AP Chemistry Flashcards: Complete 9-Unit Course Review

Review all nine AP Chemistry units with 450 cards covering concepts, models, equations, calculation setup, and laboratory reasoning.

Informazioni su questo mazzo

Review AP® Chemistry through 450 independently written English flashcards arranged in the course's nine-unit sequence. The deck moves from atomic structure and compound structure through properties of substances and mixtures, reactions, kinetics, thermochemistry, equilibrium, acids and bases, and thermodynamics and electrochemistry. Prerequisites come before dependent models and calculations.

What the cards practice

The cards use five recall paths: concept to explanation; model or representation to interpretation; equation to meaning and use; short setup to a result with units and reasoning; and laboratory observation to a chemical conclusion. They cover definitions, relationships, conditions, contrasts, particle and energy models, focused calculation steps, measurements, errors, and visible changes.

Selected reverse and contrast prompts appear only when the reverse direction has one clear standalone target. The deck excludes mechanical permutations, graph-dependent prompts that require a missing figure, copied test formats, long multipart derivations, and visual recall tied to third-party figures. The review scheduler handles long-term spacing after installation.

See the official AP Chemistry course page for College Board's current course requirements.

The Common knowledge · CC0 1.0 label applies only to the independently written prompts, answers, examples, organization, metadata, and inherited original cover, to the extent applicable rights exist. It does not claim ownership of scientific facts or equations.

This is an independent, unofficial study aid. It is not affiliated with, endorsed by, sponsored by, or official material from College Board or the AP Program. AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this product. No College Board examination questions, answer choices, scoring materials, curriculum text, logos, or trade dress were copied.

Carte in questo mazzo

  1. Carta 1

    Domanda

    What does one mole count?

    Risposta

    Exactly 6.02214076 × 10^23 representative particles.

  2. Carta 2

    Domanda

    What does a peak in an element's mass spectrum represent?

    Risposta

    An isotope with a particular mass-to-charge ratio; for singly charged monatomic ions, the position tracks isotopic mass.

  3. Carta 3

    Domanda

    What does an empirical formula show?

    Risposta

    The lowest whole-number ratio of the elements' atoms in a compound.

  4. Carta 4

    Domanda

    How does a mixture differ from a pure substance at the particle level?

    Risposta

    A mixture contains chemically distinct representative units in variable proportions; a pure substance contains one element or compound with fixed composition. Different isotopes do not make an elemental sample a mixture.

  5. Carta 5

    Domanda

    Which particles make up an atom's nucleus?

    Risposta

    Protons and neutrons. Electrons occupy the space outside the nucleus.

  6. Carta 6

    Domanda

    What does a larger binding energy on a PES spectrum mean?

    Risposta

    More energy is required to remove that electron, so it is held more strongly by the nucleus.

  7. Carta 7

    Domanda

    How does atomic radius generally change across a period and down a group?

    Risposta

    It decreases from left to right as effective nuclear charge rises, and it increases down a group as additional electron shells increase distance and shielding.

  8. Carta 8

    Domanda

    What typical ion charge do Group 1 metals form?

    Risposta

    +1, by losing their one valence electron.

  9. Carta 9

    Domanda

    How do you convert moles to particles?

    Risposta

    Multiply by Avogadro's number: particles = moles × 6.022 × 10^23 mol^-1.

  10. Carta 10

    Domanda

    How is average atomic mass estimated from isotope data?

    Risposta

    Add each isotopic mass multiplied by its fractional abundance.

  11. Carta 11

    Domanda

    How is an element's mass percent in a compound calculated?

    Risposta

    Divide the mass contributed by that element by the compound's molar mass, then multiply by 100%.

  12. Carta 12

    Domanda

    How can measured elemental composition reveal a sample's purity?

    Risposta

    Compare the measured mass fraction with the fraction expected for the pure compound; a mismatch indicates another component.

  13. Carta 13

    Domanda

    How do you build a ground-state electron configuration with the Aufbau principle?

    Risposta

    For ordinary ground states, move through the periodic table in atomic-number order, filling each s, p, d, or f block as it appears. The subshell capacities are s², p⁶, d¹⁰, and f¹⁴. For example, Br is [Ar] 4s² 3d¹⁰ 4p⁵.

  14. Carta 14

    Domanda

    What does the relative area or height of an ideal PES peak indicate?

    Risposta

    The relative number of electrons in the corresponding subshell.

  15. Carta 15

    Domanda

    How does first ionization energy generally change across a period and down a group?

    Risposta

    It increases from left to right as effective nuclear charge rises, and it decreases down a group as distance and shielding make a valence electron easier to remove.

  16. Carta 16

    Domanda

    Why do elements in the same group form similar compounds?

    Risposta

    Their ground-state valence patterns repeat, including which outer subshells are full or partly full. That leads to similar bonding and typical ion charges.

  17. Carta 17

    Domanda

    How do you convert a sample's mass to moles?

    Risposta

    Divide its mass by its molar mass: n = m/M.

  18. Carta 18

    Domanda

    Which mass-spectrum interpretation lies outside the usual single-element model used in this deck?

    Risposta

    Assigning peaks in mixtures or peaks from multiply charged or polyatomic species; the standard model uses singly charged monatomic ions of one element.

  19. Carta 19

    Domanda

    What does the law of definite proportions state?

    Risposta

    Every pure sample of a given compound has the same element mass ratios.

  20. Carta 20

    Domanda

    Why can two samples of the same mixture have different compositions?

    Risposta

    Mixture components are physically combined, so their relative amounts are not fixed by a chemical formula.

  21. Carta 21

    Domanda

    How does Coulomb's law connect charge and separation to attraction?

    Risposta

    Attraction grows with the magnitude of the charge product and decreases with the square of the separation distance.

  22. Carta 22

    Domanda

    Which PES electrons usually appear at the highest binding energy?

    Risposta

    Core electrons closest to the nucleus, because they feel the strongest nuclear attraction.

  23. Carta 23

    Domanda

    How does electron affinity generally change across a period and down a group?

    Risposta

    Electron gain generally becomes more favorable from left to right across a period and less favorable down a group as distance and shielding increase. Stable subshell patterns create substantial exceptions.

  24. Carta 24

    Domanda

    Why are alkali metals generally more reactive down the group?

    Risposta

    Their valence electron is farther from the nucleus and easier to remove.

  25. Carta 25

    Domanda

    How many moles are in 18.0 g of H₂O?

    Risposta

    About 0.999 mol. Use 18.0 g ÷ 18.02 g mol^-1.

  26. Carta 26

    Domanda

    An element is 75% isotope 10 and 25% isotope 11; what is its average atomic mass?

    Risposta

    10.25 u. Calculate (0.75 × 10) + (0.25 × 11).

  27. Carta 27

    Domanda

    A compound is 40.0% C, 6.7% H, and 53.3% O by mass; what is its empirical formula?

    Risposta

    CH₂O. For a 100 g sample, convert each mass to moles and divide by the smallest amount.

  28. Carta 28

    Domanda

    A 10.0 g impure sample contains 8.5 g of the target compound; what is its mass-percent purity?

    Risposta

    85%. Calculate (8.5 g ÷ 10.0 g) × 100%.

  29. Carta 29

    Domanda

    Which electrons are removed first when a transition metal forms a cation?

    Risposta

    Electrons in the occupied orbital with the highest principal quantum number: 4s before 3d. For example, Fe²⁺ is [Ar] 3d⁶.

  30. Carta 30

    Domanda

    A PES spectrum has peaks proportional to 2, 2, and 6 electrons; which configuration fits?

    Risposta

    1s² 2s² 2p⁶, the configuration of Ne.

  31. Carta 31

    Domanda

    How does electronegativity generally change across a period and down a group?

    Risposta

    It increases from left to right across a period and decreases down a group as atomic size and shielding increase.

  32. Carta 32

    Domanda

    What empirical formula results from Al³⁺ and O²⁻?

    Risposta

    Al₂O₃, because two Al³⁺ ions balance three O²⁻ ions.

  33. Carta 33

    Domanda

    How does a particle's mass in atomic mass units relate to its molar mass?

    Risposta

    The numerical value is the same: a molecular or formula-unit mass of x u corresponds to a molar mass of x g mol^-1.

  34. Carta 34

    Domanda

    What does the tallest isotope peak usually indicate in a simple mass spectrum?

    Risposta

    The most abundant isotope, assuming comparable detection response and singly charged ions.

  35. Carta 35

    Domanda

    How much oxygen is present in 25.0 g of a compound that is 32.0% oxygen by mass?

    Risposta

    8.00 g O. Multiply 25.0 g by 0.320.

  36. Carta 36

    Domanda

    What does a particle diagram with two unbonded species in changing ratios represent?

    Risposta

    A mixture, because more than one particle type is present and the ratio is not fixed in a formula unit.

  37. Carta 37

    Domanda

    What distinguishes valence electrons from core electrons?

    Risposta

    Valence electrons are available for bonding or ion formation; main-group valence electrons occupy the outermost shell, while transition metals may also use (n−1)d electrons. Core electrons mainly shield nuclear charge.

  38. Carta 38

    Domanda

    Why can PES peak groups reveal an atom's occupied subshells?

    Risposta

    Electrons in different subshells require distinct removal energies, producing separate binding-energy groups.

  39. Carta 39

    Domanda

    How do ion radii compare with neutral atoms and within an isoelectronic series?

    Risposta

    Cations are smaller than their neutral atoms, while anions are larger. Among species with the same electron count, more protons pull the electrons closer and produce the smaller radius.

  40. Carta 40

    Domanda

    What formula is expected for a compound between a Group 2 metal M and a Group 17 nonmetal X?

    Risposta

    MX₂, because M forms M²⁺ and X forms X⁻.

  41. Carta 41

    Domanda

    When is a covalent bond considered nonpolar?

    Risposta

    When the bonded atoms have identical or very similar electronegativities, so the shared electron density is distributed approximately evenly.

  42. Carta 42

    Domanda

    Why does a bonded pair of atoms have an equilibrium bond length?

    Risposta

    At that separation, attractive and repulsive interactions balance at minimum potential energy.

  43. Carta 43

    Domanda

    How are particles arranged in an ionic solid?

    Risposta

    Cations and anions occupy a repeating three-dimensional lattice held by electrostatic attraction.

  44. Carta 44

    Domanda

    What model explains bonding in a metal?

    Risposta

    Positive metal cores are held together by attraction to mobile, delocalized valence electrons.

  45. Carta 45

    Domanda

    How do you construct a Lewis diagram?

    Risposta

    Count total valence electrons, adding electrons for a negative charge and subtracting them for a positive charge. Choose a skeleton, connect atoms with single bonds, complete terminal duets or octets, and place remaining electrons on the central atom. Add multiple bonds if needed, then check the electron total and formal charges.

  46. Carta 46

    Domanda

    What does resonance mean in a molecule or ion?

    Risposta

    Resonance uses two or more valid Lewis diagrams with the same atom arrangement but different electron placement. The actual electron distribution is a hybrid; equivalent contributors have equal weight.

  47. Carta 47

    Domanda

    What determines molecular shape in VSEPR theory?

    Risposta

    Electron domains around the central atom arrange to minimize repulsions.

  48. Carta 48

    Domanda

    How does an ionic bond differ from a covalent bond?

    Risposta

    Ionic bonding is attraction among oppositely charged ions in an extended structure; covalent bonding uses shared electron density between atoms.

  49. Carta 49

    Domanda

    What happens to potential energy when bonded atoms are pushed much closer than equilibrium?

    Risposta

    Potential energy rises sharply because nucleus–nucleus and electron–electron repulsions dominate.

  50. Carta 50

    Domanda

    Why are many ionic solids brittle?

    Risposta

    A shifted lattice can align like charges, creating strong repulsion that splits the crystal.

  51. Carta 51

    Domanda

    What molecular shapes arise from two electron domains with no lone pairs and from three domains with zero or one lone pair?

