AP Chemistry Flashcards: Complete 9-Unit Course Review

Review all nine AP Chemistry units with 450 cards covering concepts, models, equations, calculation setup, and laboratory reasoning.

Kuhusu fungu hili

Review AP® Chemistry through 450 independently written English flashcards arranged in the course's nine-unit sequence. The deck moves from atomic structure and compound structure through properties of substances and mixtures, reactions, kinetics, thermochemistry, equilibrium, acids and bases, and thermodynamics and electrochemistry. Prerequisites come before dependent models and calculations.

What the cards practice

The cards use five recall paths: concept to explanation; model or representation to interpretation; equation to meaning and use; short setup to a result with units and reasoning; and laboratory observation to a chemical conclusion. They cover definitions, relationships, conditions, contrasts, particle and energy models, focused calculation steps, measurements, errors, and visible changes.

Selected reverse and contrast prompts appear only when the reverse direction has one clear standalone target. The deck excludes mechanical permutations, graph-dependent prompts that require a missing figure, copied test formats, long multipart derivations, and visual recall tied to third-party figures. The review scheduler handles long-term spacing after installation.

See the official AP Chemistry course page for College Board's current course requirements.

The Common knowledge · CC0 1.0 label applies only to the independently written prompts, answers, examples, organization, metadata, and inherited original cover, to the extent applicable rights exist. It does not claim ownership of scientific facts or equations.

This is an independent, unofficial study aid. It is not affiliated with, endorsed by, sponsored by, or official material from College Board or the AP Program. AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this product. No College Board examination questions, answer choices, scoring materials, curriculum text, logos, or trade dress were copied.

Kadi za fungu hili

  1. Kadi namba 1

    Swali

    What does one mole count?

    Jibu

    Exactly 6.02214076 × 10^23 representative particles.

  2. Kadi namba 2

    Swali

    What does a peak in an element's mass spectrum represent?

    Jibu

    An isotope with a particular mass-to-charge ratio; for singly charged monatomic ions, the position tracks isotopic mass.

  3. Kadi namba 3

    Swali

    What does an empirical formula show?

    Jibu

    The lowest whole-number ratio of the elements' atoms in a compound.

  4. Kadi namba 4

    Swali

    How does a mixture differ from a pure substance at the particle level?

    Jibu

    A mixture contains chemically distinct representative units in variable proportions; a pure substance contains one element or compound with fixed composition. Different isotopes do not make an elemental sample a mixture.

  5. Kadi namba 5

    Swali

    Which particles make up an atom's nucleus?

    Jibu

    Protons and neutrons. Electrons occupy the space outside the nucleus.

  6. Kadi namba 6

    Swali

    What does a larger binding energy on a PES spectrum mean?

    Jibu

    More energy is required to remove that electron, so it is held more strongly by the nucleus.

  7. Kadi namba 7

    Swali

    How does atomic radius generally change across a period and down a group?

    Jibu

    It decreases from left to right as effective nuclear charge rises, and it increases down a group as additional electron shells increase distance and shielding.

  8. Kadi namba 8

    Swali

    What typical ion charge do Group 1 metals form?

    Jibu

    +1, by losing their one valence electron.

  9. Kadi namba 9

    Swali

    How do you convert moles to particles?

    Jibu

    Multiply by Avogadro's number: particles = moles × 6.022 × 10^23 mol^-1.

  10. Kadi namba 10

    Swali

    How is average atomic mass estimated from isotope data?

    Jibu

    Add each isotopic mass multiplied by its fractional abundance.

  11. Kadi namba 11

    Swali

    How is an element's mass percent in a compound calculated?

    Jibu

    Divide the mass contributed by that element by the compound's molar mass, then multiply by 100%.

  12. Kadi namba 12

    Swali

    How can measured elemental composition reveal a sample's purity?

    Jibu

    Compare the measured mass fraction with the fraction expected for the pure compound; a mismatch indicates another component.

  13. Kadi namba 13

    Swali

    How do you build a ground-state electron configuration with the Aufbau principle?

    Jibu

    For ordinary ground states, move through the periodic table in atomic-number order, filling each s, p, d, or f block as it appears. The subshell capacities are s², p⁶, d¹⁰, and f¹⁴. For example, Br is [Ar] 4s² 3d¹⁰ 4p⁵.

  14. Kadi namba 14

    Swali

    What does the relative area or height of an ideal PES peak indicate?

    Jibu

    The relative number of electrons in the corresponding subshell.

  15. Kadi namba 15

    Swali

    How does first ionization energy generally change across a period and down a group?

    Jibu

    It increases from left to right as effective nuclear charge rises, and it decreases down a group as distance and shielding make a valence electron easier to remove.

  16. Kadi namba 16

    Swali

    Why do elements in the same group form similar compounds?

    Jibu

    Their ground-state valence patterns repeat, including which outer subshells are full or partly full. That leads to similar bonding and typical ion charges.

  17. Kadi namba 17

    Swali

    How do you convert a sample's mass to moles?

    Jibu

    Divide its mass by its molar mass: n = m/M.

  18. Kadi namba 18

    Swali

    Which mass-spectrum interpretation lies outside the usual single-element model used in this deck?

    Jibu

    Assigning peaks in mixtures or peaks from multiply charged or polyatomic species; the standard model uses singly charged monatomic ions of one element.

  19. Kadi namba 19

    Swali

    What does the law of definite proportions state?

    Jibu

    Every pure sample of a given compound has the same element mass ratios.

  20. Kadi namba 20

    Swali

    Why can two samples of the same mixture have different compositions?

    Jibu

    Mixture components are physically combined, so their relative amounts are not fixed by a chemical formula.

  21. Kadi namba 21

    Swali

    How does Coulomb's law connect charge and separation to attraction?

    Jibu

    Attraction grows with the magnitude of the charge product and decreases with the square of the separation distance.

  22. Kadi namba 22

    Swali

    Which PES electrons usually appear at the highest binding energy?

    Jibu

    Core electrons closest to the nucleus, because they feel the strongest nuclear attraction.

  23. Kadi namba 23

    Swali

    How does electron affinity generally change across a period and down a group?

    Jibu

    Electron gain generally becomes more favorable from left to right across a period and less favorable down a group as distance and shielding increase. Stable subshell patterns create substantial exceptions.

  24. Kadi namba 24

    Swali

    Why are alkali metals generally more reactive down the group?

    Jibu

    Their valence electron is farther from the nucleus and easier to remove.

  25. Kadi namba 25

    Swali

    How many moles are in 18.0 g of H₂O?

    Jibu

    About 0.999 mol. Use 18.0 g ÷ 18.02 g mol^-1.

  26. Kadi namba 26

    Swali

    An element is 75% isotope 10 and 25% isotope 11; what is its average atomic mass?

    Jibu

    10.25 u. Calculate (0.75 × 10) + (0.25 × 11).

  27. Kadi namba 27

    Swali

    A compound is 40.0% C, 6.7% H, and 53.3% O by mass; what is its empirical formula?

    Jibu

    CH₂O. For a 100 g sample, convert each mass to moles and divide by the smallest amount.

  28. Kadi namba 28

    Swali

    A 10.0 g impure sample contains 8.5 g of the target compound; what is its mass-percent purity?

    Jibu

    85%. Calculate (8.5 g ÷ 10.0 g) × 100%.

  29. Kadi namba 29

    Swali

    Which electrons are removed first when a transition metal forms a cation?

    Jibu

    Electrons in the occupied orbital with the highest principal quantum number: 4s before 3d. For example, Fe²⁺ is [Ar] 3d⁶.

  30. Kadi namba 30

    Swali

    A PES spectrum has peaks proportional to 2, 2, and 6 electrons; which configuration fits?

    Jibu

    1s² 2s² 2p⁶, the configuration of Ne.

  31. Kadi namba 31

    Swali

    How does electronegativity generally change across a period and down a group?

    Jibu

    It increases from left to right across a period and decreases down a group as atomic size and shielding increase.

  32. Kadi namba 32

    Swali

    What empirical formula results from Al³⁺ and O²⁻?

    Jibu

    Al₂O₃, because two Al³⁺ ions balance three O²⁻ ions.

  33. Kadi namba 33

    Swali

    How does a particle's mass in atomic mass units relate to its molar mass?

    Jibu

    The numerical value is the same: a molecular or formula-unit mass of x u corresponds to a molar mass of x g mol^-1.

  34. Kadi namba 34

    Swali

    What does the tallest isotope peak usually indicate in a simple mass spectrum?

    Jibu

    The most abundant isotope, assuming comparable detection response and singly charged ions.

  35. Kadi namba 35

    Swali

    How much oxygen is present in 25.0 g of a compound that is 32.0% oxygen by mass?

    Jibu

    8.00 g O. Multiply 25.0 g by 0.320.

  36. Kadi namba 36

    Swali

    What does a particle diagram with two unbonded species in changing ratios represent?

    Jibu

    A mixture, because more than one particle type is present and the ratio is not fixed in a formula unit.

  37. Kadi namba 37

    Swali

    What distinguishes valence electrons from core electrons?

    Jibu

    Valence electrons are available for bonding or ion formation; main-group valence electrons occupy the outermost shell, while transition metals may also use (n−1)d electrons. Core electrons mainly shield nuclear charge.

  38. Kadi namba 38

    Swali

    Why can PES peak groups reveal an atom's occupied subshells?

    Jibu

    Electrons in different subshells require distinct removal energies, producing separate binding-energy groups.

  39. Kadi namba 39

    Swali

    How do ion radii compare with neutral atoms and within an isoelectronic series?

    Jibu

    Cations are smaller than their neutral atoms, while anions are larger. Among species with the same electron count, more protons pull the electrons closer and produce the smaller radius.

  40. Kadi namba 40

    Swali

    What formula is expected for a compound between a Group 2 metal M and a Group 17 nonmetal X?

    Jibu

    MX₂, because M forms M²⁺ and X forms X⁻.

  41. Kadi namba 41

    Swali

    When is a covalent bond considered nonpolar?

    Jibu

    When the bonded atoms have identical or very similar electronegativities, so the shared electron density is distributed approximately evenly.

  42. Kadi namba 42

    Swali

    Why does a bonded pair of atoms have an equilibrium bond length?

    Jibu

    At that separation, attractive and repulsive interactions balance at minimum potential energy.

  43. Kadi namba 43

    Swali

    How are particles arranged in an ionic solid?

    Jibu

    Cations and anions occupy a repeating three-dimensional lattice held by electrostatic attraction.

  44. Kadi namba 44

    Swali

    What model explains bonding in a metal?

    Jibu

    Positive metal cores are held together by attraction to mobile, delocalized valence electrons.

  45. Kadi namba 45

    Swali

    How do you construct a Lewis diagram?

    Jibu

    Count total valence electrons, adding electrons for a negative charge and subtracting them for a positive charge. Choose a skeleton, connect atoms with single bonds, complete terminal duets or octets, and place remaining electrons on the central atom. Add multiple bonds if needed, then check the electron total and formal charges.

  46. Kadi namba 46

    Swali

    What does resonance mean in a molecule or ion?

    Jibu

    Resonance uses two or more valid Lewis diagrams with the same atom arrangement but different electron placement. The actual electron distribution is a hybrid; equivalent contributors have equal weight.

  47. Kadi namba 47

    Swali

    What determines molecular shape in VSEPR theory?

    Jibu

    Electron domains around the central atom arrange to minimize repulsions.

  48. Kadi namba 48

    Swali

    How does an ionic bond differ from a covalent bond?

    Jibu

    Ionic bonding is attraction among oppositely charged ions in an extended structure; covalent bonding uses shared electron density between atoms.

  49. Kadi namba 49

    Swali

    What happens to potential energy when bonded atoms are pushed much closer than equilibrium?

    Jibu

    Potential energy rises sharply because nucleus–nucleus and electron–electron repulsions dominate.

  50. Kadi namba 50

    Swali

    Why are many ionic solids brittle?

    Jibu

    A shifted lattice can align like charges, creating strong repulsion that splits the crystal.

  51. Kadi namba 51

    Swali

    What molecular shapes arise from two electron domains with no lone pairs and from three domains with zero or one lone pair?

