Bayes’ Theorem Flashcards: Base Rates & Evidence Updates

Practice 48 original Bayes theorem flashcards: build source-and-evidence weights, normalize across all sources, repair base-rate mistakes, and check sequential updates.

Об этой колоде

A signal can be common for one source without making that source likely after the signal. These 48 original Bayes theorem flashcards help you keep the source share, source-specific likelihood, total evidence, and posterior separate.

Start with priors and likelihoods. Then calculate prior × likelihood branch weights for fictional bags, batches, routes, and sensors; add every possible source branch to get the evidence total; and normalize the requested source weight. Two-source updates lead into three-source comparisons and subset posteriors. Short repair prompts target reversed conditions, missing priors or branches, the wrong complement, and branch weights mistaken for posteriors. Six cards handle sequential evidence, including when conditional independence permits multiplication and when a repeated display supplies no new observation.

The sequence introduces each prerequisite before its dependent calculation, then interleaves calculations, interpretations, and repairs. Related variants are spaced so one answer does not directly cue the next; the app’s scheduler handles later review spacing. Each card gives the model assumptions it needs and an explained answer.

This is a focused introductory probability set, not a full statistics or exam course. It avoids two-way-table count drills already covered by the separate conditional-probability deck, mechanical reverse calculations that cannot recover unknown inputs, continuous Bayesian models, odds-form algebra, medical and financial decisions, and claims about real-world sources from toy assumptions. All examples, wording, order, and cover are original. Mathematical facts were checked against NIST’s Engineering Statistics Handbook and MIT OCW’s probability lecture; their prose, exercises, and figures were not copied. AI assisted drafting, followed by individual factual and numerical review. The CC0 label covers only the original expression and generated artwork to the extent rights exist.

Карточки в этой колоде

  1. Карточка 1

    Вопрос

    For a Bayes update over hidden sources, what must the listed sources cover?

    Ответ

    Every possible source, exactly once. The sources must be exhaustive and mutually exclusive so their evidence branches can be added.

  2. Карточка 2

    Вопрос

    Before seeing a result, a token comes from bag A with probability 0.3. What is 0.3 called in a Bayes update?

    Ответ

    The prior for bag A. It is A’s source probability before the result is observed.

  3. Карточка 3

    Вопрос

    A token from bag A is blue with probability 0.8. In a Bayes update after seeing blue, what role does 0.8 play?

    Ответ

    The likelihood of blue given A. It is P(blue | A), not the chance that a blue token came from A.

  4. Карточка 4

    Вопрос

    An observed signal can come from every possible source. What probability belongs in the denominator of a source posterior?

    Ответ

    The total probability of the signal. Add its prior × likelihood branch weight across all possible sources.

  5. Карточка 5

    Вопрос

    Only bags A and B can be chosen. P(A) = 0.3 and P(red | A) = 0.8. What is the joint weight for A and red?

    Ответ

    0.24. Multiply 0.3 × 0.8; this is P(A and red), before normalization.

  6. Карточка 6

    Вопрос

    A bag yields blue with probability 0.8. A learner calls 0.8 the chance the bag was chosen after seeing blue. What is the mistake?

    Ответ

    The condition was reversed. 0.8 is P(blue | bag); P(bag | blue) also needs source priors and the other bags’ blue rates.

  7. Карточка 7

    Вопрос

    Only batches A and B supply parts. Their shares are 0.25 and 0.75; a part is marked with probabilities 0.6 and 0.2, respectively. What is P(marked)?

    Ответ

    0.30. Add both marked branches: 0.25 × 0.6 + 0.75 × 0.2 = 0.15 + 0.15.

  8. Карточка 8

    Вопрос

    A source makes 70% of its tokens striped and supplies 20% of all tokens. A learner uses 0.70 as its striped branch weight. What factor is missing?

    Ответ

    The 0.20 prior. Its striped branch weight is 0.20 × 0.70 = 0.14.

