How does detecting a proposed reaction intermediate affect a mechanism claim?

    Odgovor

    It supports a mechanism that contains that intermediate, but it doesn't prove that mechanism is unique.

  249. Kartica 249

    Pitanje

    For 2NO ⇌ N₂O₂ (fast equilibrium), followed by N₂O₂ + O₂ → 2NO₂ (slow), what observed rate law results?

    Odgovor

    rate = kobs[NO]²[O₂]. Start with rate = k₂[N₂O₂][O₂], use [N₂O₂] = K[NO]² from the fast equilibrium, then substitute.

  250. Kartica 250

    Pitanje

    What does the highest point of a one-step energy profile represent?

    Odgovor

    The transition state, an unstable arrangement at the top of the activation barrier.

  251. Kartica 251

    Pitanje

    What sign does q have for an endothermic system?

    Odgovor

    Positive, because the system absorbs heat from the surroundings.

  252. Kartica 252

    Pitanje

    How does an exothermic reaction appear on an enthalpy diagram?

    Odgovor

    Products lie below reactants, so ΔH is negative.

  253. Kartica 253

    Pitanje

    What condition defines thermal equilibrium?

    Odgovor

    Objects in contact have the same temperature, so there is no net heat transfer.

  254. Kartica 254

    Pitanje

    What equations relate heat capacity and temperature change to heat transfer?

    Odgovor

    Use q = mcΔT with specific heat capacity, or q = nCₘΔT with molar heat capacity.

  255. Kartica 255

    Pitanje

    Why is temperature constant during a phase-change plateau?

    Odgovor

    Added or removed energy changes interparticle potential energy instead of average kinetic energy.

  256. Kartica 256

    Pitanje

    What does ΔHrxn describe?

    Odgovor

    The heat absorbed or released at constant pressure for the reaction exactly as written under the stated conditions.

  257. Kartica 257

    Pitanje

    How is reaction enthalpy estimated from average bond enthalpies?

    Odgovor

    ΔHrxn ≈ Σ(bonds broken) − Σ(bonds formed).

  258. Kartica 258

    Pitanje

    What is the standard enthalpy of formation of an element in its standard state?

    Odgovor

    Zero by definition.

  259. Kartica 259

    Pitanje

    In a Hess’s law calculation, how should a step change when the target needs twice its reverse?

    Odgovor

    Reverse the equation, double every coefficient, and multiply its ΔH by -2.

  260. Kartica 260

    Pitanje

    How can energy cross a system boundary during a process?

    Odgovor

    As heat or work. Heat transferred to or work done on the system increases its energy; heat transferred from or work done by the system decreases it.

  261. Kartica 261

    Pitanje

    How does an endothermic reaction appear on an enthalpy diagram?

    Odgovor

    Products lie above reactants, so ΔH is positive.

  262. Kartica 262

    Pitanje

    How are heat gained by a system and heat lost by its surroundings related in an isolated setup?

    Odgovor

    qsystem = -qsurroundings.

  263. Kartica 263

    Pitanje

    In coffee-cup calorimetry, how is reaction heat related to solution heat?

    Odgovor

    qrxn = -qsolution when calorimeter heat is negligible and pressure is constant.

  264. Kartica 264

    Pitanje

    What heat is required to melt n moles at the melting point?

    Odgovor

    q = nΔHfus.

  265. Kartica 265

    Pitanje

    How does reversing a reaction change ΔH?

    Odgovor

    It reverses the sign of ΔH.

  266. Kartica 266

    Pitanje

    Why is breaking a bond endothermic?

    Odgovor

    Energy must be supplied to separate atoms against their bonding attraction.

  267. Kartica 267

    Pitanje

    How is ΔH°rxn calculated from standard enthalpies of formation?

    Odgovor

    ΣνΔHf°(products) − ΣνΔHf°(reactants).

  268. Kartica 268

    Pitanje

    How does multiplying an equation by 3 affect its ΔH?

    Odgovor

    Multiply ΔH by 3 because enthalpy change scales with reaction amount.

  269. Kartica 269

    Pitanje

    Why can an exothermic dissolution warm the solution?

    Odgovor

    The solution warms because forming solute–solvent attractions releases more energy than is absorbed in separating the original particles. The net potential-energy decrease raises particle kinetic energy and temperature.

  270. Kartica 270

    Pitanje

    Does an energy diagram's activation barrier determine ΔH?

    Odgovor

    No. ΔH depends on reactant and product energy levels, while the barrier controls kinetics.

  271. Kartica 271

    Pitanje

    Why does heat flow from a warmer object to a cooler object?

    Odgovor

    Energy transfers through collisions until their average kinetic energies, and therefore temperatures, equalize.

  272. Kartica 272

    Pitanje

    How much heat warms 100.0 g of water by 5.0°C?

    Odgovor

    2.1 kJ. Use q = (100.0 g)(4.184 J g^-1 °C^-1)(5.0°C).

  273. Kartica 273

    Pitanje

    How are the molar enthalpies of a phase change and its reverse related?

    Odgovor

    They have equal magnitudes and opposite signs, such as ΔHcond = -ΔHvap and ΔHfreeze = -ΔHfus.

  274. Kartica 274

    Pitanje

    How does doubling every coefficient in a thermochemical equation affect ΔH?

    Odgovor

    It doubles ΔH.

  275. Kartica 275

    Pitanje

    Why is forming a bond exothermic?

    Odgovor

    Atoms move to a lower-potential-energy bonded arrangement and release energy.

  276. Kartica 276

    Pitanje

    What formation equation defines ΔHf° for CO₂(g)?

    Odgovor

    C(s, graphite) + O₂(g) → CO₂(g), forming exactly one mole from elements in standard states.

