AP Chemistry Flashcards: Complete 9-Unit Course Review

Review all nine AP Chemistry units with 450 cards covering concepts, models, equations, calculation setup, and laboratory reasoning.

Bu deste hakkında

Review AP® Chemistry through 450 independently written English flashcards arranged in the course's nine-unit sequence. The deck moves from atomic structure and compound structure through properties of substances and mixtures, reactions, kinetics, thermochemistry, equilibrium, acids and bases, and thermodynamics and electrochemistry. Prerequisites come before dependent models and calculations.

What the cards practice

The cards use five recall paths: concept to explanation; model or representation to interpretation; equation to meaning and use; short setup to a result with units and reasoning; and laboratory observation to a chemical conclusion. They cover definitions, relationships, conditions, contrasts, particle and energy models, focused calculation steps, measurements, errors, and visible changes.

Selected reverse and contrast prompts appear only when the reverse direction has one clear standalone target. The deck excludes mechanical permutations, graph-dependent prompts that require a missing figure, copied test formats, long multipart derivations, and visual recall tied to third-party figures. The review scheduler handles long-term spacing after installation.

See the official AP Chemistry course page for College Board's current course requirements.

The Common knowledge · CC0 1.0 label applies only to the independently written prompts, answers, examples, organization, metadata, and inherited original cover, to the extent applicable rights exist. It does not claim ownership of scientific facts or equations.

This is an independent, unofficial study aid. It is not affiliated with, endorsed by, sponsored by, or official material from College Board or the AP Program. AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this product. No College Board examination questions, answer choices, scoring materials, curriculum text, logos, or trade dress were copied.

Bu destedeki kartlar

  1. Kart 1

    Soru

    What does one mole count?

    Cevap

    Exactly 6.02214076 × 10^23 representative particles.

  2. Kart 2

    Soru

    What does a peak in an element's mass spectrum represent?

    Cevap

    An isotope with a particular mass-to-charge ratio; for singly charged monatomic ions, the position tracks isotopic mass.

  3. Kart 3

    Soru

    What does an empirical formula show?

    Cevap

    The lowest whole-number ratio of the elements' atoms in a compound.

  4. Kart 4

    Soru

    How does a mixture differ from a pure substance at the particle level?

    Cevap

    A mixture contains chemically distinct representative units in variable proportions; a pure substance contains one element or compound with fixed composition. Different isotopes do not make an elemental sample a mixture.

  5. Kart 5

    Soru

    Which particles make up an atom's nucleus?

    Cevap

    Protons and neutrons. Electrons occupy the space outside the nucleus.

  6. Kart 6

    Soru

    What does a larger binding energy on a PES spectrum mean?

    Cevap

    More energy is required to remove that electron, so it is held more strongly by the nucleus.

  7. Kart 7

    Soru

    How does atomic radius generally change across a period and down a group?

    Cevap

    It decreases from left to right as effective nuclear charge rises, and it increases down a group as additional electron shells increase distance and shielding.

  8. Kart 8

    Soru

    What typical ion charge do Group 1 metals form?

    Cevap

    +1, by losing their one valence electron.

  9. Kart 9

    Soru

    How do you convert moles to particles?

    Cevap

    Multiply by Avogadro's number: particles = moles × 6.022 × 10^23 mol^-1.

  10. Kart 10

    Soru

    How is average atomic mass estimated from isotope data?

    Cevap

    Add each isotopic mass multiplied by its fractional abundance.

  11. Kart 11

    Soru

    How is an element's mass percent in a compound calculated?

    Cevap

    Divide the mass contributed by that element by the compound's molar mass, then multiply by 100%.

  12. Kart 12

    Soru

    How can measured elemental composition reveal a sample's purity?

    Cevap

    Compare the measured mass fraction with the fraction expected for the pure compound; a mismatch indicates another component.

  13. Kart 13

    Soru

    How do you build a ground-state electron configuration with the Aufbau principle?

    Cevap

    For ordinary ground states, move through the periodic table in atomic-number order, filling each s, p, d, or f block as it appears. The subshell capacities are s², p⁶, d¹⁰, and f¹⁴. For example, Br is [Ar] 4s² 3d¹⁰ 4p⁵.

  14. Kart 14

    Soru

    What does the relative area or height of an ideal PES peak indicate?

    Cevap

    The relative number of electrons in the corresponding subshell.

  15. Kart 15

    Soru

    How does first ionization energy generally change across a period and down a group?

    Cevap

    It increases from left to right as effective nuclear charge rises, and it decreases down a group as distance and shielding make a valence electron easier to remove.

  16. Kart 16

    Soru

    Why do elements in the same group form similar compounds?

    Cevap

    Their ground-state valence patterns repeat, including which outer subshells are full or partly full. That leads to similar bonding and typical ion charges.

  17. Kart 17

    Soru

    How do you convert a sample's mass to moles?

    Cevap

    Divide its mass by its molar mass: n = m/M.

  18. Kart 18

    Soru

    Which mass-spectrum interpretation lies outside the usual single-element model used in this deck?

    Cevap

    Assigning peaks in mixtures or peaks from multiply charged or polyatomic species; the standard model uses singly charged monatomic ions of one element.

  19. Kart 19

    Soru

    What does the law of definite proportions state?

    Cevap

    Every pure sample of a given compound has the same element mass ratios.

  20. Kart 20

    Soru

    Why can two samples of the same mixture have different compositions?

    Cevap

    Mixture components are physically combined, so their relative amounts are not fixed by a chemical formula.

  21. Kart 21

    Soru

    How does Coulomb's law connect charge and separation to attraction?

    Cevap

    Attraction grows with the magnitude of the charge product and decreases with the square of the separation distance.

  22. Kart 22

    Soru

    Which PES electrons usually appear at the highest binding energy?

    Cevap

    Core electrons closest to the nucleus, because they feel the strongest nuclear attraction.

  23. Kart 23

    Soru

    How does electron affinity generally change across a period and down a group?

    Cevap

    Electron gain generally becomes more favorable from left to right across a period and less favorable down a group as distance and shielding increase. Stable subshell patterns create substantial exceptions.

  24. Kart 24

    Soru

    Why are alkali metals generally more reactive down the group?

    Cevap

    Their valence electron is farther from the nucleus and easier to remove.

  25. Kart 25

    Soru

    How many moles are in 18.0 g of H₂O?

    Cevap

    About 0.999 mol. Use 18.0 g ÷ 18.02 g mol^-1.

  26. Kart 26

    Soru

    An element is 75% isotope 10 and 25% isotope 11; what is its average atomic mass?

    Cevap

    10.25 u. Calculate (0.75 × 10) + (0.25 × 11).

  27. Kart 27

    Soru

    A compound is 40.0% C, 6.7% H, and 53.3% O by mass; what is its empirical formula?

    Cevap

    CH₂O. For a 100 g sample, convert each mass to moles and divide by the smallest amount.

  28. Kart 28

    Soru

    A 10.0 g impure sample contains 8.5 g of the target compound; what is its mass-percent purity?

    Cevap

    85%. Calculate (8.5 g ÷ 10.0 g) × 100%.

  29. Kart 29

    Soru

    Which electrons are removed first when a transition metal forms a cation?

    Cevap

    Electrons in the occupied orbital with the highest principal quantum number: 4s before 3d. For example, Fe²⁺ is [Ar] 3d⁶.

  30. Kart 30

    Soru

    A PES spectrum has peaks proportional to 2, 2, and 6 electrons; which configuration fits?

    Cevap

    1s² 2s² 2p⁶, the configuration of Ne.

  31. Kart 31

    Soru

    How does electronegativity generally change across a period and down a group?

    Cevap

    It increases from left to right across a period and decreases down a group as atomic size and shielding increase.

  32. Kart 32

    Soru

    What empirical formula results from Al³⁺ and O²⁻?

    Cevap

    Al₂O₃, because two Al³⁺ ions balance three O²⁻ ions.

  33. Kart 33

    Soru

    How does a particle's mass in atomic mass units relate to its molar mass?

    Cevap

    The numerical value is the same: a molecular or formula-unit mass of x u corresponds to a molar mass of x g mol^-1.

  34. Kart 34

    Soru

    What does the tallest isotope peak usually indicate in a simple mass spectrum?

    Cevap

    The most abundant isotope, assuming comparable detection response and singly charged ions.

  35. Kart 35

    Soru

    How much oxygen is present in 25.0 g of a compound that is 32.0% oxygen by mass?

    Cevap

    8.00 g O. Multiply 25.0 g by 0.320.

  36. Kart 36

    Soru

    What does a particle diagram with two unbonded species in changing ratios represent?

    Cevap

    A mixture, because more than one particle type is present and the ratio is not fixed in a formula unit.

  37. Kart 37

    Soru

    What distinguishes valence electrons from core electrons?

    Cevap

    Valence electrons are available for bonding or ion formation; main-group valence electrons occupy the outermost shell, while transition metals may also use (n−1)d electrons. Core electrons mainly shield nuclear charge.

  38. Kart 38

    Soru

    Why can PES peak groups reveal an atom's occupied subshells?

    Cevap

    Electrons in different subshells require distinct removal energies, producing separate binding-energy groups.

  39. Kart 39

    Soru

    How do ion radii compare with neutral atoms and within an isoelectronic series?

    Cevap

    Cations are smaller than their neutral atoms, while anions are larger. Among species with the same electron count, more protons pull the electrons closer and produce the smaller radius.

  40. Kart 40

    Soru

    What formula is expected for a compound between a Group 2 metal M and a Group 17 nonmetal X?

    Cevap

    MX₂, because M forms M²⁺ and X forms X⁻.

  41. Kart 41

    Soru

    When is a covalent bond considered nonpolar?

    Cevap

    When the bonded atoms have identical or very similar electronegativities, so the shared electron density is distributed approximately evenly.

  42. Kart 42

    Soru

    Why does a bonded pair of atoms have an equilibrium bond length?

    Cevap

    At that separation, attractive and repulsive interactions balance at minimum potential energy.

  43. Kart 43

    Soru

    How are particles arranged in an ionic solid?

    Cevap

    Cations and anions occupy a repeating three-dimensional lattice held by electrostatic attraction.

  44. Kart 44

    Soru

    What model explains bonding in a metal?

    Cevap

    Positive metal cores are held together by attraction to mobile, delocalized valence electrons.

  45. Kart 45

    Soru

    How do you construct a Lewis diagram?

    Cevap

    Count total valence electrons, adding electrons for a negative charge and subtracting them for a positive charge. Choose a skeleton, connect atoms with single bonds, complete terminal duets or octets, and place remaining electrons on the central atom. Add multiple bonds if needed, then check the electron total and formal charges.

  46. Kart 46

    Soru

    What does resonance mean in a molecule or ion?

    Cevap

    Resonance uses two or more valid Lewis diagrams with the same atom arrangement but different electron placement. The actual electron distribution is a hybrid; equivalent contributors have equal weight.

  47. Kart 47

    Soru

    What determines molecular shape in VSEPR theory?

    Cevap

    Electron domains around the central atom arrange to minimize repulsions.

  48. Kart 48

    Soru

    How does an ionic bond differ from a covalent bond?

    Cevap

    Ionic bonding is attraction among oppositely charged ions in an extended structure; covalent bonding uses shared electron density between atoms.

  49. Kart 49

    Soru

    What happens to potential energy when bonded atoms are pushed much closer than equilibrium?

    Cevap

    Potential energy rises sharply because nucleus–nucleus and electron–electron repulsions dominate.

  50. Kart 50

    Soru

    Why are many ionic solids brittle?

    Cevap

    A shifted lattice can align like charges, creating strong repulsion that splits the crystal.

  51. Kart 51

    Soru

    What molecular shapes arise from two electron domains with no lone pairs and from three domains with zero or one lone pair?