    Risposta

    Two bonding domains give linear with a 180° angle. Three domains with no lone pairs give trigonal planar with 120° angles; replacing one bond with a lone pair gives bent with an angle slightly below 120°.

  52. Carta 52

    Domanda

    Why are metals electrically conductive as solids?

    Risposta

    Their delocalized electrons can move through the solid when an electric field is applied.

  53. Carta 53

    Domanda

    How is formal charge calculated for an atom in a Lewis diagram?

    Risposta

    Formal charge = valence electrons − nonbonding electrons − half the bonding electrons.

  54. Carta 54

    Domanda

    Why can't electronegativity difference alone classify a bond as ionic or covalent?

    Risposta

    Bonding lies on a continuum. A larger difference means more ionic character, but the element types and especially the compound's properties give the best classification.

  55. Carta 55

    Domanda

    Which shapes and bond-angle trends arise as lone pairs replace bonds in four electron domains?

    Risposta

    Four bonds give tetrahedral with ideal 109.5° angles. One lone pair gives trigonal pyramidal with smaller angles; two lone pairs give bent with typically smaller angles again because lone pairs repel more strongly than bonding pairs.

  56. Carta 56

    Domanda

    What feature of a potential-energy curve represents bond dissociation energy?

    Risposta

    The energy difference from the curve's minimum to the separated-atoms limit.

  57. Carta 57

    Domanda

    When does an ionic compound conduct electricity?

    Risposta

    When molten or dissolved so its ions can move; not as a rigid solid lattice.

  58. Carta 58

    Domanda

    What is a substitutional alloy?

    Risposta

    An alloy in which atoms of a similar size replace some host-metal atoms in the lattice.

  59. Carta 59

    Domanda

    How do two, three, and four electron domains map to hybridization?

    Risposta

    Two domains map to sp, three to sp², and four to sp³, with ideal angles of 180°, 120°, and 109.5°. Hybridization involving d orbitals is outside this deck’s scope.

  60. Carta 60

    Domanda

    What usually makes one resonance contributor more favorable than another?

    Risposta

    Smaller formal-charge magnitudes, appropriate negative charge on more electronegative atoms, and complete valence shells where applicable.

  61. Carta 61

    Domanda

    How many sigma and pi bonds are in single, double, and triple bonds?

    Risposta

    A single bond has one sigma bond; a double has one sigma and one pi bond; a triple has one sigma and two pi bonds. Head-on sigma overlap is stronger than side-by-side pi overlap.

  62. Carta 62

    Domanda

    Why is a polar covalent bond polar?

    Risposta

    Unequal electronegativity creates an uneven sharing of electron density and partial charges.

  63. Carta 63

    Domanda

    Which molecular shapes arise as lone pairs replace bonds in five electron domains?

    Risposta

    Five bonds give trigonal bipyramidal; four bonds and one lone pair give seesaw; three bonds and two lone pairs give T-shaped; two bonds and three lone pairs give linear.

  64. Carta 64

    Domanda

    How do ionic charge and ionic radius affect attraction between ions?

    Risposta

    Larger charge magnitudes and smaller ionic radii produce stronger attraction because the charge product increases and the ion centers are closer.

  65. Carta 65

    Domanda

    Why do ionic solids often have high melting points?

    Risposta

    Many strong Coulombic attractions throughout the lattice must be overcome to free the ions.

  66. Carta 66

    Domanda

    What is an interstitial alloy?

    Risposta

    A smaller atom occupies holes between host-metal atoms, often making lattice layers harder to slide.

  67. Carta 67

    Domanda

    What shape has six bonding domains and no lone pairs on the central atom?

    Risposta

    Octahedral.

  68. Carta 68

    Domanda

    Which elements commonly form incomplete octets in stable Lewis diagrams?

    Risposta

    Hydrogen forms a duet, and electron-deficient central atoms such as boron or beryllium can have fewer than eight electrons.

  69. Carta 69

    Domanda

    How do bond order and atomic size affect covalent bond length and strength?

    Risposta

    Within a comparable bond family, higher bond order gives shorter, stronger bonds. Larger bonded atoms generally give longer bonds, which are often weaker because their orbitals overlap less effectively.

  70. Carta 70

    Domanda

    What bonding model best fits a sample that is malleable and conducts as a solid?

    Risposta

    Metallic bonding with mobile, delocalized electrons and nondirectional attractions.

  71. Carta 71

    Domanda

    What shape has six electron domains, five bonds, and one lone pair?

    Risposta

    Square pyramidal.

  72. Carta 72

    Domanda

    Which lattice should have stronger attractions: MgO or NaCl, assuming similar separations?

    Risposta

    MgO, because the charge product for Mg²⁺ and O²⁻ is larger than for Na⁺ and Cl⁻.

  73. Carta 73

    Domanda

    Why are pure metals often malleable?

    Risposta

    Metal cores can shift while the mobile electron sea maintains nondirectional attraction instead of exposing fixed like-charge planes.

  74. Carta 74

    Domanda

    What is the best Lewis structure for CO₂?

    Risposta

    O=C=O, with two lone pairs on each oxygen and no formal charges.

  75. Carta 75

    Domanda

    What shape has six electron domains, four bonds, and two opposite lone pairs?

    Risposta

    Square planar.

  76. Carta 76

    Domanda

    What limitation does an odd total number of valence electrons create for a Lewis diagram?

    Risposta

    At least one electron must remain unpaired, so not every atom can have a complete paired-electron octet.

  77. Carta 77

    Domanda

    What does a higher bond order do to a bond's potential-energy curve?

    Risposta

    It generally places the minimum at a shorter internuclear distance and makes the well deeper, corresponding to a shorter bond and a larger bond-dissociation energy.

  78. Carta 78

    Domanda

    When can a carbon–carbon double bond produce geometric isomers?

    Risposta

    When each carbon has two different substituents. The pi bond restricts rotation, so distinct spatial arrangements can persist.

  79. Carta 79

    Domanda

    When may a third-period central atom exceed an octet in a Lewis diagram?

    Risposta

    When the valid electron count and lower formal charges favor an expanded valence shell, as in species such as SF₆.

  80. Carta 80

    Domanda

    How do you decide whether a molecule with polar bonds is polar overall?

    Risposta

    Add the bond-dipole vectors using the molecular shape; symmetry may cancel them, while an asymmetric arrangement leaves a net dipole.

  81. Carta 81

    Domanda

    Which interparticle forces act between all atoms and molecules?

    Risposta

    London dispersion forces, caused by temporary and induced dipoles.

  82. Carta 82

    Domanda

    What four broad solid types does this deck compare?

    Risposta

    Ionic, metallic, molecular, and covalent-network solids.

  83. Carta 83

    Domanda

    How do gas particles differ from liquid particles?

    Risposta

    Gas particles are much farther apart and move independently; liquid particles stay close but can move past one another.

  84. Carta 84

    Domanda

    What relationship connects pressure, volume, amount, and temperature for an ideal gas?

    Risposta

    PV = nRT, with absolute temperature in kelvins and units consistent with R.

  85. Carta 85

    Domanda

    What does temperature measure in kinetic molecular theory?

    Risposta

    The particles' average translational kinetic energy.

  86. Carta 86

    Domanda

    What two ideal-gas assumptions fail most clearly for real gases?

    Risposta

    Particles have nonzero volume and experience intermolecular attractions.

  87. Carta 87

    Domanda

    How is molarity defined?

    Risposta

    Moles of solute per liter of solution: M = n/V.

  88. Carta 88

    Domanda

    What must a correct particulate diagram of NaCl(aq) show?

    Risposta

    Separated Na⁺ and Cl⁻ ions in a 1:1 ratio, each surrounded by oriented water molecules.

  89. Carta 89

    Domanda

    Which separation method removes an insoluble solid from a liquid?

    Risposta

    Filtration: the solid stays as residue while the liquid passes as filtrate.

  90. Carta 90

    Domanda

    What does “like dissolves like” mean at the particle level?

    Risposta

    A solute tends to dissolve when new solute–solvent attractions can compete with the attractions disrupted in the pure substances.

  91. Carta 91

    Domanda

    What happens when matter absorbs electromagnetic radiation?

    Risposta

    Its particles move to an allowed higher-energy state when the photon energy matches the energy gap.

  92. Carta 92

    Domanda

    Which equations connect photon energy, frequency, and wavelength?

    Risposta

    E = hν and c = λν.

  93. Carta 93

    Domanda

    What is the Beer–Lambert law?

    Risposta

    A = εbc: absorbance equals molar absorptivity at the chosen wavelength times path length times concentration.

  94. Carta 94

    Domanda

    What molecular features generally strengthen London dispersion forces?

    Risposta

    More electrons and a more polarizable cloud strengthen temporary dipoles; greater contact area and accessible π-electron density can also strengthen the attraction.

  95. Carta 95

    Domanda

    Why do molecular solids usually have low melting points and fail to conduct electricity?

    Risposta

    Distinct molecules are held together by relatively weak intermolecular forces, while their valence electrons stay localized in bonds and lone pairs.

  96. Carta 96

    Domanda

    How do particles move in a solid?

    Risposta

    They vibrate about fixed positions and do not translate past one another.

  97. Carta 97

    Domanda

    What graph shapes connect V or P with T(K) or n for an ideal gas?

    Risposta

    All four are straight lines through the origin: V versus T(K) at fixed n and P; P versus T(K) at fixed n and V; V versus n at fixed P and T; and P versus n at fixed V and T.

  98. Carta 98

    Domanda

    At the same temperature, which gas has the greater average molecular speed: He or Xe?

    Risposta

    He. Both have the same average kinetic energy, but KE = ½mv² means the lower-mass particles move faster.

  99. Carta 99

    Domanda

    Why do real gases deviate more at high pressure?

    Risposta

    Particles are crowded, so their own volume is no longer negligible compared with the container volume.

  100. Carta 100

    Domanda

    Which relationship describes dilution when solute amount is conserved?

    Risposta

    M₁V₁ = M₂V₂.

  101. Carta 101

    Domanda

    Why does an aqueous ionic solution conduct electricity?

    Risposta

    Dissolved ions are mobile and carry charge through the solution.

  102. Carta 102

    Domanda

    Which property lets simple distillation separate two liquids?

    Risposta

    A sufficient difference in volatility or boiling point, so the vapor is enriched in the more volatile component.

  103. Carta 103

    Domanda

    Why are many ionic compounds soluble in water but poorly soluble in a nonpolar solvent?

    Risposta

    Water can form strong ion–dipole attractions that stabilize separated ions; a nonpolar solvent cannot provide comparable attractions.

  104. Carta 104

    Domanda

    Which molecular transition is commonly associated with microwave absorption?

    Risposta

    A transition between quantized rotational energy levels.

  105. Carta 105

    Domanda

    What frequency corresponds to a 600. nm photon?

    Risposta

    5.00 × 10^14 s^-1. Use ν = c/λ with 600. nm = 6.00 × 10^-7 m.

  106. Carta 106

    Domanda

    What is the absorbance to two significant figures when ε = 2.0 × 10² L mol^-1 cm^-1, b = 1.00 cm, and c = 0.0020 M?

    Risposta

    0.40. Use A = εbc.

  107. Carta 107

    Domanda

    What conditions allow hydrogen bonding between two molecules?

    Risposta

    One molecule must donate an H covalently bonded to N, O, or F, and the other must provide a lone pair on N, O, or F. A molecule can be a donor, an acceptor, or both.

  108. Carta 108

    Domanda

    Why are covalent-network solids often very hard with high melting points?

    Risposta

    A continuous network of strong covalent bonds must be disrupted to deform or melt the solid.

  109. Carta 109

    Domanda

    Why do a substance's solid and liquid phases usually have similar molar volumes?

    Risposta

    Their particles remain in close contact in both phases, even though liquid particles can move past one another.

  110. Carta 110

    Domanda

    How is a gas mixture's total pressure related to its component pressures?