  277. Kartica 277

    Pitanje

    What should happen to intermediate species when equations in a Hess’s law calculation are added?

    Odgovor

    They cancel, leaving the target overall reaction.

  278. Kartica 278

    Pitanje

    If the surroundings warm during a process, what is the likely sign of qsystem?

    Odgovor

    Negative; the system likely released heat to the surroundings.

  279. Kartica 279

    Pitanje

    For a profile with reactants at 40 kJ and products at 10 kJ, what is ΔH?

    Odgovor

    -30 kJ for the reaction as drawn.

  280. Kartica 280

    Pitanje

    Assuming no phase change, what determines the final temperature when two substances exchange heat in an insulated container?

    Odgovor

    Energy conservation: q_warm + q_cool = 0. Use each substance's mass, heat capacity, and initial temperature to solve for the common final temperature.

  281. Kartica 281

    Pitanje

    How would heat loss to the room affect an exothermic calorimetry result?

    Odgovor

    The observed temperature rise is too small, so the calculated magnitude of released heat is too low.

  282. Kartica 282

    Pitanje

    What heat expression covers warming a liquid without a phase change?

    Odgovor

    q = mcΔT, not nΔHphase.

  283. Kartica 283

    Pitanje

    If forming 1 mol of product has ΔH = -50 kJ mol^-1, what is q when 2 mol forms?

    Odgovor

    -100 kJ. Use q = nΔH = (2 mol)(-50 kJ mol^-1).

  284. Kartica 284

    Pitanje

    Breaking reactant bonds requires 500 kJ, and forming product bonds releases 650 kJ; what is the estimated ΔH?

    Odgovor

    -150 kJ, from 500 − 650.

  285. Kartica 285

    Pitanje

    For CO(g) + ½O₂(g) → CO₂(g), what is ΔH°rxn if ΔHf°[CO] = -110.5 and ΔHf°[CO₂] = -393.5 kJ mol^-1?

    Odgovor

    -283.0 kJ. Use -393.5 - [-110.5 + ½(0)], since ΔHf°[O₂(g)] = 0.

  286. Kartica 286

    Pitanje

    In a Hess’s law calculation, two valid steps have ΔH values +25 kJ and -60 kJ; what is the combined ΔH?

    Odgovor

    -35 kJ, provided the equations add to the target reaction.

  287. Kartica 287

    Pitanje

    Why is “bonds breaking releases energy” incorrect?

    Odgovor

    Bond breaking absorbs energy; the overall reaction releases energy only when forming new bonds releases more than breaking old bonds requires.

  288. Kartica 288

    Pitanje

    How would melting appear on an energy diagram?

    Odgovor

    The liquid lies above the solid, so ΔHfus is positive; the diagram represents a physical, endothermic change.

  289. Kartica 289

    Pitanje

    Can two objects at the same temperature exchange energy microscopically?

    Odgovor

    Yes, but their energy transfers balance, so there is no net heat flow.

  290. Kartica 290

    Pitanje

    Why must the calorimeter's heat capacity be included when it isn't negligible?

    Odgovor

    The apparatus can absorb or release heat, so include q_cal = C_calΔT in the energy balance: q_process + q_solution + q_cal = 0.

  291. Kartica 291

    Pitanje

    What makes chemical equilibrium dynamic?

    Odgovor

    Forward and reverse reactions continue at equal rates even though macroscopic concentrations stay constant.

  292. Kartica 292

    Pitanje

    For aA + bB ⇌ cC, what is the concentration-form expression for Q?

    Odgovor

    Q = [C]^c / ([A]^a[B]^b), using current rather than necessarily equilibrium concentrations.

  293. Kartica 293

    Pitanje

    What does K much greater than 1 indicate?

    Odgovor

    Products predominate at equilibrium, though K says nothing about reaction speed.

  294. Kartica 294

    Pitanje

    How does reversing a reaction change its equilibrium constant?

    Odgovor

    K becomes 1/K.

  295. Kartica 295

    Pitanje

    Can a reversible system reach equilibrium when it starts with only products?

    Odgovor

    Yes, if the reverse reaction is possible. The equilibrium composition depends on temperature, initial amounts, and volume or pressure.

  296. Kartica 296

    Pitanje

    How do Q and K predict reaction direction?

    Odgovor

    Q < K shifts forward, Q > K shifts reverse, and Q = K means equilibrium.

  297. Kartica 297

    Pitanje

    Which species are omitted from a heterogeneous equilibrium expression?

    Odgovor

    Pure solids and pure liquids because their activities are effectively constant.

  298. Kartica 298

    Pitanje

    How does increasing a dissolved reactant's concentration or a gaseous reactant's partial pressure affect equilibrium at constant temperature when other Q terms are initially unchanged?

    Odgovor

    It lowers Q relative to K, so the system shifts toward products until Q = K again. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that pure phase remains present.

  299. Kartica 299

    Pitanje

    What does a flat concentration-time graph mean at equilibrium?

    Odgovor

    Each concentration is constant, not necessarily equal to the others.

  300. Kartica 300

    Pitanje

    For A ⇌ B in one fixed volume, a particulate model shows 16 A and 0 B initially, then 4 A and 12 B at equilibrium. What changed, what predominates, and what is Kc?

    Odgovor

    The net change was forward: 12 A particles became 12 B particles. B predominates at equilibrium, and Kc = [B]/[A] = 12/4 = 3.0 because both counts come from the same fixed volume.

  301. Kartica 301

    Pitanje

    What can Ksp tell you about a salt's solubility, and when can two Ksp values be compared directly?

    Odgovor

    Ksp > 1 indicates a soluble salt. For salts with the same dissolution stoichiometry, a larger Ksp generally means greater molar solubility; across different stoichiometries, calculate molar solubility before comparing.

