Bayes’ Theorem Flashcards: Base Rates & Evidence Updates

Practice 48 original Bayes theorem flashcards: build source-and-evidence weights, normalize across all sources, repair base-rate mistakes, and check sequential updates.

Về bộ thẻ này

A signal can be common for one source without making that source likely after the signal. These 48 original Bayes theorem flashcards help you keep the source share, source-specific likelihood, total evidence, and posterior separate.

Start with priors and likelihoods. Then calculate prior × likelihood branch weights for fictional bags, batches, routes, and sensors; add every possible source branch to get the evidence total; and normalize the requested source weight. Two-source updates lead into three-source comparisons and subset posteriors. Short repair prompts target reversed conditions, missing priors or branches, the wrong complement, and branch weights mistaken for posteriors. Six cards handle sequential evidence, including when conditional independence permits multiplication and when a repeated display supplies no new observation.

The sequence introduces each prerequisite before its dependent calculation, then interleaves calculations, interpretations, and repairs. Related variants are spaced so one answer does not directly cue the next; the app’s scheduler handles later review spacing. Each card gives the model assumptions it needs and an explained answer.

This is a focused introductory probability set, not a full statistics or exam course. It avoids two-way-table count drills already covered by the separate conditional-probability deck, mechanical reverse calculations that cannot recover unknown inputs, continuous Bayesian models, odds-form algebra, medical and financial decisions, and claims about real-world sources from toy assumptions. All examples, wording, order, and cover are original. Mathematical facts were checked against NIST’s Engineering Statistics Handbook and MIT OCW’s probability lecture; their prose, exercises, and figures were not copied. AI assisted drafting, followed by individual factual and numerical review. The CC0 label covers only the original expression and generated artwork to the extent rights exist.

Thẻ trong bộ này

  1. Thẻ 1

    Câu hỏi

    For a Bayes update over hidden sources, what must the listed sources cover?

    Câu trả lời

    Every possible source, exactly once. The sources must be exhaustive and mutually exclusive so their evidence branches can be added.

  2. Thẻ 2

    Câu hỏi

    Before seeing a result, a token comes from bag A with probability 0.3. What is 0.3 called in a Bayes update?

    Câu trả lời

    The prior for bag A. It is A’s source probability before the result is observed.

  3. Thẻ 3

    Câu hỏi

    A token from bag A is blue with probability 0.8. In a Bayes update after seeing blue, what role does 0.8 play?

    Câu trả lời

    The likelihood of blue given A. It is P(blue | A), not the chance that a blue token came from A.

  4. Thẻ 4

    Câu hỏi

    An observed signal can come from every possible source. What probability belongs in the denominator of a source posterior?

    Câu trả lời

    The total probability of the signal. Add its prior × likelihood branch weight across all possible sources.

  5. Thẻ 5

    Câu hỏi

    Only bags A and B can be chosen. P(A) = 0.3 and P(red | A) = 0.8. What is the joint weight for A and red?

    Câu trả lời

    0.24. Multiply 0.3 × 0.8; this is P(A and red), before normalization.

  6. Thẻ 6

    Câu hỏi

    A bag yields blue with probability 0.8. A learner calls 0.8 the chance the bag was chosen after seeing blue. What is the mistake?

    Câu trả lời

    The condition was reversed. 0.8 is P(blue | bag); P(bag | blue) also needs source priors and the other bags’ blue rates.

  7. Thẻ 7

    Câu hỏi

    Only batches A and B supply parts. Their shares are 0.25 and 0.75; a part is marked with probabilities 0.6 and 0.2, respectively. What is P(marked)?

    Câu trả lời

    0.30. Add both marked branches: 0.25 × 0.6 + 0.75 × 0.2 = 0.15 + 0.15.

  8. Thẻ 8

    Câu hỏi

    A source makes 70% of its tokens striped and supplies 20% of all tokens. A learner uses 0.70 as its striped branch weight. What factor is missing?

    Câu trả lời

    The 0.20 prior. Its striped branch weight is 0.20 × 0.70 = 0.14.

  9. Thẻ 9

    Câu hỏi

    Only routes A and B are possible. Their priors are 0.4 and 0.6; P(chime | A) = 0.9 and P(chime | B) = 0.1. After a chime, what is P(A | chime)?