    Risposta

    Ptotal = ΣPi; each partial pressure is the pressure that component would exert alone in the same volume and temperature.

  111. Carta 111

    Domanda

    What microscopic events create gas pressure?

    Risposta

    Gas particles collide with container walls and transfer momentum.

  112. Carta 112

    Domanda

    Why do intermolecular attractions matter more for gases at low temperature?

    Risposta

    Particles move more slowly, so attractions can alter their paths and promote condensation.

  113. Carta 113

    Domanda

    What is the final concentration after 50.0 mL of 2.00 M solution is diluted to 200.0 mL?

    Risposta

    0.500 M. Use M₂ = M₁V₁/V₂.

  114. Carta 114

    Domanda

    What must a particulate representation of a solution communicate?

    Risposta

    The relative concentrations of its components and the particle-level interactions among those components.

  115. Carta 115

    Domanda

    What causes components to separate in chromatography?

    Risposta

    They differ in attraction to the stationary phase and the mobile phase, so they travel at different rates.

  116. Carta 116

    Domanda

    Why are many polar molecular solutes soluble in water?

    Risposta

    Dipole attractions or hydrogen bonds with water can replace the solute–solute and water–water attractions disrupted during mixing.

  117. Carta 117

    Domanda

    Why does an atom produce discrete spectral lines?

    Risposta

    Its electrons can occupy only quantized energy levels, so only photons matching allowed energy differences are absorbed or emitted.

  118. Carta 118

    Domanda

    How does photon energy change when frequency doubles?

    Risposta

    It doubles because E = hν.

  119. Carta 119

    Domanda

    Why is a calibration curve useful in spectrophotometry?

    Risposta

    It relates measured absorbance to known concentrations, letting an unknown concentration be read by interpolation within the linear range.

  120. Carta 120

    Domanda

    How does an ion–dipole attraction form, and how does it compare with dipole–dipole attraction?

    Risposta

    An ion attracts the oppositely charged end of a polar molecule. Ion–dipole attractions tend to be stronger than dipole–dipole attractions.

  121. Carta 121

    Domanda

    Which solid type is usually both conductive and malleable?

    Risposta

    A metallic solid, because its delocalized electrons move and its nondirectional bonding tolerates layer shifts.

  122. Carta 122

    Domanda

    How does a crystalline solid differ from an amorphous solid?

    Risposta

    A crystalline solid has long-range repeating order; an amorphous solid lacks that long-range periodic arrangement.

  123. Carta 123

    Domanda

    How is a gas component's partial pressure found from mole fraction?

    Risposta

    Pi = XiPtotal.

  124. Carta 124

    Domanda

    How does heating a fixed-volume gas affect its pressure in the ideal model?

    Risposta

    Pressure rises because faster particles collide with the walls more forcefully and frequently.

  125. Carta 125

    Domanda

    Why can attractions make a real gas's measured pressure lower than the ideal prediction?

    Risposta

    Attractions pull approaching particles away from the walls, reducing momentum transfer during wall collisions.

  126. Carta 126

    Domanda

    How many moles of ions result from complete dissolution of 0.20 mol CaCl₂?

    Risposta

    0.60 mol ions: 0.20 mol Ca²⁺ plus 0.40 mol Cl⁻.

  127. Carta 127

    Domanda

    How should water orient around Cl⁻ in a particle model?

    Risposta

    Its partially positive hydrogen ends point toward Cl⁻.

  128. Carta 128

    Domanda

    Can filtration separate dissolved components of a liquid solution?

    Risposta

    No. Dissolved particles pass through the filter with the solvent; filtration only retains an insoluble solid.

  129. Carta 129

    Domanda

    Why do nonpolar molecular solutes often dissolve in nonpolar solvents?

    Risposta

    Both rely mainly on compatible London dispersion forces, so mixing can replace the attractions disrupted in the separate substances.

  130. Carta 130

    Domanda

    What does a shorter absorbed wavelength imply about an energy transition?

    Risposta

    A larger energy gap because E = hc/λ.

  131. Carta 131

    Domanda

    What is the energy of a photon with frequency 5.0 × 10^14 s^-1?

    Risposta

    3.3 × 10^-19 J. Multiply by Planck's constant: E = (6.626 × 10^-34 J·s)(5.0 × 10^14 s^-1).

  132. Carta 132

    Domanda

    How does doubling cuvette path length affect absorbance in the linear Beer–Lambert range?

    Risposta

    Absorbance doubles if concentration and molar absorptivity stay constant.

  133. Carta 133

    Domanda

    How can noncovalent interactions affect a large biomolecule?

    Risposta

    Attractions between molecules or between different regions of the same molecule help set its shape, which strongly affects its properties and function.

  134. Carta 134

    Domanda

    Why does an ionic solid usually fail to conduct as a solid?

    Risposta

    Its ions are fixed in lattice positions. The same substance conducts when molten or dissolved because the ions can then move.

  135. Carta 135

    Domanda

    Why does a gas have no definite shape or volume?

    Risposta

    Its widely spaced particles move constantly and experience minimal interparticle attraction, so they spread through the available container.

  136. Carta 136

    Domanda

    What graph shapes show the inverse pressure–volume relationship for a fixed amount of ideal gas at constant temperature?

    Risposta

    A plot of P against V is a decreasing curve, while P against 1/V is a straight line through the origin.

  137. Carta 137

    Domanda

    At the same temperature, do different ideal gases have different average kinetic energies?

    Risposta

    No. Average translational kinetic energy depends only on absolute temperature.

  138. Carta 138

    Domanda

    Under which conditions is ideal-gas behavior most accurate?

    Risposta

    Low pressure and high temperature, where particles are far apart and attractions matter least.

  139. Carta 139

    Domanda

    What particle-level feature distinguishes a solution from a heterogeneous mixture?

    Risposta

    A solution—whether solid, liquid, or gas—is uniform throughout; a heterogeneous mixture has regions or phases with different compositions.

  140. Carta 140

    Domanda

    How should water orient around Na⁺ in a particulate model?

    Risposta

    Its partially negative oxygen end points toward Na⁺.

  141. Carta 141

    Domanda

    In paper chromatography, why does one solute spot travel farther than another?

    Risposta

    It interacts more strongly with the mobile phase or more weakly with the stationary phase. With known phase polarities, that travel difference can reveal relative solute polarity.

  142. Carta 142

    Domanda

    What energy competition helps explain whether an ionic solid dissolves?

    Risposta

    The energy needed to separate lattice ions competes with the energy released when ion–solvent attractions form.

  143. Carta 143

    Domanda

    Which molecular motions commonly absorb infrared radiation?

    Risposta

    Bond vibrations whose changing dipole can interact with the radiation.

  144. Carta 144

    Domanda

    Why must wavelength be converted to meters in c = λν when c is in m s^-1?

    Risposta

    Consistent units are required so meters cancel correctly and frequency comes out in s^-1.

  145. Carta 145

    Domanda

    How can fingerprints on a cuvette affect a visible-light absorbance reading?

    Risposta

    They can absorb or scatter extra light, making measured absorbance too high and the inferred concentration too high.

  146. Carta 146

    Domanda

    What causes and controls the strength of dipole–dipole attractions?

    Risposta

    Opposite partial charges on neighboring polar molecules attract. Strength increases with larger molecular dipoles and depends on how favorably the dipoles are oriented.

  147. Carta 147

    Domanda

    Why is graphite conductive and soft while diamond is insulating and hard?

    Risposta

    Graphite has delocalized electrons within its sheets, so it conducts, and its layers can slide, so it is soft. Diamond has a rigid three-dimensional network of localized covalent bonds, making it hard and insulating.

  148. Carta 148

    Domanda

    Why are gases much more compressible than liquids?

    Risposta

    Gas particles have large empty spaces between them; liquid particles are already close together.

  149. Carta 149

    Domanda

    What volume does 0.500 mol CO₂ occupy at 1.00 atm and 300. K if it behaves ideally?

    Risposta

    12.3 L. Use V = nRT/P = (0.500 mol)(0.08206 L atm mol^-1 K^-1)(300. K)/(1.00 atm).

  150. Carta 150

    Domanda

    Why does a lighter gas effuse faster than a heavier gas at the same temperature?

    Risposta

    Its particles have a higher average speed because equal average kinetic energy is shared by less mass.

  151. Carta 151

    Domanda

    How does finite particle volume affect a real gas at very high pressure?

    Risposta

    The free volume available for particle motion is smaller than the container volume assumed by the ideal model.

  152. Carta 152

    Domanda

    How should 250.0 mL of 0.100 M NaCl be prepared from solid NaCl?

    Risposta

    Dissolve 0.0250 mol NaCl, or 1.46 g, then dilute to exactly 250.0 mL in a volumetric flask.

  153. Carta 153

    Domanda

    What changes in a particle diagram when a solution is diluted without losing solute?

    Risposta

    The solute-particle count stays constant while solvent volume and particle spacing increase.

  154. Carta 154

    Domanda

    Why is fractional distillation better than simple distillation for liquids with close boiling points?

    Risposta

    Repeated vaporization–condensation steps enrich the vapor in the more volatile component more effectively.

  155. Carta 155

    Domanda

    Why are oil and water usually immiscible?

    Risposta

    Water's strong hydrogen-bond network isn't replaced by equally strong water–oil attractions, so the substances separate into phases.

  156. Carta 156

    Domanda

    Which molecular transition is commonly associated with ultraviolet or visible absorption?

    Risposta

    A transition between electronic energy levels.

  157. Carta 157

    Domanda

    Which photon carries more energy, blue light or red light?

    Risposta

    Blue light, because it has shorter wavelength and higher frequency.

  158. Carta 158

    Domanda

    Why is absorbance often measured at the wavelength of maximum absorbance in Beer–Lambert analysis?

    Risposta

    It gives the largest concentration-sensitive signal, and the flat top near the maximum makes small wavelength-setting errors less influential.

  159. Carta 159

    Domanda

    What creates a dipole–induced-dipole attraction, and what controls its strength?

    Risposta

    A permanent dipole distorts a nearby nonpolar particle's electron cloud and creates an attractive temporary dipole. A larger permanent dipole and a more polarizable nonpolar partner make the attraction stronger.

  160. Carta 160

    Domanda

    How do stronger intermolecular forces affect vapor pressure, boiling point, and melting point?

    Risposta

    They lower vapor pressure and raise boiling point. Melting point often rises too, but the trend is less direct because melting rearranges rather than fully separates particles.

  161. Carta 161

    Domanda

    How do particles behave in a liquid?

    Risposta

    They stay in close contact while moving and colliding continuously. Temperature and interparticle attractions affect their arrangement and motion.

  162. Carta 162

    Domanda

    Why must Celsius temperature be converted to kelvins in gas-law calculations?

    Risposta

    Gas-law proportionalities require an absolute temperature scale whose zero corresponds to zero extrapolated thermal motion.

  163. Carta 163

    Domanda

    How does raising temperature change a Maxwell–Boltzmann speed distribution?

    Risposta

    The distribution broadens, its peak lowers and shifts right, and a larger fraction of particles have high speed.

  164. Carta 164

    Domanda

    Why does the ideal-gas model treat collisions as elastic?

    Risposta

    It assumes total kinetic energy is conserved in particle–particle and particle–wall collisions.

  165. Carta 165

    Domanda

    How many moles of solute are in 75.0 mL of a 0.400 M solution?

    Risposta

    0.0300 mol. Multiply 0.400 mol L^-1 by 0.0750 L.

  166. Carta 166

    Domanda

    For equal solution volumes drawn at the same scale, what shows which solution is more concentrated?

    Risposta

    The more concentrated diagram contains more solute particles in that equal volume.

  167. Carta 167

    Domanda

    How do differences in intermolecular attractions let distillation separate a liquid solution?

    Risposta

    They give the components different vapor pressures, so the vapor is enriched in the more volatile component.

  168. Carta 168

    Domanda

    What comparison helps predict whether two liquids will be miscible?