    Cevap

    Two bonding domains give linear with a 180° angle. Three domains with no lone pairs give trigonal planar with 120° angles; replacing one bond with a lone pair gives bent with an angle slightly below 120°.

  52. Kart 52

    Soru

    Why are metals electrically conductive as solids?

    Cevap

    Their delocalized electrons can move through the solid when an electric field is applied.

  53. Kart 53

    Soru

    How is formal charge calculated for an atom in a Lewis diagram?

    Cevap

    Formal charge = valence electrons − nonbonding electrons − half the bonding electrons.

  54. Kart 54

    Soru

    Why can't electronegativity difference alone classify a bond as ionic or covalent?

    Cevap

    Bonding lies on a continuum. A larger difference means more ionic character, but the element types and especially the compound's properties give the best classification.

  55. Kart 55

    Soru

    Which shapes and bond-angle trends arise as lone pairs replace bonds in four electron domains?

    Cevap

    Four bonds give tetrahedral with ideal 109.5° angles. One lone pair gives trigonal pyramidal with smaller angles; two lone pairs give bent with typically smaller angles again because lone pairs repel more strongly than bonding pairs.

  56. Kart 56

    Soru

    What feature of a potential-energy curve represents bond dissociation energy?

    Cevap

    The energy difference from the curve's minimum to the separated-atoms limit.

  57. Kart 57

    Soru

    When does an ionic compound conduct electricity?

    Cevap

    When molten or dissolved so its ions can move; not as a rigid solid lattice.

  58. Kart 58

    Soru

    What is a substitutional alloy?

    Cevap

    An alloy in which atoms of a similar size replace some host-metal atoms in the lattice.

  59. Kart 59

    Soru

    How do two, three, and four electron domains map to hybridization?

    Cevap

    Two domains map to sp, three to sp², and four to sp³, with ideal angles of 180°, 120°, and 109.5°. Hybridization involving d orbitals is outside this deck’s scope.

  60. Kart 60

    Soru

    What usually makes one resonance contributor more favorable than another?

    Cevap

    Smaller formal-charge magnitudes, appropriate negative charge on more electronegative atoms, and complete valence shells where applicable.

  61. Kart 61

    Soru

    How many sigma and pi bonds are in single, double, and triple bonds?

    Cevap

    A single bond has one sigma bond; a double has one sigma and one pi bond; a triple has one sigma and two pi bonds. Head-on sigma overlap is stronger than side-by-side pi overlap.

  62. Kart 62

    Soru

    Why is a polar covalent bond polar?

    Cevap

    Unequal electronegativity creates an uneven sharing of electron density and partial charges.

  63. Kart 63

    Soru

    Which molecular shapes arise as lone pairs replace bonds in five electron domains?

    Cevap

    Five bonds give trigonal bipyramidal; four bonds and one lone pair give seesaw; three bonds and two lone pairs give T-shaped; two bonds and three lone pairs give linear.

  64. Kart 64

    Soru

    How do ionic charge and ionic radius affect attraction between ions?

    Cevap

    Larger charge magnitudes and smaller ionic radii produce stronger attraction because the charge product increases and the ion centers are closer.

  65. Kart 65

    Soru

    Why do ionic solids often have high melting points?

    Cevap

    Many strong Coulombic attractions throughout the lattice must be overcome to free the ions.

  66. Kart 66

    Soru

    What is an interstitial alloy?

    Cevap

    A smaller atom occupies holes between host-metal atoms, often making lattice layers harder to slide.

  67. Kart 67

    Soru

    What shape has six bonding domains and no lone pairs on the central atom?

    Cevap

    Octahedral.

  68. Kart 68

    Soru

    Which elements commonly form incomplete octets in stable Lewis diagrams?

    Cevap

    Hydrogen forms a duet, and electron-deficient central atoms such as boron or beryllium can have fewer than eight electrons.

  69. Kart 69

    Soru

    How do bond order and atomic size affect covalent bond length and strength?

    Cevap

    Within a comparable bond family, higher bond order gives shorter, stronger bonds. Larger bonded atoms generally give longer bonds, which are often weaker because their orbitals overlap less effectively.

  70. Kart 70

    Soru

    What bonding model best fits a sample that is malleable and conducts as a solid?

    Cevap

    Metallic bonding with mobile, delocalized electrons and nondirectional attractions.

  71. Kart 71

    Soru

    What shape has six electron domains, five bonds, and one lone pair?

    Cevap

    Square pyramidal.

  72. Kart 72

    Soru

    Which lattice should have stronger attractions: MgO or NaCl, assuming similar separations?

    Cevap

    MgO, because the charge product for Mg²⁺ and O²⁻ is larger than for Na⁺ and Cl⁻.

  73. Kart 73

    Soru

    Why are pure metals often malleable?

    Cevap

    Metal cores can shift while the mobile electron sea maintains nondirectional attraction instead of exposing fixed like-charge planes.

  74. Kart 74

    Soru

    What is the best Lewis structure for CO₂?

    Cevap

    O=C=O, with two lone pairs on each oxygen and no formal charges.

  75. Kart 75

    Soru

    What shape has six electron domains, four bonds, and two opposite lone pairs?

    Cevap

    Square planar.

  76. Kart 76

    Soru

    What limitation does an odd total number of valence electrons create for a Lewis diagram?

    Cevap

    At least one electron must remain unpaired, so not every atom can have a complete paired-electron octet.

  77. Kart 77

    Soru

    What does a higher bond order do to a bond's potential-energy curve?

    Cevap

    It generally places the minimum at a shorter internuclear distance and makes the well deeper, corresponding to a shorter bond and a larger bond-dissociation energy.

  78. Kart 78

    Soru

    When can a carbon–carbon double bond produce geometric isomers?

    Cevap

    When each carbon has two different substituents. The pi bond restricts rotation, so distinct spatial arrangements can persist.

  79. Kart 79

    Soru

    When may a third-period central atom exceed an octet in a Lewis diagram?

    Cevap

    When the valid electron count and lower formal charges favor an expanded valence shell, as in species such as SF₆.

  80. Kart 80

    Soru

    How do you decide whether a molecule with polar bonds is polar overall?

    Cevap

    Add the bond-dipole vectors using the molecular shape; symmetry may cancel them, while an asymmetric arrangement leaves a net dipole.

  81. Kart 81

    Soru

    Which interparticle forces act between all atoms and molecules?

    Cevap

    London dispersion forces, caused by temporary and induced dipoles.

  82. Kart 82

    Soru

    What four broad solid types does this deck compare?

    Cevap

    Ionic, metallic, molecular, and covalent-network solids.

  83. Kart 83

    Soru

    How do gas particles differ from liquid particles?

    Cevap

    Gas particles are much farther apart and move independently; liquid particles stay close but can move past one another.

  84. Kart 84

    Soru

    What relationship connects pressure, volume, amount, and temperature for an ideal gas?

    Cevap

    PV = nRT, with absolute temperature in kelvins and units consistent with R.

  85. Kart 85

    Soru

    What does temperature measure in kinetic molecular theory?

    Cevap

    The particles' average translational kinetic energy.

  86. Kart 86

    Soru

    What two ideal-gas assumptions fail most clearly for real gases?

    Cevap

    Particles have nonzero volume and experience intermolecular attractions.

  87. Kart 87

    Soru

    How is molarity defined?

    Cevap

    Moles of solute per liter of solution: M = n/V.

  88. Kart 88

    Soru

    What must a correct particulate diagram of NaCl(aq) show?

    Cevap

    Separated Na⁺ and Cl⁻ ions in a 1:1 ratio, each surrounded by oriented water molecules.

  89. Kart 89

    Soru

    Which separation method removes an insoluble solid from a liquid?

    Cevap

    Filtration: the solid stays as residue while the liquid passes as filtrate.

  90. Kart 90

    Soru

    What does “like dissolves like” mean at the particle level?

    Cevap

    A solute tends to dissolve when new solute–solvent attractions can compete with the attractions disrupted in the pure substances.

  91. Kart 91

    Soru

    What happens when matter absorbs electromagnetic radiation?

    Cevap

    Its particles move to an allowed higher-energy state when the photon energy matches the energy gap.

  92. Kart 92

    Soru

    Which equations connect photon energy, frequency, and wavelength?

    Cevap

    E = hν and c = λν.

  93. Kart 93

    Soru

    What is the Beer–Lambert law?

    Cevap

    A = εbc: absorbance equals molar absorptivity at the chosen wavelength times path length times concentration.

  94. Kart 94

    Soru

    What molecular features generally strengthen London dispersion forces?

    Cevap

    More electrons and a more polarizable cloud strengthen temporary dipoles; greater contact area and accessible π-electron density can also strengthen the attraction.

  95. Kart 95

    Soru

    Why do molecular solids usually have low melting points and fail to conduct electricity?

    Cevap

    Distinct molecules are held together by relatively weak intermolecular forces, while their valence electrons stay localized in bonds and lone pairs.

  96. Kart 96

    Soru

    How do particles move in a solid?

    Cevap

    They vibrate about fixed positions and do not translate past one another.

  97. Kart 97

    Soru

    What graph shapes connect V or P with T(K) or n for an ideal gas?

    Cevap

    All four are straight lines through the origin: V versus T(K) at fixed n and P; P versus T(K) at fixed n and V; V versus n at fixed P and T; and P versus n at fixed V and T.

  98. Kart 98

    Soru

    At the same temperature, which gas has the greater average molecular speed: He or Xe?

    Cevap

    He. Both have the same average kinetic energy, but KE = ½mv² means the lower-mass particles move faster.

  99. Kart 99

    Soru

    Why do real gases deviate more at high pressure?

    Cevap

    Particles are crowded, so their own volume is no longer negligible compared with the container volume.

  100. Kart 100

    Soru

    Which relationship describes dilution when solute amount is conserved?

    Cevap

    M₁V₁ = M₂V₂.

  101. Kart 101

    Soru

    Why does an aqueous ionic solution conduct electricity?

    Cevap

    Dissolved ions are mobile and carry charge through the solution.

  102. Kart 102

    Soru

    Which property lets simple distillation separate two liquids?

    Cevap

    A sufficient difference in volatility or boiling point, so the vapor is enriched in the more volatile component.

  103. Kart 103

    Soru

    Why are many ionic compounds soluble in water but poorly soluble in a nonpolar solvent?

    Cevap

    Water can form strong ion–dipole attractions that stabilize separated ions; a nonpolar solvent cannot provide comparable attractions.

  104. Kart 104

    Soru

    Which molecular transition is commonly associated with microwave absorption?

    Cevap

    A transition between quantized rotational energy levels.

  105. Kart 105

    Soru

    What frequency corresponds to a 600. nm photon?

    Cevap

    5.00 × 10^14 s^-1. Use ν = c/λ with 600. nm = 6.00 × 10^-7 m.

  106. Kart 106

    Soru

    What is the absorbance to two significant figures when ε = 2.0 × 10² L mol^-1 cm^-1, b = 1.00 cm, and c = 0.0020 M?

    Cevap

    0.40. Use A = εbc.

  107. Kart 107

    Soru

    What conditions allow hydrogen bonding between two molecules?

    Cevap

    One molecule must donate an H covalently bonded to N, O, or F, and the other must provide a lone pair on N, O, or F. A molecule can be a donor, an acceptor, or both.

  108. Kart 108

    Soru

    Why are covalent-network solids often very hard with high melting points?

    Cevap

    A continuous network of strong covalent bonds must be disrupted to deform or melt the solid.

  109. Kart 109

    Soru

    Why do a substance's solid and liquid phases usually have similar molar volumes?

    Cevap

    Their particles remain in close contact in both phases, even though liquid particles can move past one another.

  110. Kart 110

    Soru

    How is a gas mixture's total pressure related to its component pressures?