    Jibu

    Two bonding domains give linear with a 180° angle. Three domains with no lone pairs give trigonal planar with 120° angles; replacing one bond with a lone pair gives bent with an angle slightly below 120°.

  52. Kadi namba 52

    Swali

    Why are metals electrically conductive as solids?

    Jibu

    Their delocalized electrons can move through the solid when an electric field is applied.

  53. Kadi namba 53

    Swali

    How is formal charge calculated for an atom in a Lewis diagram?

    Jibu

    Formal charge = valence electrons − nonbonding electrons − half the bonding electrons.

  54. Kadi namba 54

    Swali

    Why can't electronegativity difference alone classify a bond as ionic or covalent?

    Jibu

    Bonding lies on a continuum. A larger difference means more ionic character, but the element types and especially the compound's properties give the best classification.

  55. Kadi namba 55

    Swali

    Which shapes and bond-angle trends arise as lone pairs replace bonds in four electron domains?

    Jibu

    Four bonds give tetrahedral with ideal 109.5° angles. One lone pair gives trigonal pyramidal with smaller angles; two lone pairs give bent with typically smaller angles again because lone pairs repel more strongly than bonding pairs.

  56. Kadi namba 56

    Swali

    What feature of a potential-energy curve represents bond dissociation energy?

    Jibu

    The energy difference from the curve's minimum to the separated-atoms limit.

  57. Kadi namba 57

    Swali

    When does an ionic compound conduct electricity?

    Jibu

    When molten or dissolved so its ions can move; not as a rigid solid lattice.

  58. Kadi namba 58

    Swali

    What is a substitutional alloy?

    Jibu

    An alloy in which atoms of a similar size replace some host-metal atoms in the lattice.

  59. Kadi namba 59

    Swali

    How do two, three, and four electron domains map to hybridization?

    Jibu

    Two domains map to sp, three to sp², and four to sp³, with ideal angles of 180°, 120°, and 109.5°. Hybridization involving d orbitals is outside this deck’s scope.

  60. Kadi namba 60

    Swali

    What usually makes one resonance contributor more favorable than another?

    Jibu

    Smaller formal-charge magnitudes, appropriate negative charge on more electronegative atoms, and complete valence shells where applicable.

  61. Kadi namba 61

    Swali

    How many sigma and pi bonds are in single, double, and triple bonds?

    Jibu

    A single bond has one sigma bond; a double has one sigma and one pi bond; a triple has one sigma and two pi bonds. Head-on sigma overlap is stronger than side-by-side pi overlap.

  62. Kadi namba 62

    Swali

    Why is a polar covalent bond polar?

    Jibu

    Unequal electronegativity creates an uneven sharing of electron density and partial charges.

  63. Kadi namba 63

    Swali

    Which molecular shapes arise as lone pairs replace bonds in five electron domains?

    Jibu

    Five bonds give trigonal bipyramidal; four bonds and one lone pair give seesaw; three bonds and two lone pairs give T-shaped; two bonds and three lone pairs give linear.

  64. Kadi namba 64

    Swali

    How do ionic charge and ionic radius affect attraction between ions?

    Jibu

    Larger charge magnitudes and smaller ionic radii produce stronger attraction because the charge product increases and the ion centers are closer.

  65. Kadi namba 65

    Swali

    Why do ionic solids often have high melting points?

    Jibu

    Many strong Coulombic attractions throughout the lattice must be overcome to free the ions.

  66. Kadi namba 66

    Swali

    What is an interstitial alloy?

    Jibu

    A smaller atom occupies holes between host-metal atoms, often making lattice layers harder to slide.

  67. Kadi namba 67

    Swali

    What shape has six bonding domains and no lone pairs on the central atom?

    Jibu

    Octahedral.

  68. Kadi namba 68

    Swali

    Which elements commonly form incomplete octets in stable Lewis diagrams?

    Jibu

    Hydrogen forms a duet, and electron-deficient central atoms such as boron or beryllium can have fewer than eight electrons.

  69. Kadi namba 69

    Swali

    How do bond order and atomic size affect covalent bond length and strength?

    Jibu

    Within a comparable bond family, higher bond order gives shorter, stronger bonds. Larger bonded atoms generally give longer bonds, which are often weaker because their orbitals overlap less effectively.

  70. Kadi namba 70

    Swali

    What bonding model best fits a sample that is malleable and conducts as a solid?

    Jibu

    Metallic bonding with mobile, delocalized electrons and nondirectional attractions.

  71. Kadi namba 71

    Swali

    What shape has six electron domains, five bonds, and one lone pair?

    Jibu

    Square pyramidal.

  72. Kadi namba 72

    Swali

    Which lattice should have stronger attractions: MgO or NaCl, assuming similar separations?

    Jibu

    MgO, because the charge product for Mg²⁺ and O²⁻ is larger than for Na⁺ and Cl⁻.

  73. Kadi namba 73

    Swali

    Why are pure metals often malleable?

    Jibu

    Metal cores can shift while the mobile electron sea maintains nondirectional attraction instead of exposing fixed like-charge planes.

  74. Kadi namba 74

    Swali

    What is the best Lewis structure for CO₂?

    Jibu

    O=C=O, with two lone pairs on each oxygen and no formal charges.

  75. Kadi namba 75

    Swali

    What shape has six electron domains, four bonds, and two opposite lone pairs?

    Jibu

    Square planar.

  76. Kadi namba 76

    Swali

    What limitation does an odd total number of valence electrons create for a Lewis diagram?

    Jibu

    At least one electron must remain unpaired, so not every atom can have a complete paired-electron octet.

  77. Kadi namba 77

    Swali

    What does a higher bond order do to a bond's potential-energy curve?

    Jibu

    It generally places the minimum at a shorter internuclear distance and makes the well deeper, corresponding to a shorter bond and a larger bond-dissociation energy.

  78. Kadi namba 78

    Swali

    When can a carbon–carbon double bond produce geometric isomers?

    Jibu

    When each carbon has two different substituents. The pi bond restricts rotation, so distinct spatial arrangements can persist.

  79. Kadi namba 79

    Swali

    When may a third-period central atom exceed an octet in a Lewis diagram?

    Jibu

    When the valid electron count and lower formal charges favor an expanded valence shell, as in species such as SF₆.

  80. Kadi namba 80

    Swali

    How do you decide whether a molecule with polar bonds is polar overall?

    Jibu

    Add the bond-dipole vectors using the molecular shape; symmetry may cancel them, while an asymmetric arrangement leaves a net dipole.

  81. Kadi namba 81

    Swali

    Which interparticle forces act between all atoms and molecules?

    Jibu

    London dispersion forces, caused by temporary and induced dipoles.

  82. Kadi namba 82

    Swali

    What four broad solid types does this deck compare?

    Jibu

    Ionic, metallic, molecular, and covalent-network solids.

  83. Kadi namba 83

    Swali

    How do gas particles differ from liquid particles?

    Jibu

    Gas particles are much farther apart and move independently; liquid particles stay close but can move past one another.

  84. Kadi namba 84

    Swali

    What relationship connects pressure, volume, amount, and temperature for an ideal gas?

    Jibu

    PV = nRT, with absolute temperature in kelvins and units consistent with R.

  85. Kadi namba 85

    Swali

    What does temperature measure in kinetic molecular theory?

    Jibu

    The particles' average translational kinetic energy.

  86. Kadi namba 86

    Swali

    What two ideal-gas assumptions fail most clearly for real gases?

    Jibu

    Particles have nonzero volume and experience intermolecular attractions.

  87. Kadi namba 87

    Swali

    How is molarity defined?

    Jibu

    Moles of solute per liter of solution: M = n/V.

  88. Kadi namba 88

    Swali

    What must a correct particulate diagram of NaCl(aq) show?

    Jibu

    Separated Na⁺ and Cl⁻ ions in a 1:1 ratio, each surrounded by oriented water molecules.

  89. Kadi namba 89

    Swali

    Which separation method removes an insoluble solid from a liquid?

    Jibu

    Filtration: the solid stays as residue while the liquid passes as filtrate.

  90. Kadi namba 90

    Swali

    What does “like dissolves like” mean at the particle level?

    Jibu

    A solute tends to dissolve when new solute–solvent attractions can compete with the attractions disrupted in the pure substances.

  91. Kadi namba 91

    Swali

    What happens when matter absorbs electromagnetic radiation?

    Jibu

    Its particles move to an allowed higher-energy state when the photon energy matches the energy gap.

  92. Kadi namba 92

    Swali

    Which equations connect photon energy, frequency, and wavelength?

    Jibu

    E = hν and c = λν.

  93. Kadi namba 93

    Swali

    What is the Beer–Lambert law?

    Jibu

    A = εbc: absorbance equals molar absorptivity at the chosen wavelength times path length times concentration.

  94. Kadi namba 94

    Swali

    What molecular features generally strengthen London dispersion forces?

    Jibu

    More electrons and a more polarizable cloud strengthen temporary dipoles; greater contact area and accessible π-electron density can also strengthen the attraction.

  95. Kadi namba 95

    Swali

    Why do molecular solids usually have low melting points and fail to conduct electricity?

    Jibu

    Distinct molecules are held together by relatively weak intermolecular forces, while their valence electrons stay localized in bonds and lone pairs.

  96. Kadi namba 96

    Swali

    How do particles move in a solid?

    Jibu

    They vibrate about fixed positions and do not translate past one another.

  97. Kadi namba 97

    Swali

    What graph shapes connect V or P with T(K) or n for an ideal gas?

    Jibu

    All four are straight lines through the origin: V versus T(K) at fixed n and P; P versus T(K) at fixed n and V; V versus n at fixed P and T; and P versus n at fixed V and T.

  98. Kadi namba 98

    Swali

    At the same temperature, which gas has the greater average molecular speed: He or Xe?

    Jibu

    He. Both have the same average kinetic energy, but KE = ½mv² means the lower-mass particles move faster.

  99. Kadi namba 99

    Swali

    Why do real gases deviate more at high pressure?

    Jibu

    Particles are crowded, so their own volume is no longer negligible compared with the container volume.

  100. Kadi namba 100

    Swali

    Which relationship describes dilution when solute amount is conserved?

    Jibu

    M₁V₁ = M₂V₂.

  101. Kadi namba 101

    Swali

    Why does an aqueous ionic solution conduct electricity?

    Jibu

    Dissolved ions are mobile and carry charge through the solution.

  102. Kadi namba 102

    Swali

    Which property lets simple distillation separate two liquids?

    Jibu

    A sufficient difference in volatility or boiling point, so the vapor is enriched in the more volatile component.

  103. Kadi namba 103

    Swali

    Why are many ionic compounds soluble in water but poorly soluble in a nonpolar solvent?

    Jibu

    Water can form strong ion–dipole attractions that stabilize separated ions; a nonpolar solvent cannot provide comparable attractions.

  104. Kadi namba 104

    Swali

    Which molecular transition is commonly associated with microwave absorption?

    Jibu

    A transition between quantized rotational energy levels.

  105. Kadi namba 105

    Swali

    What frequency corresponds to a 600. nm photon?

    Jibu

    5.00 × 10^14 s^-1. Use ν = c/λ with 600. nm = 6.00 × 10^-7 m.

  106. Kadi namba 106

    Swali

    What is the absorbance to two significant figures when ε = 2.0 × 10² L mol^-1 cm^-1, b = 1.00 cm, and c = 0.0020 M?

    Jibu

    0.40. Use A = εbc.

  107. Kadi namba 107

    Swali

    What conditions allow hydrogen bonding between two molecules?

    Jibu

    One molecule must donate an H covalently bonded to N, O, or F, and the other must provide a lone pair on N, O, or F. A molecule can be a donor, an acceptor, or both.

  108. Kadi namba 108

    Swali

    Why are covalent-network solids often very hard with high melting points?

    Jibu

    A continuous network of strong covalent bonds must be disrupted to deform or melt the solid.

  109. Kadi namba 109

    Swali

    Why do a substance's solid and liquid phases usually have similar molar volumes?

    Jibu

    Their particles remain in close contact in both phases, even though liquid particles can move past one another.

  110. Kadi namba 110

    Swali

    How is a gas mixture's total pressure related to its component pressures?

    Jibu

    Ptotal = ΣPi; each partial pressure is the pressure that component would exert alone in the same volume and temperature.