    Câu trả lời

    6/7. A contributes 0.36; both routes contribute 0.36 + 0.06 = 0.42. Divide 0.36/0.42.

  10. Thẻ 10

    Câu hỏi

    Only A and B exist. A learner divides A’s bell branch weight by itself and calls the result P(A | bell). What denominator term is missing?

    Câu trả lời

    P(B)P(bell | B). The bell denominator must include B’s branch too, if B can produce a bell.

  11. Thẻ 11

    Câu hỏi

    Only bins A and B exist. A’s share rises from 0.1 to 0.4 while P(glow | A) = 0.8 and P(glow | B) = 0.2 stay fixed. Does P(A | glow) rise or fall?

    Câu trả lời

    It rises. The posterior changes from 4/13 to 8/11 because the prior for A increased with both likelihoods fixed.

  12. Thẻ 12

    Câu hỏi

    Only sources A, B, and C exist. Their priors are 0.2, 0.3, 0.5; their beep rates are 0.5, 0.4, 0.2. What is P(beep)?

    Câu trả lời

    0.32. Add every branch: 0.10 + 0.12 + 0.10.

  13. Thẻ 13

    Câu hỏi

    For a source A, a learner uses P(A) × P(A) × P(glow | A) as its glow branch weight. What is the correction?

    Câu trả lời

    Use the prior once. The branch weight is P(A) × P(glow | A).

  14. Thẻ 14

    Câu hỏi

    Only sources A and B exist. A supplies 35% of items. What prior belongs on B’s branch?

    Câu trả lời

    65%. The two source shares must add to 100%.

  15. Thẻ 15

    Câu hỏi

    After a red result, the only three source-and-red weights are A: 0.12, B: 0.08, C: 0.20. What is P(A | red)?

    Câu trả lời

    0.3. The total red weight is 0.40, so normalize A’s 0.12/0.40.

  16. Thẻ 16

    Câu hỏi

    Only A and B are equally likely. Given each source, two new signals are independent. Their likelihoods are 0.8 and 0.6 under A, and 0.2 and 0.3 under B. After both signals, what is P(A | both)?

    Câu trả lời

    8/9. Joint weights are 0.5 × 0.8 × 0.6 = 0.24 for A and 0.5 × 0.2 × 0.3 = 0.03 for B.

  17. Thẻ 17

    Câu hỏi

    Only routes North and South exist. North is used 70% of the time, and P(late | North) = 10%. What is the North-and-late branch weight?

    Câu trả lời

    7%. Multiply 70% × 10%; it is not the posterior P(North | late).

  18. Thẻ 18

    Câu hỏi

    Sources A, B, C have priors 0.1, 0.3, 0.6 and signal likelihoods 0.9, 0.5, 0.4. Which source has the largest signal branch weight?

    Câu trả lời

    C. The weights are 0.09, 0.15, and 0.24; A has the largest likelihood but not the largest contribution.

  19. Thẻ 19

    Câu hỏi

    A model gives signal rates for sources A and B but says a third source may exist, without its share or signal rate. Can P(A | signal) be determined?

    Câu trả lời

    No. The evidence total needs every possible source branch; an unmodelled source leaves the denominator incomplete.

  20. Thẻ 20

    Câu hỏi

    Only sources Z and Y are possible. Their priors are 0.3 and 0.7; P(ring | Z) = 0.4 and P(ring | Y) = 0.1. After a ring, what is P(Z | ring)?

    Câu trả lời

    12/19. The branch weights are 0.12 and 0.07; normalize Z’s weight by 0.19.

  21. Thẻ 21

    Câu hỏi

    Only machines A and B produce tokens. Their shares are 0.6 and 0.4, and their stripe rates are 0.25 and 0.5. What is P(stripe)?

    Câu trả lời

    0.35. Add 0.6 × 0.25 and 0.4 × 0.5, giving 0.15 + 0.20.

  22. Thẻ 22

    Câu hỏi

    After a pulse, the only source-and-pulse weights are A: 0.10, B: 0.20, C: 0.30. What is P(A or B | pulse)?