    Risposta

    Liquids with similar types and strengths of intermolecular attractions are more likely to mix uniformly.

  169. Carta 169

    Domanda

    How can an absorption spectrum help identify a substance?

    Risposta

    Its allowed energy gaps produce a characteristic pattern of absorbed wavelengths that can be compared with known spectra.

  170. Carta 170

    Domanda

    How does absorbing or emitting a photon change an atom's or molecule's energy?

    Risposta

    Absorption raises the species' energy by exactly the photon energy; emission lowers it by the same amount.

  171. Carta 171

    Domanda

    What macroscopic evidence can support that a chemical reaction occurred?

    Risposta

    Evidence can include gas formation, precipitate formation, a persistent color change, or an energy change, interpreted with particle-level changes.

  172. Carta 172

    Domanda

    What does a net ionic equation include?

    Risposta

    Only the dissolved or reacting species that undergo chemical change; spectator ions are omitted.

  173. Carta 173

    Domanda

    What must a correct particulate reaction diagram conserve?

    Risposta

    The number of atoms of every element and the total charge.

  174. Carta 174

    Domanda

    What distinguishes a chemical change from a physical change?

    Risposta

    A chemical change rearranges bonds into new substances; a physical change alters state or arrangement without changing chemical identity.

  175. Carta 175

    Domanda

    What does a balanced equation's coefficient ratio provide?

    Risposta

    The mole ratio among reacting and produced species.

  176. Carta 176

    Domanda

    What is the equivalence point of a titration?

    Risposta

    The point where titrant and analyte have reacted in the stoichiometric ratio given by the balanced equation.

  177. Carta 177

    Domanda

    What defines a precipitation reaction?

    Risposta

    Aqueous ions combine to form a sparingly soluble solid.

  178. Carta 178

    Domanda

    What happens in a Brønsted–Lowry acid–base reaction?

    Risposta

    A proton transfers from the acid (donor) to the base (acceptor). In aqueous solution, H₂O can play either role.

  179. Carta 179

    Domanda

    What does oxidation mean in a redox reaction?

    Risposta

    Loss of electrons and an increase in oxidation number.

  180. Carta 180

    Domanda

    What particle-level change confirms that a process is chemical?

    Risposta

    Atoms rearrange into new combinations, producing substances with different compositions.

  181. Carta 181

    Domanda

    Which ions are spectators when AgNO₃(aq) reacts with NaCl(aq)?

    Risposta

    Na⁺ and NO₃⁻. The net ionic reaction is Ag⁺(aq) + Cl⁻(aq) → AgCl(s).

  182. Carta 182

    Domanda

    How does a particulate diagram reveal the limiting reactant?

    Risposta

    After forming the maximum product allowed by the ratio, none of the limiting reactant remains while excess reactant particles do.

  183. Carta 183

    Domanda

    Is melting ice a chemical or physical change?

    Risposta

    A physical change. H₂O molecules remain H₂O while their arrangement and motion change.

  184. Carta 184

    Domanda

    How is the limiting reactant identified from given amounts?

    Risposta

    Convert each reactant to the same product amount using the balanced equation; the smaller product amount identifies the limiting reactant.

  185. Carta 185

    Domanda

    How does an endpoint differ from an equivalence point?

    Risposta

    The endpoint is an observed signal such as indicator color change; the equivalence point is the exact stoichiometric condition.

  186. Carta 186

    Domanda

    How is complete combustion of a hydrocarbon in excess oxygen classified, and what products form?

    Risposta

    It is a redox combustion reaction that forms CO₂ and H₂O.

  187. Carta 187

    Domanda

    What are the conjugate acid and conjugate base in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Risposta

    NH₄⁺ is the conjugate acid of NH₃, and OH⁻ is the conjugate base of H₂O.

  188. Carta 188

    Domanda

    What does reduction mean in a redox reaction?

    Risposta

    Gain of electrons and a decrease in oxidation number.

  189. Carta 189

    Domanda

    Which common changes are physical rather than chemical?

    Risposta

    Phase changes and the formation or separation of mixtures are physical when each substance keeps its composition.

  190. Carta 190

    Domanda

    How are strong soluble electrolytes written in a complete ionic equation?

    Risposta

    As separated aqueous ions; solids, liquids, gases, and weak electrolytes stay intact.

  191. Carta 191

    Domanda

    A diagram starts with six A particles and four B₂ particles for 2A + B₂ → 2AB; what remains after completion?

    Risposta

    One B₂ remains. Six A consume three B₂ and form six AB.

  192. Carta 192

    Domanda

    Why is dissolving NaCl in water normally classified as a physical change?

    Risposta

    Na⁺ and Cl⁻ separate and become hydrated, but retain their chemical identities. Removing the water recovers NaCl; the shift from ion–ion to ion–dipole attractions does not by itself form a new substance.

  193. Carta 193

    Domanda

    What mass of AgCl can form from 25.0 mL of 0.200 M AgNO₃ mixed with excess Cl⁻?

    Risposta

    0.717 g AgCl. The 1:1 reaction gives 0.00500 mol AgCl; multiply by 143.32 g mol^-1.

  194. Carta 194

    Domanda

    What calculation finds unknown analyte moles at equivalence?

    Risposta

    Use titrant moles, n = MV, then apply the balanced-reaction mole ratio.

  195. Carta 195

    Domanda

    Which feature identifies an acid–base, redox, or precipitation reaction?

    Risposta

    Acid–base reactions transfer protons, redox reactions change oxidation numbers through electron transfer, and precipitation reactions form a sparingly soluble solid.

  196. Carta 196

    Domanda

    What is the net ionic equation for strong acid–strong base neutralization?

    Risposta

    H⁺(aq) + OH⁻(aq) → H₂O(l).

  197. Carta 197

    Domanda

    What is the oxidation number of sulfur in SO₄²⁻?

    Risposta

    +6. Four oxygens contribute -8 total, so sulfur must be +6 to give -2 overall.

  198. Carta 198

    Domanda

    Why can gas bubbles alone be ambiguous evidence of reaction?

    Risposta

    Bubbles may also come from boiling or dissolved gas escaping, so the context and particle identities must support a chemical change.

  199. Carta 199

    Domanda

    How is melting ice represented as a balanced physical-change equation?

    Risposta

    H₂O(s) → H₂O(l). The formula and atom count stay the same because only the physical state changes.

  200. Carta 200

    Domanda

    What does a particle diagram show when no reaction occurs after two aqueous ionic solutions mix?

    Risposta

    All ions remain separated and solvated, with no new bonded particles, precipitate, or gas.

  201. Carta 201

    Domanda

    Why is rusting iron a chemical change?

    Risposta

    Iron atoms form new iron-oxide substances through electron transfer and new bonding.

  202. Carta 202

    Domanda

    For 2H₂O₂(aq) → 2H₂O(l) + O₂(g), what volume of O₂ forms from 0.100 mol H₂O₂ at 298 K and 1.00 atm?

    Risposta

    1.22 L O₂. The mole ratio gives 0.0500 mol O₂, then V = nRT/P.

  203. Carta 203

    Domanda

    A 25.0 mL monoprotic acid sample requires 20.0 mL of 0.150 M NaOH; what is the acid concentration?

    Risposta

    0.120 M. At 1:1 equivalence, moles acid = 0.0200 L × 0.150 M, then divide by 0.0250 L.

  204. Carta 204

    Domanda

    Which salts does the minimum solubility rule in this deck treat as soluble?

    Risposta

    All salts containing Na⁺, K⁺, NH₄⁺, or NO₃⁻ are treated as soluble in water.

  205. Carta 205

    Domanda

    How are the strengths of a conjugate acid and its conjugate base related?

    Risposta

    A stronger acid has a weaker conjugate base, and a stronger base has a weaker conjugate acid.

  206. Carta 206

    Domanda

    How are oxidation and reduction half-reactions combined into one balanced equation?

    Risposta

    Multiply them so electrons lost equal electrons gained, add the half-reactions, then cancel electrons and any identical species on both sides.

  207. Carta 207

    Domanda

    How do molecular, complete ionic, and net ionic equations differ?

    Risposta

    Molecular equations keep compounds intact, complete ionic equations split strong soluble electrolytes, and net ionic equations remove spectators. All three conserve atoms and charge.

  208. Carta 208

    Domanda

    How should coefficients change particle counts in a reaction diagram?

    Risposta

    They set whole-particle ratios while preserving each particle's chemical formula.

  209. Carta 209

    Domanda

    Is separating a mixture by distillation a chemical or physical change?

    Risposta

    A physical change. Components change phase and location but keep their chemical identities.

  210. Carta 210

    Domanda

    What equation results from Cu → Cu²⁺ + 2e⁻ and Ag⁺ + e⁻ → Ag?

    Risposta

    Cu + 2Ag⁺ → Cu²⁺ + 2Ag. Multiply the silver half-reaction by 2 and cancel 2e⁻; both atom counts and net charge then match.

  211. Carta 211

    Domanda

    How is average reaction rate found from a reactant concentration?

    Risposta

    Use the negative concentration change divided by elapsed time, adjusted by its stoichiometric coefficient when comparing species rates.

  212. Carta 212

    Domanda

    What does a rate law express?

    Risposta

    It shows how the measured rate depends on reactant concentrations. In rate = k[A]^m[B]^n, m and n are the orders in A and B, and m + n is the overall order.

  213. Carta 213

    Domanda

    A plot of ln[A] versus time is linear; what is the order in A and its integrated rate law?

    Risposta

    First order: ln[A]t = ln[A]0 − kt, so the plot's slope is −k.

  214. Carta 214

    Domanda

    What is an elementary reaction?

    Risposta

    A single step in a mechanism whose rate law follows directly from its reactant molecularity.

  215. Carta 215

    Domanda

    What two collision conditions are needed for reaction?

    Risposta

    Sufficient collision energy and a productive molecular orientation.

  216. Carta 216

    Domanda

    What does activation energy represent on a reaction-energy profile?

    Risposta

    The energy difference from the reactants to the transition state. The reaction coordinate tracks the step's structural progress, not elapsed time.

  217. Carta 217

    Domanda

    What must the elementary steps of a valid mechanism do when added?

    Risposta

    Cancel intermediates and reproduce the overall balanced reaction.

  218. Carta 218

    Domanda

    How is a proposed mechanism tested against kinetics?

    Risposta

    Its derived rate law must agree with the experimentally measured rate law.

  219. Carta 219

    Domanda

    What does a pre-equilibrium approximation assume?

    Risposta

    A fast reversible step reaches equilibrium before a later slow step consumes its intermediate.

  220. Carta 220

    Domanda

    What does each peak on a multistep energy profile represent?

    Risposta

    A transition state for one elementary step.

  221. Carta 221

    Domanda

    How does a catalyst increase reaction rate?

    Risposta

    It provides an alternate mechanism with a lower activation-energy pathway.

  222. Carta 222

    Domanda

    Why does crushing a solid reactant usually increase its reaction rate?

    Risposta

    Crushing increases exposed surface area, so more reactant particles can collide with the other reactant each second.

  223. Carta 223

    Domanda

    How is reaction order found from initial-rate data?

    Risposta

    Compare trials where one reactant concentration changes while the others stay constant, then match the rate factor to the concentration factor.

  224. Carta 224

    Domanda

    A plot of [A] versus time is linear; what is the order in A and its integrated rate law?

    Risposta

    Zero order: [A]t = [A]0 − kt, so the plot's slope is −k.

  225. Carta 225

    Domanda

    What is the rate law for the elementary step 2A + B → products?

    Risposta

    rate = k[A]²[B]. This inference is valid because the step is elementary.

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  226. Carta 226

    Domanda

    How does raising temperature change a Maxwell–Boltzmann energy distribution and reaction rate?

    Risposta

    The distribution shifts and broadens toward higher energies, so a larger fraction of collisions exceeds the activation-energy threshold and can react.