    Cevap

    Ptotal = ΣPi; each partial pressure is the pressure that component would exert alone in the same volume and temperature.

  111. Kart 111

    Soru

    What microscopic events create gas pressure?

    Cevap

    Gas particles collide with container walls and transfer momentum.

  112. Kart 112

    Soru

    Why do intermolecular attractions matter more for gases at low temperature?

    Cevap

    Particles move more slowly, so attractions can alter their paths and promote condensation.

  113. Kart 113

    Soru

    What is the final concentration after 50.0 mL of 2.00 M solution is diluted to 200.0 mL?

    Cevap

    0.500 M. Use M₂ = M₁V₁/V₂.

  114. Kart 114

    Soru

    What must a particulate representation of a solution communicate?

    Cevap

    The relative concentrations of its components and the particle-level interactions among those components.

  115. Kart 115

    Soru

    What causes components to separate in chromatography?

    Cevap

    They differ in attraction to the stationary phase and the mobile phase, so they travel at different rates.

  116. Kart 116

    Soru

    Why are many polar molecular solutes soluble in water?

    Cevap

    Dipole attractions or hydrogen bonds with water can replace the solute–solute and water–water attractions disrupted during mixing.

  117. Kart 117

    Soru

    Why does an atom produce discrete spectral lines?

    Cevap

    Its electrons can occupy only quantized energy levels, so only photons matching allowed energy differences are absorbed or emitted.

  118. Kart 118

    Soru

    How does photon energy change when frequency doubles?

    Cevap

    It doubles because E = hν.

  119. Kart 119

    Soru

    Why is a calibration curve useful in spectrophotometry?

    Cevap

    It relates measured absorbance to known concentrations, letting an unknown concentration be read by interpolation within the linear range.

  120. Kart 120

    Soru

    How does an ion–dipole attraction form, and how does it compare with dipole–dipole attraction?

    Cevap

    An ion attracts the oppositely charged end of a polar molecule. Ion–dipole attractions tend to be stronger than dipole–dipole attractions.

  121. Kart 121

    Soru

    Which solid type is usually both conductive and malleable?

    Cevap

    A metallic solid, because its delocalized electrons move and its nondirectional bonding tolerates layer shifts.

  122. Kart 122

    Soru

    How does a crystalline solid differ from an amorphous solid?

    Cevap

    A crystalline solid has long-range repeating order; an amorphous solid lacks that long-range periodic arrangement.

  123. Kart 123

    Soru

    How is a gas component's partial pressure found from mole fraction?

    Cevap

    Pi = XiPtotal.

  124. Kart 124

    Soru

    How does heating a fixed-volume gas affect its pressure in the ideal model?

    Cevap

    Pressure rises because faster particles collide with the walls more forcefully and frequently.

  125. Kart 125

    Soru

    Why can attractions make a real gas's measured pressure lower than the ideal prediction?

    Cevap

    Attractions pull approaching particles away from the walls, reducing momentum transfer during wall collisions.

  126. Kart 126

    Soru

    How many moles of ions result from complete dissolution of 0.20 mol CaCl₂?

    Cevap

    0.60 mol ions: 0.20 mol Ca²⁺ plus 0.40 mol Cl⁻.

  127. Kart 127

    Soru

    How should water orient around Cl⁻ in a particle model?

    Cevap

    Its partially positive hydrogen ends point toward Cl⁻.

  128. Kart 128

    Soru

    Can filtration separate dissolved components of a liquid solution?

    Cevap

    No. Dissolved particles pass through the filter with the solvent; filtration only retains an insoluble solid.

  129. Kart 129

    Soru

    Why do nonpolar molecular solutes often dissolve in nonpolar solvents?

    Cevap

    Both rely mainly on compatible London dispersion forces, so mixing can replace the attractions disrupted in the separate substances.

  130. Kart 130

    Soru

    What does a shorter absorbed wavelength imply about an energy transition?

    Cevap

    A larger energy gap because E = hc/λ.

  131. Kart 131

    Soru

    What is the energy of a photon with frequency 5.0 × 10^14 s^-1?

    Cevap

    3.3 × 10^-19 J. Multiply by Planck's constant: E = (6.626 × 10^-34 J·s)(5.0 × 10^14 s^-1).

  132. Kart 132

    Soru

    How does doubling cuvette path length affect absorbance in the linear Beer–Lambert range?

    Cevap

    Absorbance doubles if concentration and molar absorptivity stay constant.

  133. Kart 133

    Soru

    How can noncovalent interactions affect a large biomolecule?

    Cevap

    Attractions between molecules or between different regions of the same molecule help set its shape, which strongly affects its properties and function.

  134. Kart 134

    Soru

    Why does an ionic solid usually fail to conduct as a solid?

    Cevap

    Its ions are fixed in lattice positions. The same substance conducts when molten or dissolved because the ions can then move.

  135. Kart 135

    Soru

    Why does a gas have no definite shape or volume?

    Cevap

    Its widely spaced particles move constantly and experience minimal interparticle attraction, so they spread through the available container.

  136. Kart 136

    Soru

    What graph shapes show the inverse pressure–volume relationship for a fixed amount of ideal gas at constant temperature?

    Cevap

    A plot of P against V is a decreasing curve, while P against 1/V is a straight line through the origin.

  137. Kart 137

    Soru

    At the same temperature, do different ideal gases have different average kinetic energies?

    Cevap

    No. Average translational kinetic energy depends only on absolute temperature.

  138. Kart 138

    Soru

    Under which conditions is ideal-gas behavior most accurate?

    Cevap

    Low pressure and high temperature, where particles are far apart and attractions matter least.

  139. Kart 139

    Soru

    What particle-level feature distinguishes a solution from a heterogeneous mixture?

    Cevap

    A solution—whether solid, liquid, or gas—is uniform throughout; a heterogeneous mixture has regions or phases with different compositions.

  140. Kart 140

    Soru

    How should water orient around Na⁺ in a particulate model?

    Cevap

    Its partially negative oxygen end points toward Na⁺.

  141. Kart 141

    Soru

    In paper chromatography, why does one solute spot travel farther than another?

    Cevap

    It interacts more strongly with the mobile phase or more weakly with the stationary phase. With known phase polarities, that travel difference can reveal relative solute polarity.

  142. Kart 142

    Soru

    What energy competition helps explain whether an ionic solid dissolves?

    Cevap

    The energy needed to separate lattice ions competes with the energy released when ion–solvent attractions form.

  143. Kart 143

    Soru

    Which molecular motions commonly absorb infrared radiation?

    Cevap

    Bond vibrations whose changing dipole can interact with the radiation.

  144. Kart 144

    Soru

    Why must wavelength be converted to meters in c = λν when c is in m s^-1?

    Cevap

    Consistent units are required so meters cancel correctly and frequency comes out in s^-1.

  145. Kart 145

    Soru

    How can fingerprints on a cuvette affect a visible-light absorbance reading?

    Cevap

    They can absorb or scatter extra light, making measured absorbance too high and the inferred concentration too high.

  146. Kart 146

    Soru

    What causes and controls the strength of dipole–dipole attractions?

    Cevap

    Opposite partial charges on neighboring polar molecules attract. Strength increases with larger molecular dipoles and depends on how favorably the dipoles are oriented.

  147. Kart 147

    Soru

    Why is graphite conductive and soft while diamond is insulating and hard?

    Cevap

    Graphite has delocalized electrons within its sheets, so it conducts, and its layers can slide, so it is soft. Diamond has a rigid three-dimensional network of localized covalent bonds, making it hard and insulating.

  148. Kart 148

    Soru

    Why are gases much more compressible than liquids?

    Cevap

    Gas particles have large empty spaces between them; liquid particles are already close together.

  149. Kart 149

    Soru

    What volume does 0.500 mol CO₂ occupy at 1.00 atm and 300. K if it behaves ideally?

    Cevap

    12.3 L. Use V = nRT/P = (0.500 mol)(0.08206 L atm mol^-1 K^-1)(300. K)/(1.00 atm).

  150. Kart 150

    Soru

    Why does a lighter gas effuse faster than a heavier gas at the same temperature?

    Cevap

    Its particles have a higher average speed because equal average kinetic energy is shared by less mass.

  151. Kart 151

    Soru

    How does finite particle volume affect a real gas at very high pressure?

    Cevap

    The free volume available for particle motion is smaller than the container volume assumed by the ideal model.

  152. Kart 152

    Soru

    How should 250.0 mL of 0.100 M NaCl be prepared from solid NaCl?

    Cevap

    Dissolve 0.0250 mol NaCl, or 1.46 g, then dilute to exactly 250.0 mL in a volumetric flask.

  153. Kart 153

    Soru

    What changes in a particle diagram when a solution is diluted without losing solute?

    Cevap

    The solute-particle count stays constant while solvent volume and particle spacing increase.

  154. Kart 154

    Soru

    Why is fractional distillation better than simple distillation for liquids with close boiling points?

    Cevap

    Repeated vaporization–condensation steps enrich the vapor in the more volatile component more effectively.

  155. Kart 155

    Soru

    Why are oil and water usually immiscible?

    Cevap

    Water's strong hydrogen-bond network isn't replaced by equally strong water–oil attractions, so the substances separate into phases.

  156. Kart 156

    Soru

    Which molecular transition is commonly associated with ultraviolet or visible absorption?

    Cevap

    A transition between electronic energy levels.

  157. Kart 157

    Soru

    Which photon carries more energy, blue light or red light?

    Cevap

    Blue light, because it has shorter wavelength and higher frequency.

  158. Kart 158

    Soru

    Why is absorbance often measured at the wavelength of maximum absorbance in Beer–Lambert analysis?

    Cevap

    It gives the largest concentration-sensitive signal, and the flat top near the maximum makes small wavelength-setting errors less influential.

  159. Kart 159

    Soru

    What creates a dipole–induced-dipole attraction, and what controls its strength?

    Cevap

    A permanent dipole distorts a nearby nonpolar particle's electron cloud and creates an attractive temporary dipole. A larger permanent dipole and a more polarizable nonpolar partner make the attraction stronger.

  160. Kart 160

    Soru

    How do stronger intermolecular forces affect vapor pressure, boiling point, and melting point?

    Cevap

    They lower vapor pressure and raise boiling point. Melting point often rises too, but the trend is less direct because melting rearranges rather than fully separates particles.

  161. Kart 161

    Soru

    How do particles behave in a liquid?

    Cevap

    They stay in close contact while moving and colliding continuously. Temperature and interparticle attractions affect their arrangement and motion.

  162. Kart 162

    Soru

    Why must Celsius temperature be converted to kelvins in gas-law calculations?

    Cevap

    Gas-law proportionalities require an absolute temperature scale whose zero corresponds to zero extrapolated thermal motion.

  163. Kart 163

    Soru

    How does raising temperature change a Maxwell–Boltzmann speed distribution?

    Cevap

    The distribution broadens, its peak lowers and shifts right, and a larger fraction of particles have high speed.

  164. Kart 164

    Soru

    Why does the ideal-gas model treat collisions as elastic?

    Cevap

    It assumes total kinetic energy is conserved in particle–particle and particle–wall collisions.

  165. Kart 165

    Soru

    How many moles of solute are in 75.0 mL of a 0.400 M solution?

    Cevap

    0.0300 mol. Multiply 0.400 mol L^-1 by 0.0750 L.

  166. Kart 166

    Soru

    For equal solution volumes drawn at the same scale, what shows which solution is more concentrated?

    Cevap

    The more concentrated diagram contains more solute particles in that equal volume.

  167. Kart 167

    Soru

    How do differences in intermolecular attractions let distillation separate a liquid solution?

    Cevap

    They give the components different vapor pressures, so the vapor is enriched in the more volatile component.

  168. Kart 168

    Soru

    What comparison helps predict whether two liquids will be miscible?