    Câu trả lời

    0.5. A and B contribute 0.30 of the total 0.60 pulse weight.

  23. Thẻ 23

    Câu hỏi

    After one observation, P(A | first result) = 0.7. A genuinely new second result arrives. What prior for A enters the next conditional update?

    Câu trả lời

    0.7. The first posterior becomes the starting probability for the new evidence; its likelihood still needs a model.

  24. Thẻ 24

    Câu hỏi

    After a click, the only branch weights are A: 0.10 and B: 0.30. A learner says P(A | click) = 0.75. What is the corrected value?

    Câu trả lời

    0.25. Normalize A’s weight, 0.10/(0.10 + 0.30); 0.75 belongs to B.

  25. Thẻ 25

    Câu hỏi

    Only bags A and B are possible. Their priors are 0.2 and 0.8; P(star | A) = 0.75 and P(star | B) = 0.25. After seeing a star, what is P(A | star)?

    Câu trả lời

    3/7. A’s star weight is 0.15 and total star weight is 0.15 + 0.20 = 0.35.

  26. Thẻ 26

    Câu hỏi

    Only sources A, B, C have priors 0.25, 0.25, 0.5 and tick likelihoods 0.4, 0.2, 0.3. A proposed P(tick) is 0.15 because it omits C. What is the corrected P(tick)?

    Câu trả lời

    0.30. Add C’s 0.5 × 0.3 = 0.15 to the A and B weights, 0.10 + 0.05.

  27. Thẻ 27

    Câu hỏi

    Only A and B exist and their priors are known. P(ping | A) is known, but P(ping | B) is missing. Is P(A | ping) uniquely determined?

    Câu trả lời

    No. B’s unknown ping contribution changes the denominator.

  28. Thẻ 28

    Câu hỏi

    Only A and B make tiles. P(A) = 0.2, P(B) = 0.8, and P(star | A) = 0.7. A learner uses 0.8 × 0.7 for A’s star branch. What is A’s correct branch weight?

    Câu trả lời

    0.14. A’s prior is 0.2, so multiply 0.2 × 0.7. The 0.8 prior belongs to B.

  29. Thẻ 29

    Câu hỏi

    A learner wants P(not A | ring) but subtracts P(A | no ring) from 1. Which probability should be subtracted from 1?

    Câu trả lời

    P(A | ring). Keep the observed condition fixed when taking the source complement.

  30. Thẻ 30

    Câu hỏi

    After a stripe, the only three source-and-stripe weights are A: 0.06, B: 0.09, C: 0.15. What is P(C | stripe)?

    Câu trả lời

    0.5. Divide C’s 0.15 by the total 0.30.

  31. Thẻ 31

    Câu hỏi

    A sensor result appears twice because the screen refreshed; no second measurement occurred. Should a Bayes update use the same result twice?

    Câu trả lời

    No. A duplicated display supplies no new evidence. Updating twice would count one observation twice.

  32. Thẻ 32

    Câu hỏi

    Only A and B exist. P(A) = 0.1, P(B) = 0.9, P(chime | A) = 0.9, and P(chime | B) = 0.4. A learner chooses A as more likely after a chime because 0.9 > 0.4. Which source is actually more likely?

    Câu trả lời

    B. The chime weights are A: 0.09 and B: 0.36; priors change the comparison.

  33. Thẻ 33

    Câu hỏi

    Only boxes A and B exist. P(A) = 0.3, and both boxes yield a square token with probability 0.4. After seeing a square, what is P(A | square)?

    Câu trả lời

    0.3. Equal likelihoods leave the prior unchanged: 0.3 × 0.4 / 0.4 = 0.3.

  34. Thẻ 34

    Câu hỏi

    Three mutually exclusive sources cover every possibility. After observing a flash with positive probability, what must their three posterior probabilities sum to?

    Câu trả lời

    1. Normalization divides every source-and-flash weight by the same positive total.

  35. Thẻ 35

    Câu hỏi

    Two signals are independent overall, but their dependence given each hidden source is unknown. Can their source-specific likelihoods safely be multiplied?

    Câu trả lời

    No. Multiplication for a source needs independence conditional on that source, or a supplied joint likelihood.