  9. Карточка 9

    Вопрос

    Only routes A and B are possible. Their priors are 0.4 and 0.6; P(chime | A) = 0.9 and P(chime | B) = 0.1. After a chime, what is P(A | chime)?

    Ответ

    6/7. A contributes 0.36; both routes contribute 0.36 + 0.06 = 0.42. Divide 0.36/0.42.

  10. Карточка 10

    Вопрос

    Only A and B exist. A learner divides A’s bell branch weight by itself and calls the result P(A | bell). What denominator term is missing?

    Ответ

    P(B)P(bell | B). The bell denominator must include B’s branch too, if B can produce a bell.

  11. Карточка 11

    Вопрос

    Only bins A and B exist. A’s share rises from 0.1 to 0.4 while P(glow | A) = 0.8 and P(glow | B) = 0.2 stay fixed. Does P(A | glow) rise or fall?

    Ответ

    It rises. The posterior changes from 4/13 to 8/11 because the prior for A increased with both likelihoods fixed.

  12. Карточка 12

    Вопрос

    Only sources A, B, and C exist. Their priors are 0.2, 0.3, 0.5; their beep rates are 0.5, 0.4, 0.2. What is P(beep)?

    Ответ

    0.32. Add every branch: 0.10 + 0.12 + 0.10.

  13. Карточка 13

    Вопрос

    For a source A, a learner uses P(A) × P(A) × P(glow | A) as its glow branch weight. What is the correction?

    Ответ

    Use the prior once. The branch weight is P(A) × P(glow | A).

  14. Карточка 14

    Вопрос

    Only sources A and B exist. A supplies 35% of items. What prior belongs on B’s branch?

    Ответ

    65%. The two source shares must add to 100%.

  15. Карточка 15

    Вопрос

    After a red result, the only three source-and-red weights are A: 0.12, B: 0.08, C: 0.20. What is P(A | red)?

    Ответ

    0.3. The total red weight is 0.40, so normalize A’s 0.12/0.40.

  16. Карточка 16

    Вопрос

    Only A and B are equally likely. Given each source, two new signals are independent. Their likelihoods are 0.8 and 0.6 under A, and 0.2 and 0.3 under B. After both signals, what is P(A | both)?

    Ответ

    8/9. Joint weights are 0.5 × 0.8 × 0.6 = 0.24 for A and 0.5 × 0.2 × 0.3 = 0.03 for B.

  17. Карточка 17

    Вопрос

    Only routes North and South exist. North is used 70% of the time, and P(late | North) = 10%. What is the North-and-late branch weight?

    Ответ

    7%. Multiply 70% × 10%; it is not the posterior P(North | late).

  18. Карточка 18

    Вопрос

    Sources A, B, C have priors 0.1, 0.3, 0.6 and signal likelihoods 0.9, 0.5, 0.4. Which source has the largest signal branch weight?

    Ответ

    C. The weights are 0.09, 0.15, and 0.24; A has the largest likelihood but not the largest contribution.

  19. Карточка 19

    Вопрос

    A model gives signal rates for sources A and B but says a third source may exist, without its share or signal rate. Can P(A | signal) be determined?

    Ответ

    No. The evidence total needs every possible source branch; an unmodelled source leaves the denominator incomplete.

  20. Карточка 20

    Вопрос

    Only sources Z and Y are possible. Their priors are 0.3 and 0.7; P(ring | Z) = 0.4 and P(ring | Y) = 0.1. After a ring, what is P(Z | ring)?

    Ответ

    12/19. The branch weights are 0.12 and 0.07; normalize Z’s weight by 0.19.

  21. Карточка 21

    Вопрос

    Only machines A and B produce tokens. Their shares are 0.6 and 0.4, and their stripe rates are 0.25 and 0.5. What is P(stripe)?

    Ответ

    0.35. Add 0.6 × 0.25 and 0.4 × 0.5, giving 0.15 + 0.20.

  22. Карточка 22

    Вопрос

    After a pulse, the only source-and-pulse weights are A: 0.10, B: 0.20, C: 0.30. What is P(A or B | pulse)?