    Cevap

    Liquids with similar types and strengths of intermolecular attractions are more likely to mix uniformly.

  169. Kart 169

    Soru

    How can an absorption spectrum help identify a substance?

    Cevap

    Its allowed energy gaps produce a characteristic pattern of absorbed wavelengths that can be compared with known spectra.

  170. Kart 170

    Soru

    How does absorbing or emitting a photon change an atom's or molecule's energy?

    Cevap

    Absorption raises the species' energy by exactly the photon energy; emission lowers it by the same amount.

  171. Kart 171

    Soru

    What macroscopic evidence can support that a chemical reaction occurred?

    Cevap

    Evidence can include gas formation, precipitate formation, a persistent color change, or an energy change, interpreted with particle-level changes.

  172. Kart 172

    Soru

    What does a net ionic equation include?

    Cevap

    Only the dissolved or reacting species that undergo chemical change; spectator ions are omitted.

  173. Kart 173

    Soru

    What must a correct particulate reaction diagram conserve?

    Cevap

    The number of atoms of every element and the total charge.

  174. Kart 174

    Soru

    What distinguishes a chemical change from a physical change?

    Cevap

    A chemical change rearranges bonds into new substances; a physical change alters state or arrangement without changing chemical identity.

  175. Kart 175

    Soru

    What does a balanced equation's coefficient ratio provide?

    Cevap

    The mole ratio among reacting and produced species.

  176. Kart 176

    Soru

    What is the equivalence point of a titration?

    Cevap

    The point where titrant and analyte have reacted in the stoichiometric ratio given by the balanced equation.

  177. Kart 177

    Soru

    What defines a precipitation reaction?

    Cevap

    Aqueous ions combine to form a sparingly soluble solid.

  178. Kart 178

    Soru

    What happens in a Brønsted–Lowry acid–base reaction?

    Cevap

    A proton transfers from the acid (donor) to the base (acceptor). In aqueous solution, H₂O can play either role.

  179. Kart 179

    Soru

    What does oxidation mean in a redox reaction?

    Cevap

    Loss of electrons and an increase in oxidation number.

  180. Kart 180

    Soru

    What particle-level change confirms that a process is chemical?

    Cevap

    Atoms rearrange into new combinations, producing substances with different compositions.

  181. Kart 181

    Soru

    Which ions are spectators when AgNO₃(aq) reacts with NaCl(aq)?

    Cevap

    Na⁺ and NO₃⁻. The net ionic reaction is Ag⁺(aq) + Cl⁻(aq) → AgCl(s).

  182. Kart 182

    Soru

    How does a particulate diagram reveal the limiting reactant?

    Cevap

    After forming the maximum product allowed by the ratio, none of the limiting reactant remains while excess reactant particles do.

  183. Kart 183

    Soru

    Is melting ice a chemical or physical change?

    Cevap

    A physical change. H₂O molecules remain H₂O while their arrangement and motion change.

  184. Kart 184

    Soru

    How is the limiting reactant identified from given amounts?

    Cevap

    Convert each reactant to the same product amount using the balanced equation; the smaller product amount identifies the limiting reactant.

  185. Kart 185

    Soru

    How does an endpoint differ from an equivalence point?

    Cevap

    The endpoint is an observed signal such as indicator color change; the equivalence point is the exact stoichiometric condition.

  186. Kart 186

    Soru

    How is complete combustion of a hydrocarbon in excess oxygen classified, and what products form?

    Cevap

    It is a redox combustion reaction that forms CO₂ and H₂O.

  187. Kart 187

    Soru

    What are the conjugate acid and conjugate base in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Cevap

    NH₄⁺ is the conjugate acid of NH₃, and OH⁻ is the conjugate base of H₂O.

  188. Kart 188

    Soru

    What does reduction mean in a redox reaction?

    Cevap

    Gain of electrons and a decrease in oxidation number.

  189. Kart 189

    Soru

    Which common changes are physical rather than chemical?

    Cevap

    Phase changes and the formation or separation of mixtures are physical when each substance keeps its composition.

  190. Kart 190

    Soru

    How are strong soluble electrolytes written in a complete ionic equation?

    Cevap

    As separated aqueous ions; solids, liquids, gases, and weak electrolytes stay intact.

  191. Kart 191

    Soru

    A diagram starts with six A particles and four B₂ particles for 2A + B₂ → 2AB; what remains after completion?

    Cevap

    One B₂ remains. Six A consume three B₂ and form six AB.

  192. Kart 192

    Soru

    Why is dissolving NaCl in water normally classified as a physical change?

    Cevap

    Na⁺ and Cl⁻ separate and become hydrated, but retain their chemical identities. Removing the water recovers NaCl; the shift from ion–ion to ion–dipole attractions does not by itself form a new substance.

  193. Kart 193

    Soru

    What mass of AgCl can form from 25.0 mL of 0.200 M AgNO₃ mixed with excess Cl⁻?

    Cevap

    0.717 g AgCl. The 1:1 reaction gives 0.00500 mol AgCl; multiply by 143.32 g mol^-1.

  194. Kart 194

    Soru

    What calculation finds unknown analyte moles at equivalence?

    Cevap

    Use titrant moles, n = MV, then apply the balanced-reaction mole ratio.

  195. Kart 195

    Soru

    Which feature identifies an acid–base, redox, or precipitation reaction?

    Cevap

    Acid–base reactions transfer protons, redox reactions change oxidation numbers through electron transfer, and precipitation reactions form a sparingly soluble solid.

  196. Kart 196

    Soru

    What is the net ionic equation for strong acid–strong base neutralization?

    Cevap

    H⁺(aq) + OH⁻(aq) → H₂O(l).

  197. Kart 197

    Soru

    What is the oxidation number of sulfur in SO₄²⁻?

    Cevap

    +6. Four oxygens contribute -8 total, so sulfur must be +6 to give -2 overall.

  198. Kart 198

    Soru

    Why can gas bubbles alone be ambiguous evidence of reaction?

    Cevap

    Bubbles may also come from boiling or dissolved gas escaping, so the context and particle identities must support a chemical change.

  199. Kart 199

    Soru

    How is melting ice represented as a balanced physical-change equation?

    Cevap

    H₂O(s) → H₂O(l). The formula and atom count stay the same because only the physical state changes.

  200. Kart 200

    Soru

    What does a particle diagram show when no reaction occurs after two aqueous ionic solutions mix?

    Cevap

    All ions remain separated and solvated, with no new bonded particles, precipitate, or gas.

  201. Kart 201

    Soru

    Why is rusting iron a chemical change?

    Cevap

    Iron atoms form new iron-oxide substances through electron transfer and new bonding.

  202. Kart 202

    Soru

    For 2H₂O₂(aq) → 2H₂O(l) + O₂(g), what volume of O₂ forms from 0.100 mol H₂O₂ at 298 K and 1.00 atm?

    Cevap

    1.22 L O₂. The mole ratio gives 0.0500 mol O₂, then V = nRT/P.

  203. Kart 203

    Soru

    A 25.0 mL monoprotic acid sample requires 20.0 mL of 0.150 M NaOH; what is the acid concentration?

    Cevap

    0.120 M. At 1:1 equivalence, moles acid = 0.0200 L × 0.150 M, then divide by 0.0250 L.

  204. Kart 204

    Soru

    Which salts does the minimum solubility rule in this deck treat as soluble?

    Cevap

    All salts containing Na⁺, K⁺, NH₄⁺, or NO₃⁻ are treated as soluble in water.

  205. Kart 205

    Soru

    How are the strengths of a conjugate acid and its conjugate base related?

    Cevap

    A stronger acid has a weaker conjugate base, and a stronger base has a weaker conjugate acid.

  206. Kart 206

    Soru

    How are oxidation and reduction half-reactions combined into one balanced equation?

    Cevap

    Multiply them so electrons lost equal electrons gained, add the half-reactions, then cancel electrons and any identical species on both sides.

  207. Kart 207

    Soru

    How do molecular, complete ionic, and net ionic equations differ?

    Cevap

    Molecular equations keep compounds intact, complete ionic equations split strong soluble electrolytes, and net ionic equations remove spectators. All three conserve atoms and charge.

  208. Kart 208

    Soru

    How should coefficients change particle counts in a reaction diagram?

    Cevap

    They set whole-particle ratios while preserving each particle's chemical formula.

  209. Kart 209

    Soru

    Is separating a mixture by distillation a chemical or physical change?

    Cevap

    A physical change. Components change phase and location but keep their chemical identities.

  210. Kart 210

    Soru

    What equation results from Cu → Cu²⁺ + 2e⁻ and Ag⁺ + e⁻ → Ag?

    Cevap

    Cu + 2Ag⁺ → Cu²⁺ + 2Ag. Multiply the silver half-reaction by 2 and cancel 2e⁻; both atom counts and net charge then match.

  211. Kart 211

    Soru

    How is average reaction rate found from a reactant concentration?

    Cevap

    Use the negative concentration change divided by elapsed time, adjusted by its stoichiometric coefficient when comparing species rates.

  212. Kart 212

    Soru

    What does a rate law express?

    Cevap

    It shows how the measured rate depends on reactant concentrations. In rate = k[A]^m[B]^n, m and n are the orders in A and B, and m + n is the overall order.

  213. Kart 213

    Soru

    A plot of ln[A] versus time is linear; what is the order in A and its integrated rate law?

    Cevap

    First order: ln[A]t = ln[A]0 − kt, so the plot's slope is −k.

  214. Kart 214

    Soru

    What is an elementary reaction?

    Cevap

    A single step in a mechanism whose rate law follows directly from its reactant molecularity.

  215. Kart 215

    Soru

    What two collision conditions are needed for reaction?

    Cevap

    Sufficient collision energy and a productive molecular orientation.

  216. Kart 216

    Soru

    What does activation energy represent on a reaction-energy profile?

    Cevap

    The energy difference from the reactants to the transition state. The reaction coordinate tracks the step's structural progress, not elapsed time.

  217. Kart 217

    Soru

    What must the elementary steps of a valid mechanism do when added?

    Cevap

    Cancel intermediates and reproduce the overall balanced reaction.

  218. Kart 218

    Soru

    How is a proposed mechanism tested against kinetics?

    Cevap

    Its derived rate law must agree with the experimentally measured rate law.

  219. Kart 219

    Soru

    What does a pre-equilibrium approximation assume?

    Cevap

    A fast reversible step reaches equilibrium before a later slow step consumes its intermediate.

  220. Kart 220

    Soru

    What does each peak on a multistep energy profile represent?

    Cevap

    A transition state for one elementary step.

  221. Kart 221

    Soru

    How does a catalyst increase reaction rate?

    Cevap

    It provides an alternate mechanism with a lower activation-energy pathway.

  222. Kart 222

    Soru

    Why does crushing a solid reactant usually increase its reaction rate?

    Cevap

    Crushing increases exposed surface area, so more reactant particles can collide with the other reactant each second.

  223. Kart 223

    Soru

    How is reaction order found from initial-rate data?

    Cevap

    Compare trials where one reactant concentration changes while the others stay constant, then match the rate factor to the concentration factor.

  224. Kart 224

    Soru

    A plot of [A] versus time is linear; what is the order in A and its integrated rate law?

    Cevap

    Zero order: [A]t = [A]0 − kt, so the plot's slope is −k.

  225. Kart 225

    Soru

    What is the rate law for the elementary step 2A + B → products?

    Cevap

    rate = k[A]²[B]. This inference is valid because the step is elementary.

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  226. Kart 226

    Soru

    How does raising temperature change a Maxwell–Boltzmann energy distribution and reaction rate?

    Cevap

    The distribution shifts and broadens toward higher energies, so a larger fraction of collisions exceeds the activation-energy threshold and can react.

  227. Kart 227

    Soru

    How is ΔH read from a reaction-energy profile?