  302. Kartica 302

    Pitanje

    What is the common-ion effect on solubility?

    Odgovor

    Adding an ion already in the dissolution equilibrium usually decreases the solid's molar solubility.

  303. Kartica 303

    Pitanje

    How does uniform dilution shift an aqueous equilibrium based on the stoichiometric powers in Q?

    Odgovor

    It shifts toward the side with the larger sum of stoichiometric coefficients for dissolved species included in Q. If the sums are equal, dilution causes no shift by this effect; pure solids and liquids remain omitted.

  304. Kartica 304

    Pitanje

    What happens if a reversible reaction starts with reactants only?

    Odgovor

    The forward rate is initially largest; products form, the reverse rate grows, and the rates eventually become equal.

  305. Kartica 305

    Pitanje

    What is the purpose of an ICE table?

    Odgovor

    To organize initial, change, and equilibrium concentrations using reaction stoichiometry.

  306. Kartica 306

    Pitanje

    Can a reaction with a very large K be slow?

    Odgovor

    Yes. K describes thermodynamic equilibrium position, while rate depends on kinetics and activation energy.

  307. Kartica 307

    Pitanje

    What happens to Q immediately after product concentration increases?

    Odgovor

    Q increases; if it rises above K, the reaction shifts toward reactants.

  308. Kartica 308

    Pitanje

    How does multiplying every reaction coefficient by 2 affect K?

    Odgovor

    The new equilibrium constant is K².

  309. Kartica 309

    Pitanje

    For A ⇌ B, Kc = 4.0 and initially [A] = 1.0 M and [B] = 0, what are the equilibrium concentrations?

    Odgovor

    [A] = 0.20 M and [B] = 0.80 M. Let x form: Kc = x/(1.0 − x) = 4.0, so x = 0.80 M.

  310. Kartica 310

    Pitanje

    What macroscopic properties stay constant at equilibrium?

    Odgovor

    Properties such as concentration, color, and pressure remain constant when external conditions are fixed.

  311. Kartica 311

    Pitanje

    How does decreasing volume shift a gaseous equilibrium?

    Odgovor

    Toward the side with fewer moles of gas, if the two sides have different gaseous mole counts.

  312. Kartica 312

    Pitanje

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kc?

    Odgovor

    Kc = [NH₃]² / ([N₂][H₂]³).

  313. Kartica 313

    Pitanje

    For CaF₂(s) ⇌ Ca²⁺ + 2F⁻, how is Ksp written in terms of molar solubility s in pure water?

    Odgovor

    Ksp = s(2s)² = 4s³ because [Ca²⁺] = s and [F⁻] = 2s.

  314. Kartica 314

    Pitanje

    What does K much less than 1 indicate?

    Odgovor

    Reactants predominate at equilibrium.

  315. Kartica 315

    Pitanje

    How does decreasing a dissolved product's concentration or a gaseous product's partial pressure affect equilibrium when other Q terms are initially unchanged?

    Odgovor

    It lowers Q and drives a net forward reaction until equilibrium returns. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that phase remains.

  316. Kartica 316

    Pitanje

    Does equilibrium mean the reaction has stopped?

    Odgovor

    No. Both directions continue, but equal rates produce no net macroscopic change.

  317. Kartica 317

    Pitanje

    Why does adding NaF reduce CaF₂ solubility?

    Odgovor

    The added F⁻ raises Qsp, shifting the dissolution equilibrium toward solid CaF₂.

  318. Kartica 318

    Pitanje

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kp when P_N₂ = 0.50 atm, P_H₂ = 1.50 atm, and P_NH₃ = 0.25 atm?

    Odgovor

    0.037. Use Kp = (P_NH₃)²/[(P_N₂)(P_H₂)³] = (0.25)²/[(0.50)(1.50)³]. Use equilibrium partial pressures directly; Kc↔Kp conversion isn't assessed.

  319. Kartica 319

    Pitanje

    What happens to Q when a gaseous equilibrium mixture is compressed at constant temperature if products have fewer gas moles?

    Odgovor

    Q falls relative to K, so the reaction shifts toward products.

  320. Kartica 320

    Pitanje

    How do K and Q transform when a reaction is reversed, its coefficients are multiplied, or reactions are added?

    Odgovor

    They follow the same algebra: reversing takes the reciprocal, multiplying every coefficient by c raises the value to the power c, and adding reactions multiplies their K or Q values.

  321. Kartica 321

    Pitanje

    When is the small-x approximation acceptable?

    Odgovor

    When x is small relative to the initial concentration and the final result confirms the neglected change is suitably small.

  322. Kartica 322

    Pitanje

    What graph feature shows a disturbance followed by re-equilibration?

    Odgovor

    A sudden or gradual concentration change followed by new constant plateaus while rates return to equality.

  323. Kartica 323

    Pitanje

    If Q = 0.20 and K = 5.0, which direction is favored next?

    Odgovor

    Forward, because Q < K.

  324. Kartica 324

    Pitanje

    At equilibrium, are reactant and product concentrations equal?

    Odgovor

    Not necessarily. They are constant, while forward and reverse rates are equal.

  325. Kartica 325

    Pitanje

    CaF₂ has Ksp = 3.2 × 10^-11 in pure water; what is its molar solubility?

    Odgovor

    2.0 × 10^-4 M. If the molar solubility is s, then [Ca²⁺] = s, [F⁻] = 2s, and Ksp = 4s³.

  326. Kartica 326

    Pitanje

    For N₂ + 3H₂ ⇌ 2NH₃, how is Qp written?

    Odgovor

    Qp = (P_NH₃)²/[(P_N₂)(P_H₂)³], using the current partial pressures rather than necessarily equilibrium values.