  111. Kadi namba 111

    Swali

    What microscopic events create gas pressure?

    Jibu

    Gas particles collide with container walls and transfer momentum.

  112. Kadi namba 112

    Swali

    Why do intermolecular attractions matter more for gases at low temperature?

    Jibu

    Particles move more slowly, so attractions can alter their paths and promote condensation.

  113. Kadi namba 113

    Swali

    What is the final concentration after 50.0 mL of 2.00 M solution is diluted to 200.0 mL?

    Jibu

    0.500 M. Use M₂ = M₁V₁/V₂.

  114. Kadi namba 114

    Swali

    What must a particulate representation of a solution communicate?

    Jibu

    The relative concentrations of its components and the particle-level interactions among those components.

  115. Kadi namba 115

    Swali

    What causes components to separate in chromatography?

    Jibu

    They differ in attraction to the stationary phase and the mobile phase, so they travel at different rates.

  116. Kadi namba 116

    Swali

    Why are many polar molecular solutes soluble in water?

    Jibu

    Dipole attractions or hydrogen bonds with water can replace the solute–solute and water–water attractions disrupted during mixing.

  117. Kadi namba 117

    Swali

    Why does an atom produce discrete spectral lines?

    Jibu

    Its electrons can occupy only quantized energy levels, so only photons matching allowed energy differences are absorbed or emitted.

  118. Kadi namba 118

    Swali

    How does photon energy change when frequency doubles?

    Jibu

    It doubles because E = hν.

  119. Kadi namba 119

    Swali

    Why is a calibration curve useful in spectrophotometry?

    Jibu

    It relates measured absorbance to known concentrations, letting an unknown concentration be read by interpolation within the linear range.

  120. Kadi namba 120

    Swali

    How does an ion–dipole attraction form, and how does it compare with dipole–dipole attraction?

    Jibu

    An ion attracts the oppositely charged end of a polar molecule. Ion–dipole attractions tend to be stronger than dipole–dipole attractions.

  121. Kadi namba 121

    Swali

    Which solid type is usually both conductive and malleable?

    Jibu

    A metallic solid, because its delocalized electrons move and its nondirectional bonding tolerates layer shifts.

  122. Kadi namba 122

    Swali

    How does a crystalline solid differ from an amorphous solid?

    Jibu

    A crystalline solid has long-range repeating order; an amorphous solid lacks that long-range periodic arrangement.

  123. Kadi namba 123

    Swali

    How is a gas component's partial pressure found from mole fraction?

    Jibu

    Pi = XiPtotal.

  124. Kadi namba 124

    Swali

    How does heating a fixed-volume gas affect its pressure in the ideal model?

    Jibu

    Pressure rises because faster particles collide with the walls more forcefully and frequently.

  125. Kadi namba 125

    Swali

    Why can attractions make a real gas's measured pressure lower than the ideal prediction?

    Jibu

    Attractions pull approaching particles away from the walls, reducing momentum transfer during wall collisions.

  126. Kadi namba 126

    Swali

    How many moles of ions result from complete dissolution of 0.20 mol CaCl₂?

    Jibu

    0.60 mol ions: 0.20 mol Ca²⁺ plus 0.40 mol Cl⁻.

  127. Kadi namba 127

    Swali

    How should water orient around Cl⁻ in a particle model?

    Jibu

    Its partially positive hydrogen ends point toward Cl⁻.

  128. Kadi namba 128

    Swali

    Can filtration separate dissolved components of a liquid solution?

    Jibu

    No. Dissolved particles pass through the filter with the solvent; filtration only retains an insoluble solid.

  129. Kadi namba 129

    Swali

    Why do nonpolar molecular solutes often dissolve in nonpolar solvents?

    Jibu

    Both rely mainly on compatible London dispersion forces, so mixing can replace the attractions disrupted in the separate substances.

  130. Kadi namba 130

    Swali

    What does a shorter absorbed wavelength imply about an energy transition?

    Jibu

    A larger energy gap because E = hc/λ.

  131. Kadi namba 131

    Swali

    What is the energy of a photon with frequency 5.0 × 10^14 s^-1?

    Jibu

    3.3 × 10^-19 J. Multiply by Planck's constant: E = (6.626 × 10^-34 J·s)(5.0 × 10^14 s^-1).

  132. Kadi namba 132

    Swali

    How does doubling cuvette path length affect absorbance in the linear Beer–Lambert range?

    Jibu

    Absorbance doubles if concentration and molar absorptivity stay constant.

  133. Kadi namba 133

    Swali

    How can noncovalent interactions affect a large biomolecule?

    Jibu

    Attractions between molecules or between different regions of the same molecule help set its shape, which strongly affects its properties and function.

  134. Kadi namba 134

    Swali

    Why does an ionic solid usually fail to conduct as a solid?

    Jibu

    Its ions are fixed in lattice positions. The same substance conducts when molten or dissolved because the ions can then move.

  135. Kadi namba 135

    Swali

    Why does a gas have no definite shape or volume?

    Jibu

    Its widely spaced particles move constantly and experience minimal interparticle attraction, so they spread through the available container.

  136. Kadi namba 136

    Swali

    What graph shapes show the inverse pressure–volume relationship for a fixed amount of ideal gas at constant temperature?

    Jibu

    A plot of P against V is a decreasing curve, while P against 1/V is a straight line through the origin.

  137. Kadi namba 137

    Swali

    At the same temperature, do different ideal gases have different average kinetic energies?

    Jibu

    No. Average translational kinetic energy depends only on absolute temperature.

  138. Kadi namba 138

    Swali

    Under which conditions is ideal-gas behavior most accurate?

    Jibu

    Low pressure and high temperature, where particles are far apart and attractions matter least.

  139. Kadi namba 139

    Swali

    What particle-level feature distinguishes a solution from a heterogeneous mixture?

    Jibu

    A solution—whether solid, liquid, or gas—is uniform throughout; a heterogeneous mixture has regions or phases with different compositions.

  140. Kadi namba 140

    Swali

    How should water orient around Na⁺ in a particulate model?

    Jibu

    Its partially negative oxygen end points toward Na⁺.

  141. Kadi namba 141

    Swali

    In paper chromatography, why does one solute spot travel farther than another?

    Jibu

    It interacts more strongly with the mobile phase or more weakly with the stationary phase. With known phase polarities, that travel difference can reveal relative solute polarity.

  142. Kadi namba 142

    Swali

    What energy competition helps explain whether an ionic solid dissolves?

    Jibu

    The energy needed to separate lattice ions competes with the energy released when ion–solvent attractions form.

  143. Kadi namba 143

    Swali

    Which molecular motions commonly absorb infrared radiation?

    Jibu

    Bond vibrations whose changing dipole can interact with the radiation.

  144. Kadi namba 144

    Swali

    Why must wavelength be converted to meters in c = λν when c is in m s^-1?

    Jibu

    Consistent units are required so meters cancel correctly and frequency comes out in s^-1.

  145. Kadi namba 145

    Swali

    How can fingerprints on a cuvette affect a visible-light absorbance reading?

    Jibu

    They can absorb or scatter extra light, making measured absorbance too high and the inferred concentration too high.

  146. Kadi namba 146

    Swali

    What causes and controls the strength of dipole–dipole attractions?

    Jibu

    Opposite partial charges on neighboring polar molecules attract. Strength increases with larger molecular dipoles and depends on how favorably the dipoles are oriented.

  147. Kadi namba 147

    Swali

    Why is graphite conductive and soft while diamond is insulating and hard?

    Jibu

    Graphite has delocalized electrons within its sheets, so it conducts, and its layers can slide, so it is soft. Diamond has a rigid three-dimensional network of localized covalent bonds, making it hard and insulating.

  148. Kadi namba 148

    Swali

    Why are gases much more compressible than liquids?

    Jibu

    Gas particles have large empty spaces between them; liquid particles are already close together.

  149. Kadi namba 149

    Swali

    What volume does 0.500 mol CO₂ occupy at 1.00 atm and 300. K if it behaves ideally?

    Jibu

    12.3 L. Use V = nRT/P = (0.500 mol)(0.08206 L atm mol^-1 K^-1)(300. K)/(1.00 atm).

  150. Kadi namba 150

    Swali

    Why does a lighter gas effuse faster than a heavier gas at the same temperature?

    Jibu

    Its particles have a higher average speed because equal average kinetic energy is shared by less mass.

  151. Kadi namba 151

    Swali

    How does finite particle volume affect a real gas at very high pressure?

    Jibu

    The free volume available for particle motion is smaller than the container volume assumed by the ideal model.

  152. Kadi namba 152

    Swali

    How should 250.0 mL of 0.100 M NaCl be prepared from solid NaCl?

    Jibu

    Dissolve 0.0250 mol NaCl, or 1.46 g, then dilute to exactly 250.0 mL in a volumetric flask.

  153. Kadi namba 153

    Swali

    What changes in a particle diagram when a solution is diluted without losing solute?

    Jibu

    The solute-particle count stays constant while solvent volume and particle spacing increase.

  154. Kadi namba 154

    Swali

    Why is fractional distillation better than simple distillation for liquids with close boiling points?

    Jibu

    Repeated vaporization–condensation steps enrich the vapor in the more volatile component more effectively.

  155. Kadi namba 155

    Swali

    Why are oil and water usually immiscible?

    Jibu

    Water's strong hydrogen-bond network isn't replaced by equally strong water–oil attractions, so the substances separate into phases.

  156. Kadi namba 156

    Swali

    Which molecular transition is commonly associated with ultraviolet or visible absorption?

    Jibu

    A transition between electronic energy levels.

  157. Kadi namba 157

    Swali

    Which photon carries more energy, blue light or red light?

    Jibu

    Blue light, because it has shorter wavelength and higher frequency.

  158. Kadi namba 158

    Swali

    Why is absorbance often measured at the wavelength of maximum absorbance in Beer–Lambert analysis?

    Jibu

    It gives the largest concentration-sensitive signal, and the flat top near the maximum makes small wavelength-setting errors less influential.

  159. Kadi namba 159

    Swali

    What creates a dipole–induced-dipole attraction, and what controls its strength?

    Jibu

    A permanent dipole distorts a nearby nonpolar particle's electron cloud and creates an attractive temporary dipole. A larger permanent dipole and a more polarizable nonpolar partner make the attraction stronger.

  160. Kadi namba 160

    Swali

    How do stronger intermolecular forces affect vapor pressure, boiling point, and melting point?

    Jibu

    They lower vapor pressure and raise boiling point. Melting point often rises too, but the trend is less direct because melting rearranges rather than fully separates particles.

  161. Kadi namba 161

    Swali

    How do particles behave in a liquid?

    Jibu

    They stay in close contact while moving and colliding continuously. Temperature and interparticle attractions affect their arrangement and motion.

  162. Kadi namba 162

    Swali

    Why must Celsius temperature be converted to kelvins in gas-law calculations?

    Jibu

    Gas-law proportionalities require an absolute temperature scale whose zero corresponds to zero extrapolated thermal motion.

  163. Kadi namba 163

    Swali

    How does raising temperature change a Maxwell–Boltzmann speed distribution?

    Jibu

    The distribution broadens, its peak lowers and shifts right, and a larger fraction of particles have high speed.

  164. Kadi namba 164

    Swali

    Why does the ideal-gas model treat collisions as elastic?

    Jibu

    It assumes total kinetic energy is conserved in particle–particle and particle–wall collisions.

  165. Kadi namba 165

    Swali

    How many moles of solute are in 75.0 mL of a 0.400 M solution?

    Jibu

    0.0300 mol. Multiply 0.400 mol L^-1 by 0.0750 L.

  166. Kadi namba 166

    Swali

    For equal solution volumes drawn at the same scale, what shows which solution is more concentrated?

    Jibu

    The more concentrated diagram contains more solute particles in that equal volume.

  167. Kadi namba 167

    Swali

    How do differences in intermolecular attractions let distillation separate a liquid solution?

    Jibu

    They give the components different vapor pressures, so the vapor is enriched in the more volatile component.

  168. Kadi namba 168

    Swali

    What comparison helps predict whether two liquids will be miscible?

    Jibu

    Liquids with similar types and strengths of intermolecular attractions are more likely to mix uniformly.