    Cevap

    ΔH = energy of products − energy of reactants.

  228. Kart 228

    Soru

    What is a reaction intermediate?

    Cevap

    A species formed in one mechanism step and consumed in a later step, so it cancels from the overall equation.

  229. Kart 229

    Soru

    Why can't overall reaction coefficients usually supply rate-law exponents?

    Cevap

    The overall equation hides the mechanism; exponents come from experiment unless the reaction is a stated elementary step.

  230. Kart 230

    Soru

    How does pre-equilibrium remove an intermediate from a rate law?

    Cevap

    Use the fast-step equilibrium relation to express the intermediate concentration in terms of stable reactants.

  231. Kart 231

    Soru

    What does each valley between peaks represent on a multistep profile?

    Cevap

    A reaction intermediate.

  232. Kart 232

    Soru

    Does a catalyst change ΔH or the equilibrium constant?

    Cevap

    No. It changes the pathway and rates, not reactant/product energies or the equilibrium composition.

  233. Kart 233

    Soru

    For 2A → B, how are disappearance of A and appearance of B related?

    Cevap

    Reaction rate = -(1/2)Δ[A]/Δt = Δ[B]/Δt.

  234. Kart 234

    Soru

    How do the units of k depend on a rate law's overall order?

    Cevap

    They must make the rate unit M s^-1: zero order uses M s^-1, first order s^-1, and second order M^-1 s^-1.

  235. Kart 235

    Soru

    A plot of 1/[A] versus time is linear; what is the order in A and its integrated rate law?

    Cevap

    Second order: 1/[A]t = 1/[A]0 + kt, so the plot's slope is +k.

  236. Kart 236

    Soru

    What is molecularity?

    Cevap

    The number of reacting particles in an elementary step, such as unimolecular or bimolecular.

  237. Kart 237

    Soru

    How does raising temperature affect k in the qualitative Arrhenius model?

    Cevap

    k increases, often sharply, because a larger fraction of collisions can reach the transition state. Arrhenius-equation calculations are outside this deck’s scope.

  238. Kart 238

    Soru

    A reactant falls from 0.80 M to 0.50 M in 30. s; what is its average disappearance rate to two significant figures?

    Cevap

    0.010 M s^-1. Use -(0.50 − 0.80) M ÷ 30. s.

  239. Kart 239

    Soru

    How does a catalyst differ from an intermediate in a mechanism?

    Cevap

    A catalyst is consumed early and regenerated later; an intermediate is formed early and consumed later.

  240. Kart 240

    Soru

    For 2NO₂ → NO₃ + NO (slow), followed by NO₃ + CO → NO₂ + CO₂ (fast), what rate law is predicted?

    Cevap

    rate = k[NO₂]². The first step is elementary and rate-limiting, so its molecularity sets the observed rate law.

  241. Kart 241

    Soru

    On a multistep reaction-energy profile, which feature often identifies the rate-determining step?

    Cevap

    The step with the largest activation barrier measured from its preceding valley to its peak.

  242. Kart 242

    Soru

    If changing [B] leaves rate unchanged, what is the order in B?

    Cevap

    Zero order, so [B]^0 = 1 in the measured rate law.

  243. Kart 243

    Soru

    What mechanism changes can binding, acid–base, or surface catalysis introduce?

    Cevap

    They can orient reactants, lower activation barriers, or create new bound, protonated, or deprotonated intermediates and elementary steps; the catalyst is regenerated.

  244. Kart 244

    Soru

    What is special about a first-order reaction's half-life?

    Cevap

    It is constant and independent of starting concentration: t1/2 = ln 2/k. Radioactive decay is a common first-order example.

  245. Kart 245

    Soru

    Why is a termolecular elementary collision uncommon?

    Cevap

    Three particles must collide simultaneously with suitable energy and orientation, which is much less probable than one- or two-particle events.

  246. Kart 246

    Soru

    On a reaction-energy profile, how are reverse activation energy, forward activation energy, and ΔH related?

    Cevap

    Ea,reverse = Ea,forward − ΔH. The reverse barrier is measured from products to the same transition state.

  247. Kart 247

    Soru

    Why can correct orientation matter even above the activation energy?

    Cevap

    The colliding reactive sites must align so old bonds can break and new bonds can form along the reaction pathway.

  248. Kart 248

    Soru

    How does detecting a proposed reaction intermediate affect a mechanism claim?

    Cevap

    It supports a mechanism that contains that intermediate, but it doesn't prove that mechanism is unique.

  249. Kart 249

    Soru

    For 2NO ⇌ N₂O₂ (fast equilibrium), followed by N₂O₂ + O₂ → 2NO₂ (slow), what observed rate law results?

    Cevap

    rate = kobs[NO]²[O₂]. Start with rate = k₂[N₂O₂][O₂], use [N₂O₂] = K[NO]² from the fast equilibrium, then substitute.

  250. Kart 250

    Soru

    What does the highest point of a one-step energy profile represent?

    Cevap

    The transition state, an unstable arrangement at the top of the activation barrier.

  251. Kart 251

    Soru

    What sign does q have for an endothermic system?

    Cevap

    Positive, because the system absorbs heat from the surroundings.

  252. Kart 252

    Soru

    How does an exothermic reaction appear on an enthalpy diagram?

    Cevap

    Products lie below reactants, so ΔH is negative.

  253. Kart 253

    Soru

    What condition defines thermal equilibrium?

    Cevap

    Objects in contact have the same temperature, so there is no net heat transfer.

  254. Kart 254

    Soru

    What equations relate heat capacity and temperature change to heat transfer?

    Cevap

    Use q = mcΔT with specific heat capacity, or q = nCₘΔT with molar heat capacity.

  255. Kart 255

    Soru

    Why is temperature constant during a phase-change plateau?

    Cevap

    Added or removed energy changes interparticle potential energy instead of average kinetic energy.

  256. Kart 256

    Soru

    What does ΔHrxn describe?

    Cevap

    The heat absorbed or released at constant pressure for the reaction exactly as written under the stated conditions.

  257. Kart 257

    Soru

    How is reaction enthalpy estimated from average bond enthalpies?

    Cevap

    ΔHrxn ≈ Σ(bonds broken) − Σ(bonds formed).

  258. Kart 258

    Soru

    What is the standard enthalpy of formation of an element in its standard state?

    Cevap

    Zero by definition.

  259. Kart 259

    Soru

    In a Hess’s law calculation, how should a step change when the target needs twice its reverse?

    Cevap

    Reverse the equation, double every coefficient, and multiply its ΔH by -2.

  260. Kart 260

    Soru

    How can energy cross a system boundary during a process?

    Cevap

    As heat or work. Heat transferred to or work done on the system increases its energy; heat transferred from or work done by the system decreases it.

  261. Kart 261

    Soru

    How does an endothermic reaction appear on an enthalpy diagram?

    Cevap

    Products lie above reactants, so ΔH is positive.

  262. Kart 262

    Soru

    How are heat gained by a system and heat lost by its surroundings related in an isolated setup?

    Cevap

    qsystem = -qsurroundings.

  263. Kart 263

    Soru

    In coffee-cup calorimetry, how is reaction heat related to solution heat?

    Cevap

    qrxn = -qsolution when calorimeter heat is negligible and pressure is constant.

  264. Kart 264

    Soru

    What heat is required to melt n moles at the melting point?

    Cevap

    q = nΔHfus.

  265. Kart 265

    Soru

    How does reversing a reaction change ΔH?

    Cevap

    It reverses the sign of ΔH.

  266. Kart 266

    Soru

    Why is breaking a bond endothermic?

    Cevap

    Energy must be supplied to separate atoms against their bonding attraction.

  267. Kart 267

    Soru

    How is ΔH°rxn calculated from standard enthalpies of formation?

    Cevap

    ΣνΔHf°(products) − ΣνΔHf°(reactants).

  268. Kart 268

    Soru

    How does multiplying an equation by 3 affect its ΔH?

    Cevap

    Multiply ΔH by 3 because enthalpy change scales with reaction amount.

  269. Kart 269

    Soru

    Why can an exothermic dissolution warm the solution?

    Cevap

    The solution warms because forming solute–solvent attractions releases more energy than is absorbed in separating the original particles. The net potential-energy decrease raises particle kinetic energy and temperature.

  270. Kart 270

    Soru

    Does an energy diagram's activation barrier determine ΔH?

    Cevap

    No. ΔH depends on reactant and product energy levels, while the barrier controls kinetics.

  271. Kart 271

    Soru

    Why does heat flow from a warmer object to a cooler object?

    Cevap

    Energy transfers through collisions until their average kinetic energies, and therefore temperatures, equalize.

  272. Kart 272

    Soru

    How much heat warms 100.0 g of water by 5.0°C?

    Cevap

    2.1 kJ. Use q = (100.0 g)(4.184 J g^-1 °C^-1)(5.0°C).

  273. Kart 273

    Soru

    How are the molar enthalpies of a phase change and its reverse related?

    Cevap

    They have equal magnitudes and opposite signs, such as ΔHcond = -ΔHvap and ΔHfreeze = -ΔHfus.

  274. Kart 274

    Soru

    How does doubling every coefficient in a thermochemical equation affect ΔH?

    Cevap

    It doubles ΔH.

  275. Kart 275

    Soru

    Why is forming a bond exothermic?

    Cevap

    Atoms move to a lower-potential-energy bonded arrangement and release energy.

  276. Kart 276

    Soru

    What formation equation defines ΔHf° for CO₂(g)?

    Cevap

    C(s, graphite) + O₂(g) → CO₂(g), forming exactly one mole from elements in standard states.

  277. Kart 277

    Soru

    What should happen to intermediate species when equations in a Hess’s law calculation are added?

    Cevap

    They cancel, leaving the target overall reaction.

  278. Kart 278

    Soru

    If the surroundings warm during a process, what is the likely sign of qsystem?

    Cevap

    Negative; the system likely released heat to the surroundings.

  279. Kart 279

    Soru

    For a profile with reactants at 40 kJ and products at 10 kJ, what is ΔH?

    Cevap

    -30 kJ for the reaction as drawn.

  280. Kart 280

    Soru

    Assuming no phase change, what determines the final temperature when two substances exchange heat in an insulated container?

    Cevap

    Energy conservation: q_warm + q_cool = 0. Use each substance's mass, heat capacity, and initial temperature to solve for the common final temperature.

  281. Kart 281

    Soru

    How would heat loss to the room affect an exothermic calorimetry result?

    Cevap

    The observed temperature rise is too small, so the calculated magnitude of released heat is too low.

  282. Kart 282

    Soru

    What heat expression covers warming a liquid without a phase change?

    Cevap

    q = mcΔT, not nΔHphase.

  283. Kart 283

    Soru

    If forming 1 mol of product has ΔH = -50 kJ mol^-1, what is q when 2 mol forms?

    Cevap

    -100 kJ. Use q = nΔH = (2 mol)(-50 kJ mol^-1).

  284. Kart 284

    Soru

    Breaking reactant bonds requires 500 kJ, and forming product bonds releases 650 kJ; what is the estimated ΔH?

    Cevap

    -150 kJ, from 500 − 650.

  285. Kart 285

    Soru

    For CO(g) + ½O₂(g) → CO₂(g), what is ΔH°rxn if ΔHf°[CO] = -110.5 and ΔHf°[CO₂] = -393.5 kJ mol^-1?

    Cevap

    -283.0 kJ. Use -393.5 - [-110.5 + ½(0)], since ΔHf°[O₂(g)] = 0.

  286. Kart 286

    Soru

    In a Hess’s law calculation, two valid steps have ΔH values +25 kJ and -60 kJ; what is the combined ΔH?

    Cevap

    -35 kJ, provided the equations add to the target reaction.

  287. Kart 287

    Soru

    Why is “bonds breaking releases energy” incorrect?