    Ответ

    0.5. A and B contribute 0.30 of the total 0.60 pulse weight.

  23. Карточка 23

    Вопрос

    After one observation, P(A | first result) = 0.7. A genuinely new second result arrives. What prior for A enters the next conditional update?

    Ответ

    0.7. The first posterior becomes the starting probability for the new evidence; its likelihood still needs a model.

  24. Карточка 24

    Вопрос

    After a click, the only branch weights are A: 0.10 and B: 0.30. A learner says P(A | click) = 0.75. What is the corrected value?

    Ответ

    0.25. Normalize A’s weight, 0.10/(0.10 + 0.30); 0.75 belongs to B.

  25. Карточка 25

    Вопрос

    Only bags A and B are possible. Their priors are 0.2 and 0.8; P(star | A) = 0.75 and P(star | B) = 0.25. After seeing a star, what is P(A | star)?

    Ответ

    3/7. A’s star weight is 0.15 and total star weight is 0.15 + 0.20 = 0.35.

  26. Карточка 26

    Вопрос

    Only sources A, B, C have priors 0.25, 0.25, 0.5 and tick likelihoods 0.4, 0.2, 0.3. A proposed P(tick) is 0.15 because it omits C. What is the corrected P(tick)?

    Ответ

    0.30. Add C’s 0.5 × 0.3 = 0.15 to the A and B weights, 0.10 + 0.05.

  27. Карточка 27

    Вопрос

    Only A and B exist and their priors are known. P(ping | A) is known, but P(ping | B) is missing. Is P(A | ping) uniquely determined?

    Ответ

    No. B’s unknown ping contribution changes the denominator.

  28. Карточка 28

    Вопрос

    Only A and B make tiles. P(A) = 0.2, P(B) = 0.8, and P(star | A) = 0.7. A learner uses 0.8 × 0.7 for A’s star branch. What is A’s correct branch weight?

    Ответ

    0.14. A’s prior is 0.2, so multiply 0.2 × 0.7. The 0.8 prior belongs to B.

  29. Карточка 29

    Вопрос

    A learner wants P(not A | ring) but subtracts P(A | no ring) from 1. Which probability should be subtracted from 1?

    Ответ

    P(A | ring). Keep the observed condition fixed when taking the source complement.

  30. Карточка 30

    Вопрос

    After a stripe, the only three source-and-stripe weights are A: 0.06, B: 0.09, C: 0.15. What is P(C | stripe)?

    Ответ

    0.5. Divide C’s 0.15 by the total 0.30.

  31. Карточка 31

    Вопрос

    A sensor result appears twice because the screen refreshed; no second measurement occurred. Should a Bayes update use the same result twice?

    Ответ

    No. A duplicated display supplies no new evidence. Updating twice would count one observation twice.

  32. Карточка 32

    Вопрос

    Only A and B exist. P(A) = 0.1, P(B) = 0.9, P(chime | A) = 0.9, and P(chime | B) = 0.4. A learner chooses A as more likely after a chime because 0.9 > 0.4. Which source is actually more likely?

    Ответ

    B. The chime weights are A: 0.09 and B: 0.36; priors change the comparison.

  33. Карточка 33

    Вопрос

    Only boxes A and B exist. P(A) = 0.3, and both boxes yield a square token with probability 0.4. After seeing a square, what is P(A | square)?

    Ответ

    0.3. Equal likelihoods leave the prior unchanged: 0.3 × 0.4 / 0.4 = 0.3.

  34. Карточка 34

    Вопрос

    Three mutually exclusive sources cover every possibility. After observing a flash with positive probability, what must their three posterior probabilities sum to?

    Ответ

    1. Normalization divides every source-and-flash weight by the same positive total.

  35. Карточка 35

    Вопрос

    Two signals are independent overall, but their dependence given each hidden source is unknown. Can their source-specific likelihoods safely be multiplied?

    Ответ

    No. Multiplication for a source needs independence conditional on that source, or a supplied joint likelihood.