  327. Kartica 327

    Pitanje

    How does heating shift an endothermic forward reaction?

    Odgovor

    Toward products, and K increases because temperature changes the equilibrium constant.

  328. Kartica 328

    Pitanje

    Why do both forward and reverse rates change as equilibrium is approached?

    Odgovor

    As reactant and product concentrations change, the collision frequencies for the two directions change until their rates match.

  329. Kartica 329

    Pitanje

    CaF₂ has Ksp = 3.2 × 10^-11. What is its molar solubility in 0.10 M NaF?

    Odgovor

    About 3.2 × 10^-9 M. With [F⁻] ≈ 0.10 M, Ksp = [Ca²⁺][F⁻]² gives s = (3.2 × 10^-11)/(0.10)². The common ion lowers solubility but does not change Ksp at constant temperature.

  330. Kartica 330

    Pitanje

    What concentration data must be used to calculate Kc?

    Odgovor

    Equilibrium concentrations, each raised to its stoichiometric coefficient and excluding pure solids and liquids.

  331. Kartica 331

    Pitanje

    What is a Brønsted–Lowry acid?

    Odgovor

    A proton donor.

  332. Kartica 332

    Pitanje

    How is pH defined?

    Odgovor

    pH = -log[H₃O⁺].

  333. Kartica 333

    Pitanje

    What is Ka for HA + H₂O ⇌ H₃O⁺ + A⁻?

    Odgovor

    Ka = [H₃O⁺][A⁻]/[HA].

  334. Kartica 334

    Pitanje

    How does stabilizing a base affect its basicity and the strength of its conjugate acid?

    Odgovor

    It makes the base weaker and its conjugate acid stronger. A more stable base is less willing to accept H⁺.

  335. Kartica 335

    Pitanje

    What is a Brønsted–Lowry base?

    Odgovor

    A proton acceptor.

  336. Kartica 336

    Pitanje

    At 25°C, what are Kw and the relationship between pH and pOH?

    Odgovor

    Kw = [H₃O⁺][OH⁻] = 1.0 × 10^-14. Taking negative logarithms gives pH + pOH = 14.00.

  337. Kartica 337

    Pitanje

    What is Kb for B + H₂O ⇌ BH⁺ + OH⁻?

    Odgovor

    Kb = [BH⁺][OH⁻]/[B].

  338. Kartica 338

    Pitanje

    Why can lowering pH increase the solubility of a salt containing a basic anion?

    Odgovor

    H₃O⁺ consumes the anion, pulling the dissolution equilibrium toward more dissolved ions.

  339. Kartica 339

    Pitanje

    What are conjugate acid–base pairs?

    Odgovor

    Species that differ by exactly one proton.

  340. Kartica 340

    Pitanje

    What is the pH of 1.0 × 10^-3 M HCl?

    Odgovor

    3.00, assuming complete dissociation and negligible water contribution.

  341. Kartica 341

    Pitanje

    How are pKa and pKb defined?

    Odgovor

    pKa = -log Ka, and pKb = -log Kb.

  342. Kartica 342

    Pitanje

    Why does acid strength increase across a row of comparable hydrides?

    Odgovor

    Increasing electronegativity stabilizes the conjugate base and polarizes the H–A bond.

  343. Kartica 343

    Pitanje

    What is an amphiprotic species?

    Odgovor

    A species that can donate or accept a proton, such as HCO₃⁻.

  344. Kartica 344

    Pitanje

    What amounts remain after a limited amount of strong base partially neutralizes weak acid HA?

    Odgovor

    Subtract the reacted moles from HA and form the same number of moles of A⁻. The result gives the remaining HA and formed A⁻ amounts before any equilibrium or buffer-pH calculation.

  345. Kartica 345

    Pitanje

    How are Ka, Kb, pKa, and pKb related for a conjugate pair at 25°C?

    Odgovor

    KaKb = Kw = 1.0 × 10^-14, and pKa + pKb = pKw = 14.00.

  346. Kartica 346

    Pitanje

    When does pH have little effect on a salt's solubility?

    Odgovor

    When neither dissolved ion reacts appreciably with H₃O⁺ or OH⁻.

  347. Kartica 347

    Pitanje

    How does H₂O act in HCl + H₂O → H₃O⁺ + Cl⁻ and in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Odgovor

    It acts as a base in the first reaction by accepting H⁺, and as an acid in the second by donating H⁺.

  348. Kartica 348

    Pitanje

    After mixing weak base B with strong acid, what controls the final solution in the three stoichiometric regimes?

    Odgovor

    Excess B leaves a B/BH⁺ buffer; equimolar amounts leave BH⁺, so the solution is acidic; excess strong acid sets the pH from the remaining H₃O⁺.

  349. Kartica 349

    Pitanje

    What two components make a typical weak-acid buffer?

    Odgovor

    A weak acid and a significant amount of its conjugate base.

  350. Kartica 350

    Pitanje

    What do the successive half-equivalence pH values approximate in a diprotic weak-acid titration?

    Odgovor

    The first approximates pKa₁ and the second approximates pKa₂ because each conjugate pair has equal concentrations at its half-equivalence point.

  351. Kartica 351

    Pitanje

    Which acid is stronger, one with pKa 2 or pKa 5?

    Odgovor

    The acid with pKa 2; lower pKa means larger Ka.

  352. Kartica 352

    Pitanje

    What is the Henderson–Hasselbalch equation?

    Odgovor

    pH = pKa + log([A⁻]/[HA]).

  353. Kartica 353

    Pitanje

    Why are larger binary hydrides down a group often stronger acids?

    Odgovor

    The H–A bond becomes weaker as the central atom grows, so proton release is easier.