  169. Kadi namba 169

    Swali

    How can an absorption spectrum help identify a substance?

    Jibu

    Its allowed energy gaps produce a characteristic pattern of absorbed wavelengths that can be compared with known spectra.

  170. Kadi namba 170

    Swali

    How does absorbing or emitting a photon change an atom's or molecule's energy?

    Jibu

    Absorption raises the species' energy by exactly the photon energy; emission lowers it by the same amount.

  171. Kadi namba 171

    Swali

    What macroscopic evidence can support that a chemical reaction occurred?

    Jibu

    Evidence can include gas formation, precipitate formation, a persistent color change, or an energy change, interpreted with particle-level changes.

  172. Kadi namba 172

    Swali

    What does a net ionic equation include?

    Jibu

    Only the dissolved or reacting species that undergo chemical change; spectator ions are omitted.

  173. Kadi namba 173

    Swali

    What must a correct particulate reaction diagram conserve?

    Jibu

    The number of atoms of every element and the total charge.

  174. Kadi namba 174

    Swali

    What distinguishes a chemical change from a physical change?

    Jibu

    A chemical change rearranges bonds into new substances; a physical change alters state or arrangement without changing chemical identity.

  175. Kadi namba 175

    Swali

    What does a balanced equation's coefficient ratio provide?

    Jibu

    The mole ratio among reacting and produced species.

  176. Kadi namba 176

    Swali

    What is the equivalence point of a titration?

    Jibu

    The point where titrant and analyte have reacted in the stoichiometric ratio given by the balanced equation.

  177. Kadi namba 177

    Swali

    What defines a precipitation reaction?

    Jibu

    Aqueous ions combine to form a sparingly soluble solid.

  178. Kadi namba 178

    Swali

    What happens in a Brønsted–Lowry acid–base reaction?

    Jibu

    A proton transfers from the acid (donor) to the base (acceptor). In aqueous solution, H₂O can play either role.

  179. Kadi namba 179

    Swali

    What does oxidation mean in a redox reaction?

    Jibu

    Loss of electrons and an increase in oxidation number.

  180. Kadi namba 180

    Swali

    What particle-level change confirms that a process is chemical?

    Jibu

    Atoms rearrange into new combinations, producing substances with different compositions.

  181. Kadi namba 181

    Swali

    Which ions are spectators when AgNO₃(aq) reacts with NaCl(aq)?

    Jibu

    Na⁺ and NO₃⁻. The net ionic reaction is Ag⁺(aq) + Cl⁻(aq) → AgCl(s).

  182. Kadi namba 182

    Swali

    How does a particulate diagram reveal the limiting reactant?

    Jibu

    After forming the maximum product allowed by the ratio, none of the limiting reactant remains while excess reactant particles do.

  183. Kadi namba 183

    Swali

    Is melting ice a chemical or physical change?

    Jibu

    A physical change. H₂O molecules remain H₂O while their arrangement and motion change.

  184. Kadi namba 184

    Swali

    How is the limiting reactant identified from given amounts?

    Jibu

    Convert each reactant to the same product amount using the balanced equation; the smaller product amount identifies the limiting reactant.

  185. Kadi namba 185

    Swali

    How does an endpoint differ from an equivalence point?

    Jibu

    The endpoint is an observed signal such as indicator color change; the equivalence point is the exact stoichiometric condition.

  186. Kadi namba 186

    Swali

    How is complete combustion of a hydrocarbon in excess oxygen classified, and what products form?

    Jibu

    It is a redox combustion reaction that forms CO₂ and H₂O.

  187. Kadi namba 187

    Swali

    What are the conjugate acid and conjugate base in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Jibu

    NH₄⁺ is the conjugate acid of NH₃, and OH⁻ is the conjugate base of H₂O.

  188. Kadi namba 188

    Swali

    What does reduction mean in a redox reaction?

    Jibu

    Gain of electrons and a decrease in oxidation number.

  189. Kadi namba 189

    Swali

    Which common changes are physical rather than chemical?

    Jibu

    Phase changes and the formation or separation of mixtures are physical when each substance keeps its composition.

  190. Kadi namba 190

    Swali

    How are strong soluble electrolytes written in a complete ionic equation?

    Jibu

    As separated aqueous ions; solids, liquids, gases, and weak electrolytes stay intact.

  191. Kadi namba 191

    Swali

    A diagram starts with six A particles and four B₂ particles for 2A + B₂ → 2AB; what remains after completion?

    Jibu

    One B₂ remains. Six A consume three B₂ and form six AB.

  192. Kadi namba 192

    Swali

    Why is dissolving NaCl in water normally classified as a physical change?

    Jibu

    Na⁺ and Cl⁻ separate and become hydrated, but retain their chemical identities. Removing the water recovers NaCl; the shift from ion–ion to ion–dipole attractions does not by itself form a new substance.

  193. Kadi namba 193

    Swali

    What mass of AgCl can form from 25.0 mL of 0.200 M AgNO₃ mixed with excess Cl⁻?

    Jibu

    0.717 g AgCl. The 1:1 reaction gives 0.00500 mol AgCl; multiply by 143.32 g mol^-1.

  194. Kadi namba 194

    Swali

    What calculation finds unknown analyte moles at equivalence?

    Jibu

    Use titrant moles, n = MV, then apply the balanced-reaction mole ratio.

  195. Kadi namba 195

    Swali

    Which feature identifies an acid–base, redox, or precipitation reaction?

    Jibu

    Acid–base reactions transfer protons, redox reactions change oxidation numbers through electron transfer, and precipitation reactions form a sparingly soluble solid.

  196. Kadi namba 196

    Swali

    What is the net ionic equation for strong acid–strong base neutralization?

    Jibu

    H⁺(aq) + OH⁻(aq) → H₂O(l).

  197. Kadi namba 197

    Swali

    What is the oxidation number of sulfur in SO₄²⁻?

    Jibu

    +6. Four oxygens contribute -8 total, so sulfur must be +6 to give -2 overall.

  198. Kadi namba 198

    Swali

    Why can gas bubbles alone be ambiguous evidence of reaction?

    Jibu

    Bubbles may also come from boiling or dissolved gas escaping, so the context and particle identities must support a chemical change.

  199. Kadi namba 199

    Swali

    How is melting ice represented as a balanced physical-change equation?

    Jibu

    H₂O(s) → H₂O(l). The formula and atom count stay the same because only the physical state changes.

  200. Kadi namba 200

    Swali

    What does a particle diagram show when no reaction occurs after two aqueous ionic solutions mix?

    Jibu

    All ions remain separated and solvated, with no new bonded particles, precipitate, or gas.

  201. Kadi namba 201

    Swali

    Why is rusting iron a chemical change?

    Jibu

    Iron atoms form new iron-oxide substances through electron transfer and new bonding.

  202. Kadi namba 202

    Swali

    For 2H₂O₂(aq) → 2H₂O(l) + O₂(g), what volume of O₂ forms from 0.100 mol H₂O₂ at 298 K and 1.00 atm?

    Jibu

    1.22 L O₂. The mole ratio gives 0.0500 mol O₂, then V = nRT/P.

  203. Kadi namba 203

    Swali

    A 25.0 mL monoprotic acid sample requires 20.0 mL of 0.150 M NaOH; what is the acid concentration?

    Jibu

    0.120 M. At 1:1 equivalence, moles acid = 0.0200 L × 0.150 M, then divide by 0.0250 L.

  204. Kadi namba 204

    Swali

    Which salts does the minimum solubility rule in this deck treat as soluble?

    Jibu

    All salts containing Na⁺, K⁺, NH₄⁺, or NO₃⁻ are treated as soluble in water.

  205. Kadi namba 205

    Swali

    How are the strengths of a conjugate acid and its conjugate base related?

    Jibu

    A stronger acid has a weaker conjugate base, and a stronger base has a weaker conjugate acid.

  206. Kadi namba 206

    Swali

    How are oxidation and reduction half-reactions combined into one balanced equation?

    Jibu

    Multiply them so electrons lost equal electrons gained, add the half-reactions, then cancel electrons and any identical species on both sides.

  207. Kadi namba 207

    Swali

    How do molecular, complete ionic, and net ionic equations differ?

    Jibu

    Molecular equations keep compounds intact, complete ionic equations split strong soluble electrolytes, and net ionic equations remove spectators. All three conserve atoms and charge.

  208. Kadi namba 208

    Swali

    How should coefficients change particle counts in a reaction diagram?

    Jibu

    They set whole-particle ratios while preserving each particle's chemical formula.

  209. Kadi namba 209

    Swali

    Is separating a mixture by distillation a chemical or physical change?

    Jibu

    A physical change. Components change phase and location but keep their chemical identities.

  210. Kadi namba 210

    Swali

    What equation results from Cu → Cu²⁺ + 2e⁻ and Ag⁺ + e⁻ → Ag?

    Jibu

    Cu + 2Ag⁺ → Cu²⁺ + 2Ag. Multiply the silver half-reaction by 2 and cancel 2e⁻; both atom counts and net charge then match.

  211. Kadi namba 211

    Swali

    How is average reaction rate found from a reactant concentration?

    Jibu

    Use the negative concentration change divided by elapsed time, adjusted by its stoichiometric coefficient when comparing species rates.

  212. Kadi namba 212

    Swali

    What does a rate law express?

    Jibu

    It shows how the measured rate depends on reactant concentrations. In rate = k[A]^m[B]^n, m and n are the orders in A and B, and m + n is the overall order.

  213. Kadi namba 213

    Swali

    A plot of ln[A] versus time is linear; what is the order in A and its integrated rate law?

    Jibu

    First order: ln[A]t = ln[A]0 − kt, so the plot's slope is −k.

  214. Kadi namba 214

    Swali

    What is an elementary reaction?

    Jibu

    A single step in a mechanism whose rate law follows directly from its reactant molecularity.

  215. Kadi namba 215

    Swali

    What two collision conditions are needed for reaction?

    Jibu

    Sufficient collision energy and a productive molecular orientation.

  216. Kadi namba 216

    Swali

    What does activation energy represent on a reaction-energy profile?

    Jibu

    The energy difference from the reactants to the transition state. The reaction coordinate tracks the step's structural progress, not elapsed time.

  217. Kadi namba 217

    Swali

    What must the elementary steps of a valid mechanism do when added?

    Jibu

    Cancel intermediates and reproduce the overall balanced reaction.

  218. Kadi namba 218

    Swali

    How is a proposed mechanism tested against kinetics?

    Jibu

    Its derived rate law must agree with the experimentally measured rate law.

  219. Kadi namba 219

    Swali

    What does a pre-equilibrium approximation assume?

    Jibu

    A fast reversible step reaches equilibrium before a later slow step consumes its intermediate.

  220. Kadi namba 220

    Swali

    What does each peak on a multistep energy profile represent?

    Jibu

    A transition state for one elementary step.

  221. Kadi namba 221

    Swali

    How does a catalyst increase reaction rate?

    Jibu

    It provides an alternate mechanism with a lower activation-energy pathway.

  222. Kadi namba 222

    Swali

    Why does crushing a solid reactant usually increase its reaction rate?

    Jibu

    Crushing increases exposed surface area, so more reactant particles can collide with the other reactant each second.

  223. Kadi namba 223

    Swali

    How is reaction order found from initial-rate data?

    Jibu

    Compare trials where one reactant concentration changes while the others stay constant, then match the rate factor to the concentration factor.

  224. Kadi namba 224

    Swali

    A plot of [A] versus time is linear; what is the order in A and its integrated rate law?

    Jibu

    Zero order: [A]t = [A]0 − kt, so the plot's slope is −k.

  225. Kadi namba 225

    Swali

    What is the rate law for the elementary step 2A + B → products?

    Jibu

    rate = k[A]²[B]. This inference is valid because the step is elementary.

    Translucent laboratory glassware, particle clusters, and flowing blue-to-amber energy curves on a dark background.

    kadi 450

    AP Chemistry Flashcards: Complete 9-Unit Course Review

    Soma fungu hili bila malipo

    Nibomo itafunguka ili uanze kusoma.

  226. Kadi namba 226

    Swali

    How does raising temperature change a Maxwell–Boltzmann energy distribution and reaction rate?