  227. Carta 227

    Domanda

    How is ΔH read from a reaction-energy profile?

    Risposta

    ΔH = energy of products − energy of reactants.

  228. Carta 228

    Domanda

    What is a reaction intermediate?

    Risposta

    A species formed in one mechanism step and consumed in a later step, so it cancels from the overall equation.

  229. Carta 229

    Domanda

    Why can't overall reaction coefficients usually supply rate-law exponents?

    Risposta

    The overall equation hides the mechanism; exponents come from experiment unless the reaction is a stated elementary step.

  230. Carta 230

    Domanda

    How does pre-equilibrium remove an intermediate from a rate law?

    Risposta

    Use the fast-step equilibrium relation to express the intermediate concentration in terms of stable reactants.

  231. Carta 231

    Domanda

    What does each valley between peaks represent on a multistep profile?

    Risposta

    A reaction intermediate.

  232. Carta 232

    Domanda

    Does a catalyst change ΔH or the equilibrium constant?

    Risposta

    No. It changes the pathway and rates, not reactant/product energies or the equilibrium composition.

  233. Carta 233

    Domanda

    For 2A → B, how are disappearance of A and appearance of B related?

    Risposta

    Reaction rate = -(1/2)Δ[A]/Δt = Δ[B]/Δt.

  234. Carta 234

    Domanda

    How do the units of k depend on a rate law's overall order?

    Risposta

    They must make the rate unit M s^-1: zero order uses M s^-1, first order s^-1, and second order M^-1 s^-1.

  235. Carta 235

    Domanda

    A plot of 1/[A] versus time is linear; what is the order in A and its integrated rate law?

    Risposta

    Second order: 1/[A]t = 1/[A]0 + kt, so the plot's slope is +k.

  236. Carta 236

    Domanda

    What is molecularity?

    Risposta

    The number of reacting particles in an elementary step, such as unimolecular or bimolecular.

  237. Carta 237

    Domanda

    How does raising temperature affect k in the qualitative Arrhenius model?

    Risposta

    k increases, often sharply, because a larger fraction of collisions can reach the transition state. Arrhenius-equation calculations are outside this deck’s scope.

  238. Carta 238

    Domanda

    A reactant falls from 0.80 M to 0.50 M in 30. s; what is its average disappearance rate to two significant figures?

    Risposta

    0.010 M s^-1. Use -(0.50 − 0.80) M ÷ 30. s.

  239. Carta 239

    Domanda

    How does a catalyst differ from an intermediate in a mechanism?

    Risposta

    A catalyst is consumed early and regenerated later; an intermediate is formed early and consumed later.

  240. Carta 240

    Domanda

    For 2NO₂ → NO₃ + NO (slow), followed by NO₃ + CO → NO₂ + CO₂ (fast), what rate law is predicted?

    Risposta

    rate = k[NO₂]². The first step is elementary and rate-limiting, so its molecularity sets the observed rate law.

  241. Carta 241

    Domanda

    On a multistep reaction-energy profile, which feature often identifies the rate-determining step?

    Risposta

    The step with the largest activation barrier measured from its preceding valley to its peak.

  242. Carta 242

    Domanda

    If changing [B] leaves rate unchanged, what is the order in B?

    Risposta

    Zero order, so [B]^0 = 1 in the measured rate law.

  243. Carta 243

    Domanda

    What mechanism changes can binding, acid–base, or surface catalysis introduce?

    Risposta

    They can orient reactants, lower activation barriers, or create new bound, protonated, or deprotonated intermediates and elementary steps; the catalyst is regenerated.

  244. Carta 244

    Domanda

    What is special about a first-order reaction's half-life?

    Risposta

    It is constant and independent of starting concentration: t1/2 = ln 2/k. Radioactive decay is a common first-order example.

  245. Carta 245

    Domanda

    Why is a termolecular elementary collision uncommon?

    Risposta

    Three particles must collide simultaneously with suitable energy and orientation, which is much less probable than one- or two-particle events.

  246. Carta 246

    Domanda

    On a reaction-energy profile, how are reverse activation energy, forward activation energy, and ΔH related?

    Risposta

    Ea,reverse = Ea,forward − ΔH. The reverse barrier is measured from products to the same transition state.

  247. Carta 247

    Domanda

    Why can correct orientation matter even above the activation energy?

    Risposta

    The colliding reactive sites must align so old bonds can break and new bonds can form along the reaction pathway.

  248. Carta 248

    Domanda

    How does detecting a proposed reaction intermediate affect a mechanism claim?

    Risposta

    It supports a mechanism that contains that intermediate, but it doesn't prove that mechanism is unique.

  249. Carta 249

    Domanda

    For 2NO ⇌ N₂O₂ (fast equilibrium), followed by N₂O₂ + O₂ → 2NO₂ (slow), what observed rate law results?

    Risposta

    rate = kobs[NO]²[O₂]. Start with rate = k₂[N₂O₂][O₂], use [N₂O₂] = K[NO]² from the fast equilibrium, then substitute.

  250. Carta 250

    Domanda

    What does the highest point of a one-step energy profile represent?

    Risposta

    The transition state, an unstable arrangement at the top of the activation barrier.

  251. Carta 251

    Domanda

    What sign does q have for an endothermic system?

    Risposta

    Positive, because the system absorbs heat from the surroundings.

  252. Carta 252

    Domanda

    How does an exothermic reaction appear on an enthalpy diagram?

    Risposta

    Products lie below reactants, so ΔH is negative.

  253. Carta 253

    Domanda

    What condition defines thermal equilibrium?

    Risposta

    Objects in contact have the same temperature, so there is no net heat transfer.

  254. Carta 254

    Domanda

    What equations relate heat capacity and temperature change to heat transfer?

    Risposta

    Use q = mcΔT with specific heat capacity, or q = nCₘΔT with molar heat capacity.

  255. Carta 255

    Domanda

    Why is temperature constant during a phase-change plateau?

    Risposta

    Added or removed energy changes interparticle potential energy instead of average kinetic energy.

  256. Carta 256

    Domanda

    What does ΔHrxn describe?

    Risposta

    The heat absorbed or released at constant pressure for the reaction exactly as written under the stated conditions.

  257. Carta 257

    Domanda

    How is reaction enthalpy estimated from average bond enthalpies?

    Risposta

    ΔHrxn ≈ Σ(bonds broken) − Σ(bonds formed).

  258. Carta 258

    Domanda

    What is the standard enthalpy of formation of an element in its standard state?

    Risposta

    Zero by definition.

  259. Carta 259

    Domanda

    In a Hess’s law calculation, how should a step change when the target needs twice its reverse?

    Risposta

    Reverse the equation, double every coefficient, and multiply its ΔH by -2.

  260. Carta 260

    Domanda

    How can energy cross a system boundary during a process?

    Risposta

    As heat or work. Heat transferred to or work done on the system increases its energy; heat transferred from or work done by the system decreases it.

  261. Carta 261

    Domanda

    How does an endothermic reaction appear on an enthalpy diagram?

    Risposta

    Products lie above reactants, so ΔH is positive.

  262. Carta 262

    Domanda

    How are heat gained by a system and heat lost by its surroundings related in an isolated setup?

    Risposta

    qsystem = -qsurroundings.

  263. Carta 263

    Domanda

    In coffee-cup calorimetry, how is reaction heat related to solution heat?

    Risposta

    qrxn = -qsolution when calorimeter heat is negligible and pressure is constant.

  264. Carta 264

    Domanda

    What heat is required to melt n moles at the melting point?

    Risposta

    q = nΔHfus.

  265. Carta 265

    Domanda

    How does reversing a reaction change ΔH?

    Risposta

    It reverses the sign of ΔH.

  266. Carta 266

    Domanda

    Why is breaking a bond endothermic?

    Risposta

    Energy must be supplied to separate atoms against their bonding attraction.

  267. Carta 267

    Domanda

    How is ΔH°rxn calculated from standard enthalpies of formation?

    Risposta

    ΣνΔHf°(products) − ΣνΔHf°(reactants).

  268. Carta 268

    Domanda

    How does multiplying an equation by 3 affect its ΔH?

    Risposta

    Multiply ΔH by 3 because enthalpy change scales with reaction amount.

  269. Carta 269

    Domanda

    Why can an exothermic dissolution warm the solution?

    Risposta

    The solution warms because forming solute–solvent attractions releases more energy than is absorbed in separating the original particles. The net potential-energy decrease raises particle kinetic energy and temperature.

  270. Carta 270

    Domanda

    Does an energy diagram's activation barrier determine ΔH?

    Risposta

    No. ΔH depends on reactant and product energy levels, while the barrier controls kinetics.

  271. Carta 271

    Domanda

    Why does heat flow from a warmer object to a cooler object?

    Risposta

    Energy transfers through collisions until their average kinetic energies, and therefore temperatures, equalize.

  272. Carta 272

    Domanda

    How much heat warms 100.0 g of water by 5.0°C?

    Risposta

    2.1 kJ. Use q = (100.0 g)(4.184 J g^-1 °C^-1)(5.0°C).

  273. Carta 273

    Domanda

    How are the molar enthalpies of a phase change and its reverse related?

    Risposta

    They have equal magnitudes and opposite signs, such as ΔHcond = -ΔHvap and ΔHfreeze = -ΔHfus.

  274. Carta 274

    Domanda

    How does doubling every coefficient in a thermochemical equation affect ΔH?

    Risposta

    It doubles ΔH.

  275. Carta 275

    Domanda

    Why is forming a bond exothermic?

    Risposta

    Atoms move to a lower-potential-energy bonded arrangement and release energy.

  276. Carta 276

    Domanda

    What formation equation defines ΔHf° for CO₂(g)?

    Risposta

    C(s, graphite) + O₂(g) → CO₂(g), forming exactly one mole from elements in standard states.

  277. Carta 277

    Domanda

    What should happen to intermediate species when equations in a Hess’s law calculation are added?

    Risposta

    They cancel, leaving the target overall reaction.

  278. Carta 278

    Domanda

    If the surroundings warm during a process, what is the likely sign of qsystem?

    Risposta

    Negative; the system likely released heat to the surroundings.

  279. Carta 279

    Domanda

    For a profile with reactants at 40 kJ and products at 10 kJ, what is ΔH?

    Risposta

    -30 kJ for the reaction as drawn.

  280. Carta 280

    Domanda

    Assuming no phase change, what determines the final temperature when two substances exchange heat in an insulated container?

    Risposta

    Energy conservation: q_warm + q_cool = 0. Use each substance's mass, heat capacity, and initial temperature to solve for the common final temperature.

  281. Carta 281

    Domanda

    How would heat loss to the room affect an exothermic calorimetry result?

    Risposta

    The observed temperature rise is too small, so the calculated magnitude of released heat is too low.

  282. Carta 282

    Domanda

    What heat expression covers warming a liquid without a phase change?

    Risposta

    q = mcΔT, not nΔHphase.

  283. Carta 283

    Domanda

    If forming 1 mol of product has ΔH = -50 kJ mol^-1, what is q when 2 mol forms?

    Risposta

    -100 kJ. Use q = nΔH = (2 mol)(-50 kJ mol^-1).

  284. Carta 284

    Domanda

    Breaking reactant bonds requires 500 kJ, and forming product bonds releases 650 kJ; what is the estimated ΔH?

    Risposta

    -150 kJ, from 500 − 650.

  285. Carta 285

    Domanda

    For CO(g) + ½O₂(g) → CO₂(g), what is ΔH°rxn if ΔHf°[CO] = -110.5 and ΔHf°[CO₂] = -393.5 kJ mol^-1?

    Risposta

    -283.0 kJ. Use -393.5 - [-110.5 + ½(0)], since ΔHf°[O₂(g)] = 0.

  286. Carta 286

    Domanda

    In a Hess’s law calculation, two valid steps have ΔH values +25 kJ and -60 kJ; what is the combined ΔH?

    Risposta

    -35 kJ, provided the equations add to the target reaction.