  354. Kartica 354

    Pitanje

    What mainly determines buffer capacity?

    Odgovor

    The concentrations of both members of the conjugate acid–base pair. Increasing both concentrations at a fixed ratio increases capacity without changing pH; capacity is best balanced for added acid and base when their concentrations are similar.

  355. Kartica 355

    Pitanje

    Why does acid increase CaCO₃ solubility?

    Odgovor

    H₃O⁺ converts CO₃²⁻ to HCO₃⁻ or carbonic acid species, reducing free carbonate and driving more CaCO₃ to dissolve.

  356. Kartica 356

    Pitanje

    What does pH < pKa imply for a weak-acid pair?

    Odgovor

    The protonated form HA predominates over A⁻.

  357. Kartica 357

    Pitanje

    What happens when stoichiometrically equal amounts of a monoprotic weak acid and strong base are mixed?

    Odgovor

    The weak acid is consumed to its conjugate base; at equivalence, the solution isn't a buffer containing both forms.

  358. Kartica 358

    Pitanje

    What is [H₃O⁺] when pH = 4.50?

    Odgovor

    3.2 × 10^-5 M, from [H₃O⁺] = 10^-pH.

  359. Kartica 359

    Pitanje

    What is the pH of 0.010 M Ba(OH)₂ at 25°C?

    Odgovor

    About 12.30. Complete dissociation gives [OH⁻] = 0.020 M, so pOH = 1.70. At 25°C, pH + pOH = 14.00, so pH = 12.30.

  360. Kartica 360

    Pitanje

    How does a buffer respond to a small amount of added strong acid?

    Odgovor

    Its conjugate base consumes H⁺, converting to the weak acid and limiting the pH change.

  361. Kartica 361

    Pitanje

    Why is the equivalence-point solution basic in a monoprotic weak-acid–strong-base titration?

    Odgovor

    The conjugate base produced at equivalence reacts with water to form OH⁻, so the pH is above neutral—above 7.00 at 25°C.

  362. Kartica 362

    Pitanje

    How is percent ionization calculated for a weak acid or weak base?

    Odgovor

    For HA, use ([H₃O⁺]equilibrium ÷ [HA]initial) × 100%. For B, use ([BH⁺]equilibrium ÷ [B]initial) × 100%, under the usual monoprotic setup.

  363. Kartica 363

    Pitanje

    When is Henderson–Hasselbalch useful for an initial buffer-pH calculation?

    Odgovor

    Use it when both members of a conjugate acid–base pair are present in meaningful amounts, including after in-scope stoichiometry creates a buffer. Calculating the pH change after acid or base is added to an existing buffer is outside this deck’s scope.

  364. Kartica 364

    Pitanje

    Why does adding oxygen atoms usually strengthen oxyacids with the same central atom?

    Odgovor

    Extra oxygens withdraw electron density and delocalize negative charge in the conjugate base.

  365. Kartica 365

    Pitanje

    A prepared buffer is accidentally diluted to twice its intended volume; what happens to its pH and capacity?

    Odgovor

    Its pH stays nearly the same, and its capacity per liter is halved because both component concentrations halve. The total neutralizing moles in the sample remain unchanged.

  366. Kartica 366

    Pitanje

    How does adding OH⁻ affect Mg(OH)₂ solubility?

    Odgovor

    It decreases solubility through the common-ion effect, shifting Mg(OH)₂(s) ⇌ Mg²⁺ + 2OH⁻ toward the solid.

  367. Kartica 367

    Pitanje

    A buffer has equal [A⁻] and [HA]; what is its pH?

    Odgovor

    pH = pKa because log(1) = 0.

  368. Kartica 368

    Pitanje

    How should a weak acid–strong base mixture be solved before equivalence?

    Odgovor

    First use mole stoichiometry; if both HA and A⁻ remain, use the resulting buffer relation.

  369. Kartica 369

    Pitanje

    Why can pure neutral water have a pH other than 7.00?

    Odgovor

    Kw changes with temperature. Neutrality means [H₃O⁺] = [OH⁻], while pH = 7.00 only when Kw = 1.0 × 10^-14 at 25°C.

  370. Kartica 370

    Pitanje

    25.0 mL of 0.200 M HCl is diluted to 100.0 mL; what is the pH?

    Odgovor

    1.301. Dilution gives [H₃O⁺] = (0.200 M)(25.0 mL)/(100.0 mL) = 0.0500 M, so pH = -log(0.0500).

  371. Kartica 371

    Pitanje

    How does a buffer respond to a small amount of added strong base?

    Odgovor

    The weak acid consumes OH⁻, forming conjugate base and water.

  372. Kartica 372

    Pitanje

    How do you find the final pH after mixing a strong acid and strong base at 25°C?

    Odgovor

    Use H₃O⁺ + OH⁻ → 2H₂O and compare their moles. Divide excess H₃O⁺ or OH⁻ by the total volume, then calculate pH or pOH from that excess concentration. Equal moles give pH 7.00 at 25°C.

  373. Kartica 373

    Pitanje

    What distinguishes acid strength from acid concentration?

    Odgovor

    Strength is the equilibrium tendency to donate H⁺, reflected by Ka or pKa; concentration is the amount of acid per solution volume.

  374. Kartica 374

    Pitanje

    If [A⁻]/[HA] = 10, how does pH compare with pKa?

    Odgovor

    pH = pKa + 1 because log 10 = 1.

  375. Kartica 375

    Pitanje

    Which conjugate base is more stable, one with localized or resonance-delocalized charge?

    Odgovor

    The resonance-delocalized conjugate base, which generally corresponds to the stronger acid.

  376. Kartica 376

    Pitanje

    Which 1.0 L buffer has greater capacity: 1.0 mol each of HA/A⁻ or 0.10 mol each at the same ratio?