    Jibu

    The distribution shifts and broadens toward higher energies, so a larger fraction of collisions exceeds the activation-energy threshold and can react.

  227. Kadi namba 227

    Swali

    How is ΔH read from a reaction-energy profile?

    Jibu

    ΔH = energy of products − energy of reactants.

  228. Kadi namba 228

    Swali

    What is a reaction intermediate?

    Jibu

    A species formed in one mechanism step and consumed in a later step, so it cancels from the overall equation.

  229. Kadi namba 229

    Swali

    Why can't overall reaction coefficients usually supply rate-law exponents?

    Jibu

    The overall equation hides the mechanism; exponents come from experiment unless the reaction is a stated elementary step.

  230. Kadi namba 230

    Swali

    How does pre-equilibrium remove an intermediate from a rate law?

    Jibu

    Use the fast-step equilibrium relation to express the intermediate concentration in terms of stable reactants.

  231. Kadi namba 231

    Swali

    What does each valley between peaks represent on a multistep profile?

    Jibu

    A reaction intermediate.

  232. Kadi namba 232

    Swali

    Does a catalyst change ΔH or the equilibrium constant?

    Jibu

    No. It changes the pathway and rates, not reactant/product energies or the equilibrium composition.

  233. Kadi namba 233

    Swali

    For 2A → B, how are disappearance of A and appearance of B related?

    Jibu

    Reaction rate = -(1/2)Δ[A]/Δt = Δ[B]/Δt.

  234. Kadi namba 234

    Swali

    How do the units of k depend on a rate law's overall order?

    Jibu

    They must make the rate unit M s^-1: zero order uses M s^-1, first order s^-1, and second order M^-1 s^-1.

  235. Kadi namba 235

    Swali

    A plot of 1/[A] versus time is linear; what is the order in A and its integrated rate law?

    Jibu

    Second order: 1/[A]t = 1/[A]0 + kt, so the plot's slope is +k.

  236. Kadi namba 236

    Swali

    What is molecularity?

    Jibu

    The number of reacting particles in an elementary step, such as unimolecular or bimolecular.

  237. Kadi namba 237

    Swali

    How does raising temperature affect k in the qualitative Arrhenius model?

    Jibu

    k increases, often sharply, because a larger fraction of collisions can reach the transition state. Arrhenius-equation calculations are outside this deck’s scope.

  238. Kadi namba 238

    Swali

    A reactant falls from 0.80 M to 0.50 M in 30. s; what is its average disappearance rate to two significant figures?

    Jibu

    0.010 M s^-1. Use -(0.50 − 0.80) M ÷ 30. s.

  239. Kadi namba 239

    Swali

    How does a catalyst differ from an intermediate in a mechanism?

    Jibu

    A catalyst is consumed early and regenerated later; an intermediate is formed early and consumed later.

  240. Kadi namba 240

    Swali

    For 2NO₂ → NO₃ + NO (slow), followed by NO₃ + CO → NO₂ + CO₂ (fast), what rate law is predicted?

    Jibu

    rate = k[NO₂]². The first step is elementary and rate-limiting, so its molecularity sets the observed rate law.

  241. Kadi namba 241

    Swali

    On a multistep reaction-energy profile, which feature often identifies the rate-determining step?

    Jibu

    The step with the largest activation barrier measured from its preceding valley to its peak.

  242. Kadi namba 242

    Swali

    If changing [B] leaves rate unchanged, what is the order in B?

    Jibu

    Zero order, so [B]^0 = 1 in the measured rate law.

  243. Kadi namba 243

    Swali

    What mechanism changes can binding, acid–base, or surface catalysis introduce?

    Jibu

    They can orient reactants, lower activation barriers, or create new bound, protonated, or deprotonated intermediates and elementary steps; the catalyst is regenerated.

  244. Kadi namba 244

    Swali

    What is special about a first-order reaction's half-life?

    Jibu

    It is constant and independent of starting concentration: t1/2 = ln 2/k. Radioactive decay is a common first-order example.

  245. Kadi namba 245

    Swali

    Why is a termolecular elementary collision uncommon?

    Jibu

    Three particles must collide simultaneously with suitable energy and orientation, which is much less probable than one- or two-particle events.

  246. Kadi namba 246

    Swali

    On a reaction-energy profile, how are reverse activation energy, forward activation energy, and ΔH related?

    Jibu

    Ea,reverse = Ea,forward − ΔH. The reverse barrier is measured from products to the same transition state.

  247. Kadi namba 247

    Swali

    Why can correct orientation matter even above the activation energy?

    Jibu

    The colliding reactive sites must align so old bonds can break and new bonds can form along the reaction pathway.

  248. Kadi namba 248

    Swali

    How does detecting a proposed reaction intermediate affect a mechanism claim?

    Jibu

    It supports a mechanism that contains that intermediate, but it doesn't prove that mechanism is unique.

  249. Kadi namba 249

    Swali

    For 2NO ⇌ N₂O₂ (fast equilibrium), followed by N₂O₂ + O₂ → 2NO₂ (slow), what observed rate law results?

    Jibu

    rate = kobs[NO]²[O₂]. Start with rate = k₂[N₂O₂][O₂], use [N₂O₂] = K[NO]² from the fast equilibrium, then substitute.

  250. Kadi namba 250

    Swali

    What does the highest point of a one-step energy profile represent?

    Jibu

    The transition state, an unstable arrangement at the top of the activation barrier.

  251. Kadi namba 251

    Swali

    What sign does q have for an endothermic system?

    Jibu

    Positive, because the system absorbs heat from the surroundings.

  252. Kadi namba 252

    Swali

    How does an exothermic reaction appear on an enthalpy diagram?

    Jibu

    Products lie below reactants, so ΔH is negative.

  253. Kadi namba 253

    Swali

    What condition defines thermal equilibrium?

    Jibu

    Objects in contact have the same temperature, so there is no net heat transfer.

  254. Kadi namba 254

    Swali

    What equations relate heat capacity and temperature change to heat transfer?

    Jibu

    Use q = mcΔT with specific heat capacity, or q = nCₘΔT with molar heat capacity.

  255. Kadi namba 255

    Swali

    Why is temperature constant during a phase-change plateau?

    Jibu

    Added or removed energy changes interparticle potential energy instead of average kinetic energy.

  256. Kadi namba 256

    Swali

    What does ΔHrxn describe?

    Jibu

    The heat absorbed or released at constant pressure for the reaction exactly as written under the stated conditions.

  257. Kadi namba 257

    Swali

    How is reaction enthalpy estimated from average bond enthalpies?

    Jibu

    ΔHrxn ≈ Σ(bonds broken) − Σ(bonds formed).

  258. Kadi namba 258

    Swali

    What is the standard enthalpy of formation of an element in its standard state?

    Jibu

    Zero by definition.

  259. Kadi namba 259

    Swali

    In a Hess’s law calculation, how should a step change when the target needs twice its reverse?

    Jibu

    Reverse the equation, double every coefficient, and multiply its ΔH by -2.

  260. Kadi namba 260

    Swali

    How can energy cross a system boundary during a process?

    Jibu

    As heat or work. Heat transferred to or work done on the system increases its energy; heat transferred from or work done by the system decreases it.

  261. Kadi namba 261

    Swali

    How does an endothermic reaction appear on an enthalpy diagram?

    Jibu

    Products lie above reactants, so ΔH is positive.

  262. Kadi namba 262

    Swali

    How are heat gained by a system and heat lost by its surroundings related in an isolated setup?

    Jibu

    qsystem = -qsurroundings.

  263. Kadi namba 263

    Swali

    In coffee-cup calorimetry, how is reaction heat related to solution heat?

    Jibu

    qrxn = -qsolution when calorimeter heat is negligible and pressure is constant.

  264. Kadi namba 264

    Swali

    What heat is required to melt n moles at the melting point?

    Jibu

    q = nΔHfus.

  265. Kadi namba 265

    Swali

    How does reversing a reaction change ΔH?

    Jibu

    It reverses the sign of ΔH.

  266. Kadi namba 266

    Swali

    Why is breaking a bond endothermic?

    Jibu

    Energy must be supplied to separate atoms against their bonding attraction.

  267. Kadi namba 267

    Swali

    How is ΔH°rxn calculated from standard enthalpies of formation?

    Jibu

    ΣνΔHf°(products) − ΣνΔHf°(reactants).

  268. Kadi namba 268

    Swali

    How does multiplying an equation by 3 affect its ΔH?

    Jibu

    Multiply ΔH by 3 because enthalpy change scales with reaction amount.

  269. Kadi namba 269

    Swali

    Why can an exothermic dissolution warm the solution?

    Jibu

    The solution warms because forming solute–solvent attractions releases more energy than is absorbed in separating the original particles. The net potential-energy decrease raises particle kinetic energy and temperature.

  270. Kadi namba 270

    Swali

    Does an energy diagram's activation barrier determine ΔH?

    Jibu

    No. ΔH depends on reactant and product energy levels, while the barrier controls kinetics.

  271. Kadi namba 271

    Swali

    Why does heat flow from a warmer object to a cooler object?

    Jibu

    Energy transfers through collisions until their average kinetic energies, and therefore temperatures, equalize.

  272. Kadi namba 272

    Swali

    How much heat warms 100.0 g of water by 5.0°C?

    Jibu

    2.1 kJ. Use q = (100.0 g)(4.184 J g^-1 °C^-1)(5.0°C).

  273. Kadi namba 273

    Swali

    How are the molar enthalpies of a phase change and its reverse related?

    Jibu

    They have equal magnitudes and opposite signs, such as ΔHcond = -ΔHvap and ΔHfreeze = -ΔHfus.

  274. Kadi namba 274

    Swali

    How does doubling every coefficient in a thermochemical equation affect ΔH?

    Jibu

    It doubles ΔH.

  275. Kadi namba 275

    Swali

    Why is forming a bond exothermic?

    Jibu

    Atoms move to a lower-potential-energy bonded arrangement and release energy.

  276. Kadi namba 276

    Swali

    What formation equation defines ΔHf° for CO₂(g)?

    Jibu

    C(s, graphite) + O₂(g) → CO₂(g), forming exactly one mole from elements in standard states.

  277. Kadi namba 277

    Swali

    What should happen to intermediate species when equations in a Hess’s law calculation are added?

    Jibu

    They cancel, leaving the target overall reaction.

  278. Kadi namba 278

    Swali

    If the surroundings warm during a process, what is the likely sign of qsystem?

    Jibu

    Negative; the system likely released heat to the surroundings.

  279. Kadi namba 279

    Swali

    For a profile with reactants at 40 kJ and products at 10 kJ, what is ΔH?

    Jibu

    -30 kJ for the reaction as drawn.

  280. Kadi namba 280

    Swali

    Assuming no phase change, what determines the final temperature when two substances exchange heat in an insulated container?

    Jibu

    Energy conservation: q_warm + q_cool = 0. Use each substance's mass, heat capacity, and initial temperature to solve for the common final temperature.

  281. Kadi namba 281

    Swali

    How would heat loss to the room affect an exothermic calorimetry result?

    Jibu

    The observed temperature rise is too small, so the calculated magnitude of released heat is too low.

  282. Kadi namba 282

    Swali

    What heat expression covers warming a liquid without a phase change?

    Jibu

    q = mcΔT, not nΔHphase.

  283. Kadi namba 283

    Swali

    If forming 1 mol of product has ΔH = -50 kJ mol^-1, what is q when 2 mol forms?

    Jibu

    -100 kJ. Use q = nΔH = (2 mol)(-50 kJ mol^-1).

  284. Kadi namba 284

    Swali

    Breaking reactant bonds requires 500 kJ, and forming product bonds releases 650 kJ; what is the estimated ΔH?

    Jibu

    -150 kJ, from 500 − 650.

  285. Kadi namba 285

    Swali

    For CO(g) + ½O₂(g) → CO₂(g), what is ΔH°rxn if ΔHf°[CO] = -110.5 and ΔHf°[CO₂] = -393.5 kJ mol^-1?

    Jibu

    -283.0 kJ. Use -393.5 - [-110.5 + ½(0)], since ΔHf°[O₂(g)] = 0.

  286. Kadi namba 286

    Swali

    In a Hess’s law calculation, two valid steps have ΔH values +25 kJ and -60 kJ; what is the combined ΔH?