  287. Carta 287

    Domanda

    Why is “bonds breaking releases energy” incorrect?

    Risposta

    Bond breaking absorbs energy; the overall reaction releases energy only when forming new bonds releases more than breaking old bonds requires.

  288. Carta 288

    Domanda

    How would melting appear on an energy diagram?

    Risposta

    The liquid lies above the solid, so ΔHfus is positive; the diagram represents a physical, endothermic change.

  289. Carta 289

    Domanda

    Can two objects at the same temperature exchange energy microscopically?

    Risposta

    Yes, but their energy transfers balance, so there is no net heat flow.

  290. Carta 290

    Domanda

    Why must the calorimeter's heat capacity be included when it isn't negligible?

    Risposta

    The apparatus can absorb or release heat, so include q_cal = C_calΔT in the energy balance: q_process + q_solution + q_cal = 0.

  291. Carta 291

    Domanda

    What makes chemical equilibrium dynamic?

    Risposta

    Forward and reverse reactions continue at equal rates even though macroscopic concentrations stay constant.

  292. Carta 292

    Domanda

    For aA + bB ⇌ cC, what is the concentration-form expression for Q?

    Risposta

    Q = [C]^c / ([A]^a[B]^b), using current rather than necessarily equilibrium concentrations.

  293. Carta 293

    Domanda

    What does K much greater than 1 indicate?

    Risposta

    Products predominate at equilibrium, though K says nothing about reaction speed.

  294. Carta 294

    Domanda

    How does reversing a reaction change its equilibrium constant?

    Risposta

    K becomes 1/K.

  295. Carta 295

    Domanda

    Can a reversible system reach equilibrium when it starts with only products?

    Risposta

    Yes, if the reverse reaction is possible. The equilibrium composition depends on temperature, initial amounts, and volume or pressure.

  296. Carta 296

    Domanda

    How do Q and K predict reaction direction?

    Risposta

    Q < K shifts forward, Q > K shifts reverse, and Q = K means equilibrium.

  297. Carta 297

    Domanda

    Which species are omitted from a heterogeneous equilibrium expression?

    Risposta

    Pure solids and pure liquids because their activities are effectively constant.

  298. Carta 298

    Domanda

    How does increasing a dissolved reactant's concentration or a gaseous reactant's partial pressure affect equilibrium at constant temperature when other Q terms are initially unchanged?

    Risposta

    It lowers Q relative to K, so the system shifts toward products until Q = K again. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that pure phase remains present.

  299. Carta 299

    Domanda

    What does a flat concentration-time graph mean at equilibrium?

    Risposta

    Each concentration is constant, not necessarily equal to the others.

  300. Carta 300

    Domanda

    For A ⇌ B in one fixed volume, a particulate model shows 16 A and 0 B initially, then 4 A and 12 B at equilibrium. What changed, what predominates, and what is Kc?

    Risposta

    The net change was forward: 12 A particles became 12 B particles. B predominates at equilibrium, and Kc = [B]/[A] = 12/4 = 3.0 because both counts come from the same fixed volume.

  301. Carta 301

    Domanda

    What can Ksp tell you about a salt's solubility, and when can two Ksp values be compared directly?

    Risposta

    Ksp > 1 indicates a soluble salt. For salts with the same dissolution stoichiometry, a larger Ksp generally means greater molar solubility; across different stoichiometries, calculate molar solubility before comparing.

  302. Carta 302

    Domanda

    What is the common-ion effect on solubility?

    Risposta

    Adding an ion already in the dissolution equilibrium usually decreases the solid's molar solubility.

  303. Carta 303

    Domanda

    How does uniform dilution shift an aqueous equilibrium based on the stoichiometric powers in Q?

    Risposta

    It shifts toward the side with the larger sum of stoichiometric coefficients for dissolved species included in Q. If the sums are equal, dilution causes no shift by this effect; pure solids and liquids remain omitted.

  304. Carta 304

    Domanda

    What happens if a reversible reaction starts with reactants only?

    Risposta

    The forward rate is initially largest; products form, the reverse rate grows, and the rates eventually become equal.

  305. Carta 305

    Domanda

    What is the purpose of an ICE table?

    Risposta

    To organize initial, change, and equilibrium concentrations using reaction stoichiometry.

  306. Carta 306

    Domanda

    Can a reaction with a very large K be slow?

    Risposta

    Yes. K describes thermodynamic equilibrium position, while rate depends on kinetics and activation energy.

  307. Carta 307

    Domanda

    What happens to Q immediately after product concentration increases?

    Risposta

    Q increases; if it rises above K, the reaction shifts toward reactants.

  308. Carta 308

    Domanda

    How does multiplying every reaction coefficient by 2 affect K?

    Risposta

    The new equilibrium constant is K².

  309. Carta 309

    Domanda

    For A ⇌ B, Kc = 4.0 and initially [A] = 1.0 M and [B] = 0, what are the equilibrium concentrations?

    Risposta

    [A] = 0.20 M and [B] = 0.80 M. Let x form: Kc = x/(1.0 − x) = 4.0, so x = 0.80 M.

  310. Carta 310

    Domanda

    What macroscopic properties stay constant at equilibrium?

    Risposta

    Properties such as concentration, color, and pressure remain constant when external conditions are fixed.

  311. Carta 311

    Domanda

    How does decreasing volume shift a gaseous equilibrium?

    Risposta

    Toward the side with fewer moles of gas, if the two sides have different gaseous mole counts.

  312. Carta 312

    Domanda

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kc?

    Risposta

    Kc = [NH₃]² / ([N₂][H₂]³).

  313. Carta 313

    Domanda

    For CaF₂(s) ⇌ Ca²⁺ + 2F⁻, how is Ksp written in terms of molar solubility s in pure water?

    Risposta

    Ksp = s(2s)² = 4s³ because [Ca²⁺] = s and [F⁻] = 2s.

  314. Carta 314

    Domanda

    What does K much less than 1 indicate?

    Risposta

    Reactants predominate at equilibrium.

  315. Carta 315

    Domanda

    How does decreasing a dissolved product's concentration or a gaseous product's partial pressure affect equilibrium when other Q terms are initially unchanged?

    Risposta

    It lowers Q and drives a net forward reaction until equilibrium returns. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that phase remains.

  316. Carta 316

    Domanda

    Does equilibrium mean the reaction has stopped?

    Risposta

    No. Both directions continue, but equal rates produce no net macroscopic change.

  317. Carta 317

    Domanda

    Why does adding NaF reduce CaF₂ solubility?

    Risposta

    The added F⁻ raises Qsp, shifting the dissolution equilibrium toward solid CaF₂.

  318. Carta 318

    Domanda

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kp when P_N₂ = 0.50 atm, P_H₂ = 1.50 atm, and P_NH₃ = 0.25 atm?

    Risposta

    0.037. Use Kp = (P_NH₃)²/[(P_N₂)(P_H₂)³] = (0.25)²/[(0.50)(1.50)³]. Use equilibrium partial pressures directly; Kc↔Kp conversion isn't assessed.

  319. Carta 319

    Domanda

    What happens to Q when a gaseous equilibrium mixture is compressed at constant temperature if products have fewer gas moles?

    Risposta

    Q falls relative to K, so the reaction shifts toward products.

  320. Carta 320

    Domanda

    How do K and Q transform when a reaction is reversed, its coefficients are multiplied, or reactions are added?

    Risposta

    They follow the same algebra: reversing takes the reciprocal, multiplying every coefficient by c raises the value to the power c, and adding reactions multiplies their K or Q values.

  321. Carta 321

    Domanda

    When is the small-x approximation acceptable?

    Risposta

    When x is small relative to the initial concentration and the final result confirms the neglected change is suitably small.

  322. Carta 322

    Domanda

    What graph feature shows a disturbance followed by re-equilibration?

    Risposta

    A sudden or gradual concentration change followed by new constant plateaus while rates return to equality.

  323. Carta 323

    Domanda

    If Q = 0.20 and K = 5.0, which direction is favored next?

    Risposta

    Forward, because Q < K.

  324. Carta 324

    Domanda

    At equilibrium, are reactant and product concentrations equal?

    Risposta

    Not necessarily. They are constant, while forward and reverse rates are equal.

  325. Carta 325

    Domanda

    CaF₂ has Ksp = 3.2 × 10^-11 in pure water; what is its molar solubility?

    Risposta

    2.0 × 10^-4 M. If the molar solubility is s, then [Ca²⁺] = s, [F⁻] = 2s, and Ksp = 4s³.

  326. Carta 326

    Domanda

    For N₂ + 3H₂ ⇌ 2NH₃, how is Qp written?

    Risposta

    Qp = (P_NH₃)²/[(P_N₂)(P_H₂)³], using the current partial pressures rather than necessarily equilibrium values.

  327. Carta 327

    Domanda

    How does heating shift an endothermic forward reaction?

    Risposta

    Toward products, and K increases because temperature changes the equilibrium constant.

  328. Carta 328

    Domanda

    Why do both forward and reverse rates change as equilibrium is approached?

    Risposta

    As reactant and product concentrations change, the collision frequencies for the two directions change until their rates match.

  329. Carta 329

    Domanda

    CaF₂ has Ksp = 3.2 × 10^-11. What is its molar solubility in 0.10 M NaF?

    Risposta

    About 3.2 × 10^-9 M. With [F⁻] ≈ 0.10 M, Ksp = [Ca²⁺][F⁻]² gives s = (3.2 × 10^-11)/(0.10)². The common ion lowers solubility but does not change Ksp at constant temperature.

  330. Carta 330

    Domanda

    What concentration data must be used to calculate Kc?

    Risposta

    Equilibrium concentrations, each raised to its stoichiometric coefficient and excluding pure solids and liquids.

  331. Carta 331

    Domanda

    What is a Brønsted–Lowry acid?

    Risposta

    A proton donor.

  332. Carta 332

    Domanda

    How is pH defined?

    Risposta

    pH = -log[H₃O⁺].

  333. Carta 333

    Domanda

    What is Ka for HA + H₂O ⇌ H₃O⁺ + A⁻?

    Risposta

    Ka = [H₃O⁺][A⁻]/[HA].

  334. Carta 334

    Domanda

    How does stabilizing a base affect its basicity and the strength of its conjugate acid?

    Risposta

    It makes the base weaker and its conjugate acid stronger. A more stable base is less willing to accept H⁺.

  335. Carta 335

    Domanda

    What is a Brønsted–Lowry base?

    Risposta

    A proton acceptor.

  336. Carta 336

    Domanda

    At 25°C, what are Kw and the relationship between pH and pOH?

    Risposta

    Kw = [H₃O⁺][OH⁻] = 1.0 × 10^-14. Taking negative logarithms gives pH + pOH = 14.00.

  337. Carta 337

    Domanda

    What is Kb for B + H₂O ⇌ BH⁺ + OH⁻?

    Risposta

    Kb = [BH⁺][OH⁻]/[B].

  338. Carta 338

    Domanda

    Why can lowering pH increase the solubility of a salt containing a basic anion?

    Risposta

    H₃O⁺ consumes the anion, pulling the dissolution equilibrium toward more dissolved ions.

  339. Carta 339

    Domanda

    What are conjugate acid–base pairs?

    Risposta

    Species that differ by exactly one proton.

  340. Carta 340

    Domanda

    What is the pH of 1.0 × 10^-3 M HCl?

    Risposta

    3.00, assuming complete dissociation and negligible water contribution.

  341. Carta 341

    Domanda

    How are pKa and pKb defined?

    Risposta

    pKa = -log Ka, and pKb = -log Kb.

  342. Carta 342

    Domanda

    Why does acid strength increase across a row of comparable hydrides?

    Risposta

    Increasing electronegativity stabilizes the conjugate base and polarizes the H–A bond.

  343. Carta 343

    Domanda

    What is an amphiprotic species?

    Risposta

    A species that can donate or accept a proton, such as HCO₃⁻.