    Odgovor

    The 1.0 mol pair; both have the same initial pH, but the larger amounts neutralize more added acid or base.

  377. Kartica 377

    Pitanje

    For BHX(s) ⇌ BH⁺ + X⁻, why can raising pH increase the salt's solubility?

    Odgovor

    OH⁻ consumes BH⁺ to form B and H₂O, so dissolution shifts right to replace BH⁺. This is a qualitative prediction, not a pH-dependent solubility calculation.

  378. Kartica 378

    Pitanje

    What does pH > pKa imply for a weak-acid pair?

    Odgovor

    The deprotonated form A⁻ predominates over HA.

  379. Kartica 379

    Pitanje

    For HA + B ⇌ A⁻ + BH⁺, which side is favored when pKa(HA) = 4 and pKa(BH⁺) = 9?

    Odgovor

    Products are favored. Proton transfer moves toward the weaker acid–base pair, and K ≈ 10^(9 − 4) = 10^5.

  380. Kartica 380

    Pitanje

    What is the pOH when [OH⁻] = 2.5 × 10^-4 M?

    Odgovor

    3.60, from -log(2.5 × 10^-4).

  381. Kartica 381

    Pitanje

    What is the pH of 0.100 M HA when Ka = 1.0 × 10^-5?

    Odgovor

    About 3.00. The ICE setup gives Ka = x²/(0.100 − x); x ≈ 1.0 × 10^-3 M, and the 1.0% change validates the approximation.

  382. Kartica 382

    Pitanje

    Why does a buffer fail after too much strong acid is added?

    Odgovor

    Its conjugate base is depleted, so added H⁺ is no longer consumed effectively.

  383. Kartica 383

    Pitanje

    What do two clear equivalence regions on an acid titration curve suggest?

    Odgovor

    At least two distinguishable titratable protons; on a clean ideal curve with exactly two equivalence regions, this is consistent with a diprotic acid.

  384. Kartica 384

    Pitanje

    A buffer has pKa 4.8 and [A⁻]/[HA] = 0.10; what is pH?

    Odgovor

    3.8, from 4.8 + log(0.10).

  385. Kartica 385

    Pitanje

    Why is HCl stronger than HF in water despite F being more electronegative?

    Odgovor

    The H–F bond is much stronger; bond strength dominates this down-group binary-acid comparison.

  386. Kartica 386

    Pitanje

    Why does percent ionization increase when a weak acid is diluted?

    Odgovor

    Dilution shifts ionization toward more particles, so a larger fraction ionizes even though [H₃O⁺] decreases.

  387. Kartica 387

    Pitanje

    A buffer contains more HA than A⁻. Which addition can it neutralize in greater amount: strong acid or strong base?

    Odgovor

    Strong base. The larger HA reserve consumes more added OH⁻; a buffer with more A⁻ than HA instead has greater capacity for added strong acid.

  388. Kartica 388

    Pitanje

    Why can removing a basic anion increase a salt's molar solubility without changing Ksp?

    Odgovor

    The equilibrium shifts to replace the consumed ion; Ksp remains fixed at the same temperature.

  389. Kartica 389

    Pitanje

    Why can an acid–base indicator change color as pH changes?

    Odgovor

    Its protonated and deprotonated forms have different colors or other observable properties, and their relative amounts change with pH.

  390. Kartica 390

    Pitanje

    What buffer results from mixing 1.0 mol HA with 0.40 mol OH⁻?

    Odgovor

    0.60 mol HA and 0.40 mol A⁻ remain, forming a buffer before any equilibrium calculation.

  391. Kartica 391

    Pitanje

    What is the pH of 0.200 M weak base B when Kb = 2.0 × 10^-5 at 25°C?

    Odgovor

    About 11.30. The ICE setup gives Kb = x²/(0.200 − x); x ≈ 2.0 × 10^-3 M OH⁻, and the 1.0% change validates the approximation.

  392. Kartica 392

    Pitanje

    Why does a weak acid alone not make an effective buffer?

    Odgovor

    It lacks a substantial conjugate-base reserve to consume added strong acid.

  393. Kartica 393

    Pitanje

    What controls pH after excess strong base passes equivalence?

    Odgovor

    The concentration of excess OH⁻ after accounting for reaction stoichiometry and total volume.

  394. Kartica 394

    Pitanje

    How should an indicator be chosen for a titration?

    Odgovor

    Its color-change range should fall within the steep pH change near the equivalence point.

  395. Kartica 395

    Pitanje

    How can a measured pH and known pKa give a conjugate-base/acid ratio?

    Odgovor

    Rearrange Henderson–Hasselbalch: [A⁻]/[HA] = 10^(pH − pKa).

  396. Kartica 396

    Pitanje

    Can a weak base and its conjugate acid form a buffer?

    Odgovor

    Yes, when both are present in significant amounts.

  397. Kartica 397

    Pitanje

    For equal-volume buffers with the same conjugate-base/acid ratio, how does adding the same amount of strong acid affect a more concentrated versus less concentrated buffer?

    Odgovor

    The concentrated buffer changes pH less because it has greater capacity.

  398. Kartica 398

    Pitanje

    How does equivalence-point pH compare for strong acid–strong base, weak acid–strong base, and weak base–strong acid titrations at 25°C?

    Odgovor

    Strong acid–strong base: pH 7.00. Weak acid–strong base: above 7.00 because the conjugate base reacts with water. Weak base–strong acid: below 7.00 because the conjugate acid reacts with water.

  399. Kartica 399

    Pitanje

    Why should mole ratios replace concentration ratios after mixing buffer solutions?

    Odgovor

    Both components share the same final volume, so that volume cancels in [A⁻]/[HA].