    Cevap

    Bond breaking absorbs energy; the overall reaction releases energy only when forming new bonds releases more than breaking old bonds requires.

  288. Kart 288

    Soru

    How would melting appear on an energy diagram?

    Cevap

    The liquid lies above the solid, so ΔHfus is positive; the diagram represents a physical, endothermic change.

  289. Kart 289

    Soru

    Can two objects at the same temperature exchange energy microscopically?

    Cevap

    Yes, but their energy transfers balance, so there is no net heat flow.

  290. Kart 290

    Soru

    Why must the calorimeter's heat capacity be included when it isn't negligible?

    Cevap

    The apparatus can absorb or release heat, so include q_cal = C_calΔT in the energy balance: q_process + q_solution + q_cal = 0.

  291. Kart 291

    Soru

    What makes chemical equilibrium dynamic?

    Cevap

    Forward and reverse reactions continue at equal rates even though macroscopic concentrations stay constant.

  292. Kart 292

    Soru

    For aA + bB ⇌ cC, what is the concentration-form expression for Q?

    Cevap

    Q = [C]^c / ([A]^a[B]^b), using current rather than necessarily equilibrium concentrations.

  293. Kart 293

    Soru

    What does K much greater than 1 indicate?

    Cevap

    Products predominate at equilibrium, though K says nothing about reaction speed.

  294. Kart 294

    Soru

    How does reversing a reaction change its equilibrium constant?

    Cevap

    K becomes 1/K.

  295. Kart 295

    Soru

    Can a reversible system reach equilibrium when it starts with only products?

    Cevap

    Yes, if the reverse reaction is possible. The equilibrium composition depends on temperature, initial amounts, and volume or pressure.

  296. Kart 296

    Soru

    How do Q and K predict reaction direction?

    Cevap

    Q < K shifts forward, Q > K shifts reverse, and Q = K means equilibrium.

  297. Kart 297

    Soru

    Which species are omitted from a heterogeneous equilibrium expression?

    Cevap

    Pure solids and pure liquids because their activities are effectively constant.

  298. Kart 298

    Soru

    How does increasing a dissolved reactant's concentration or a gaseous reactant's partial pressure affect equilibrium at constant temperature when other Q terms are initially unchanged?

    Cevap

    It lowers Q relative to K, so the system shifts toward products until Q = K again. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that pure phase remains present.

  299. Kart 299

    Soru

    What does a flat concentration-time graph mean at equilibrium?

    Cevap

    Each concentration is constant, not necessarily equal to the others.

  300. Kart 300

    Soru

    For A ⇌ B in one fixed volume, a particulate model shows 16 A and 0 B initially, then 4 A and 12 B at equilibrium. What changed, what predominates, and what is Kc?

    Cevap

    The net change was forward: 12 A particles became 12 B particles. B predominates at equilibrium, and Kc = [B]/[A] = 12/4 = 3.0 because both counts come from the same fixed volume.

  301. Kart 301

    Soru

    What can Ksp tell you about a salt's solubility, and when can two Ksp values be compared directly?

    Cevap

    Ksp > 1 indicates a soluble salt. For salts with the same dissolution stoichiometry, a larger Ksp generally means greater molar solubility; across different stoichiometries, calculate molar solubility before comparing.

  302. Kart 302

    Soru

    What is the common-ion effect on solubility?

    Cevap

    Adding an ion already in the dissolution equilibrium usually decreases the solid's molar solubility.

  303. Kart 303

    Soru

    How does uniform dilution shift an aqueous equilibrium based on the stoichiometric powers in Q?

    Cevap

    It shifts toward the side with the larger sum of stoichiometric coefficients for dissolved species included in Q. If the sums are equal, dilution causes no shift by this effect; pure solids and liquids remain omitted.

  304. Kart 304

    Soru

    What happens if a reversible reaction starts with reactants only?

    Cevap

    The forward rate is initially largest; products form, the reverse rate grows, and the rates eventually become equal.

  305. Kart 305

    Soru

    What is the purpose of an ICE table?

    Cevap

    To organize initial, change, and equilibrium concentrations using reaction stoichiometry.

  306. Kart 306

    Soru

    Can a reaction with a very large K be slow?

    Cevap

    Yes. K describes thermodynamic equilibrium position, while rate depends on kinetics and activation energy.

  307. Kart 307

    Soru

    What happens to Q immediately after product concentration increases?

    Cevap

    Q increases; if it rises above K, the reaction shifts toward reactants.

  308. Kart 308

    Soru

    How does multiplying every reaction coefficient by 2 affect K?

    Cevap

    The new equilibrium constant is K².

  309. Kart 309

    Soru

    For A ⇌ B, Kc = 4.0 and initially [A] = 1.0 M and [B] = 0, what are the equilibrium concentrations?

    Cevap

    [A] = 0.20 M and [B] = 0.80 M. Let x form: Kc = x/(1.0 − x) = 4.0, so x = 0.80 M.

  310. Kart 310

    Soru

    What macroscopic properties stay constant at equilibrium?

    Cevap

    Properties such as concentration, color, and pressure remain constant when external conditions are fixed.

  311. Kart 311

    Soru

    How does decreasing volume shift a gaseous equilibrium?

    Cevap

    Toward the side with fewer moles of gas, if the two sides have different gaseous mole counts.

  312. Kart 312

    Soru

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kc?

    Cevap

    Kc = [NH₃]² / ([N₂][H₂]³).

  313. Kart 313

    Soru

    For CaF₂(s) ⇌ Ca²⁺ + 2F⁻, how is Ksp written in terms of molar solubility s in pure water?

    Cevap

    Ksp = s(2s)² = 4s³ because [Ca²⁺] = s and [F⁻] = 2s.

  314. Kart 314

    Soru

    What does K much less than 1 indicate?

    Cevap

    Reactants predominate at equilibrium.

  315. Kart 315

    Soru

    How does decreasing a dissolved product's concentration or a gaseous product's partial pressure affect equilibrium when other Q terms are initially unchanged?

    Cevap

    It lowers Q and drives a net forward reaction until equilibrium returns. Changing the amount of a pure solid or liquid omitted from Q does not cause this shift while that phase remains.

  316. Kart 316

    Soru

    Does equilibrium mean the reaction has stopped?

    Cevap

    No. Both directions continue, but equal rates produce no net macroscopic change.

  317. Kart 317

    Soru

    Why does adding NaF reduce CaF₂ solubility?

    Cevap

    The added F⁻ raises Qsp, shifting the dissolution equilibrium toward solid CaF₂.

  318. Kart 318

    Soru

    For N₂ + 3H₂ ⇌ 2NH₃, what is Kp when P_N₂ = 0.50 atm, P_H₂ = 1.50 atm, and P_NH₃ = 0.25 atm?

    Cevap

    0.037. Use Kp = (P_NH₃)²/[(P_N₂)(P_H₂)³] = (0.25)²/[(0.50)(1.50)³]. Use equilibrium partial pressures directly; Kc↔Kp conversion isn't assessed.

  319. Kart 319

    Soru

    What happens to Q when a gaseous equilibrium mixture is compressed at constant temperature if products have fewer gas moles?

    Cevap

    Q falls relative to K, so the reaction shifts toward products.

  320. Kart 320

    Soru

    How do K and Q transform when a reaction is reversed, its coefficients are multiplied, or reactions are added?

    Cevap

    They follow the same algebra: reversing takes the reciprocal, multiplying every coefficient by c raises the value to the power c, and adding reactions multiplies their K or Q values.

  321. Kart 321

    Soru

    When is the small-x approximation acceptable?

    Cevap

    When x is small relative to the initial concentration and the final result confirms the neglected change is suitably small.

  322. Kart 322

    Soru

    What graph feature shows a disturbance followed by re-equilibration?

    Cevap

    A sudden or gradual concentration change followed by new constant plateaus while rates return to equality.

  323. Kart 323

    Soru

    If Q = 0.20 and K = 5.0, which direction is favored next?

    Cevap

    Forward, because Q < K.

  324. Kart 324

    Soru

    At equilibrium, are reactant and product concentrations equal?

    Cevap

    Not necessarily. They are constant, while forward and reverse rates are equal.

  325. Kart 325

    Soru

    CaF₂ has Ksp = 3.2 × 10^-11 in pure water; what is its molar solubility?

    Cevap

    2.0 × 10^-4 M. If the molar solubility is s, then [Ca²⁺] = s, [F⁻] = 2s, and Ksp = 4s³.

  326. Kart 326

    Soru

    For N₂ + 3H₂ ⇌ 2NH₃, how is Qp written?

    Cevap

    Qp = (P_NH₃)²/[(P_N₂)(P_H₂)³], using the current partial pressures rather than necessarily equilibrium values.

  327. Kart 327

    Soru

    How does heating shift an endothermic forward reaction?

    Cevap

    Toward products, and K increases because temperature changes the equilibrium constant.

  328. Kart 328

    Soru

    Why do both forward and reverse rates change as equilibrium is approached?

    Cevap

    As reactant and product concentrations change, the collision frequencies for the two directions change until their rates match.

  329. Kart 329

    Soru

    CaF₂ has Ksp = 3.2 × 10^-11. What is its molar solubility in 0.10 M NaF?

    Cevap

    About 3.2 × 10^-9 M. With [F⁻] ≈ 0.10 M, Ksp = [Ca²⁺][F⁻]² gives s = (3.2 × 10^-11)/(0.10)². The common ion lowers solubility but does not change Ksp at constant temperature.

  330. Kart 330

    Soru

    What concentration data must be used to calculate Kc?

    Cevap

    Equilibrium concentrations, each raised to its stoichiometric coefficient and excluding pure solids and liquids.

  331. Kart 331

    Soru

    What is a Brønsted–Lowry acid?

    Cevap

    A proton donor.

  332. Kart 332

    Soru

    How is pH defined?

    Cevap

    pH = -log[H₃O⁺].

  333. Kart 333

    Soru

    What is Ka for HA + H₂O ⇌ H₃O⁺ + A⁻?

    Cevap

    Ka = [H₃O⁺][A⁻]/[HA].

  334. Kart 334

    Soru

    How does stabilizing a base affect its basicity and the strength of its conjugate acid?

    Cevap

    It makes the base weaker and its conjugate acid stronger. A more stable base is less willing to accept H⁺.

  335. Kart 335

    Soru

    What is a Brønsted–Lowry base?

    Cevap

    A proton acceptor.

  336. Kart 336

    Soru

    At 25°C, what are Kw and the relationship between pH and pOH?

    Cevap

    Kw = [H₃O⁺][OH⁻] = 1.0 × 10^-14. Taking negative logarithms gives pH + pOH = 14.00.

  337. Kart 337

    Soru

    What is Kb for B + H₂O ⇌ BH⁺ + OH⁻?

    Cevap

    Kb = [BH⁺][OH⁻]/[B].

  338. Kart 338

    Soru

    Why can lowering pH increase the solubility of a salt containing a basic anion?

    Cevap

    H₃O⁺ consumes the anion, pulling the dissolution equilibrium toward more dissolved ions.

  339. Kart 339

    Soru

    What are conjugate acid–base pairs?

    Cevap

    Species that differ by exactly one proton.

  340. Kart 340

    Soru

    What is the pH of 1.0 × 10^-3 M HCl?

    Cevap

    3.00, assuming complete dissociation and negligible water contribution.

  341. Kart 341

    Soru

    How are pKa and pKb defined?

    Cevap

    pKa = -log Ka, and pKb = -log Kb.

  342. Kart 342

    Soru

    Why does acid strength increase across a row of comparable hydrides?

    Cevap

    Increasing electronegativity stabilizes the conjugate base and polarizes the H–A bond.

  343. Kart 343

    Soru

    What is an amphiprotic species?

    Cevap

    A species that can donate or accept a proton, such as HCO₃⁻.