    Jibu

    -35 kJ, provided the equations add to the target reaction.

  287. Kadi namba 287

    Swali

    Why is “bonds breaking releases energy” incorrect?

    Jibu

    Bond breaking absorbs energy; the overall reaction releases energy only when forming new bonds releases more than breaking old bonds requires.

  288. Kadi namba 288

    Swali

    How would melting appear on an energy diagram?

    Jibu

    The liquid lies above the solid, so ΔHfus is positive; the diagram represents a physical, endothermic change.

  289. Kadi namba 289

    Swali

    Can two objects at the same temperature exchange energy microscopically?

    Jibu

    Yes, but their energy transfers balance, so there is no net heat flow.

  290. Kadi namba 290

    Swali

    Why must the calorimeter's heat capacity be included when it isn't negligible?

    Jibu

    The apparatus can absorb or release heat, so include q_cal = C_calΔT in the energy balance: q_process + q_solution + q_cal = 0.

  291. Kadi namba 291

    Swali

    What makes chemical equilibrium dynamic?

    Jibu

    Forward and reverse reactions continue at equal rates even though macroscopic concentrations stay constant.

  292. Kadi namba 292

    Swali

    For aA + bB ⇌ cC, what is the concentration-form expression for Q?

    Jibu

    Q = [C]^c / ([A]^a[B]^b), using current rather than necessarily equilibrium concentrations.

  293. Kadi namba 293

    Swali

    What does K much greater than 1 indicate?

    Jibu

    Products predominate at equilibrium, though K says nothing about reaction speed.

  294. Kadi namba 294

    Swali

    How does reversing a reaction change its equilibrium constant?

    Jibu

    K becomes 1/K.

  295. Kadi namba 295

    Swali

    Can a reversible system reach equilibrium when it starts with only products?

    Jibu

    Yes, if the reverse reaction is possible. The equilibrium composition depends on temperature, initial amounts, and volume or pressure.

  296. Kadi namba 296

    Swali

    How do Q and K predict reaction direction?

    Jibu

    Q < K shifts forward, Q > K shifts reverse, and Q = K means equilibrium.

  297. Kadi namba 297

    Swali

    Which species are omitted from a heterogeneous equilibrium expression?

    Jibu

    Pure solids and pure liquids because their activities are effectively constant.

  298. Kadi namba 298

    Swali

    How does increasing a dissolved reactant's concentration or a gaseous reactant's partial pressure affect equilibrium at constant temperature when other Q terms are initially unchanged?

    Jibu

    It lowers Q relative to K, so the system shifts toward products until Q = K again. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that pure phase remains present.

  299. Kadi namba 299

    Swali

    What does a flat concentration-time graph mean at equilibrium?

    Jibu

    Each concentration is constant, not necessarily equal to the others.

  300. Kadi namba 300

    Swali

    For A ⇌ B in one fixed volume, a particulate model shows 16 A and 0 B initially, then 4 A and 12 B at equilibrium. What changed, what predominates, and what is Kc?

    Jibu

    The net change was forward: 12 A particles became 12 B particles. B predominates at equilibrium, and Kc = [B]/[A] = 12/4 = 3.0 because both counts come from the same fixed volume.

  301. Kadi namba 301

    Swali

    What can Ksp tell you about a salt's solubility, and when can two Ksp values be compared directly?

    Jibu

    Ksp > 1 indicates a soluble salt. For salts with the same dissolution stoichiometry, a larger Ksp generally means greater molar solubility; across different stoichiometries, calculate molar solubility before comparing.

  302. Kadi namba 302

    Swali

    What is the common-ion effect on solubility?

    Jibu

    Adding an ion already in the dissolution equilibrium usually decreases the solid's molar solubility.

  303. Kadi namba 303

    Swali

    How does uniform dilution shift an aqueous equilibrium based on the stoichiometric powers in Q?

    Jibu

    It shifts toward the side with the larger sum of stoichiometric coefficients for dissolved species included in Q. If the sums are equal, dilution causes no shift by this effect; pure solids and liquids remain omitted.

  304. Kadi namba 304

    Swali

    What happens if a reversible reaction starts with reactants only?

    Jibu

    The forward rate is initially largest; products form, the reverse rate grows, and the rates eventually become equal.

  305. Kadi namba 305

    Swali

    What is the purpose of an ICE table?

    Jibu

    To organize initial, change, and equilibrium concentrations using reaction stoichiometry.

  306. Kadi namba 306

    Swali

    Can a reaction with a very large K be slow?

    Jibu

    Yes. K describes thermodynamic equilibrium position, while rate depends on kinetics and activation energy.

  307. Kadi namba 307

    Swali

    What happens to Q immediately after product concentration increases?

    Jibu

    Q increases; if it rises above K, the reaction shifts toward reactants.

  308. Kadi namba 308

    Swali

    How does multiplying every reaction coefficient by 2 affect K?

    Jibu

    The new equilibrium constant is K².

  309. Kadi namba 309

    Swali

    For A ⇌ B, Kc = 4.0 and initially [A] = 1.0 M and [B] = 0, what are the equilibrium concentrations?

    Jibu

    [A] = 0.20 M and [B] = 0.80 M. Let x form: Kc = x/(1.0 − x) = 4.0, so x = 0.80 M.

  310. Kadi namba 310

    Swali

    What macroscopic properties stay constant at equilibrium?

    Jibu

    Properties such as concentration, color, and pressure remain constant when external conditions are fixed.

  311. Kadi namba 311

    Swali

    How does decreasing volume shift a gaseous equilibrium?

    Jibu

    Toward the side with fewer moles of gas, if the two sides have different gaseous mole counts.

  312. Kadi namba 312

    Swali

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kc?

    Jibu

    Kc = [NH₃]² / ([N₂][H₂]³).

  313. Kadi namba 313

    Swali

    For CaF₂(s) ⇌ Ca²⁺ + 2F⁻, how is Ksp written in terms of molar solubility s in pure water?

    Jibu

    Ksp = s(2s)² = 4s³ because [Ca²⁺] = s and [F⁻] = 2s.

  314. Kadi namba 314

    Swali

    What does K much less than 1 indicate?

    Jibu

    Reactants predominate at equilibrium.

  315. Kadi namba 315

    Swali

    How does decreasing a dissolved product's concentration or a gaseous product's partial pressure affect equilibrium when other Q terms are initially unchanged?

    Jibu

    It lowers Q and drives a net forward reaction until equilibrium returns. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that phase remains.

  316. Kadi namba 316

    Swali

    Does equilibrium mean the reaction has stopped?

    Jibu

    No. Both directions continue, but equal rates produce no net macroscopic change.

  317. Kadi namba 317

    Swali

    Why does adding NaF reduce CaF₂ solubility?

    Jibu

    The added F⁻ raises Qsp, shifting the dissolution equilibrium toward solid CaF₂.

  318. Kadi namba 318

    Swali

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kp when P_N₂ = 0.50 atm, P_H₂ = 1.50 atm, and P_NH₃ = 0.25 atm?

    Jibu

    0.037. Use Kp = (P_NH₃)²/[(P_N₂)(P_H₂)³] = (0.25)²/[(0.50)(1.50)³]. Use equilibrium partial pressures directly; Kc↔Kp conversion isn't assessed.

  319. Kadi namba 319

    Swali

    What happens to Q when a gaseous equilibrium mixture is compressed at constant temperature if products have fewer gas moles?

    Jibu

    Q falls relative to K, so the reaction shifts toward products.

  320. Kadi namba 320

    Swali

    How do K and Q transform when a reaction is reversed, its coefficients are multiplied, or reactions are added?

    Jibu

    They follow the same algebra: reversing takes the reciprocal, multiplying every coefficient by c raises the value to the power c, and adding reactions multiplies their K or Q values.

  321. Kadi namba 321

    Swali

    When is the small-x approximation acceptable?

    Jibu

    When x is small relative to the initial concentration and the final result confirms the neglected change is suitably small.

  322. Kadi namba 322

    Swali

    What graph feature shows a disturbance followed by re-equilibration?

    Jibu

    A sudden or gradual concentration change followed by new constant plateaus while rates return to equality.

  323. Kadi namba 323

    Swali

    If Q = 0.20 and K = 5.0, which direction is favored next?

    Jibu

    Forward, because Q < K.

  324. Kadi namba 324

    Swali

    At equilibrium, are reactant and product concentrations equal?

    Jibu

    Not necessarily. They are constant, while forward and reverse rates are equal.

  325. Kadi namba 325

    Swali

    CaF₂ has Ksp = 3.2 × 10^-11 in pure water; what is its molar solubility?

    Jibu

    2.0 × 10^-4 M. If the molar solubility is s, then [Ca²⁺] = s, [F⁻] = 2s, and Ksp = 4s³.

  326. Kadi namba 326

    Swali

    For N₂ + 3H₂ ⇌ 2NH₃, how is Qp written?

    Jibu

    Qp = (P_NH₃)²/[(P_N₂)(P_H₂)³], using the current partial pressures rather than necessarily equilibrium values.

  327. Kadi namba 327

    Swali

    How does heating shift an endothermic forward reaction?

    Jibu

    Toward products, and K increases because temperature changes the equilibrium constant.

  328. Kadi namba 328

    Swali

    Why do both forward and reverse rates change as equilibrium is approached?

    Jibu

    As reactant and product concentrations change, the collision frequencies for the two directions change until their rates match.

  329. Kadi namba 329

    Swali

    CaF₂ has Ksp = 3.2 × 10^-11. What is its molar solubility in 0.10 M NaF?

    Jibu

    About 3.2 × 10^-9 M. With [F⁻] ≈ 0.10 M, Ksp = [Ca²⁺][F⁻]² gives s = (3.2 × 10^-11)/(0.10)². The common ion lowers solubility but does not change Ksp at constant temperature.

  330. Kadi namba 330

    Swali

    What concentration data must be used to calculate Kc?

    Jibu

    Equilibrium concentrations, each raised to its stoichiometric coefficient and excluding pure solids and liquids.

  331. Kadi namba 331

    Swali

    What is a Brønsted–Lowry acid?

    Jibu

    A proton donor.

  332. Kadi namba 332

    Swali

    How is pH defined?

    Jibu

    pH = -log[H₃O⁺].

  333. Kadi namba 333

    Swali

    What is Ka for HA + H₂O ⇌ H₃O⁺ + A⁻?

    Jibu

    Ka = [H₃O⁺][A⁻]/[HA].

  334. Kadi namba 334

    Swali

    How does stabilizing a base affect its basicity and the strength of its conjugate acid?

    Jibu

    It makes the base weaker and its conjugate acid stronger. A more stable base is less willing to accept H⁺.

  335. Kadi namba 335

    Swali

    What is a Brønsted–Lowry base?

    Jibu

    A proton acceptor.

  336. Kadi namba 336

    Swali

    At 25°C, what are Kw and the relationship between pH and pOH?

    Jibu

    Kw = [H₃O⁺][OH⁻] = 1.0 × 10^-14. Taking negative logarithms gives pH + pOH = 14.00.

  337. Kadi namba 337

    Swali

    What is Kb for B + H₂O ⇌ BH⁺ + OH⁻?

    Jibu

    Kb = [BH⁺][OH⁻]/[B].

  338. Kadi namba 338

    Swali

    Why can lowering pH increase the solubility of a salt containing a basic anion?

    Jibu

    H₃O⁺ consumes the anion, pulling the dissolution equilibrium toward more dissolved ions.

  339. Kadi namba 339

    Swali

    What are conjugate acid–base pairs?

    Jibu

    Species that differ by exactly one proton.

  340. Kadi namba 340

    Swali

    What is the pH of 1.0 × 10^-3 M HCl?

    Jibu

    3.00, assuming complete dissociation and negligible water contribution.

  341. Kadi namba 341

    Swali

    How are pKa and pKb defined?

    Jibu

    pKa = -log Ka, and pKb = -log Kb.

  342. Kadi namba 342

    Swali

    Why does acid strength increase across a row of comparable hydrides?

    Jibu

    Increasing electronegativity stabilizes the conjugate base and polarizes the H–A bond.

  343. Kadi namba 343

    Swali

    What is an amphiprotic species?