  344. Carta 344

    Domanda

    What amounts remain after a limited amount of strong base partially neutralizes weak acid HA?

    Risposta

    Subtract the reacted moles from HA and form the same number of moles of A⁻. The result gives the remaining HA and formed A⁻ amounts before any equilibrium or buffer-pH calculation.

  345. Carta 345

    Domanda

    How are Ka, Kb, pKa, and pKb related for a conjugate pair at 25°C?

    Risposta

    KaKb = Kw = 1.0 × 10^-14, and pKa + pKb = pKw = 14.00.

  346. Carta 346

    Domanda

    When does pH have little effect on a salt's solubility?

    Risposta

    When neither dissolved ion reacts appreciably with H₃O⁺ or OH⁻.

  347. Carta 347

    Domanda

    How does H₂O act in HCl + H₂O → H₃O⁺ + Cl⁻ and in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Risposta

    It acts as a base in the first reaction by accepting H⁺, and as an acid in the second by donating H⁺.

  348. Carta 348

    Domanda

    After mixing weak base B with strong acid, what controls the final solution in the three stoichiometric regimes?

    Risposta

    Excess B leaves a B/BH⁺ buffer; equimolar amounts leave BH⁺, so the solution is acidic; excess strong acid sets the pH from the remaining H₃O⁺.

  349. Carta 349

    Domanda

    What two components make a typical weak-acid buffer?

    Risposta

    A weak acid and a significant amount of its conjugate base.

  350. Carta 350

    Domanda

    What do the successive half-equivalence pH values approximate in a diprotic weak-acid titration?

    Risposta

    The first approximates pKa₁ and the second approximates pKa₂ because each conjugate pair has equal concentrations at its half-equivalence point.

  351. Carta 351

    Domanda

    Which acid is stronger, one with pKa 2 or pKa 5?

    Risposta

    The acid with pKa 2; lower pKa means larger Ka.

  352. Carta 352

    Domanda

    What is the Henderson–Hasselbalch equation?

    Risposta

    pH = pKa + log([A⁻]/[HA]).

  353. Carta 353

    Domanda

    Why are larger binary hydrides down a group often stronger acids?

    Risposta

    The H–A bond becomes weaker as the central atom grows, so proton release is easier.

  354. Carta 354

    Domanda

    What mainly determines buffer capacity?

    Risposta

    The concentrations of both members of the conjugate acid–base pair. Increasing both concentrations at a fixed ratio increases capacity without changing pH; capacity is best balanced for added acid and base when their concentrations are similar.

  355. Carta 355

    Domanda

    Why does acid increase CaCO₃ solubility?

    Risposta

    H₃O⁺ converts CO₃²⁻ to HCO₃⁻ or carbonic acid species, reducing free carbonate and driving more CaCO₃ to dissolve.

  356. Carta 356

    Domanda

    What does pH < pKa imply for a weak-acid pair?

    Risposta

    The protonated form HA predominates over A⁻.

  357. Carta 357

    Domanda

    What happens when stoichiometrically equal amounts of a monoprotic weak acid and strong base are mixed?

    Risposta

    The weak acid is consumed to its conjugate base; at equivalence, the solution isn't a buffer containing both forms.

  358. Carta 358

    Domanda

    What is [H₃O⁺] when pH = 4.50?

    Risposta

    3.2 × 10^-5 M, from [H₃O⁺] = 10^-pH.

  359. Carta 359

    Domanda

    What is the pH of 0.010 M Ba(OH)₂ at 25°C?

    Risposta

    About 12.30. Complete dissociation gives [OH⁻] = 0.020 M, so pOH = 1.70. At 25°C, pH + pOH = 14.00, so pH = 12.30.

  360. Carta 360

    Domanda

    How does a buffer respond to a small amount of added strong acid?

    Risposta

    Its conjugate base consumes H⁺, converting to the weak acid and limiting the pH change.

  361. Carta 361

    Domanda

    Why is the equivalence-point solution basic in a monoprotic weak-acid–strong-base titration?

    Risposta

    The conjugate base produced at equivalence reacts with water to form OH⁻, so the pH is above neutral—above 7.00 at 25°C.

  362. Carta 362

    Domanda

    How is percent ionization calculated for a weak acid or weak base?

    Risposta

    For HA, use ([H₃O⁺]equilibrium ÷ [HA]initial) × 100%. For B, use ([BH⁺]equilibrium ÷ [B]initial) × 100%, under the usual monoprotic setup.

  363. Carta 363

    Domanda

    When is Henderson–Hasselbalch useful for an initial buffer-pH calculation?

    Risposta

    Use it when both members of a conjugate acid–base pair are present in meaningful amounts, including after in-scope stoichiometry creates a buffer. Calculating the pH change after acid or base is added to an existing buffer is outside this deck’s scope.

  364. Carta 364

    Domanda

    Why does adding oxygen atoms usually strengthen oxyacids with the same central atom?

    Risposta

    Extra oxygens withdraw electron density and delocalize negative charge in the conjugate base.

  365. Carta 365

    Domanda

    A prepared buffer is accidentally diluted to twice its intended volume; what happens to its pH and capacity?

    Risposta

    Its pH stays nearly the same, and its capacity per liter is halved because both component concentrations halve. The total neutralizing moles in the sample remain unchanged.

  366. Carta 366

    Domanda

    How does adding OH⁻ affect Mg(OH)₂ solubility?

    Risposta

    It decreases solubility through the common-ion effect, shifting Mg(OH)₂(s) ⇌ Mg²⁺ + 2OH⁻ toward the solid.

  367. Carta 367

    Domanda

    A buffer has equal [A⁻] and [HA]; what is its pH?

    Risposta

    pH = pKa because log(1) = 0.

  368. Carta 368

    Domanda

    How should a weak acid–strong base mixture be solved before equivalence?

    Risposta

    First use mole stoichiometry; if both HA and A⁻ remain, use the resulting buffer relation.

  369. Carta 369

    Domanda

    Why can pure neutral water have a pH other than 7.00?

    Risposta

    Kw changes with temperature. Neutrality means [H₃O⁺] = [OH⁻], while pH = 7.00 only when Kw = 1.0 × 10^-14 at 25°C.

  370. Carta 370

    Domanda

    25.0 mL of 0.200 M HCl is diluted to 100.0 mL; what is the pH?

    Risposta

    1.301. Dilution gives [H₃O⁺] = (0.200 M)(25.0 mL)/(100.0 mL) = 0.0500 M, so pH = -log(0.0500).

  371. Carta 371

    Domanda

    How does a buffer respond to a small amount of added strong base?

    Risposta

    The weak acid consumes OH⁻, forming conjugate base and water.

  372. Carta 372

    Domanda

    How do you find the final pH after mixing a strong acid and strong base at 25°C?

    Risposta

    Use H₃O⁺ + OH⁻ → 2H₂O and compare their moles. Divide excess H₃O⁺ or OH⁻ by the total volume, then calculate pH or pOH from that excess concentration. Equal moles give pH 7.00 at 25°C.

  373. Carta 373

    Domanda

    What distinguishes acid strength from acid concentration?

    Risposta

    Strength is the equilibrium tendency to donate H⁺, reflected by Ka or pKa; concentration is the amount of acid per solution volume.

  374. Carta 374

    Domanda

    If [A⁻]/[HA] = 10, how does pH compare with pKa?

    Risposta

    pH = pKa + 1 because log 10 = 1.

  375. Carta 375

    Domanda

    Which conjugate base is more stable, one with localized or resonance-delocalized charge?

    Risposta

    The resonance-delocalized conjugate base, which generally corresponds to the stronger acid.

  376. Carta 376

    Domanda

    Which 1.0 L buffer has greater capacity: 1.0 mol each of HA/A⁻ or 0.10 mol each at the same ratio?

    Risposta

    The 1.0 mol pair; both have the same initial pH, but the larger amounts neutralize more added acid or base.

  377. Carta 377

    Domanda

    For BHX(s) ⇌ BH⁺ + X⁻, why can raising pH increase the salt's solubility?

    Risposta

    OH⁻ consumes BH⁺ to form B and H₂O, so dissolution shifts right to replace BH⁺. This is a qualitative prediction, not a pH-dependent solubility calculation.

  378. Carta 378

    Domanda

    What does pH > pKa imply for a weak-acid pair?

    Risposta

    The deprotonated form A⁻ predominates over HA.

  379. Carta 379

    Domanda

    For HA + B ⇌ A⁻ + BH⁺, which side is favored when pKa(HA) = 4 and pKa(BH⁺) = 9?

    Risposta

    Products are favored. Proton transfer moves toward the weaker acid–base pair, and K ≈ 10^(9 − 4) = 10^5.

  380. Carta 380

    Domanda

    What is the pOH when [OH⁻] = 2.5 × 10^-4 M?

    Risposta

    3.60, from -log(2.5 × 10^-4).

  381. Carta 381

    Domanda

    What is the pH of 0.100 M HA when Ka = 1.0 × 10^-5?

    Risposta

    About 3.00. The ICE setup gives Ka = x²/(0.100 − x); x ≈ 1.0 × 10^-3 M, and the 1.0% change validates the approximation.

  382. Carta 382

    Domanda

    Why does a buffer fail after too much strong acid is added?

    Risposta

    Its conjugate base is depleted, so added H⁺ is no longer consumed effectively.

  383. Carta 383

    Domanda

    What do two clear equivalence regions on an acid titration curve suggest?

    Risposta

    At least two distinguishable titratable protons; on a clean ideal curve with exactly two equivalence regions, this is consistent with a diprotic acid.

  384. Carta 384

    Domanda

    A buffer has pKa 4.8 and [A⁻]/[HA] = 0.10; what is pH?

    Risposta

    3.8, from 4.8 + log(0.10).

  385. Carta 385

    Domanda

    Why is HCl stronger than HF in water despite F being more electronegative?

    Risposta

    The H–F bond is much stronger; bond strength dominates this down-group binary-acid comparison.

  386. Carta 386

    Domanda

    Why does percent ionization increase when a weak acid is diluted?

    Risposta

    Dilution shifts ionization toward more particles, so a larger fraction ionizes even though [H₃O⁺] decreases.

  387. Carta 387

    Domanda

    A buffer contains more HA than A⁻. Which addition can it neutralize in greater amount: strong acid or strong base?

    Risposta

    Strong base. The larger HA reserve consumes more added OH⁻; a buffer with more A⁻ than HA instead has greater capacity for added strong acid.

  388. Carta 388

    Domanda

    Why can removing a basic anion increase a salt's molar solubility without changing Ksp?

    Risposta

    The equilibrium shifts to replace the consumed ion; Ksp remains fixed at the same temperature.

  389. Carta 389

    Domanda

    Why can an acid–base indicator change color as pH changes?

    Risposta

    Its protonated and deprotonated forms have different colors or other observable properties, and their relative amounts change with pH.

  390. Carta 390

    Domanda

    What buffer results from mixing 1.0 mol HA with 0.40 mol OH⁻?

    Risposta

    0.60 mol HA and 0.40 mol A⁻ remain, forming a buffer before any equilibrium calculation.

  391. Carta 391

    Domanda

    What is the pH of 0.200 M weak base B when Kb = 2.0 × 10^-5 at 25°C?

    Risposta

    About 11.30. The ICE setup gives Kb = x²/(0.200 − x); x ≈ 2.0 × 10^-3 M OH⁻, and the 1.0% change validates the approximation.

  392. Carta 392

    Domanda

    Why does a weak acid alone not make an effective buffer?

    Risposta

    It lacks a substantial conjugate-base reserve to consume added strong acid.

  393. Carta 393

    Domanda

    What controls pH after excess strong base passes equivalence?

    Risposta

    The concentration of excess OH⁻ after accounting for reaction stoichiometry and total volume.

  394. Carta 394

    Domanda

    How should an indicator be chosen for a titration?

    Risposta

    Its color-change range should fall within the steep pH change near the equivalence point.