  344. Kart 344

    Soru

    What amounts remain after a limited amount of strong base partially neutralizes weak acid HA?

    Cevap

    Subtract the reacted moles from HA and form the same number of moles of A⁻. The result gives the remaining HA and formed A⁻ amounts before any equilibrium or buffer-pH calculation.

  345. Kart 345

    Soru

    How are Ka, Kb, pKa, and pKb related for a conjugate pair at 25°C?

    Cevap

    KaKb = Kw = 1.0 × 10^-14, and pKa + pKb = pKw = 14.00.

  346. Kart 346

    Soru

    When does pH have little effect on a salt's solubility?

    Cevap

    When neither dissolved ion reacts appreciably with H₃O⁺ or OH⁻.

  347. Kart 347

    Soru

    How does H₂O act in HCl + H₂O → H₃O⁺ + Cl⁻ and in NH₃ + H₂O ⇌ NH₄⁺ + OH⁻?

    Cevap

    It acts as a base in the first reaction by accepting H⁺, and as an acid in the second by donating H⁺.

  348. Kart 348

    Soru

    After mixing weak base B with strong acid, what controls the final solution in the three stoichiometric regimes?

    Cevap

    Excess B leaves a B/BH⁺ buffer; equimolar amounts leave BH⁺, so the solution is acidic; excess strong acid sets the pH from the remaining H₃O⁺.

  349. Kart 349

    Soru

    What two components make a typical weak-acid buffer?

    Cevap

    A weak acid and a significant amount of its conjugate base.

  350. Kart 350

    Soru

    What do the successive half-equivalence pH values approximate in a diprotic weak-acid titration?

    Cevap

    The first approximates pKa₁ and the second approximates pKa₂ because each conjugate pair has equal concentrations at its half-equivalence point.

  351. Kart 351

    Soru

    Which acid is stronger, one with pKa 2 or pKa 5?

    Cevap

    The acid with pKa 2; lower pKa means larger Ka.

  352. Kart 352

    Soru

    What is the Henderson–Hasselbalch equation?

    Cevap

    pH = pKa + log([A⁻]/[HA]).

  353. Kart 353

    Soru

    Why are larger binary hydrides down a group often stronger acids?

    Cevap

    The H–A bond becomes weaker as the central atom grows, so proton release is easier.

  354. Kart 354

    Soru

    What mainly determines buffer capacity?

    Cevap

    The concentrations of both members of the conjugate acid–base pair. Increasing both concentrations at a fixed ratio increases capacity without changing pH; capacity is best balanced for added acid and base when their concentrations are similar.

  355. Kart 355

    Soru

    Why does acid increase CaCO₃ solubility?

    Cevap

    H₃O⁺ converts CO₃²⁻ to HCO₃⁻ or carbonic acid species, reducing free carbonate and driving more CaCO₃ to dissolve.

  356. Kart 356

    Soru

    What does pH < pKa imply for a weak-acid pair?

    Cevap

    The protonated form HA predominates over A⁻.

  357. Kart 357

    Soru

    What happens when stoichiometrically equal amounts of a monoprotic weak acid and strong base are mixed?

    Cevap

    The weak acid is consumed to its conjugate base; at equivalence, the solution isn't a buffer containing both forms.

  358. Kart 358

    Soru

    What is [H₃O⁺] when pH = 4.50?

    Cevap

    3.2 × 10^-5 M, from [H₃O⁺] = 10^-pH.

  359. Kart 359

    Soru

    What is the pH of 0.010 M Ba(OH)₂ at 25°C?

    Cevap

    About 12.30. Complete dissociation gives [OH⁻] = 0.020 M, so pOH = 1.70. At 25°C, pH + pOH = 14.00, so pH = 12.30.

  360. Kart 360

    Soru

    How does a buffer respond to a small amount of added strong acid?

    Cevap

    Its conjugate base consumes H⁺, converting to the weak acid and limiting the pH change.

  361. Kart 361

    Soru

    Why is the equivalence-point solution basic in a monoprotic weak-acid–strong-base titration?

    Cevap

    The conjugate base produced at equivalence reacts with water to form OH⁻, so the pH is above neutral—above 7.00 at 25°C.

  362. Kart 362

    Soru

    How is percent ionization calculated for a weak acid or weak base?

    Cevap

    For HA, use ([H₃O⁺]equilibrium ÷ [HA]initial) × 100%. For B, use ([BH⁺]equilibrium ÷ [B]initial) × 100%, under the usual monoprotic setup.

  363. Kart 363

    Soru

    When is Henderson–Hasselbalch useful for an initial buffer-pH calculation?

    Cevap

    Use it when both members of a conjugate acid–base pair are present in meaningful amounts, including after in-scope stoichiometry creates a buffer. Calculating the pH change after acid or base is added to an existing buffer is outside this deck’s scope.

  364. Kart 364

    Soru

    Why does adding oxygen atoms usually strengthen oxyacids with the same central atom?

    Cevap

    Extra oxygens withdraw electron density and delocalize negative charge in the conjugate base.

  365. Kart 365

    Soru

    A prepared buffer is accidentally diluted to twice its intended volume; what happens to its pH and capacity?

    Cevap

    Its pH stays nearly the same, and its capacity per liter is halved because both component concentrations halve. The total neutralizing moles in the sample remain unchanged.

  366. Kart 366

    Soru

    How does adding OH⁻ affect Mg(OH)₂ solubility?

    Cevap

    It decreases solubility through the common-ion effect, shifting Mg(OH)₂(s) ⇌ Mg²⁺ + 2OH⁻ toward the solid.

  367. Kart 367

    Soru

    A buffer has equal [A⁻] and [HA]; what is its pH?

    Cevap

    pH = pKa because log(1) = 0.

  368. Kart 368

    Soru

    How should a weak acid–strong base mixture be solved before equivalence?

    Cevap

    First use mole stoichiometry; if both HA and A⁻ remain, use the resulting buffer relation.

  369. Kart 369

    Soru

    Why can pure neutral water have a pH other than 7.00?

    Cevap

    Kw changes with temperature. Neutrality means [H₃O⁺] = [OH⁻], while pH = 7.00 only when Kw = 1.0 × 10^-14 at 25°C.

  370. Kart 370

    Soru

    25.0 mL of 0.200 M HCl is diluted to 100.0 mL; what is the pH?

    Cevap

    1.301. Dilution gives [H₃O⁺] = (0.200 M)(25.0 mL)/(100.0 mL) = 0.0500 M, so pH = -log(0.0500).

  371. Kart 371

    Soru

    How does a buffer respond to a small amount of added strong base?

    Cevap

    The weak acid consumes OH⁻, forming conjugate base and water.

  372. Kart 372

    Soru

    How do you find the final pH after mixing a strong acid and strong base at 25°C?

    Cevap

    Use H₃O⁺ + OH⁻ → 2H₂O and compare their moles. Divide excess H₃O⁺ or OH⁻ by the total volume, then calculate pH or pOH from that excess concentration. Equal moles give pH 7.00 at 25°C.

  373. Kart 373

    Soru

    What distinguishes acid strength from acid concentration?

    Cevap

    Strength is the equilibrium tendency to donate H⁺, reflected by Ka or pKa; concentration is the amount of acid per solution volume.

  374. Kart 374

    Soru

    If [A⁻]/[HA] = 10, how does pH compare with pKa?

    Cevap

    pH = pKa + 1 because log 10 = 1.

  375. Kart 375

    Soru

    Which conjugate base is more stable, one with localized or resonance-delocalized charge?

    Cevap

    The resonance-delocalized conjugate base, which generally corresponds to the stronger acid.

  376. Kart 376

    Soru

    Which 1.0 L buffer has greater capacity: 1.0 mol each of HA/A⁻ or 0.10 mol each at the same ratio?

    Cevap

    The 1.0 mol pair; both have the same initial pH, but the larger amounts neutralize more added acid or base.

  377. Kart 377

    Soru

    For BHX(s) ⇌ BH⁺ + X⁻, why can raising pH increase the salt's solubility?

    Cevap

    OH⁻ consumes BH⁺ to form B and H₂O, so dissolution shifts right to replace BH⁺. This is a qualitative prediction, not a pH-dependent solubility calculation.

  378. Kart 378

    Soru

    What does pH > pKa imply for a weak-acid pair?

    Cevap

    The deprotonated form A⁻ predominates over HA.

  379. Kart 379

    Soru

    For HA + B ⇌ A⁻ + BH⁺, which side is favored when pKa(HA) = 4 and pKa(BH⁺) = 9?

    Cevap

    Products are favored. Proton transfer moves toward the weaker acid–base pair, and K ≈ 10^(9 − 4) = 10^5.

  380. Kart 380

    Soru

    What is the pOH when [OH⁻] = 2.5 × 10^-4 M?

    Cevap

    3.60, from -log(2.5 × 10^-4).

  381. Kart 381

    Soru

    What is the pH of 0.100 M HA when Ka = 1.0 × 10^-5?

    Cevap

    About 3.00. The ICE setup gives Ka = x²/(0.100 − x); x ≈ 1.0 × 10^-3 M, and the 1.0% change validates the approximation.

  382. Kart 382

    Soru

    Why does a buffer fail after too much strong acid is added?

    Cevap

    Its conjugate base is depleted, so added H⁺ is no longer consumed effectively.

  383. Kart 383

    Soru

    What do two clear equivalence regions on an acid titration curve suggest?

    Cevap

    At least two distinguishable titratable protons; on a clean ideal curve with exactly two equivalence regions, this is consistent with a diprotic acid.

  384. Kart 384

    Soru

    A buffer has pKa 4.8 and [A⁻]/[HA] = 0.10; what is pH?

    Cevap

    3.8, from 4.8 + log(0.10).

  385. Kart 385

    Soru

    Why is HCl stronger than HF in water despite F being more electronegative?

    Cevap

    The H–F bond is much stronger; bond strength dominates this down-group binary-acid comparison.

  386. Kart 386

    Soru

    Why does percent ionization increase when a weak acid is diluted?

    Cevap

    Dilution shifts ionization toward more particles, so a larger fraction ionizes even though [H₃O⁺] decreases.

  387. Kart 387

    Soru

    A buffer contains more HA than A⁻. Which addition can it neutralize in greater amount: strong acid or strong base?

    Cevap

    Strong base. The larger HA reserve consumes more added OH⁻; a buffer with more A⁻ than HA instead has greater capacity for added strong acid.

  388. Kart 388

    Soru

    Why can removing a basic anion increase a salt's molar solubility without changing Ksp?

    Cevap

    The equilibrium shifts to replace the consumed ion; Ksp remains fixed at the same temperature.

  389. Kart 389

    Soru

    Why can an acid–base indicator change color as pH changes?

    Cevap

    Its protonated and deprotonated forms have different colors or other observable properties, and their relative amounts change with pH.

  390. Kart 390

    Soru

    What buffer results from mixing 1.0 mol HA with 0.40 mol OH⁻?

    Cevap

    0.60 mol HA and 0.40 mol A⁻ remain, forming a buffer before any equilibrium calculation.

  391. Kart 391

    Soru

    What is the pH of 0.200 M weak base B when Kb = 2.0 × 10^-5 at 25°C?

    Cevap

    About 11.30. The ICE setup gives Kb = x²/(0.200 − x); x ≈ 2.0 × 10^-3 M OH⁻, and the 1.0% change validates the approximation.

  392. Kart 392

    Soru

    Why does a weak acid alone not make an effective buffer?

    Cevap

    It lacks a substantial conjugate-base reserve to consume added strong acid.

  393. Kart 393

    Soru

    What controls pH after excess strong base passes equivalence?

    Cevap

    The concentration of excess OH⁻ after accounting for reaction stoichiometry and total volume.

  394. Kart 394

    Soru

    How should an indicator be chosen for a titration?