  36. Карточка 36

    Вопрос

    After a pulse, the only two source-and-pulse weights are 0.40 and 0.10. A learner reports the first source’s posterior as 0.40. What is it?

    Ответ

    0.8. Divide 0.40 by the total pulse weight 0.50; a branch weight is not yet a posterior.

  37. Карточка 37

    Вопрос

    Only trays A and B exist and are equally likely. Their dot rates are 0.6 and 0.3. After seeing a dot, what is P(A | dot)?

    Ответ

    2/3. The weights are 0.30 and 0.15; A contributes 0.30/0.45.

  38. Карточка 38

    Вопрос

    Only sensors A, B, C are possible. Their priors are 0.5, 0.3, 0.2 and ping likelihoods are 0.1, 0.4, 0.5. After a ping, what is P(C | ping)?

    Ответ

    10/27. C contributes 0.10; all sources contribute 0.05 + 0.12 + 0.10 = 0.27.

  39. Карточка 39

    Вопрос

    A model assigns an observed flash probability of zero across every possible source. Is P(A | flash) defined by the ordinary Bayes ratio?

    Ответ

    No. Its denominator P(flash) is zero, so the conditional probability is undefined in this discrete model.

  40. Карточка 40

    Вопрос

    Only sources A and B exist. A supplies 5% of items; P(flash | A) = 0.9 and P(flash | B) = 0.1. What is P(flash)?

    Ответ

    0.14. Add 0.05 × 0.9 and 0.95 × 0.1, giving 0.045 + 0.095.

  41. Карточка 41

    Вопрос

    Only A, B, C have priors 0.1, 0.4, 0.5 and mark likelihoods 0.9, 0.1, 0.1. Which source is most probable after a mark?

    Ответ

    A. Its weight 0.09 exceeds B’s 0.04 and C’s 0.05, despite A’s smallest prior.

  42. Карточка 42

    Вопрос

    Signals are independent given source A, but nothing is stated about their dependence given source B. Can both sources’ two-signal branch weights be built by multiplying separate likelihoods?

    Ответ

    No. The B branch still needs P(both signals | B) or conditional independence given B.

  43. Карточка 43

    Вопрос

    A proposed evidence total adds source A, source B, and a third label that includes every B item. What is the structural error?

    Ответ

    B is counted twice. The branches used in a total must be disjoint and cover all possible sources.

  44. Карточка 44

    Вопрос

    An observed click has branch weights 0.12 from source A and 0.18 from source B; A and B are the only sources. What is P(A | click)?

    Ответ

    0.4. Normalize A’s weight: 0.12/(0.12 + 0.18).

  45. Карточка 45

    Вопрос

    After a glow, the only source-and-glow weights are A: 0.08, B: 0.12, C: 0.20. What is P(not C | glow)?

    Ответ

    0.5. A and B contribute 0.20 of the 0.40 total; the complement is taken after conditioning on glow.

  46. Карточка 46

    Вопрос

    A classroom model assigns fixed bag shares and color rates. Does a posterior computed from it establish the source of a real token outside that model?

    Ответ

    No. The result is conditional on the stipulated shares, rates, and source list; a real setting needs checked assumptions and data.

  47. Карточка 47

    Вопрос

    Only sources A and B exist with priors 0.4 and 0.6. Supplied joint likelihoods for two signals are P(both | A) = 0.12 and P(both | B) = 0.24. What is P(A | both)?

    Ответ

    0.25. The weights are 0.4 × 0.12 = 0.048 and 0.6 × 0.24 = 0.144; divide 0.048 by 0.192.

  48. Карточка 48

    Вопрос

    Only sources A and B exist. P(A) = 0.4, P(light | A) = 0.8, and P(light | B) = 0.3. After no light, what is P(A | no light)?

    Ответ

    4/25. No-light weights are 0.4 × 0.2 = 0.08 and 0.6 × 0.7 = 0.42; divide 0.08 by 0.50.

Two small bags of teal and amber wooden tokens beside a bowl containing both colors on a wooden desk.

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Bayes’ Theorem Flashcards: Base Rates & Evidence Updates

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