  400. Kartica 400

    Pitanje

    How does adding a little strong acid change a buffer's conjugate-base and conjugate-acid amounts?

    Odgovor

    The conjugate base decreases and its conjugate acid increases by the amount of strong acid consumed.

  401. Kartica 401

    Pitanje

    What does entropy measure qualitatively?

    Odgovor

    The dispersal of matter and energy among available microstates.

  402. Kartica 402

    Pitanje

    How is standard reaction entropy calculated?

    Odgovor

    ΔS°rxn = ΣνS°(products) − ΣνS°(reactants).

  403. Kartica 403

    Pitanje

    What equation gives ΔG° from ΔH° and ΔS°, and what standard states do the degree symbols assume?

    Odgovor

    ΔG° = ΔH° − TΔS°. The standard states are pure substances, 1.0 M solutions, and gases at 1 atm or 1 bar; T is in kelvins and energy units must match.

  404. Kartica 404

    Pitanje

    Does thermodynamic favorability guarantee a fast reaction?

    Odgovor

    No. A favorable reaction can be slow when its activation barrier is large.

  405. Kartica 405

    Pitanje

    What is ΔG at equilibrium?

    Odgovor

    Zero under the current conditions because there is no net driving force.

  406. Kartica 406

    Pitanje

    Why can an endothermic dissolution still be thermodynamically favorable?

    Odgovor

    A sufficiently positive entropy change can make TΔS exceed positive ΔH, giving negative ΔG.

  407. Kartica 407

    Pitanje

    How can an unfavorable reaction be driven by a favorable one?

    Odgovor

    Couple them so their equations and ΔG values add to a negative overall ΔG.

  408. Kartica 408

    Pitanje

    Where does oxidation occur in every electrochemical cell?

    Odgovor

    At the anode.

  409. Kartica 409

    Pitanje

    How are standard cell potential and standard free energy related?

    Odgovor

    ΔG° = -nFE°cell.

  410. Kartica 410

    Pitanje

    What equation gives cell potential under nonstandard conditions?

    Odgovor

    E = E° − (RT/nF) ln Q. When Q = 1, ln Q = 0, so E = E°.

  411. Kartica 411

    Pitanje

    How is electrical charge related to current and time?

    Odgovor

    q = It.

  412. Kartica 412

    Pitanje

    Which phase has greater molar entropy, liquid water or ice at the same temperature?

    Odgovor

    Liquid water because its molecules have more accessible arrangements and motion.

  413. Kartica 413

    Pitanje

    Do elements in their standard states have zero standard molar entropy?

    Odgovor

    No. Their ΔHf° is zero, but their absolute S° values are positive above 0 K.

  414. Kartica 414

    Pitanje

    How do the four ΔH° and ΔS° sign combinations determine thermodynamic favorability across temperature?

    Odgovor

    ΔH° < 0 and ΔS° > 0 is favorable at every temperature; ΔH° > 0 and ΔS° < 0 is thermodynamically unfavored at every temperature. If both are positive, favorability requires high temperature; if both are negative, it requires low temperature.

  415. Kartica 415

    Pitanje

    What does it indicate when a thermodynamically favored process does not occur at a measurable rate?

    Odgovor

    It is under kinetic control, commonly because of a high activation energy; no measurable reaction does not mean the system is at equilibrium.

  416. Kartica 416

    Pitanje

    How are ΔG° and K related?

    Odgovor

    ΔG° = -RT ln K.

  417. Kartica 417

    Pitanje

    What two contributions compete in dissolving an ionic solid?

    Odgovor

    Enthalpy changes from separating and solvating particles, and entropy changes from their new dispersal and solvent organization.

  418. Kartica 418

    Pitanje

    What must cancel when coupled reactions are added?

    Odgovor

    Shared intermediates, leaving the desired net reaction.

  419. Kartica 419

    Pitanje

    Where does reduction occur in every electrochemical cell?

    Odgovor

    At the cathode.

  420. Kartica 420

    Pitanje

    What sign of E°cell indicates a favorable standard galvanic reaction?

    Odgovor

    Positive E°cell, corresponding to negative ΔG°.

  421. Kartica 421

    Pitanje

    If Q increases for a galvanic reaction, how does E change at fixed temperature?

    Odgovor

    E decreases according to the Nernst equation. Le Châtelier's principle does not apply to an operating cell away from equilibrium; use Q and Nernst reasoning instead.

  422. Kartica 422

    Pitanje

    How are moles of electrons found from charge?

    Odgovor

    Moles e⁻ = q/F, where F ≈ 96485 C mol^-1 e⁻.

  423. Kartica 423

    Pitanje

    How does producing more gas particles usually affect system entropy?

    Odgovor

    It increases entropy because the particles have more positional microstates.

  424. Kartica 424

    Pitanje

    Can a dissolution with negative ΔH be unfavorable?

    Odgovor

    Yes. A sufficiently negative entropy change at the stated temperature can make ΔG positive.

  425. Kartica 425

    Pitanje

    When can a process with ΔH > 0 and ΔS > 0 become favorable?

    Odgovor

    At sufficiently high temperature, when TΔS exceeds ΔH.

  426. Kartica 426

    Pitanje

    How does a catalyst affect ΔG?

    Odgovor

    It does not change ΔG; it lowers the activation barrier for both directions.

  427. Kartica 427

    Pitanje

    For A → B, ΔGf°(A) = -50 kJ mol^-1 and ΔGf°(B) = -80 kJ mol^-1. What is ΔG°rxn?

    Odgovor

    -30 kJ mol^-1. Use ΣνΔGf°(products) − ΣνΔGf°(reactants) = -80 − (-50).