    Cevap

    Its color-change range should fall within the steep pH change near the equivalence point.

  395. Kart 395

    Soru

    How can a measured pH and known pKa give a conjugate-base/acid ratio?

    Cevap

    Rearrange Henderson–Hasselbalch: [A⁻]/[HA] = 10^(pH − pKa).

  396. Kart 396

    Soru

    Can a weak base and its conjugate acid form a buffer?

    Cevap

    Yes, when both are present in significant amounts.

  397. Kart 397

    Soru

    For equal-volume buffers with the same conjugate-base/acid ratio, how does adding the same amount of strong acid affect a more concentrated versus less concentrated buffer?

    Cevap

    The concentrated buffer changes pH less because it has greater capacity.

  398. Kart 398

    Soru

    How does equivalence-point pH compare for strong acid–strong base, weak acid–strong base, and weak base–strong acid titrations at 25°C?

    Cevap

    Strong acid–strong base: pH 7.00. Weak acid–strong base: above 7.00 because the conjugate base reacts with water. Weak base–strong acid: below 7.00 because the conjugate acid reacts with water.

  399. Kart 399

    Soru

    Why should mole ratios replace concentration ratios after mixing buffer solutions?

    Cevap

    Both components share the same final volume, so that volume cancels in [A⁻]/[HA].

  400. Kart 400

    Soru

    How does adding a little strong acid change a buffer's conjugate-base and conjugate-acid amounts?

    Cevap

    The conjugate base decreases and its conjugate acid increases by the amount of strong acid consumed.

  401. Kart 401

    Soru

    What does entropy measure qualitatively?

    Cevap

    The dispersal of matter and energy among available microstates.

  402. Kart 402

    Soru

    How is standard reaction entropy calculated?

    Cevap

    ΔS°rxn = ΣνS°(products) − ΣνS°(reactants).

  403. Kart 403

    Soru

    What equation gives ΔG° from ΔH° and ΔS°, and what standard states do the degree symbols assume?

    Cevap

    ΔG° = ΔH° − TΔS°. The standard states are pure substances, 1.0 M solutions, and gases at 1 atm or 1 bar; T is in kelvins and energy units must match.

  404. Kart 404

    Soru

    Does thermodynamic favorability guarantee a fast reaction?

    Cevap

    No. A favorable reaction can be slow when its activation barrier is large.

  405. Kart 405

    Soru

    What is ΔG at equilibrium?

    Cevap

    Zero under the current conditions because there is no net driving force.

  406. Kart 406

    Soru

    Why can an endothermic dissolution still be thermodynamically favorable?

    Cevap

    A sufficiently positive entropy change can make TΔS exceed positive ΔH, giving negative ΔG.

  407. Kart 407

    Soru

    How can an unfavorable reaction be driven by a favorable one?

    Cevap

    Couple them so their equations and ΔG values add to a negative overall ΔG.

  408. Kart 408

    Soru

    Where does oxidation occur in every electrochemical cell?

    Cevap

    At the anode.

  409. Kart 409

    Soru

    How are standard cell potential and standard free energy related?

    Cevap

    ΔG° = -nFE°cell.

  410. Kart 410

    Soru

    What equation gives cell potential under nonstandard conditions?

    Cevap

    E = E° − (RT/nF) ln Q. When Q = 1, ln Q = 0, so E = E°.

  411. Kart 411

    Soru

    How is electrical charge related to current and time?

    Cevap

    q = It.

  412. Kart 412

    Soru

    Which phase has greater molar entropy, liquid water or ice at the same temperature?

    Cevap

    Liquid water because its molecules have more accessible arrangements and motion.

  413. Kart 413

    Soru

    Do elements in their standard states have zero standard molar entropy?

    Cevap

    No. Their ΔHf° is zero, but their absolute S° values are positive above 0 K.

  414. Kart 414

    Soru

    How do the four ΔH° and ΔS° sign combinations determine thermodynamic favorability across temperature?

    Cevap

    ΔH° < 0 and ΔS° > 0 is favorable at every temperature; ΔH° > 0 and ΔS° < 0 is thermodynamically unfavored at every temperature. If both are positive, favorability requires high temperature; if both are negative, it requires low temperature.

  415. Kart 415

    Soru

    What does it indicate when a thermodynamically favored process does not occur at a measurable rate?

    Cevap

    It is under kinetic control, commonly because of a high activation energy; no measurable reaction does not mean the system is at equilibrium.

  416. Kart 416

    Soru

    How are ΔG° and K related?

    Cevap

    ΔG° = -RT ln K.

  417. Kart 417

    Soru

    What two contributions compete in dissolving an ionic solid?

    Cevap

    Enthalpy changes from separating and solvating particles, and entropy changes from their new dispersal and solvent organization.

  418. Kart 418

    Soru

    What must cancel when coupled reactions are added?

    Cevap

    Shared intermediates, leaving the desired net reaction.

  419. Kart 419

    Soru

    Where does reduction occur in every electrochemical cell?

    Cevap

    At the cathode.

  420. Kart 420

    Soru

    What sign of E°cell indicates a favorable standard galvanic reaction?

    Cevap

    Positive E°cell, corresponding to negative ΔG°.

  421. Kart 421

    Soru

    If Q increases for a galvanic reaction, how does E change at fixed temperature?

    Cevap

    E decreases according to the Nernst equation. Le Châtelier's principle does not apply to an operating cell away from equilibrium; use Q and Nernst reasoning instead.

  422. Kart 422

    Soru

    How are moles of electrons found from charge?

    Cevap

    Moles e⁻ = q/F, where F ≈ 96485 C mol^-1 e⁻.

  423. Kart 423

    Soru

    How does producing more gas particles usually affect system entropy?

    Cevap

    It increases entropy because the particles have more positional microstates.

  424. Kart 424

    Soru

    Can a dissolution with negative ΔH be unfavorable?

    Cevap

    Yes. A sufficiently negative entropy change at the stated temperature can make ΔG positive.

  425. Kart 425

    Soru

    When can a process with ΔH > 0 and ΔS > 0 become favorable?

    Cevap

    At sufficiently high temperature, when TΔS exceeds ΔH.

  426. Kart 426

    Soru

    How does a catalyst affect ΔG?

    Cevap

    It does not change ΔG; it lowers the activation barrier for both directions.

  427. Kart 427

    Soru

    For A → B, ΔGf°(A) = -50 kJ mol^-1 and ΔGf°(B) = -80 kJ mol^-1. What is ΔG°rxn?

    Cevap

    -30 kJ mol^-1. Use ΣνΔGf°(products) − ΣνΔGf°(reactants) = -80 − (-50).

  428. Kart 428

    Soru

    Why can dissolving a gas in a liquid have a negative entropy change?

    Cevap

    Gas particles lose much of their translational freedom when confined and solvated in the liquid.

  429. Kart 429

    Soru

    If coupled steps have ΔG values +20 kJ and -35 kJ, what is overall ΔG?

    Cevap

    -15 kJ, so the combined process is thermodynamically favorable under those conditions.

  430. Kart 430

    Soru

    What role does each half-cell solution play in an electrochemical cell?

    Cevap

    It supplies dissolved redox species at an electrode interface and carries ions within its compartment. Separate compartments prevent direct mixing while the external circuit and salt bridge connect the half-cells.

  431. Kart 431

    Soru

    How is E°cell found from standard reduction potentials?

    Cevap

    E°cell = E°cathode − E°anode, using both tabulated values as reductions.

  432. Kart 432

    Soru

    How does a cell's potential magnitude change as Q approaches or moves away from K, and what is E at equilibrium?

    Cevap

    |E| falls toward zero as Q approaches K and grows as the system moves farther from equilibrium. At equilibrium, Q = K and E = 0.

  433. Kart 433

    Soru

    How many moles of electrons pass when 1.93 × 10^5 C flows?

    Cevap

    2.00 mol e⁻, from q/F.

  434. Kart 434

    Soru

    How does a salt bridge maintain charge balance in a galvanic cell?

    Cevap

    Anions migrate toward the anode compartment and cations toward the cathode compartment, countering the net charge imbalances created by the two half-reactions.

  435. Kart 435

    Soru

    Why does raising a substance's temperature generally increase its entropy?

    Cevap

    Energy spreads across more accessible particle energy states, increasing the number of possible microscopic arrangements.

  436. Kart 436

    Soru

    When can a process with ΔH < 0 and ΔS < 0 be favorable?

    Cevap

    At sufficiently low temperature, where the unfavorable -TΔS term is small.

  437. Kart 437

    Soru

    Why can diamond persist even though graphite is more stable at standard conditions?

    Cevap

    Conversion has a large activation barrier, so diamond is kinetically persistent.

  438. Kart 438

    Soru

    What do the external circuit and measuring device do in an electrochemical cell?

    Cevap

    The circuit carries electrons from anode to cathode; a voltmeter measures potential difference, while an ammeter in series measures current.

  439. Kart 439

    Soru

    At constant temperature, how does increasing the volume available to a gas affect its entropy?

    Cevap

    Entropy increases because the gas particles can occupy more positions in the larger space, so more microstates are accessible.

  440. Kart 440

    Soru

    How does reversing one coupled reaction affect its ΔG?

    Cevap

    It reverses the sign of that reaction's ΔG.

  441. Kart 441

    Soru

    Why is n required in ΔG° = -nFE°?

    Cevap

    It is the moles of electrons transferred per balanced reaction, linking charge flow to reaction extent.

  442. Kart 442

    Soru

    What makes an electrolytic cell operate?

    Cevap

    An external power source drives a thermodynamically unfavorable redox reaction; oxidation still occurs at the anode and reduction at the cathode.

  443. Kart 443

    Soru

    In an Mⁿ⁺/M concentration cell, which half-cell is the anode: the dilute or concentrated ion solution?

    Cevap

    The dilute half-cell. Oxidation produces Mⁿ⁺ there, while reduction consumes Mⁿ⁺ in the concentrated half-cell, so electrons flow from dilute to concentrated as the concentrations move toward equality.

  444. Kart 444

    Soru

    How is deposited metal mass found from current and time?

    Cevap

    Find q = It, convert q/F to moles e⁻, use the half-reaction ratio to moles metal, then multiply by molar mass.

  445. Kart 445

    Soru

    Given product S° total 500 J mol^-1 K^-1 and reactant total 420 J mol^-1 K^-1, what is ΔS°?

    Cevap

    +80 J mol^-1 K^-1.

  446. Kart 446

    Soru

    How do electrode masses change in a Zn–Cu galvanic cell?

    Cevap

    The Zn anode loses mass as Zn → Zn²⁺ + 2e⁻, while the Cu cathode gains mass as Cu²⁺ + 2e⁻ → Cu.

  447. Kart 447

    Soru

    What is ΔG° when ΔH° = 50 kJ mol^-1, ΔS° = 0.200 kJ mol^-1 K^-1, and T = 300 K?

    Cevap

    -10 kJ mol^-1, from ΔG° = 50 − (300)(0.200).

  448. Kart 448

    Soru

    Why can temperature change a solid's solubility?

    Cevap

    Temperature changes the balance of ΔH and TΔS, so it changes the free energy of dissolution and the equilibrium constant.

  449. Kart 449

    Soru

    What does the size of ΔG° relative to RT imply about K?

    Cevap

    ΔG° near zero gives K near 1. When |ΔG°| is much larger than RT, K is far from 1: negative ΔG° gives K ≫ 1, while positive ΔG° gives K ≪ 1.

  450. Kart 450

    Soru

    Bubbles form at an inert cathode in acidic solution; which half-reaction can explain them?

    Cevap

    2H⁺ + 2e⁻ → H₂(g). Gas evolution at the cathode can be direct evidence of reduction.

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AP Chemistry Flashcards: Complete 9-Unit Course Review

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