    Jibu

    A species that can donate or accept a proton, such as HCO₃⁻.

  344. Kadi namba 344

    Swali

    What amounts remain after a limited amount of strong base partially neutralizes weak acid HA?

    Jibu

    Subtract the reacted moles from HA and form the same number of moles of A⁻. The result gives the remaining HA and formed A⁻ amounts before any equilibrium or buffer-pH calculation.

  345. Kadi namba 345

    Swali

    How are Ka, Kb, pKa, and pKb related for a conjugate pair at 25°C?

    Jibu

    KaKb = Kw = 1.0 × 10^-14, and pKa + pKb = pKw = 14.00.

  346. Kadi namba 346

    Swali

    When does pH have little effect on a salt's solubility?

    Jibu

    When neither dissolved ion reacts appreciably with H₃O⁺ or OH⁻.

  347. Kadi namba 347

    Swali

    How does H₂O act in HCl + H₂O → H₃O⁺ + Cl⁻ and in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Jibu

    It acts as a base in the first reaction by accepting H⁺, and as an acid in the second by donating H⁺.

  348. Kadi namba 348

    Swali

    After mixing weak base B with strong acid, what controls the final solution in the three stoichiometric regimes?

    Jibu

    Excess B leaves a B/BH⁺ buffer; equimolar amounts leave BH⁺, so the solution is acidic; excess strong acid sets the pH from the remaining H₃O⁺.

  349. Kadi namba 349

    Swali

    What two components make a typical weak-acid buffer?

    Jibu

    A weak acid and a significant amount of its conjugate base.

  350. Kadi namba 350

    Swali

    What do the successive half-equivalence pH values approximate in a diprotic weak-acid titration?

    Jibu

    The first approximates pKa₁ and the second approximates pKa₂ because each conjugate pair has equal concentrations at its half-equivalence point.

  351. Kadi namba 351

    Swali

    Which acid is stronger, one with pKa 2 or pKa 5?

    Jibu

    The acid with pKa 2; lower pKa means larger Ka.

  352. Kadi namba 352

    Swali

    What is the Henderson–Hasselbalch equation?

    Jibu

    pH = pKa + log([A⁻]/[HA]).

  353. Kadi namba 353

    Swali

    Why are larger binary hydrides down a group often stronger acids?

    Jibu

    The H–A bond becomes weaker as the central atom grows, so proton release is easier.

  354. Kadi namba 354

    Swali

    What mainly determines buffer capacity?

    Jibu

    The concentrations of both members of the conjugate acid–base pair. Increasing both concentrations at a fixed ratio increases capacity without changing pH; capacity is best balanced for added acid and base when their concentrations are similar.

  355. Kadi namba 355

    Swali

    Why does acid increase CaCO₃ solubility?

    Jibu

    H₃O⁺ converts CO₃²⁻ to HCO₃⁻ or carbonic acid species, reducing free carbonate and driving more CaCO₃ to dissolve.

  356. Kadi namba 356

    Swali

    What does pH < pKa imply for a weak-acid pair?

    Jibu

    The protonated form HA predominates over A⁻.

  357. Kadi namba 357

    Swali

    What happens when stoichiometrically equal amounts of a monoprotic weak acid and strong base are mixed?

    Jibu

    The weak acid is consumed to its conjugate base; at equivalence, the solution isn't a buffer containing both forms.

  358. Kadi namba 358

    Swali

    What is [H₃O⁺] when pH = 4.50?

    Jibu

    3.2 × 10^-5 M, from [H₃O⁺] = 10^-pH.

  359. Kadi namba 359

    Swali

    What is the pH of 0.010 M Ba(OH)₂ at 25°C?

    Jibu

    About 12.30. Complete dissociation gives [OH⁻] = 0.020 M, so pOH = 1.70. At 25°C, pH + pOH = 14.00, so pH = 12.30.

  360. Kadi namba 360

    Swali

    How does a buffer respond to a small amount of added strong acid?

    Jibu

    Its conjugate base consumes H⁺, converting to the weak acid and limiting the pH change.

  361. Kadi namba 361

    Swali

    Why is the equivalence-point solution basic in a monoprotic weak-acid–strong-base titration?

    Jibu

    The conjugate base produced at equivalence reacts with water to form OH⁻, so the pH is above neutral—above 7.00 at 25°C.

  362. Kadi namba 362

    Swali

    How is percent ionization calculated for a weak acid or weak base?

    Jibu

    For HA, use ([H₃O⁺]equilibrium ÷ [HA]initial) × 100%. For B, use ([BH⁺]equilibrium ÷ [B]initial) × 100%, under the usual monoprotic setup.

  363. Kadi namba 363

    Swali

    When is Henderson–Hasselbalch useful for an initial buffer-pH calculation?

    Jibu

    Use it when both members of a conjugate acid–base pair are present in meaningful amounts, including after in-scope stoichiometry creates a buffer. Calculating the pH change after acid or base is added to an existing buffer is outside this deck’s scope.

  364. Kadi namba 364

    Swali

    Why does adding oxygen atoms usually strengthen oxyacids with the same central atom?

    Jibu

    Extra oxygens withdraw electron density and delocalize negative charge in the conjugate base.

  365. Kadi namba 365

    Swali

    A prepared buffer is accidentally diluted to twice its intended volume; what happens to its pH and capacity?

    Jibu

    Its pH stays nearly the same, and its capacity per liter is halved because both component concentrations halve. The total neutralizing moles in the sample remain unchanged.

  366. Kadi namba 366

    Swali

    How does adding OH⁻ affect Mg(OH)₂ solubility?

    Jibu

    It decreases solubility through the common-ion effect, shifting Mg(OH)₂(s) ⇌ Mg²⁺ + 2OH⁻ toward the solid.

  367. Kadi namba 367

    Swali

    A buffer has equal [A⁻] and [HA]; what is its pH?

    Jibu

    pH = pKa because log(1) = 0.

  368. Kadi namba 368

    Swali

    How should a weak acid–strong base mixture be solved before equivalence?

    Jibu

    First use mole stoichiometry; if both HA and A⁻ remain, use the resulting buffer relation.

  369. Kadi namba 369

    Swali

    Why can pure neutral water have a pH other than 7.00?

    Jibu

    Kw changes with temperature. Neutrality means [H₃O⁺] = [OH⁻], while pH = 7.00 only when Kw = 1.0 × 10^-14 at 25°C.

  370. Kadi namba 370

    Swali

    25.0 mL of 0.200 M HCl is diluted to 100.0 mL; what is the pH?

    Jibu

    1.301. Dilution gives [H₃O⁺] = (0.200 M)(25.0 mL)/(100.0 mL) = 0.0500 M, so pH = -log(0.0500).

  371. Kadi namba 371

    Swali

    How does a buffer respond to a small amount of added strong base?

    Jibu

    The weak acid consumes OH⁻, forming conjugate base and water.

  372. Kadi namba 372

    Swali

    How do you find the final pH after mixing a strong acid and strong base at 25°C?

    Jibu

    Use H₃O⁺ + OH⁻ → 2H₂O and compare their moles. Divide excess H₃O⁺ or OH⁻ by the total volume, then calculate pH or pOH from that excess concentration. Equal moles give pH 7.00 at 25°C.

  373. Kadi namba 373

    Swali

    What distinguishes acid strength from acid concentration?

    Jibu

    Strength is the equilibrium tendency to donate H⁺, reflected by Ka or pKa; concentration is the amount of acid per solution volume.

  374. Kadi namba 374

    Swali

    If [A⁻]/[HA] = 10, how does pH compare with pKa?

    Jibu

    pH = pKa + 1 because log 10 = 1.

  375. Kadi namba 375

    Swali

    Which conjugate base is more stable, one with localized or resonance-delocalized charge?

    Jibu

    The resonance-delocalized conjugate base, which generally corresponds to the stronger acid.

  376. Kadi namba 376

    Swali

    Which 1.0 L buffer has greater capacity: 1.0 mol each of HA/A⁻ or 0.10 mol each at the same ratio?

    Jibu

    The 1.0 mol pair; both have the same initial pH, but the larger amounts neutralize more added acid or base.

  377. Kadi namba 377

    Swali

    For BHX(s) ⇌ BH⁺ + X⁻, why can raising pH increase the salt's solubility?

    Jibu

    OH⁻ consumes BH⁺ to form B and H₂O, so dissolution shifts right to replace BH⁺. This is a qualitative prediction, not a pH-dependent solubility calculation.

  378. Kadi namba 378

    Swali

    What does pH > pKa imply for a weak-acid pair?

    Jibu

    The deprotonated form A⁻ predominates over HA.

  379. Kadi namba 379

    Swali

    For HA + B ⇌ A⁻ + BH⁺, which side is favored when pKa(HA) = 4 and pKa(BH⁺) = 9?

    Jibu

    Products are favored. Proton transfer moves toward the weaker acid–base pair, and K ≈ 10^(9 − 4) = 10^5.

  380. Kadi namba 380

    Swali

    What is the pOH when [OH⁻] = 2.5 × 10^-4 M?

    Jibu

    3.60, from -log(2.5 × 10^-4).

  381. Kadi namba 381

    Swali

    What is the pH of 0.100 M HA when Ka = 1.0 × 10^-5?

    Jibu

    About 3.00. The ICE setup gives Ka = x²/(0.100 − x); x ≈ 1.0 × 10^-3 M, and the 1.0% change validates the approximation.

  382. Kadi namba 382

    Swali

    Why does a buffer fail after too much strong acid is added?

    Jibu

    Its conjugate base is depleted, so added H⁺ is no longer consumed effectively.

  383. Kadi namba 383

    Swali

    What do two clear equivalence regions on an acid titration curve suggest?

    Jibu

    At least two distinguishable titratable protons; on a clean ideal curve with exactly two equivalence regions, this is consistent with a diprotic acid.

  384. Kadi namba 384

    Swali

    A buffer has pKa 4.8 and [A⁻]/[HA] = 0.10; what is pH?

    Jibu

    3.8, from 4.8 + log(0.10).

  385. Kadi namba 385

    Swali

    Why is HCl stronger than HF in water despite F being more electronegative?

    Jibu

    The H–F bond is much stronger; bond strength dominates this down-group binary-acid comparison.

  386. Kadi namba 386

    Swali

    Why does percent ionization increase when a weak acid is diluted?

    Jibu

    Dilution shifts ionization toward more particles, so a larger fraction ionizes even though [H₃O⁺] decreases.

  387. Kadi namba 387

    Swali

    A buffer contains more HA than A⁻. Which addition can it neutralize in greater amount: strong acid or strong base?

    Jibu

    Strong base. The larger HA reserve consumes more added OH⁻; a buffer with more A⁻ than HA instead has greater capacity for added strong acid.

  388. Kadi namba 388

    Swali

    Why can removing a basic anion increase a salt's molar solubility without changing Ksp?

    Jibu

    The equilibrium shifts to replace the consumed ion; Ksp remains fixed at the same temperature.

  389. Kadi namba 389

    Swali

    Why can an acid–base indicator change color as pH changes?

    Jibu

    Its protonated and deprotonated forms have different colors or other observable properties, and their relative amounts change with pH.

  390. Kadi namba 390

    Swali

    What buffer results from mixing 1.0 mol HA with 0.40 mol OH⁻?

    Jibu

    0.60 mol HA and 0.40 mol A⁻ remain, forming a buffer before any equilibrium calculation.

  391. Kadi namba 391

    Swali

    What is the pH of 0.200 M weak base B when Kb = 2.0 × 10^-5 at 25°C?

    Jibu

    About 11.30. The ICE setup gives Kb = x²/(0.200 − x); x ≈ 2.0 × 10^-3 M OH⁻, and the 1.0% change validates the approximation.

  392. Kadi namba 392

    Swali

    Why does a weak acid alone not make an effective buffer?

    Jibu

    It lacks a substantial conjugate-base reserve to consume added strong acid.

  393. Kadi namba 393

    Swali

    What controls pH after excess strong base passes equivalence?

    Jibu

    The concentration of excess OH⁻ after accounting for reaction stoichiometry and total volume.

  394. Kadi namba 394

    Swali

    How should an indicator be chosen for a titration?

    Jibu

    Its color-change range should fall within the steep pH change near the equivalence point.