  395. Carta 395

    Domanda

    How can a measured pH and known pKa give a conjugate-base/acid ratio?

    Risposta

    Rearrange Henderson–Hasselbalch: [A⁻]/[HA] = 10^(pH − pKa).

  396. Carta 396

    Domanda

    Can a weak base and its conjugate acid form a buffer?

    Risposta

    Yes, when both are present in significant amounts.

  397. Carta 397

    Domanda

    For equal-volume buffers with the same conjugate-base/acid ratio, how does adding the same amount of strong acid affect a more concentrated versus less concentrated buffer?

    Risposta

    The concentrated buffer changes pH less because it has greater capacity.

  398. Carta 398

    Domanda

    How does equivalence-point pH compare for strong acid–strong base, weak acid–strong base, and weak base–strong acid titrations at 25°C?

    Risposta

    Strong acid–strong base: pH 7.00. Weak acid–strong base: above 7.00 because the conjugate base reacts with water. Weak base–strong acid: below 7.00 because the conjugate acid reacts with water.

  399. Carta 399

    Domanda

    Why should mole ratios replace concentration ratios after mixing buffer solutions?

    Risposta

    Both components share the same final volume, so that volume cancels in [A⁻]/[HA].

  400. Carta 400

    Domanda

    How does adding a little strong acid change a buffer's conjugate-base and conjugate-acid amounts?

    Risposta

    The conjugate base decreases and its conjugate acid increases by the amount of strong acid consumed.

  401. Carta 401

    Domanda

    What does entropy measure qualitatively?

    Risposta

    The dispersal of matter and energy among available microstates.

  402. Carta 402

    Domanda

    How is standard reaction entropy calculated?

    Risposta

    ΔS°rxn = ΣνS°(products) − ΣνS°(reactants).

  403. Carta 403

    Domanda

    What equation gives ΔG° from ΔH° and ΔS°, and what standard states do the degree symbols assume?

    Risposta

    ΔG° = ΔH° − TΔS°. The standard states are pure substances, 1.0 M solutions, and gases at 1 atm or 1 bar; T is in kelvins and energy units must match.

  404. Carta 404

    Domanda

    Does thermodynamic favorability guarantee a fast reaction?

    Risposta

    No. A favorable reaction can be slow when its activation barrier is large.

  405. Carta 405

    Domanda

    What is ΔG at equilibrium?

    Risposta

    Zero under the current conditions because there is no net driving force.

  406. Carta 406

    Domanda

    Why can an endothermic dissolution still be thermodynamically favorable?

    Risposta

    A sufficiently positive entropy change can make TΔS exceed positive ΔH, giving negative ΔG.

  407. Carta 407

    Domanda

    How can an unfavorable reaction be driven by a favorable one?

    Risposta

    Couple them so their equations and ΔG values add to a negative overall ΔG.

  408. Carta 408

    Domanda

    Where does oxidation occur in every electrochemical cell?

    Risposta

    At the anode.

  409. Carta 409

    Domanda

    How are standard cell potential and standard free energy related?

    Risposta

    ΔG° = -nFE°cell.

  410. Carta 410

    Domanda

    What equation gives cell potential under nonstandard conditions?

    Risposta

    E = E° − (RT/nF) ln Q. When Q = 1, ln Q = 0, so E = E°.

  411. Carta 411

    Domanda

    How is electrical charge related to current and time?

    Risposta

    q = It.

  412. Carta 412

    Domanda

    Which phase has greater molar entropy, liquid water or ice at the same temperature?

    Risposta

    Liquid water because its molecules have more accessible arrangements and motion.

  413. Carta 413

    Domanda

    Do elements in their standard states have zero standard molar entropy?

    Risposta

    No. Their ΔHf° is zero, but their absolute S° values are positive above 0 K.

  414. Carta 414

    Domanda

    How do the four ΔH° and ΔS° sign combinations determine thermodynamic favorability across temperature?

    Risposta

    ΔH° < 0 and ΔS° > 0 is favorable at every temperature; ΔH° > 0 and ΔS° < 0 is thermodynamically unfavored at every temperature. If both are positive, favorability requires high temperature; if both are negative, it requires low temperature.

  415. Carta 415

    Domanda

    What does it indicate when a thermodynamically favored process does not occur at a measurable rate?

    Risposta

    It is under kinetic control, commonly because of a high activation energy; no measurable reaction does not mean the system is at equilibrium.

  416. Carta 416

    Domanda

    How are ΔG° and K related?

    Risposta

    ΔG° = -RT ln K.

  417. Carta 417

    Domanda

    What two contributions compete in dissolving an ionic solid?

    Risposta

    Enthalpy changes from separating and solvating particles, and entropy changes from their new dispersal and solvent organization.

  418. Carta 418

    Domanda

    What must cancel when coupled reactions are added?

    Risposta

    Shared intermediates, leaving the desired net reaction.

  419. Carta 419

    Domanda

    Where does reduction occur in every electrochemical cell?

    Risposta

    At the cathode.

  420. Carta 420

    Domanda

    What sign of E°cell indicates a favorable standard galvanic reaction?

    Risposta

    Positive E°cell, corresponding to negative ΔG°.

  421. Carta 421

    Domanda

    If Q increases for a galvanic reaction, how does E change at fixed temperature?

    Risposta

    E decreases according to the Nernst equation. Le Châtelier's principle does not apply to an operating cell away from equilibrium; use Q and Nernst reasoning instead.

  422. Carta 422

    Domanda

    How are moles of electrons found from charge?

    Risposta

    Moles e⁻ = q/F, where F ≈ 96485 C mol^-1 e⁻.

  423. Carta 423

    Domanda

    How does producing more gas particles usually affect system entropy?

    Risposta

    It increases entropy because the particles have more positional microstates.

  424. Carta 424

    Domanda

    Can a dissolution with negative ΔH be unfavorable?

    Risposta

    Yes. A sufficiently negative entropy change at the stated temperature can make ΔG positive.

  425. Carta 425

    Domanda

    When can a process with ΔH > 0 and ΔS > 0 become favorable?

    Risposta

    At sufficiently high temperature, when TΔS exceeds ΔH.

  426. Carta 426

    Domanda

    How does a catalyst affect ΔG?

    Risposta

    It does not change ΔG; it lowers the activation barrier for both directions.

  427. Carta 427

    Domanda

    For A → B, ΔGf°(A) = -50 kJ mol^-1 and ΔGf°(B) = -80 kJ mol^-1. What is ΔG°rxn?

    Risposta

    -30 kJ mol^-1. Use ΣνΔGf°(products) − ΣνΔGf°(reactants) = -80 − (-50).

  428. Carta 428

    Domanda

    Why can dissolving a gas in a liquid have a negative entropy change?

    Risposta

    Gas particles lose much of their translational freedom when confined and solvated in the liquid.

  429. Carta 429

    Domanda

    If coupled steps have ΔG values +20 kJ and -35 kJ, what is overall ΔG?

    Risposta

    -15 kJ, so the combined process is thermodynamically favorable under those conditions.

  430. Carta 430

    Domanda

    What role does each half-cell solution play in an electrochemical cell?

    Risposta

    It supplies dissolved redox species at an electrode interface and carries ions within its compartment. Separate compartments prevent direct mixing while the external circuit and salt bridge connect the half-cells.

  431. Carta 431

    Domanda

    How is E°cell found from standard reduction potentials?

    Risposta

    E°cell = E°cathode − E°anode, using both tabulated values as reductions.

  432. Carta 432

    Domanda

    How does a cell's potential magnitude change as Q approaches or moves away from K, and what is E at equilibrium?

    Risposta

    |E| falls toward zero as Q approaches K and grows as the system moves farther from equilibrium. At equilibrium, Q = K and E = 0.

  433. Carta 433

    Domanda

    How many moles of electrons pass when 1.93 × 10^5 C flows?

    Risposta

    2.00 mol e⁻, from q/F.

  434. Carta 434

    Domanda

    How does a salt bridge maintain charge balance in a galvanic cell?

    Risposta

    Anions migrate toward the anode compartment and cations toward the cathode compartment, countering the net charge imbalances created by the two half-reactions.

  435. Carta 435

    Domanda

    Why does raising a substance's temperature generally increase its entropy?

    Risposta

    Energy spreads across more accessible particle energy states, increasing the number of possible microscopic arrangements.

  436. Carta 436

    Domanda

    When can a process with ΔH < 0 and ΔS < 0 be favorable?

    Risposta

    At sufficiently low temperature, where the unfavorable -TΔS term is small.

  437. Carta 437

    Domanda

    Why can diamond persist even though graphite is more stable at standard conditions?

    Risposta

    Conversion has a large activation barrier, so diamond is kinetically persistent.

  438. Carta 438

    Domanda

    What do the external circuit and measuring device do in an electrochemical cell?

    Risposta

    The circuit carries electrons from anode to cathode; a voltmeter measures potential difference, while an ammeter in series measures current.

  439. Carta 439

    Domanda

    At constant temperature, how does increasing the volume available to a gas affect its entropy?

    Risposta

    Entropy increases because the gas particles can occupy more positions in the larger space, so more microstates are accessible.

  440. Carta 440

    Domanda

    How does reversing one coupled reaction affect its ΔG?

    Risposta

    It reverses the sign of that reaction's ΔG.

  441. Carta 441

    Domanda

    Why is n required in ΔG° = -nFE°?

    Risposta

    It is the moles of electrons transferred per balanced reaction, linking charge flow to reaction extent.

  442. Carta 442

    Domanda

    What makes an electrolytic cell operate?

    Risposta

    An external power source drives a thermodynamically unfavorable redox reaction; oxidation still occurs at the anode and reduction at the cathode.

  443. Carta 443

    Domanda

    In an Mⁿ⁺/M concentration cell, which half-cell is the anode: the dilute or concentrated ion solution?

    Risposta

    The dilute half-cell. Oxidation produces Mⁿ⁺ there, while reduction consumes Mⁿ⁺ in the concentrated half-cell, so electrons flow from dilute to concentrated as the concentrations move toward equality.

  444. Carta 444

    Domanda

    How is deposited metal mass found from current and time?

    Risposta

    Find q = It, convert q/F to moles e⁻, use the half-reaction ratio to moles metal, then multiply by molar mass.

  445. Carta 445

    Domanda

    Given product S° total 500 J mol^-1 K^-1 and reactant total 420 J mol^-1 K^-1, what is ΔS°?

    Risposta

    +80 J mol^-1 K^-1.

  446. Carta 446

    Domanda

    How do electrode masses change in a Zn–Cu galvanic cell?

    Risposta

    The Zn anode loses mass as Zn → Zn²⁺ + 2e⁻, while the Cu cathode gains mass as Cu²⁺ + 2e⁻ → Cu.

  447. Carta 447

    Domanda

    What is ΔG° when ΔH° = 50 kJ mol^-1, ΔS° = 0.200 kJ mol^-1 K^-1, and T = 300 K?

    Risposta

    -10 kJ mol^-1, from ΔG° = 50 − (300)(0.200).

  448. Carta 448

    Domanda

    Why can temperature change a solid's solubility?

    Risposta

    Temperature changes the balance of ΔH and TΔS, so it changes the free energy of dissolution and the equilibrium constant.

  449. Carta 449

    Domanda

    What does the size of ΔG° relative to RT imply about K?

    Risposta

    ΔG° near zero gives K near 1. When |ΔG°| is much larger than RT, K is far from 1: negative ΔG° gives K ≫ 1, while positive ΔG° gives K ≪ 1.

  450. Carta 450

    Domanda

    Bubbles form at an inert cathode in acidic solution; which half-reaction can explain them?

    Risposta

    2H⁺ + 2e⁻ → H₂(g). Gas evolution at the cathode can be direct evidence of reduction.

Translucent laboratory glassware, particle clusters, and flowing blue-to-amber energy curves on a dark background.

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AP Chemistry Flashcards: Complete 9-Unit Course Review

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