  428. Kartica 428

    Pitanje

    Why can dissolving a gas in a liquid have a negative entropy change?

    Odgovor

    Gas particles lose much of their translational freedom when confined and solvated in the liquid.

  429. Kartica 429

    Pitanje

    If coupled steps have ΔG values +20 kJ and -35 kJ, what is overall ΔG?

    Odgovor

    -15 kJ, so the combined process is thermodynamically favorable under those conditions.

  430. Kartica 430

    Pitanje

    What role does each half-cell solution play in an electrochemical cell?

    Odgovor

    It supplies dissolved redox species at an electrode interface and carries ions within its compartment. Separate compartments prevent direct mixing while the external circuit and salt bridge connect the half-cells.

  431. Kartica 431

    Pitanje

    How is E°cell found from standard reduction potentials?

    Odgovor

    E°cell = E°cathode − E°anode, using both tabulated values as reductions.

  432. Kartica 432

    Pitanje

    How does a cell's potential magnitude change as Q approaches or moves away from K, and what is E at equilibrium?

    Odgovor

    |E| falls toward zero as Q approaches K and grows as the system moves farther from equilibrium. At equilibrium, Q = K and E = 0.

  433. Kartica 433

    Pitanje

    How many moles of electrons pass when 1.93 × 10^5 C flows?

    Odgovor

    2.00 mol e⁻, from q/F.

  434. Kartica 434

    Pitanje

    How does a salt bridge maintain charge balance in a galvanic cell?

    Odgovor

    Anions migrate toward the anode compartment and cations toward the cathode compartment, countering the net charge imbalances created by the two half-reactions.

  435. Kartica 435

    Pitanje

    Why does raising a substance's temperature generally increase its entropy?

    Odgovor

    Energy spreads across more accessible particle energy states, increasing the number of possible microscopic arrangements.

  436. Kartica 436

    Pitanje

    When can a process with ΔH < 0 and ΔS < 0 be favorable?

    Odgovor

    At sufficiently low temperature, where the unfavorable -TΔS term is small.

  437. Kartica 437

    Pitanje

    Why can diamond persist even though graphite is more stable at standard conditions?

    Odgovor

    Conversion has a large activation barrier, so diamond is kinetically persistent.

  438. Kartica 438

    Pitanje

    What do the external circuit and measuring device do in an electrochemical cell?

    Odgovor

    The circuit carries electrons from anode to cathode; a voltmeter measures potential difference, while an ammeter in series measures current.

  439. Kartica 439

    Pitanje

    At constant temperature, how does increasing the volume available to a gas affect its entropy?

    Odgovor

    Entropy increases because the gas particles can occupy more positions in the larger space, so more microstates are accessible.

  440. Kartica 440

    Pitanje

    How does reversing one coupled reaction affect its ΔG?

    Odgovor

    It reverses the sign of that reaction's ΔG.

  441. Kartica 441

    Pitanje

    Why is n required in ΔG° = -nFE°?

    Odgovor

    It is the moles of electrons transferred per balanced reaction, linking charge flow to reaction extent.

  442. Kartica 442

    Pitanje

    What makes an electrolytic cell operate?

    Odgovor

    An external power source drives a thermodynamically unfavorable redox reaction; oxidation still occurs at the anode and reduction at the cathode.

  443. Kartica 443

    Pitanje

    In an Mⁿ⁺/M concentration cell, which half-cell is the anode: the dilute or concentrated ion solution?

    Odgovor

    The dilute half-cell. Oxidation produces Mⁿ⁺ there, while reduction consumes Mⁿ⁺ in the concentrated half-cell, so electrons flow from dilute to concentrated as the concentrations move toward equality.

  444. Kartica 444

    Pitanje

    How is deposited metal mass found from current and time?

    Odgovor

    Find q = It, convert q/F to moles e⁻, use the half-reaction ratio to moles metal, then multiply by molar mass.

  445. Kartica 445

    Pitanje

    Given product S° total 500 J mol^-1 K^-1 and reactant total 420 J mol^-1 K^-1, what is ΔS°?

    Odgovor

    +80 J mol^-1 K^-1.

  446. Kartica 446

    Pitanje

    How do electrode masses change in a Zn–Cu galvanic cell?

    Odgovor

    The Zn anode loses mass as Zn → Zn²⁺ + 2e⁻, while the Cu cathode gains mass as Cu²⁺ + 2e⁻ → Cu.

  447. Kartica 447

    Pitanje

    What is ΔG° when ΔH° = 50 kJ mol^-1, ΔS° = 0.200 kJ mol^-1 K^-1, and T = 300 K?

    Odgovor

    -10 kJ mol^-1, from ΔG° = 50 − (300)(0.200).

  448. Kartica 448

    Pitanje

    Why can temperature change a solid's solubility?

    Odgovor

    Temperature changes the balance of ΔH and TΔS, so it changes the free energy of dissolution and the equilibrium constant.

  449. Kartica 449

    Pitanje

    What does the size of ΔG° relative to RT imply about K?

    Odgovor

    ΔG° near zero gives K near 1. When |ΔG°| is much larger than RT, K is far from 1: negative ΔG° gives K ≫ 1, while positive ΔG° gives K ≪ 1.

  450. Kartica 450

    Pitanje

    Bubbles form at an inert cathode in acidic solution; which half-reaction can explain them?

    Odgovor

    2H⁺ + 2e⁻ → H₂(g). Gas evolution at the cathode can be direct evidence of reduction.

Translucent laboratory glassware, particle clusters, and flowing blue-to-amber energy curves on a dark background.

450 kartica

AP Chemistry Flashcards: Complete 9-Unit Course Review

Učite iz ovog špila besplatno

Nibomo se otvara kako biste mogli početi učiti.