  395. Kadi namba 395

    Swali

    How can a measured pH and known pKa give a conjugate-base/acid ratio?

    Jibu

    Rearrange Henderson–Hasselbalch: [A⁻]/[HA] = 10^(pH − pKa).

  396. Kadi namba 396

    Swali

    Can a weak base and its conjugate acid form a buffer?

    Jibu

    Yes, when both are present in significant amounts.

  397. Kadi namba 397

    Swali

    For equal-volume buffers with the same conjugate-base/acid ratio, how does adding the same amount of strong acid affect a more concentrated versus less concentrated buffer?

    Jibu

    The concentrated buffer changes pH less because it has greater capacity.

  398. Kadi namba 398

    Swali

    How does equivalence-point pH compare for strong acid–strong base, weak acid–strong base, and weak base–strong acid titrations at 25°C?

    Jibu

    Strong acid–strong base: pH 7.00. Weak acid–strong base: above 7.00 because the conjugate base reacts with water. Weak base–strong acid: below 7.00 because the conjugate acid reacts with water.

  399. Kadi namba 399

    Swali

    Why should mole ratios replace concentration ratios after mixing buffer solutions?

    Jibu

    Both components share the same final volume, so that volume cancels in [A⁻]/[HA].

  400. Kadi namba 400

    Swali

    How does adding a little strong acid change a buffer's conjugate-base and conjugate-acid amounts?

    Jibu

    The conjugate base decreases and its conjugate acid increases by the amount of strong acid consumed.

  401. Kadi namba 401

    Swali

    What does entropy measure qualitatively?

    Jibu

    The dispersal of matter and energy among available microstates.

  402. Kadi namba 402

    Swali

    How is standard reaction entropy calculated?

    Jibu

    ΔS°rxn = ΣνS°(products) − ΣνS°(reactants).

  403. Kadi namba 403

    Swali

    What equation gives ΔG° from ΔH° and ΔS°, and what standard states do the degree symbols assume?

    Jibu

    ΔG° = ΔH° − TΔS°. The standard states are pure substances, 1.0 M solutions, and gases at 1 atm or 1 bar; T is in kelvins and energy units must match.

  404. Kadi namba 404

    Swali

    Does thermodynamic favorability guarantee a fast reaction?

    Jibu

    No. A favorable reaction can be slow when its activation barrier is large.

  405. Kadi namba 405

    Swali

    What is ΔG at equilibrium?

    Jibu

    Zero under the current conditions because there is no net driving force.

  406. Kadi namba 406

    Swali

    Why can an endothermic dissolution still be thermodynamically favorable?

    Jibu

    A sufficiently positive entropy change can make TΔS exceed positive ΔH, giving negative ΔG.

  407. Kadi namba 407

    Swali

    How can an unfavorable reaction be driven by a favorable one?

    Jibu

    Couple them so their equations and ΔG values add to a negative overall ΔG.

  408. Kadi namba 408

    Swali

    Where does oxidation occur in every electrochemical cell?

    Jibu

    At the anode.

  409. Kadi namba 409

    Swali

    How are standard cell potential and standard free energy related?

    Jibu

    ΔG° = -nFE°cell.

  410. Kadi namba 410

    Swali

    What equation gives cell potential under nonstandard conditions?

    Jibu

    E = E° − (RT/nF) ln Q. When Q = 1, ln Q = 0, so E = E°.

  411. Kadi namba 411

    Swali

    How is electrical charge related to current and time?

    Jibu

    q = It.

  412. Kadi namba 412

    Swali

    Which phase has greater molar entropy, liquid water or ice at the same temperature?

    Jibu

    Liquid water because its molecules have more accessible arrangements and motion.

  413. Kadi namba 413

    Swali

    Do elements in their standard states have zero standard molar entropy?

    Jibu

    No. Their ΔHf° is zero, but their absolute S° values are positive above 0 K.

  414. Kadi namba 414

    Swali

    How do the four ΔH° and ΔS° sign combinations determine thermodynamic favorability across temperature?

    Jibu

    ΔH° < 0 and ΔS° > 0 is favorable at every temperature; ΔH° > 0 and ΔS° < 0 is thermodynamically unfavored at every temperature. If both are positive, favorability requires high temperature; if both are negative, it requires low temperature.

  415. Kadi namba 415

    Swali

    What does it indicate when a thermodynamically favored process does not occur at a measurable rate?

    Jibu

    It is under kinetic control, commonly because of a high activation energy; no measurable reaction does not mean the system is at equilibrium.

  416. Kadi namba 416

    Swali

    How are ΔG° and K related?

    Jibu

    ΔG° = -RT ln K.

  417. Kadi namba 417

    Swali

    What two contributions compete in dissolving an ionic solid?

    Jibu

    Enthalpy changes from separating and solvating particles, and entropy changes from their new dispersal and solvent organization.

  418. Kadi namba 418

    Swali

    What must cancel when coupled reactions are added?

    Jibu

    Shared intermediates, leaving the desired net reaction.

  419. Kadi namba 419

    Swali

    Where does reduction occur in every electrochemical cell?

    Jibu

    At the cathode.

  420. Kadi namba 420

    Swali

    What sign of E°cell indicates a favorable standard galvanic reaction?

    Jibu

    Positive E°cell, corresponding to negative ΔG°.

  421. Kadi namba 421

    Swali

    If Q increases for a galvanic reaction, how does E change at fixed temperature?

    Jibu

    E decreases according to the Nernst equation. Le Châtelier's principle does not apply to an operating cell away from equilibrium; use Q and Nernst reasoning instead.

  422. Kadi namba 422

    Swali

    How are moles of electrons found from charge?

    Jibu

    Moles e⁻ = q/F, where F ≈ 96485 C mol^-1 e⁻.

  423. Kadi namba 423

    Swali

    How does producing more gas particles usually affect system entropy?

    Jibu

    It increases entropy because the particles have more positional microstates.

  424. Kadi namba 424

    Swali

    Can a dissolution with negative ΔH be unfavorable?

    Jibu

    Yes. A sufficiently negative entropy change at the stated temperature can make ΔG positive.

  425. Kadi namba 425

    Swali

    When can a process with ΔH > 0 and ΔS > 0 become favorable?

    Jibu

    At sufficiently high temperature, when TΔS exceeds ΔH.

  426. Kadi namba 426

    Swali

    How does a catalyst affect ΔG?

    Jibu

    It does not change ΔG; it lowers the activation barrier for both directions.

  427. Kadi namba 427

    Swali

    For A → B, ΔGf°(A) = -50 kJ mol^-1 and ΔGf°(B) = -80 kJ mol^-1. What is ΔG°rxn?

    Jibu

    -30 kJ mol^-1. Use ΣνΔGf°(products) − ΣνΔGf°(reactants) = -80 − (-50).

  428. Kadi namba 428

    Swali

    Why can dissolving a gas in a liquid have a negative entropy change?

    Jibu

    Gas particles lose much of their translational freedom when confined and solvated in the liquid.

  429. Kadi namba 429

    Swali

    If coupled steps have ΔG values +20 kJ and -35 kJ, what is overall ΔG?

    Jibu

    -15 kJ, so the combined process is thermodynamically favorable under those conditions.

  430. Kadi namba 430

    Swali

    What role does each half-cell solution play in an electrochemical cell?

    Jibu

    It supplies dissolved redox species at an electrode interface and carries ions within its compartment. Separate compartments prevent direct mixing while the external circuit and salt bridge connect the half-cells.

  431. Kadi namba 431

    Swali

    How is E°cell found from standard reduction potentials?

    Jibu

    E°cell = E°cathode − E°anode, using both tabulated values as reductions.

  432. Kadi namba 432

    Swali

    How does a cell's potential magnitude change as Q approaches or moves away from K, and what is E at equilibrium?

    Jibu

    |E| falls toward zero as Q approaches K and grows as the system moves farther from equilibrium. At equilibrium, Q = K and E = 0.

  433. Kadi namba 433

    Swali

    How many moles of electrons pass when 1.93 × 10^5 C flows?

    Jibu

    2.00 mol e⁻, from q/F.

  434. Kadi namba 434

    Swali

    How does a salt bridge maintain charge balance in a galvanic cell?

    Jibu

    Anions migrate toward the anode compartment and cations toward the cathode compartment, countering the net charge imbalances created by the two half-reactions.

  435. Kadi namba 435

    Swali

    Why does raising a substance's temperature generally increase its entropy?

    Jibu

    Energy spreads across more accessible particle energy states, increasing the number of possible microscopic arrangements.

  436. Kadi namba 436

    Swali

    When can a process with ΔH < 0 and ΔS < 0 be favorable?

    Jibu

    At sufficiently low temperature, where the unfavorable -TΔS term is small.

  437. Kadi namba 437

    Swali

    Why can diamond persist even though graphite is more stable at standard conditions?

    Jibu

    Conversion has a large activation barrier, so diamond is kinetically persistent.

  438. Kadi namba 438

    Swali

    What do the external circuit and measuring device do in an electrochemical cell?

    Jibu

    The circuit carries electrons from anode to cathode; a voltmeter measures potential difference, while an ammeter in series measures current.

  439. Kadi namba 439

    Swali

    At constant temperature, how does increasing the volume available to a gas affect its entropy?

    Jibu

    Entropy increases because the gas particles can occupy more positions in the larger space, so more microstates are accessible.

  440. Kadi namba 440

    Swali

    How does reversing one coupled reaction affect its ΔG?

    Jibu

    It reverses the sign of that reaction's ΔG.

  441. Kadi namba 441

    Swali

    Why is n required in ΔG° = -nFE°?

    Jibu

    It is the moles of electrons transferred per balanced reaction, linking charge flow to reaction extent.

  442. Kadi namba 442

    Swali

    What makes an electrolytic cell operate?

    Jibu

    An external power source drives a thermodynamically unfavorable redox reaction; oxidation still occurs at the anode and reduction at the cathode.

  443. Kadi namba 443

    Swali

    In an Mⁿ⁺/M concentration cell, which half-cell is the anode: the dilute or concentrated ion solution?

    Jibu

    The dilute half-cell. Oxidation produces Mⁿ⁺ there, while reduction consumes Mⁿ⁺ in the concentrated half-cell, so electrons flow from dilute to concentrated as the concentrations move toward equality.

  444. Kadi namba 444

    Swali

    How is deposited metal mass found from current and time?

    Jibu

    Find q = It, convert q/F to moles e⁻, use the half-reaction ratio to moles metal, then multiply by molar mass.

  445. Kadi namba 445

    Swali

    Given product S° total 500 J mol^-1 K^-1 and reactant total 420 J mol^-1 K^-1, what is ΔS°?

    Jibu

    +80 J mol^-1 K^-1.

  446. Kadi namba 446

    Swali

    How do electrode masses change in a Zn–Cu galvanic cell?

    Jibu

    The Zn anode loses mass as Zn → Zn²⁺ + 2e⁻, while the Cu cathode gains mass as Cu²⁺ + 2e⁻ → Cu.

  447. Kadi namba 447

    Swali

    What is ΔG° when ΔH° = 50 kJ mol^-1, ΔS° = 0.200 kJ mol^-1 K^-1, and T = 300 K?

    Jibu

    -10 kJ mol^-1, from ΔG° = 50 − (300)(0.200).

  448. Kadi namba 448

    Swali

    Why can temperature change a solid's solubility?

    Jibu

    Temperature changes the balance of ΔH and TΔS, so it changes the free energy of dissolution and the equilibrium constant.

  449. Kadi namba 449

    Swali

    What does the size of ΔG° relative to RT imply about K?

    Jibu

    ΔG° near zero gives K near 1. When |ΔG°| is much larger than RT, K is far from 1: negative ΔG° gives K ≫ 1, while positive ΔG° gives K ≪ 1.

  450. Kadi namba 450

    Swali

    Bubbles form at an inert cathode in acidic solution; which half-reaction can explain them?

    Jibu

    2H⁺ + 2e⁻ → H₂(g). Gas evolution at the cathode can be direct evidence of reduction.

Translucent laboratory glassware, particle clusters, and flowing blue-to-amber energy curves on a dark background.

kadi 450

AP Chemistry Flashcards: Complete 9-Unit Course Review

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