  36. Thẻ 36

    Câu hỏi

    After a pulse, the only two source-and-pulse weights are 0.40 and 0.10. A learner reports the first source’s posterior as 0.40. What is it?

    Câu trả lời

    0.8. Divide 0.40 by the total pulse weight 0.50; a branch weight is not yet a posterior.

  37. Thẻ 37

    Câu hỏi

    Only trays A and B exist and are equally likely. Their dot rates are 0.6 and 0.3. After seeing a dot, what is P(A | dot)?

    Câu trả lời

    2/3. The weights are 0.30 and 0.15; A contributes 0.30/0.45.

  38. Thẻ 38

    Câu hỏi

    Only sensors A, B, C are possible. Their priors are 0.5, 0.3, 0.2 and ping likelihoods are 0.1, 0.4, 0.5. After a ping, what is P(C | ping)?

    Câu trả lời

    10/27. C contributes 0.10; all sources contribute 0.05 + 0.12 + 0.10 = 0.27.

  39. Thẻ 39

    Câu hỏi

    A model assigns an observed flash probability of zero across every possible source. Is P(A | flash) defined by the ordinary Bayes ratio?

    Câu trả lời

    No. Its denominator P(flash) is zero, so the conditional probability is undefined in this discrete model.

  40. Thẻ 40

    Câu hỏi

    Only sources A and B exist. A supplies 5% of items; P(flash | A) = 0.9 and P(flash | B) = 0.1. What is P(flash)?

    Câu trả lời

    0.14. Add 0.05 × 0.9 and 0.95 × 0.1, giving 0.045 + 0.095.

  41. Thẻ 41

    Câu hỏi

    Only A, B, C have priors 0.1, 0.4, 0.5 and mark likelihoods 0.9, 0.1, 0.1. Which source is most probable after a mark?

    Câu trả lời

    A. Its weight 0.09 exceeds B’s 0.04 and C’s 0.05, despite A’s smallest prior.

  42. Thẻ 42

    Câu hỏi

    Signals are independent given source A, but nothing is stated about their dependence given source B. Can both sources’ two-signal branch weights be built by multiplying separate likelihoods?

    Câu trả lời

    No. The B branch still needs P(both signals | B) or conditional independence given B.

  43. Thẻ 43

    Câu hỏi

    A proposed evidence total adds source A, source B, and a third label that includes every B item. What is the structural error?

    Câu trả lời

    B is counted twice. The branches used in a total must be disjoint and cover all possible sources.

  44. Thẻ 44

    Câu hỏi

    An observed click has branch weights 0.12 from source A and 0.18 from source B; A and B are the only sources. What is P(A | click)?

    Câu trả lời

    0.4. Normalize A’s weight: 0.12/(0.12 + 0.18).

  45. Thẻ 45

    Câu hỏi

    After a glow, the only source-and-glow weights are A: 0.08, B: 0.12, C: 0.20. What is P(not C | glow)?

    Câu trả lời

    0.5. A and B contribute 0.20 of the 0.40 total; the complement is taken after conditioning on glow.

  46. Thẻ 46

    Câu hỏi

    A classroom model assigns fixed bag shares and color rates. Does a posterior computed from it establish the source of a real token outside that model?

    Câu trả lời

    No. The result is conditional on the stipulated shares, rates, and source list; a real setting needs checked assumptions and data.

  47. Thẻ 47

    Câu hỏi

    Only sources A and B exist with priors 0.4 and 0.6. Supplied joint likelihoods for two signals are P(both | A) = 0.12 and P(both | B) = 0.24. What is P(A | both)?

    Câu trả lời

    0.25. The weights are 0.4 × 0.12 = 0.048 and 0.6 × 0.24 = 0.144; divide 0.048 by 0.192.

  48. Thẻ 48

    Câu hỏi

    Only sources A and B exist. P(A) = 0.4, P(light | A) = 0.8, and P(light | B) = 0.3. After no light, what is P(A | no light)?

    Câu trả lời

    4/25. No-light weights are 0.4 × 0.2 = 0.08 and 0.6 × 0.7 = 0.42; divide 0.08 by 0.50.

Two small bags of teal and amber wooden tokens beside a bowl containing both colors on a wooden desk.

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Bayes’ Theorem Flashcards: Base Rates & Evidence Updates

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